将两个LISTS的值之和添加到新的LIST中-Python 实用宝典

将两个LISTS的值之和添加到新的LIST中

我有以下两个列表: first = [1,2,3,4,5] second = [6,7,8,9,10] 现在,我想将这两个列表中的项目添加到新列表中。 输出应该是 third = [7,9,11,13,15]

问题:将两个LISTS的值之和添加到新的LIST中

我有以下两个列表:

first = [1,2,3,4,5]
second = [6,7,8,9,10]

现在,我想将这两个列表中的项目添加到新列表中。

输出应该是

third = [7,9,11,13,15]

I have the following two lists:

first = [1,2,3,4,5]
second = [6,7,8,9,10]

Now I want to add the items from both of these lists into a new list.

output should be

third = [7,9,11,13,15]

回答 0

zip功能在此处有用,可与列表推导一起使用。

[x + y for x, y in zip(first, second)]

如果您有一个列表列表(而不是两个列表):

lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum(x) for x in zip(*lists_of_lists)]
# -> [5, 7, 9]

The zip function is useful here, used with a list comprehension.

[x + y for x, y in zip(first, second)]

If you have a list of lists (instead of just two lists):

lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum(x) for x in zip(*lists_of_lists)]
# -> [5, 7, 9]

回答 1

来自文档

import operator
list(map(operator.add, first,second))

From docs

import operator
list(map(operator.add, first,second))

回答 2

假设两个列表a,并b具有相同的长度,你不需要压缩,numpy的或其他任何东西。

Python 2.x和3.x:

[a[i]+b[i] for i in range(len(a))]

Assuming both lists a and b have same length, you do not need zip, numpy or anything else.

Python 2.x and 3.x:

[a[i]+b[i] for i in range(len(a))]

回答 3

numpy中的默认行为是逐组件添加

import numpy as np
np.add(first, second)

哪个输出

array([7,9,11,13,15])

Default behavior in numpy is add componentwise

import numpy as np
np.add(first, second)

which outputs

array([7,9,11,13,15])

回答 4

这可以扩展到任意数量的列表:

[sum(sublist) for sublist in itertools.izip(*myListOfLists)]

在你的情况下,myListOfLists[first, second]

This extends itself to any number of lists:

[sum(sublist) for sublist in itertools.izip(*myListOfLists)]

In your case, myListOfLists would be [first, second]


回答 5

尝试以下代码:

first = [1, 2, 3, 4]
second = [2, 3, 4, 5]
third = map(sum, zip(first, second))

Try the following code:

first = [1, 2, 3, 4]
second = [2, 3, 4, 5]
third = map(sum, zip(first, second))

回答 6

执行此操作的简单方法和快速方法是:

three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]

另外,您可以使用numpy sum:

from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])

The easy way and fast way to do this is:

three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]

Alternatively, you can use numpy sum:

from numpy import sum
three = sum([first,second], axis=0) # array([7,9,11,13,15])

回答 7

first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
three = map(lambda x,y: x+y,first,second)
print three



Output 
[7, 9, 11, 13, 15]
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
three = map(lambda x,y: x+y,first,second)
print three



Output 
[7, 9, 11, 13, 15]

回答 8

一线解决方案

list(map(lambda x,y: x+y, a,b))

one-liner solution

list(map(lambda x,y: x+y, a,b))

回答 9

Thiru在3月17日9:25回答了我的问题。

这更加简单快捷,这是他的解决方案:

执行此操作的简单方法和快速方法是:

 three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]

另外,您可以使用numpy sum:

 from numpy import sum
 three = sum([first,second], axis=0) # array([7,9,11,13,15])

您需要numpy!

numpy数组可以做一些像矢量的操作

import numpy as np
a = [1,2,3,4,5]
b = [6,7,8,9,10]
c = list(np.array(a) + np.array(b))
print c
# [7, 9, 11, 13, 15]

My answer is repeated with Thiru's that answered it in Mar 17 at 9:25.

It was simpler and quicker, here are his solutions:

The easy way and fast way to do this is:

 three = [sum(i) for i in zip(first,second)] # [7,9,11,13,15]

Alternatively, you can use numpy sum:

 from numpy import sum
 three = sum([first,second], axis=0) # array([7,9,11,13,15])

You need numpy!

numpy array could do some operation like vectors
import numpy as np
a = [1,2,3,4,5]
b = [6,7,8,9,10]
c = list(np.array(a) + np.array(b))
print c
# [7, 9, 11, 13, 15]

回答 10

如果未知数量的相同长度的列表,则可以使用以下功能。

在这里,* args接受可变数量的列表参数(但每个参数仅求和相同数量的元素)。再次使用*来解压缩每个列表中的元素。

def sum_lists(*args):
    return list(map(sum, zip(*args)))

a = [1,2,3]
b = [1,2,3]  

sum_lists(a,b)

输出:

[2, 4, 6]

或有3个清单

sum_lists([5,5,5,5,5], [10,10,10,10,10], [4,4,4,4,4])

输出:

[19, 19, 19, 19, 19]

If you have an unknown number of lists of the same length, you can use the below function.

Here the *args accepts a variable number of list arguments (but only sums the same number of elements in each). The * is used again to unpack the elements in each of the lists.

def sum_lists(*args):
    return list(map(sum, zip(*args)))

a = [1,2,3]
b = [1,2,3]  

sum_lists(a,b)

Output:

[2, 4, 6]

Or with 3 lists

sum_lists([5,5,5,5,5], [10,10,10,10,10], [4,4,4,4,4])

Output:

[19, 19, 19, 19, 19]

回答 11

您可以使用zip(),将两个数组“交织”在一起,然后使用map(),它将对一个可迭代对象中的每个元素应用一个函数:

>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> zip(a, b)
[(1, 6), (2, 7), (3, 8), (4, 9), (5, 10)]
>>> map(lambda x: x[0] + x[1], zip(a, b))
[7, 9, 11, 13, 15]

You can use zip(), which will "interleave" the two arrays together, and then map(), which will apply a function to each element in an iterable:

>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> zip(a, b)
[(1, 6), (2, 7), (3, 8), (4, 9), (5, 10)]
>>> map(lambda x: x[0] + x[1], zip(a, b))
[7, 9, 11, 13, 15]

回答 12

这是另一种方法。我们利用python的内部__add__函数:

class SumList(object):
    def __init__(self, this_list):
        self.mylist = this_list

    def __add__(self, other):
        new_list = []
        zipped_list = zip(self.mylist, other.mylist)
        for item in zipped_list:
            new_list.append(item[0] + item[1])
        return SumList(new_list)

    def __repr__(self):
        return str(self.mylist)

list1 = SumList([1,2,3,4,5])
list2 = SumList([10,20,30,40,50])
sum_list1_list2 = list1 + list2
print(sum_list1_list2)

输出量

[11, 22, 33, 44, 55]

Here is another way to do it. We make use of the internal __add__ function of python:

class SumList(object):
    def __init__(self, this_list):
        self.mylist = this_list

    def __add__(self, other):
        new_list = []
        zipped_list = zip(self.mylist, other.mylist)
        for item in zipped_list:
            new_list.append(item[0] + item[1])
        return SumList(new_list)

    def __repr__(self):
        return str(self.mylist)

list1 = SumList([1,2,3,4,5])
list2 = SumList([10,20,30,40,50])
sum_list1_list2 = list1 + list2
print(sum_list1_list2)

Output

[11, 22, 33, 44, 55]

回答 13

如果您还想添加列表中的其余值,则可以使用它(在Python3.5中有效)

def addVectors(v1, v2):
    sum = [x + y for x, y in zip(v1, v2)]
    if not len(v1) >= len(v2):
        sum += v2[len(v1):]
    else:
        sum += v1[len(v2):]

    return sum


#for testing 
if __name__=='__main__':
    a = [1, 2]
    b = [1, 2, 3, 4]
    print(a)
    print(b)
    print(addVectors(a,b))

If you want to add also the rest of the values in the lists you can use this (this is working in Python3.5)

def addVectors(v1, v2):
    sum = [x + y for x, y in zip(v1, v2)]
    if not len(v1) >= len(v2):
        sum += v2[len(v1):]
    else:
        sum += v1[len(v2):]

    return sum


#for testing 
if __name__=='__main__':
    a = [1, 2]
    b = [1, 2, 3, 4]
    print(a)
    print(b)
    print(addVectors(a,b))

回答 14

    first = [1,2,3,4,5]
    second = [6,7,8,9,10]
    #one way
    third = [x + y for x, y in zip(first, second)]
    print("third" , third) 
    #otherway
    fourth = []
    for i,j in zip(first,second):
        global fourth
        fourth.append(i + j)
    print("fourth" , fourth )
#third [7, 9, 11, 13, 15]
#fourth [7, 9, 11, 13, 15]
    first = [1,2,3,4,5]
    second = [6,7,8,9,10]
    #one way
    third = [x + y for x, y in zip(first, second)]
    print("third" , third) 
    #otherway
    fourth = []
    for i,j in zip(first,second):
        global fourth
        fourth.append(i + j)
    print("fourth" , fourth )
#third [7, 9, 11, 13, 15]
#fourth [7, 9, 11, 13, 15]

回答 15

这是另一种方法。它对我来说很好。

N=int(input())
num1 = list(map(int, input().split()))
num2 = list(map(int, input().split()))
sum=[]

for i in range(0,N):
  sum.append(num1[i]+num2[i])

for element in sum:
  print(element, end=" ")

print("")

Here is another way to do it.It is working fine for me .

N=int(input())
num1 = list(map(int, input().split()))
num2 = list(map(int, input().split()))
sum=[]

for i in range(0,N):
  sum.append(num1[i]+num2[i])

for element in sum:
  print(element, end=" ")

print("")

回答 16

j = min(len(l1), len(l2))
l3 = [l1[i]+l2[i] for i in range(j)]
j = min(len(l1), len(l2))
l3 = [l1[i]+l2[i] for i in range(j)]

回答 17

也许是最简单的方法:

first = [1,2,3,4,5]
second = [6,7,8,9,10]
three=[]

for i in range(0,5):
    three.append(first[i]+second[i])

print(three)

Perhaps the simplest approach:

first = [1,2,3,4,5]
second = [6,7,8,9,10]
three=[]

for i in range(0,5):
    three.append(first[i]+second[i])

print(three)

回答 18

如果您将列表视为numpy数组,则需要轻松对其求和:

import numpy as np

third = np.array(first) + np.array(second)

print third

[7, 9, 11, 13, 15]

If you consider your lists as numpy array, then you need to easily sum them:

import numpy as np

third = np.array(first) + np.array(second)

print third

[7, 9, 11, 13, 15]

回答 19

如果您有不同长度的列表怎么办,那么您可以尝试这样的操作(使用zip_longest

from itertools import zip_longest  # izip_longest for python2.x

l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]

>>> list(map(sum, zip_longest(l1, l2, fillvalue=0)))
[5, 7, 9, 7]

What if you have list with different length, then you can try something like this (using zip_longest)

from itertools import zip_longest  # izip_longest for python2.x

l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]

>>> list(map(sum, zip_longest(l1, l2, fillvalue=0)))
[5, 7, 9, 7]

回答 20

您可以使用此方法,但仅当两个列表的大小相同时,该方法才有效:

first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
third = []

a = len(first)
b = int(0)
while True:
    x = first[b]
    y = second[b]
    ans = x + y
    third.append(ans)
    b = b + 1
    if b == a:
        break

print third

You can use this method but it will work only if both the list are of the same size:

first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
third = []

a = len(first)
b = int(0)
while True:
    x = first[b]
    y = second[b]
    ans = x + y
    third.append(ans)
    b = b + 1
    if b == a:
        break

print third

本文由 Python 实用宝典 作者:Python实用宝典 发表,其版权均为 Python 实用宝典 所有,文章内容系作者个人观点,不代表 Python 实用宝典 对观点赞同或支持。如需转载,请注明文章来源。
13

抱歉,评论已关闭!