问题:通过标签选择的熊猫有时返回Series,有时返回DataFrame

在Pandas中,当我选择一个索引中仅包含一个条目的标签时,我会得到一个系列,但是当我选择一个具有多于一个条目的条目时,我就会得到一个数据框。

这是为什么?有没有办法确保我总是取回数据帧?

In [1]: import pandas as pd

In [2]: df = pd.DataFrame(data=range(5), index=[1, 2, 3, 3, 3])

In [3]: type(df.loc[3])
Out[3]: pandas.core.frame.DataFrame

In [4]: type(df.loc[1])
Out[4]: pandas.core.series.Series

In Pandas, when I select a label that only has one entry in the index I get back a Series, but when I select an entry that has more then one entry I get back a data frame.

Why is that? Is there a way to ensure I always get back a data frame?

In [1]: import pandas as pd

In [2]: df = pd.DataFrame(data=range(5), index=[1, 2, 3, 3, 3])

In [3]: type(df.loc[3])
Out[3]: pandas.core.frame.DataFrame

In [4]: type(df.loc[1])
Out[4]: pandas.core.series.Series

回答 0

可以肯定的是,这种行为是不一致的,但是我认为很容易想到这种情况是方便的。无论如何,要每次获取一个DataFrame,只需将一个列表传递给即可loc。还有其他方法,但我认为这是最干净的方法。

In [2]: type(df.loc[[3]])
Out[2]: pandas.core.frame.DataFrame

In [3]: type(df.loc[[1]])
Out[3]: pandas.core.frame.DataFrame

Granted that the behavior is inconsistent, but I think it’s easy to imagine cases where this is convenient. Anyway, to get a DataFrame every time, just pass a list to loc. There are other ways, but in my opinion this is the cleanest.

In [2]: type(df.loc[[3]])
Out[2]: pandas.core.frame.DataFrame

In [3]: type(df.loc[[1]])
Out[3]: pandas.core.frame.DataFrame

回答 1

您有一个包含三个索引项的索引3。因此,df.loc[3]将返回一个数据帧。

原因是您未指定列。因此,df.loc[3]选择所有列中的三个项目(即column 0),同时df.loc[3,0]将返回一个Series。例如df.loc[1:2],由于对行进行了切片,因此它还会返回一个数据框。

选择单个行(如df.loc[1])将返回一个以列名作为索引的Series。

如果要确保始终有一个DataFrame,可以像这样切片df.loc[1:1]。另一个选项是布尔索引(df.loc[df.index==1])或take方法(df.take([0]),但是此使用的位置不是标签!)。

You have an index with three index items 3. For this reason df.loc[3] will return a dataframe.

The reason is that you don’t specify the column. So df.loc[3] selects three items of all columns (which is column 0), while df.loc[3,0] will return a Series. E.g. df.loc[1:2] also returns a dataframe, because you slice the rows.

Selecting a single row (as df.loc[1]) returns a Series with the column names as the index.

If you want to be sure to always have a DataFrame, you can slice like df.loc[1:1]. Another option is boolean indexing (df.loc[df.index==1]) or the take method (df.take([0]), but this used location not labels!).


回答 2

TLDR

使用时 loc

df.loc[:]=数据

df.loc[int]=数据框(如果您有多于一列)和系列(如果您在数据框中只有一列)

df.loc[:, ["col_name"]]=数据

df.loc[:, "col_name"]= 系列

不使用 loc

df["col_name"]= 系列

df[["col_name"]]=数据

The TLDR

When using loc

df.loc[:] = Dataframe

df.loc[int] = Dataframe if you have more than one column and Series if you have only 1 column in the dataframe

df.loc[:, ["col_name"]] = Dataframe

df.loc[:, "col_name"] = Series

Not using loc

df["col_name"] = Series

df[["col_name"]] = Dataframe


回答 3

使用df['columnName']得到一个系列,并df[['columnName']]得到一个数据帧。

Use df['columnName'] to get a Series and df[['columnName']] to get a Dataframe.


回答 4

您在评论joris的答案中写道:

“我不理解将单行转换为系列的设计决策-为什么不将一行数据框呢?”

单行不会在系列中转换
一个系列:No, I don't think so, in fact; see the edit

考虑熊猫数据结构的最佳方法是将其作为低维数据的灵活容器。例如,DataFrame是Series的容器,Panel是DataFrame对象的容器。我们希望能够以类似字典的方式从这些容器中插入和删除对象。

http://pandas.pydata.org/pandas-docs/stable/overview.html#why-more-than-1-data-structure

这样选择了Pandas对象的数据模型。原因当然在于它确保了一些我不知道的优势(我不完全理解引文的最后一句话,也许是原因)

编辑:我不同意

DataFrame不能由可能 Series 的元素组成,因为以下代码为行和列提供相同的“ Series”类型:

import pandas as pd

df = pd.DataFrame(data=[11,12,13], index=[2, 3, 3])

print '-------- df -------------'
print df

print '\n------- df.loc[2] --------'
print df.loc[2]
print 'type(df.loc[1]) : ',type(df.loc[2])

print '\n--------- df[0] ----------'
print df[0]
print 'type(df[0]) : ',type(df[0])

结果

-------- df -------------
    0
2  11
3  12
3  13

------- df.loc[2] --------
0    11
Name: 2, dtype: int64
type(df.loc[1]) :  <class 'pandas.core.series.Series'>

--------- df[0] ----------
2    11
3    12
3    13
Name: 0, dtype: int64
type(df[0]) :  <class 'pandas.core.series.Series'>

因此,没有理由假装DataFrame由Series组成,因为这些Series应该是什么:列或行?愚蠢的问题和远见。

那么什么是DataFrame?

在此答案的先前版本中,我提出了这个问题,试图在他的评论之一中找到Why is that?OP问题部分的答案以及类似的审问single rows to get converted into a series - why not a data frame with one row?
Is there a way to ensure I always get back a data frame?Dan Allan 对此部分做了回答。

然后,正如上面引用的Pandas的文档所述,最好将Pandas的数据结构看作是低维数据的容器,在我看来,对为什么的理解可以从DataFrame结构的性质中找到。

但是,我意识到,不应将引用的建议作为对熊猫数据结构本质的精确描述。
此建议并不意味着DataFrame是Series的容器。
它表示,将DataFrame作为Series的容器的心理表示形式(根据推理的某个时刻考虑的选项是行还是列)是考虑DataFrame的一种好方法,即使实际上并非严格如此。“良好”意味着该愿景可以高效地使用DataFrame。就这样。

那么什么是DataFrame对象?

所述数据帧类产生具有特定结构起源于实例NDFrame基类,本身从派生 PandasContainer基类,也是一个父类的系列类。
请注意,这对于0.12版之前的Pandas才是正确的。在即将发布的0.13版本中,Series也将仅从NDFrame类派生。

# with pandas 0.12

from pandas import Series
print 'Series  :\n',Series
print 'Series.__bases__  :\n',Series.__bases__

from pandas import DataFrame
print '\nDataFrame  :\n',DataFrame
print 'DataFrame.__bases__  :\n',DataFrame.__bases__

print '\n-------------------'

from pandas.core.generic import NDFrame
print '\nNDFrame.__bases__  :\n',NDFrame.__bases__

from pandas.core.generic import PandasContainer
print '\nPandasContainer.__bases__  :\n',PandasContainer.__bases__

from pandas.core.base import PandasObject
print '\nPandasObject.__bases__  :\n',PandasObject.__bases__

from pandas.core.base import StringMixin
print '\nStringMixin.__bases__  :\n',StringMixin.__bases__

结果

Series  :
<class 'pandas.core.series.Series'>
Series.__bases__  :
(<class 'pandas.core.generic.PandasContainer'>, <type 'numpy.ndarray'>)

DataFrame  :
<class 'pandas.core.frame.DataFrame'>
DataFrame.__bases__  :
(<class 'pandas.core.generic.NDFrame'>,)

-------------------

NDFrame.__bases__  :
(<class 'pandas.core.generic.PandasContainer'>,)

PandasContainer.__bases__  :
(<class 'pandas.core.base.PandasObject'>,)

PandasObject.__bases__  :
(<class 'pandas.core.base.StringMixin'>,)

StringMixin.__bases__  :
(<type 'object'>,)

因此,我的理解是,DataFrame实例具有精心设计的某些方法,以控制从行和列中提取数据的方式。

本页介绍了这些提取方法的工作方式:http : //pandas.pydata.org/pandas-docs/stable/indexing.html#indexing
我们在其中找到了Dan Allan给出的方法和其他方法。

为什么这些提取方法是照原样制作的?
当然,这是因为它们被认为是提供更好的可能性和简化数据分析的方法。
这句话正是这样表达的:

考虑熊猫数据结构的最佳方法是将其作为低维数据的灵活容器。

为什么数据从数据帧的实例提取的不在于它的结构,它位于为什么这种结构。我猜想,Pandas数据结构的结构和功能已经过精心设计,以便尽可能地提高智力上的直观性,并且要了解详细信息,必须阅读Wes McKinney的博客。

You wrote in a comment to joris’ answer:

“I don’t understand the design decision for single rows to get converted into a series – why not a data frame with one row?”

A single row isn’t converted in a Series.
It IS a Series: No, I don't think so, in fact; see the edit

The best way to think about the pandas data structures is as flexible containers for lower dimensional data. For example, DataFrame is a container for Series, and Panel is a container for DataFrame objects. We would like to be able to insert and remove objects from these containers in a dictionary-like fashion.

http://pandas.pydata.org/pandas-docs/stable/overview.html#why-more-than-1-data-structure

The data model of Pandas objects has been choosen like that. The reason certainly lies in the fact that it ensures some advantages I don’t know (I don’t fully understand the last sentence of the citation, maybe it’s the reason)

.

Edit : I don’t agree with me

A DataFrame can’t be composed of elements that would be Series, because the following code gives the same type “Series” as well for a row as for a column:

import pandas as pd

df = pd.DataFrame(data=[11,12,13], index=[2, 3, 3])

print '-------- df -------------'
print df

print '\n------- df.loc[2] --------'
print df.loc[2]
print 'type(df.loc[1]) : ',type(df.loc[2])

print '\n--------- df[0] ----------'
print df[0]
print 'type(df[0]) : ',type(df[0])

result

-------- df -------------
    0
2  11
3  12
3  13

------- df.loc[2] --------
0    11
Name: 2, dtype: int64
type(df.loc[1]) :  <class 'pandas.core.series.Series'>

--------- df[0] ----------
2    11
3    12
3    13
Name: 0, dtype: int64
type(df[0]) :  <class 'pandas.core.series.Series'>

So, there is no sense to pretend that a DataFrame is composed of Series because what would these said Series be supposed to be : columns or rows ? Stupid question and vision.

.

Then what is a DataFrame ?

In the previous version of this answer, I asked this question, trying to find the answer to the Why is that? part of the question of the OP and the similar interrogation single rows to get converted into a series - why not a data frame with one row? in one of his comment,
while the Is there a way to ensure I always get back a data frame? part has been answered by Dan Allan.

Then, as the Pandas’ docs cited above says that the pandas’ data structures are best seen as containers of lower dimensional data, it seemed to me that the understanding of the why would be found in the characteristcs of the nature of DataFrame structures.

However, I realized that this cited advice must not be taken as a precise description of the nature of Pandas’ data structures.
This advice doesn’t mean that a DataFrame is a container of Series.
It expresses that the mental representation of a DataFrame as a container of Series (either rows or columns according the option considered at one moment of a reasoning) is a good way to consider DataFrames, even if it isn’t strictly the case in reality. “Good” meaning that this vision enables to use DataFrames with efficiency. That’s all.

.

Then what is a DataFrame object ?

The DataFrame class produces instances that have a particular structure originated in the NDFrame base class, itself derived from the PandasContainer base class that is also a parent class of the Series class.
Note that this is correct for Pandas until version 0.12. In the upcoming version 0.13, Series will derive also from NDFrame class only.

# with pandas 0.12

from pandas import Series
print 'Series  :\n',Series
print 'Series.__bases__  :\n',Series.__bases__

from pandas import DataFrame
print '\nDataFrame  :\n',DataFrame
print 'DataFrame.__bases__  :\n',DataFrame.__bases__

print '\n-------------------'

from pandas.core.generic import NDFrame
print '\nNDFrame.__bases__  :\n',NDFrame.__bases__

from pandas.core.generic import PandasContainer
print '\nPandasContainer.__bases__  :\n',PandasContainer.__bases__

from pandas.core.base import PandasObject
print '\nPandasObject.__bases__  :\n',PandasObject.__bases__

from pandas.core.base import StringMixin
print '\nStringMixin.__bases__  :\n',StringMixin.__bases__

result

Series  :
<class 'pandas.core.series.Series'>
Series.__bases__  :
(<class 'pandas.core.generic.PandasContainer'>, <type 'numpy.ndarray'>)

DataFrame  :
<class 'pandas.core.frame.DataFrame'>
DataFrame.__bases__  :
(<class 'pandas.core.generic.NDFrame'>,)

-------------------

NDFrame.__bases__  :
(<class 'pandas.core.generic.PandasContainer'>,)

PandasContainer.__bases__  :
(<class 'pandas.core.base.PandasObject'>,)

PandasObject.__bases__  :
(<class 'pandas.core.base.StringMixin'>,)

StringMixin.__bases__  :
(<type 'object'>,)

So my understanding is now that a DataFrame instance has certain methods that have been crafted in order to control the way data are extracted from rows and columns.

The ways these extracting methods work are described in this page: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing
We find in it the method given by Dan Allan and other methods.

Why these extracting methods have been crafted as they were ?
That’s certainly because they have been appraised as the ones giving the better possibilities and ease in data analysis.
It’s precisely what is expressed in this sentence:

The best way to think about the pandas data structures is as flexible containers for lower dimensional data.

The why of the extraction of data from a DataFRame instance doesn’t lies in its structure, it lies in the why of this structure. I guess that the structure and functionning of the Pandas’ data structure have been chiseled in order to be as much intellectually intuitive as possible, and that to understand the details, one must read the blog of Wes McKinney.


回答 5

如果目标是使用索引获取数据集的子集,则最好避免使用lociloc。相反,您应该使用类似于以下的语法:

df = pd.DataFrame(data=range(5), index=[1, 2, 3, 3, 3])
result = df[df.index == 3] 
isinstance(result, pd.DataFrame) # True

result = df[df.index == 1]
isinstance(result, pd.DataFrame) # True

If the objective is to get a subset of the data set using the index, it is best to avoid using loc or iloc. Instead you should use syntax similar to this :

df = pd.DataFrame(data=range(5), index=[1, 2, 3, 3, 3])
result = df[df.index == 3] 
isinstance(result, pd.DataFrame) # True

result = df[df.index == 1]
isinstance(result, pd.DataFrame) # True

回答 6

如果您还选择数据框的索引,则结果可以是DataFrame或Series 也可以是Series或标量(单个值)。

此函数可确保您始终从选择中获得列表(如果df,index和column有效):

def get_list_from_df_column(df, index, column):
    df_or_series = df.loc[index,[column]] 
    # df.loc[index,column] is also possible and returns a series or a scalar
    if isinstance(df_or_series, pd.Series):
        resulting_list = df_or_series.tolist() #get list from series
    else:
        resulting_list = df_or_series[column].tolist() 
        # use the column key to get a series from the dataframe
    return(resulting_list)

If you also select on the index of the dataframe then the result can be either a DataFrame or a Series or it can be a Series or a scalar (single value).

This function ensures that you always get a list from your selection (if the df, index and column are valid):

def get_list_from_df_column(df, index, column):
    df_or_series = df.loc[index,[column]] 
    # df.loc[index,column] is also possible and returns a series or a scalar
    if isinstance(df_or_series, pd.Series):
        resulting_list = df_or_series.tolist() #get list from series
    else:
        resulting_list = df_or_series[column].tolist() 
        # use the column key to get a series from the dataframe
    return(resulting_list)

声明:本站所有文章,如无特殊说明或标注,均为本站原创发布。任何个人或组织,在未征得本站同意时,禁止复制、盗用、采集、发布本站内容到任何网站、书籍等各类媒体平台。如若本站内容侵犯了原著者的合法权益,可联系我们进行处理。