如何在Django模板的词典中遍历词典?-Python 实用宝典

如何在Django模板的词典中遍历词典?

我的字典看起来像这样(字典中的字典): {'0': { 'chosen_unit': <Unit: Kg>, 'cost': Decimal('10.0000'), 'unit__name_abbrev': u'G', 'supplier__supplier': u"Steve's Meat Locker", 'price': Decimal('5.00'), 'supplier__address': u'No\r\naddress here', 'chosen_unit_amount': u'2', 'city__name': u'Joburg, Central', 'supplier__phone_number': u'02299944444', 'supplier__website': None, 'supplier__price_list': u'', 'supplier__email': u'ss.sss@ssssss.com', 'unit__name': u'Gram', 'name': u'Rump Bone', }} 现在,我只是想在模板上显示信息,但是我很挣扎。我的模板代码如下: {% if landing_dict.ingredients %} <hr> {% for ingredient in landing_dict.ingredients %} …

问题:如何在Django模板的词典中遍历词典?

我的字典看起来像这样(字典中的字典):

{'0': {
    'chosen_unit': <Unit: Kg>,
    'cost': Decimal('10.0000'),
    'unit__name_abbrev': u'G',
    'supplier__supplier': u"Steve's Meat Locker",
    'price': Decimal('5.00'),
    'supplier__address': u'No\r\naddress here',
    'chosen_unit_amount': u'2',
    'city__name': u'Joburg, Central',
    'supplier__phone_number': u'02299944444',
    'supplier__website': None,
    'supplier__price_list': u'',
    'supplier__email': u'ss.sss@ssssss.com',
    'unit__name': u'Gram',
    'name': u'Rump Bone',
}}

现在,我只是想在模板上显示信息,但是我很挣扎。我的模板代码如下:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {{ ingredient }}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

它只是在模板上显示“ 0”?

我也尝试过:

{% for ingredient in landing_dict.ingredients %}
  {{ ingredient.cost }}
{% endfor %}

这甚至不显示结果。

我认为也许我需要更深一层地迭代,所以尝试了一下:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {% for field in ingredient %}
      {{ field }}
    {% endfor %}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

但这不会显示任何内容。

我究竟做错了什么?

My dictionary looks like this(Dictionary within a dictionary):

{'0': {
    'chosen_unit': <Unit: Kg>,
    'cost': Decimal('10.0000'),
    'unit__name_abbrev': u'G',
    'supplier__supplier': u"Steve's Meat Locker",
    'price': Decimal('5.00'),
    'supplier__address': u'No\r\naddress here',
    'chosen_unit_amount': u'2',
    'city__name': u'Joburg, Central',
    'supplier__phone_number': u'02299944444',
    'supplier__website': None,
    'supplier__price_list': u'',
    'supplier__email': u'ss.sss@ssssss.com',
    'unit__name': u'Gram',
    'name': u'Rump Bone',
}}

Now I'm just trying to display the information on my template but I'm struggling. My code for the template looks like:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {{ ingredient }}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

It just shows me '0' on my template?

I also tried:

{% for ingredient in landing_dict.ingredients %}
  {{ ingredient.cost }}
{% endfor %}

This doesn't even display a result.

I thought perhaps I need to iterate one level deeper so tried this:

{% if landing_dict.ingredients %}
  <hr>
  {% for ingredient in landing_dict.ingredients %}
    {% for field in ingredient %}
      {{ field }}
    {% endfor %}
  {% endfor %}
  <a href="/">Print {{ landing_dict.recipe_name }}</a>
{% else %}
  Please search for an ingredient below
{% endif %}

But this doesn't display anything.

What am I doing wrong?


回答 0

可以说您的数据是-

data = {'a': [ [1, 2] ], 'b': [ [3, 4] ],'c':[ [5,6]] }

您可以使用该data.items()方法来获取字典元素。请注意,在Django模板中,我们不放置()。另外提到的一些用户values[0]不起作用,如果是这种情况,请尝试values.items

<table>
    <tr>
        <td>a</td>
        <td>b</td>
        <td>c</td>
    </tr>

    {% for key, values in data.items %}
    <tr>
        <td>{{key}}</td>
        {% for v in values[0] %}
        <td>{{v}}</td>
        {% endfor %}
    </tr>
    {% endfor %}
</table>

相当确定您可以将此逻辑扩展到您的特定字典。


要以排序的顺序遍历dict键 -首先,我们在python中排序,然后在django模板中进行迭代和渲染。

return render_to_response('some_page.html', {'data': sorted(data.items())})

在模板文件中:

{% for key, value in data %}
    <tr>
        <td> Key: {{ key }} </td> 
        <td> Value: {{ value }} </td>
    </tr>
{% endfor %}

Lets say your data is -

data = {'a': [ [1, 2] ], 'b': [ [3, 4] ],'c':[ [5,6]] }

You can use the data.items() method to get the dictionary elements. Note, in django templates we do NOT put (). Also some users mentioned values[0] does not work, if that is the case then try values.items.

<table>
    <tr>
        <td>a</td>
        <td>b</td>
        <td>c</td>
    </tr>

    {% for key, values in data.items %}
    <tr>
        <td>{{key}}</td>
        {% for v in values[0] %}
        <td>{{v}}</td>
        {% endfor %}
    </tr>
    {% endfor %}
</table>

Am pretty sure you can extend this logic to your specific dict.


To iterate over dict keys in a sorted order - First we sort in python then iterate & render in django template.

return render_to_response('some_page.html', {'data': sorted(data.items())})

In template file:

{% for key, value in data %}
    <tr>
        <td> Key: {{ key }} </td> 
        <td> Value: {{ value }} </td>
    </tr>
{% endfor %}

回答 1

这个答案对我没有用,但是我自己找到了答案。但是,没有人发布我的问题。我懒得先问再回答,所以就把它放在这里。

这用于以下查询:

data = Leaderboard.objects.filter(id=custom_user.id).values(
    'value1',
    'value2',
    'value3')

在模板中:

{% for dictionary in data %}
  {% for key, value in dictionary.items %}
    <p>{{ key }} : {{ value }}</p>
  {% endfor %}
{% endfor %}

This answer didn't work for me, but I found the answer myself. No one, however, has posted my question. I'm too lazy to ask it and then answer it, so will just put it here.

This is for the following query:

data = Leaderboard.objects.filter(id=custom_user.id).values(
    'value1',
    'value2',
    'value3')

In template:

{% for dictionary in data %}
  {% for key, value in dictionary.items %}
    <p>{{ key }} : {{ value }}</p>
  {% endfor %}
{% endfor %}

回答 2

如果将变量data(字典类型)作为上下文传递给模板,则代码应为:

{% for key, value in data.items %}
    <p>{{ key }} : {{ value }}</p> 
{% endfor %}

If you pass a variable data (dictionary type) as context to a template, then you code should be:

{% for key, value in data.items %}
    <p>{{ key }} : {{ value }}</p> 
{% endfor %}

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