问题:如何更新SQLAlchemy行条目?

假设表有三列:usernamepasswordno_of_logins

当用户尝试登录时,将使用查询之类的内容检查条目

user = User.query.filter_by(username=form.username.data).first()

如果密码匹配,他将继续。我想做的是计算用户登录的次数。因此,无论他何时成功登录,我都希望增加该no_of_logins字段并将其存储回用户表。我不确定如何使用SqlAlchemy运行更新查询。

Assume table has three columns: username, password and no_of_logins.

When user tries to login, it’s checked for an entry with a query like

user = User.query.filter_by(username=form.username.data).first()

If password matches, he proceeds further. What I would like to do is count how many times the user logged in. Thus whenever he successfully logs in, I would like to increment the no_of_logins field and store it back to the user table. I’m not sure how to run update query with SqlAlchemy.


回答 0

user.no_of_logins += 1
session.commit()
user.no_of_logins += 1
session.commit()

回答 1

有几种UPDATE使用方法sqlalchemy

1) user.no_of_logins += 1
   session.commit()

2) session.query().\
       filter(User.username == form.username.data).\
       update({"no_of_logins": (User.no_of_logins +1)})
   session.commit()

3) conn = engine.connect()
   stmt = User.update().\
       values(no_of_logins=(User.no_of_logins + 1)).\
       where(User.username == form.username.data)
   conn.execute(stmt)

4) setattr(user, 'no_of_logins', user.no_of_logins+1)
   session.commit()

There are several ways to UPDATE using sqlalchemy

1) user.no_of_logins += 1
   session.commit()

2) session.query().\
       filter(User.username == form.username.data).\
       update({"no_of_logins": (User.no_of_logins +1)})
   session.commit()

3) conn = engine.connect()
   stmt = User.update().\
       values(no_of_logins=(User.no_of_logins + 1)).\
       where(User.username == form.username.data)
   conn.execute(stmt)

4) setattr(user, 'no_of_logins', user.no_of_logins+1)
   session.commit()

回答 2

举例说明澄清已接受答案的重要问题

直到我自己玩弄它之前,我都不了解它,所以我认为还会有其他人感到困惑。假设您正在id == 6no_of_logins == 30启动时的用户和用户一起工作。

# 1 (bad)
user.no_of_logins += 1
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 2 (bad)
user.no_of_logins = user.no_of_logins + 1
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 3 (bad)
setattr(user, 'no_of_logins', user.no_of_logins + 1)
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 4 (ok)
user.no_of_logins = User.no_of_logins + 1
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

# 5 (ok)
setattr(user, 'no_of_logins', User.no_of_logins + 1)
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

重点

通过引用类而不是实例,您可以使SQLAlchemy更加智能地进行增量,使其在数据库端而不是Python端发生。在数据库中执行此操作会更好,因为它不易受到数据损坏的影响(例如,两个客户端尝试同时进行增量操作,而最终结果仅是一次增量而不是两次增量)。我认为,如果您设置了锁或提高了隔离级别,则可以在Python中进行增量操作,但是如果不必这样做,为什么还要打扰呢?

注意事项

如果您要通过产生SQL之类的代码来增加两次SET no_of_logins = no_of_logins + 1,那么您将需要提交或至少刷新两次增加之间的增量,否则总共将只获得一个增量:

# 6 (bad)
user.no_of_logins = User.no_of_logins + 1
user.no_of_logins = User.no_of_logins + 1
session.commit()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

# 7 (ok)
user.no_of_logins = User.no_of_logins + 1
session.flush()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6
user.no_of_logins = User.no_of_logins + 1
session.commit()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

Examples to clarify the important issue in accepted answer’s comments

I didn’t understand it until I played around with it myself, so I figured there would be others who were confused as well. Say you are working on the user whose id == 6 and whose no_of_logins == 30 when you start.

# 1 (bad)
user.no_of_logins += 1
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 2 (bad)
user.no_of_logins = user.no_of_logins + 1
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 3 (bad)
setattr(user, 'no_of_logins', user.no_of_logins + 1)
# result: UPDATE user SET no_of_logins = 31 WHERE user.id = 6

# 4 (ok)
user.no_of_logins = User.no_of_logins + 1
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

# 5 (ok)
setattr(user, 'no_of_logins', User.no_of_logins + 1)
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

The point

By referencing the class instead of the instance, you can get SQLAlchemy to be smarter about incrementing, getting it to happen on the database side instead of the Python side. Doing it within the database is better since it’s less vulnerable to data corruption (e.g. two clients attempt to increment at the same time with a net result of only one increment instead of two). I assume it’s possible to do the incrementing in Python if you set locks or bump up the isolation level, but why bother if you don’t have to?

A caveat

If you are going to increment twice via code that produces SQL like SET no_of_logins = no_of_logins + 1, then you will need to commit or at least flush in between increments, or else you will only get one increment in total:

# 6 (bad)
user.no_of_logins = User.no_of_logins + 1
user.no_of_logins = User.no_of_logins + 1
session.commit()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

# 7 (ok)
user.no_of_logins = User.no_of_logins + 1
session.flush()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6
user.no_of_logins = User.no_of_logins + 1
session.commit()
# result: UPDATE user SET no_of_logins = no_of_logins + 1 WHERE user.id = 6

回答 3

借助user=User.query.filter_by(username=form.username.data).first()声明,您将获得指定用户的user变量。

现在,您可以像一样user.no_of_logins += 1更改新对象变量的值,并使用session的commit方法保存更改。

With the help of user=User.query.filter_by(username=form.username.data).first() statement you will get the specified user in user variable.

Now you can change the value of the new object variable like user.no_of_logins += 1 and save the changes with the session‘s commit method.


回答 4

我写了电报bot,并且在更新行时遇到了一些问题。如果您有模型,请使用此示例

def update_state(chat_id, state):
    try:
        value = Users.query.filter(Users.chat_id == str(chat_id)).first()
        value.state = str(state)
        db.session.flush()
        db.session.commit()
        #db.session.close()
    except:
        print('Error in def update_state')

为什么要使用db.session.flush()?这就是为什么>>> SQLAlchemy:flush()和commit()有什么区别?

I wrote telegram bot, and have some problem with update rows. Use this example, if you have Model

def update_state(chat_id, state):
    try:
        value = Users.query.filter(Users.chat_id == str(chat_id)).first()
        value.state = str(state)
        db.session.flush()
        db.session.commit()
        #db.session.close()
    except:
        print('Error in def update_state')

Why use db.session.flush()? That’s why >>> SQLAlchemy: What’s the difference between flush() and commit()?


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