问题:如何在Python中创建GUID / UUID

如何在独立于平台的Python中创建GUID?我听说有一种在Windows上使用ActivePython的方法,但这仅是Windows,因为它使用COM。有没有使用普通Python的方法?

How do I create a GUID in Python that is platform independent? I hear there is a method using ActivePython on Windows but it’s Windows only because it uses COM. Is there a method using plain Python?


回答 0

Python 2.5及更高版本中的uuid模块提供了符合RFC的UUID生成。有关详细信息,请参见模块文档和RFC。[ 来源 ]

文件:

示例(在2和3上工作):

>>> import uuid
>>> uuid.uuid4()
UUID('bd65600d-8669-4903-8a14-af88203add38')
>>> str(uuid.uuid4())
'f50ec0b7-f960-400d-91f0-c42a6d44e3d0'
>>> uuid.uuid4().hex
'9fe2c4e93f654fdbb24c02b15259716c'

The uuid module, in Python 2.5 and up, provides RFC compliant UUID generation. See the module docs and the RFC for details. [source]

Docs:

Example (working on 2 and 3):

>>> import uuid
>>> uuid.uuid4()
UUID('bd65600d-8669-4903-8a14-af88203add38')
>>> str(uuid.uuid4())
'f50ec0b7-f960-400d-91f0-c42a6d44e3d0'
>>> uuid.uuid4().hex
'9fe2c4e93f654fdbb24c02b15259716c'

回答 1

如果您使用的是Python 2.5或更高版本,则uuid模块已经包含在Python标准发行版中。

例如:

>>> import uuid
>>> uuid.uuid4()
UUID('5361a11b-615c-42bf-9bdb-e2c3790ada14')

If you’re using Python 2.5 or later, the uuid module is already included with the Python standard distribution.

Ex:

>>> import uuid
>>> uuid.uuid4()
UUID('5361a11b-615c-42bf-9bdb-e2c3790ada14')

回答 2

复制自:https : //docs.python.org/2/library/uuid.html(由于发布的链接无效,并且会不断更新)

>>> import uuid

>>> # make a UUID based on the host ID and current time
>>> uuid.uuid1()
UUID('a8098c1a-f86e-11da-bd1a-00112444be1e')

>>> # make a UUID using an MD5 hash of a namespace UUID and a name
>>> uuid.uuid3(uuid.NAMESPACE_DNS, 'python.org')
UUID('6fa459ea-ee8a-3ca4-894e-db77e160355e')

>>> # make a random UUID
>>> uuid.uuid4()
UUID('16fd2706-8baf-433b-82eb-8c7fada847da')

>>> # make a UUID using a SHA-1 hash of a namespace UUID and a name
>>> uuid.uuid5(uuid.NAMESPACE_DNS, 'python.org')
UUID('886313e1-3b8a-5372-9b90-0c9aee199e5d')

>>> # make a UUID from a string of hex digits (braces and hyphens ignored)
>>> x = uuid.UUID('{00010203-0405-0607-0809-0a0b0c0d0e0f}')

>>> # convert a UUID to a string of hex digits in standard form
>>> str(x)
'00010203-0405-0607-0809-0a0b0c0d0e0f'

>>> # get the raw 16 bytes of the UUID
>>> x.bytes
'\x00\x01\x02\x03\x04\x05\x06\x07\x08\t\n\x0b\x0c\r\x0e\x0f'

>>> # make a UUID from a 16-byte string
>>> uuid.UUID(bytes=x.bytes)
UUID('00010203-0405-0607-0809-0a0b0c0d0e0f')

Copied from : https://docs.python.org/2/library/uuid.html (Since the links posted were not active and they keep updating)

>>> import uuid

>>> # make a UUID based on the host ID and current time
>>> uuid.uuid1()
UUID('a8098c1a-f86e-11da-bd1a-00112444be1e')

>>> # make a UUID using an MD5 hash of a namespace UUID and a name
>>> uuid.uuid3(uuid.NAMESPACE_DNS, 'python.org')
UUID('6fa459ea-ee8a-3ca4-894e-db77e160355e')

>>> # make a random UUID
>>> uuid.uuid4()
UUID('16fd2706-8baf-433b-82eb-8c7fada847da')

>>> # make a UUID using a SHA-1 hash of a namespace UUID and a name
>>> uuid.uuid5(uuid.NAMESPACE_DNS, 'python.org')
UUID('886313e1-3b8a-5372-9b90-0c9aee199e5d')

>>> # make a UUID from a string of hex digits (braces and hyphens ignored)
>>> x = uuid.UUID('{00010203-0405-0607-0809-0a0b0c0d0e0f}')

>>> # convert a UUID to a string of hex digits in standard form
>>> str(x)
'00010203-0405-0607-0809-0a0b0c0d0e0f'

>>> # get the raw 16 bytes of the UUID
>>> x.bytes
'\x00\x01\x02\x03\x04\x05\x06\x07\x08\t\n\x0b\x0c\r\x0e\x0f'

>>> # make a UUID from a 16-byte string
>>> uuid.UUID(bytes=x.bytes)
UUID('00010203-0405-0607-0809-0a0b0c0d0e0f')

回答 3

我将GUID用作数据库类型操作的随机密钥。

对我来说,带有破折号和多余字符的十六进制形式似乎不必要。但我也喜欢表示十六进制数字的字符串,因为它们不包含在某些情况下可能导致问题的字符,例如“ +”,“ =”等,因此非常安全。

我使用的是网址安全的base64字符串,而不是十六进制的。但是,以下内容不符合任何UUID / GUID规范(除了具有所需的随机性之外)。

import base64
import uuid

# get a UUID - URL safe, Base64
def get_a_uuid():
    r_uuid = base64.urlsafe_b64encode(uuid.uuid4().bytes)
    return r_uuid.replace('=', '')

I use GUIDs as random keys for database type operations.

The hexadecimal form, with the dashes and extra characters seem unnecessarily long to me. But I also like that strings representing hexadecimal numbers are very safe in that they do not contain characters that can cause problems in some situations such as ‘+’,’=’, etc..

Instead of hexadecimal, I use a url-safe base64 string. The following does not conform to any UUID/GUID spec though (other than having the required amount of randomness).

import base64
import uuid

# get a UUID - URL safe, Base64
def get_a_uuid():
    r_uuid = base64.urlsafe_b64encode(uuid.uuid4().bytes)
    return r_uuid.replace('=', '')

回答 4

如果您需要为模型或唯一字段的主键传递UUID,则下面的代码将返回UUID对象-

 import uuid
 uuid.uuid4()

如果您需要将UUID用作URL的参数,则可以执行以下代码-

import uuid
str(uuid.uuid4())

如果您想要UUID的十六进制值,则可以执行以下操作-

import uuid    
uuid.uuid4().hex

If you need to pass UUID for a primary key for your model or unique field then below code returns the UUID object –

 import uuid
 uuid.uuid4()

If you need to pass UUID as a parameter for URL you can do like below code –

import uuid
str(uuid.uuid4())

If you want the hex value for a UUID you can do the below one –

import uuid    
uuid.uuid4().hex

回答 5

此功能是完全可配置的,并根据指定的格式生成唯一的uid

例如:-[8,4,4,4,12],这是提到的格式,它将生成以下uuid

LxoYNyXe-7hbQ-caJt-DSdU-PDAht56cMEWi

 import random as r

 def generate_uuid():
        random_string = ''
        random_str_seq = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
        uuid_format = [8, 4, 4, 4, 12]
        for n in uuid_format:
            for i in range(0,n):
                random_string += str(random_str_seq[r.randint(0, len(random_str_seq) - 1)])
            if n != 12:
                random_string += '-'
        return random_string

This function is fully configurable and generates unique uid based on the format specified

eg:- [8, 4, 4, 4, 12] , this is the format mentioned and it will generate the following uuid

LxoYNyXe-7hbQ-caJt-DSdU-PDAht56cMEWi

 import random as r

 def generate_uuid():
        random_string = ''
        random_str_seq = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
        uuid_format = [8, 4, 4, 4, 12]
        for n in uuid_format:
            for i in range(0,n):
                random_string += str(random_str_seq[r.randint(0, len(random_str_seq) - 1)])
            if n != 12:
                random_string += '-'
        return random_string

回答 6

2019年答案(对于Windows):

如果您希望使用永久性的UUID在Windows上唯一标识一台机器,则可以使用以下技巧:(摘自https://stackoverflow.com/a/58416992/8874388的答案)。

from typing import Optional
import re
import subprocess
import uuid

def get_windows_uuid() -> Optional[uuid.UUID]:
    try:
        # Ask Windows for the device's permanent UUID. Throws if command missing/fails.
        txt = subprocess.check_output("wmic csproduct get uuid").decode()

        # Attempt to extract the UUID from the command's result.
        match = re.search(r"\bUUID\b[\s\r\n]+([^\s\r\n]+)", txt)
        if match is not None:
            txt = match.group(1)
            if txt is not None:
                # Remove the surrounding whitespace (newlines, space, etc)
                # and useless dashes etc, by only keeping hex (0-9 A-F) chars.
                txt = re.sub(r"[^0-9A-Fa-f]+", "", txt)

                # Ensure we have exactly 32 characters (16 bytes).
                if len(txt) == 32:
                    return uuid.UUID(txt)
    except:
        pass # Silence subprocess exception.

    return None

print(get_windows_uuid())

使用Windows API获取计算机的永久UUID,然后处理字符串以确保它是有效的UUID,最后返回一个Python对象(https://docs.python.org/3/library/uuid.html),这为您提供了方便使用数据的方式(例如128位整数,十六进制字符串等)。

祝好运!

PS:子进程调用可能被直接调用Windows内核/ DLL的ctypes代替。但是出于我的目的,此功能是我所需要的。它会进行严格的验证并产生正确的结果。

2019 Answer (for Windows):

If you want a permanent UUID that identifies a machine uniquely on Windows, you can use this trick: (Copied from my answer at https://stackoverflow.com/a/58416992/8874388).

from typing import Optional
import re
import subprocess
import uuid

def get_windows_uuid() -> Optional[uuid.UUID]:
    try:
        # Ask Windows for the device's permanent UUID. Throws if command missing/fails.
        txt = subprocess.check_output("wmic csproduct get uuid").decode()

        # Attempt to extract the UUID from the command's result.
        match = re.search(r"\bUUID\b[\s\r\n]+([^\s\r\n]+)", txt)
        if match is not None:
            txt = match.group(1)
            if txt is not None:
                # Remove the surrounding whitespace (newlines, space, etc)
                # and useless dashes etc, by only keeping hex (0-9 A-F) chars.
                txt = re.sub(r"[^0-9A-Fa-f]+", "", txt)

                # Ensure we have exactly 32 characters (16 bytes).
                if len(txt) == 32:
                    return uuid.UUID(txt)
    except:
        pass # Silence subprocess exception.

    return None

print(get_windows_uuid())

Uses Windows API to get the computer’s permanent UUID, then processes the string to ensure it’s a valid UUID, and lastly returns a Python object (https://docs.python.org/3/library/uuid.html) which gives you convenient ways to use the data (such as 128-bit integer, hex string, etc).

Good luck!

PS: The subprocess call could probably be replaced with ctypes directly calling Windows kernel/DLLs. But for my purposes this function is all I need. It does strong validation and produces correct results.


回答 7

查看这篇文章,对我有很大帮助。简而言之,对我来说最好的选择是:

import random 
import string 

# defining function for random 
# string id with parameter 
def ran_gen(size, chars=string.ascii_uppercase + string.digits): 
    return ''.join(random.choice(chars) for x in range(size)) 

# function call for random string 
# generation with size 8 and string  
print (ran_gen(8, "AEIOSUMA23")) 

因为我只需要4-6个随机字符,而不需要笨重的GUID。

Check this post, helped me a lot. In short, the best option for me was:

import random 
import string 

# defining function for random 
# string id with parameter 
def ran_gen(size, chars=string.ascii_uppercase + string.digits): 
    return ''.join(random.choice(chars) for x in range(size)) 

# function call for random string 
# generation with size 8 and string  
print (ran_gen(8, "AEIOSUMA23")) 

Because I needed just 4-6 random characters instead of bulky GUID.


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