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将Python字典转换为kwargs？

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问题：将Python字典转换为kwargs？
回答 0
回答 1
回答 2

问题：将Python字典转换为kwargs？

我想使用类继承构建一个针对sunburnt（solr interface）的查询，因此将键-值对加在一起。sunburnt接口带有关键字参数。如何将字典({'type':'Event'})转换为关键字参数(type='Event')？

点击查看英文原文

I want to build a query for sunburnt(solr interface) using class inheritance and therefore adding key – value pairs together. The sunburnt interface takes keyword arguments. How can I transform a dict ({'type':'Event'}) into keyword arguments (type='Event')?

回答 0

使用双星运算符（又名double-splat？）：

func(**{'type':'Event'})

相当于

func(type='Event')
点击查看英文原文

Use the double-star (aka double-splat?) operator:

func(**{'type':'Event'})

is equivalent to

func(type='Event')

回答 1

** 操作员在这里会有所帮助。

**操作员将解开dict元素的包装，因此**{'type':'Event'}将被视为type='Event'

func(**{'type':'Event'}) 与…相同 func(type='Event') dict元素将转换为相同keyword arguments。

费耶

* 将解压缩列表元素，它们将被视为 positional arguments。

func(*['one', 'two']) 与…相同 func('one', 'two')

点击查看英文原文

** operator would be helpful here.

** operator will unpack the dict elements and thus **{'type':'Event'} would be treated as type='Event'

func(**{'type':'Event'}) is same as func(type='Event') i.e the dict elements would be converted to the keyword arguments.

FYI

* will unpack the list elements and they would be treated as positional arguments.

func(*['one', 'two']) is same as func('one', 'two')

回答 2

这是一个完整的示例，显示了如何使用**运算符将字典中的值作为关键字参数传递。

>>> def f(x=2):
...     print(x)
... 
>>> new_x = {'x': 4}
>>> f()        #    default value x=2
2
>>> f(x=3)     #   explicit value x=3
3
>>> f(**new_x) # dictionary value x=4 
4
点击查看英文原文

Here is a complete example showing how to use the ** operator to pass values from a dictionary as keyword arguments.

>>> def f(x=2):
...     print(x)
... 
>>> new_x = {'x': 4}
>>> f()        #    default value x=2
2
>>> f(x=3)     #   explicit value x=3
3
>>> f(**new_x) # dictionary value x=4 
4

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