问题:创建动态选择字段
我在尝试了解如何在Django中创建动态选择字段时遇到了一些麻烦。我有一个模型设置类似:
class rider(models.Model):
user = models.ForeignKey(User)
waypoint = models.ManyToManyField(Waypoint)
class Waypoint(models.Model):
lat = models.FloatField()
lng = models.FloatField()
我想做的是创建一个选择字段whos的值是与该骑手相关联的航点(将是登录的人)。
目前,我以如下形式覆盖init:
class waypointForm(forms.Form):
def __init__(self, *args, **kwargs):
super(joinTripForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.all()])
但是所有要做的就是列出所有路标,它们与任何特定的骑手都没有关联。有任何想法吗?谢谢。
I’m having some trouble trying to understand how to create a dynamic choice field in django. I have a model set up something like:
class rider(models.Model):
user = models.ForeignKey(User)
waypoint = models.ManyToManyField(Waypoint)
class Waypoint(models.Model):
lat = models.FloatField()
lng = models.FloatField()
What I’m trying to do is create a choice Field whos values are the waypoints associated with that rider (which would be the person logged in).
Currently I’m overriding init in my forms like so:
class waypointForm(forms.Form):
def __init__(self, *args, **kwargs):
super(joinTripForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.all()])
But all that does is list all the waypoints, they’re not associated with any particular rider. Any ideas? Thanks.
回答 0
您可以通过将用户传递给表单init来过滤航点
class waypointForm(forms.Form):
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(
choices=[(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
)
您在启动表单时的视线通过了用户
form = waypointForm(user)
在模型形式的情况下
class waypointForm(forms.ModelForm):
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ModelChoiceField(
queryset=Waypoint.objects.filter(user=user)
)
class Meta:
model = Waypoint
you can filter the waypoints by passing the user to the form init
class waypointForm(forms.Form):
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(
choices=[(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
)
from your view while initiating the form pass the user
form = waypointForm(user)
in case of model form
class waypointForm(forms.ModelForm):
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ModelChoiceField(
queryset=Waypoint.objects.filter(user=user)
)
class Meta:
model = Waypoint
回答 1
有针对您的问题的内置解决方案:ModelChoiceField。
通常,ModelForm
当您需要创建/更改数据库对象时,总是值得尝试使用。在95%的情况下都有效,并且比创建自己的实现要干净得多。
There’s built-in solution for your problem: ModelChoiceField.
Generally, it’s always worth trying to use ModelForm
when you need to create/change database objects. Works in 95% of the cases and it’s much cleaner than creating your own implementation.
回答 2
问题是你什么时候做
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.filter(user=user)])
在更新请求中,先前的值将丢失!
the problem is when you do
def __init__(self, user, *args, **kwargs):
super(waypointForm, self).__init__(*args, **kwargs)
self.fields['waypoints'] = forms.ChoiceField(choices=[ (o.id, str(o)) for o in Waypoint.objects.filter(user=user)])
in a update request, the previous value will lost!
回答 3
在初始化骑乘者实例时将其传递给表单怎么样?
class WaypointForm(forms.Form):
def __init__(self, rider, *args, **kwargs):
super(joinTripForm, self).__init__(*args, **kwargs)
qs = rider.Waypoint_set.all()
self.fields['waypoints'] = forms.ChoiceField(choices=[(o.id, str(o)) for o in qs])
# In view:
rider = request.user
form = WaypointForm(rider)
How about passing the rider instance to the form while initializing it?
class WaypointForm(forms.Form):
def __init__(self, rider, *args, **kwargs):
super(joinTripForm, self).__init__(*args, **kwargs)
qs = rider.Waypoint_set.all()
self.fields['waypoints'] = forms.ChoiceField(choices=[(o.id, str(o)) for o in qs])
# In view:
rider = request.user
form = WaypointForm(rider)
回答 4
在正常选择字段下的工作解决方案下。我的问题是,每个用户都基于很少的条件有自己的CUSTOM选择字段选项。
class SupportForm(BaseForm):
affiliated = ChoiceField(required=False, label='Fieldname', choices=[], widget=Select(attrs={'onchange': 'sysAdminCheck();'}))
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
grid_id = get_user_from_request(self.request)
for l in get_all_choices().filter(user=user_id):
admin = 'y' if l in self.core else 'n'
choice = (('%s_%s' % (l.name, admin)), ('%s' % l.name))
self.affiliated_choices.append(choice)
super(SupportForm, self).__init__(*args, **kwargs)
self.fields['affiliated'].choices = self.affiliated_choice
Underneath working solution with normal choice field. my problem was that each user have their own CUSTOM choicefield options based on few conditions.
class SupportForm(BaseForm):
affiliated = ChoiceField(required=False, label='Fieldname', choices=[], widget=Select(attrs={'onchange': 'sysAdminCheck();'}))
def __init__(self, *args, **kwargs):
self.request = kwargs.pop('request', None)
grid_id = get_user_from_request(self.request)
for l in get_all_choices().filter(user=user_id):
admin = 'y' if l in self.core else 'n'
choice = (('%s_%s' % (l.name, admin)), ('%s' % l.name))
self.affiliated_choices.append(choice)
super(SupportForm, self).__init__(*args, **kwargs)
self.fields['affiliated'].choices = self.affiliated_choice
回答 5
正如Breedly和Liang指出的那样,Ashok的解决方案将阻止您在发布表单时获取选择值。
一种稍微不同但仍然不完善的解决方法是:
class waypointForm(forms.Form):
def __init__(self, user, *args, **kwargs):
self.base_fields['waypoints'].choices = self._do_the_choicy_thing()
super(waypointForm, self).__init__(*args, **kwargs)
但是,这可能会导致一些并发问题。
As pointed by Breedly and Liang, Ashok’s solution will prevent you from getting the select value when posting the form.
One slightly different, but still imperfect, way to solve that would be:
class waypointForm(forms.Form):
def __init__(self, user, *args, **kwargs):
self.base_fields['waypoints'].choices = self._do_the_choicy_thing()
super(waypointForm, self).__init__(*args, **kwargs)
This could cause some concurrence problems, though.
回答 6
您可以将字段声明为表单的一流属性,并且可以动态设置选项:
class WaypointForm(forms.Form):
waypoints = forms.ChoiceField(choices=[])
def __init__(self, user, *args, **kwargs):
super().__init__(*args, **kwargs)
waypoint_choices = [(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
self.fields['waypoints'].choices = waypoint_choices
您也可以使用ModelChoiceField并以类似方式在init上设置queryset。
You can declare the field as a first-class attribute of your form and just set choices dynamically:
class WaypointForm(forms.Form):
waypoints = forms.ChoiceField(choices=[])
def __init__(self, user, *args, **kwargs):
super().__init__(*args, **kwargs)
waypoint_choices = [(o.id, str(o)) for o in Waypoint.objects.filter(user=user)]
self.fields['waypoints'].choices = waypoint_choices
You can also use a ModelChoiceField and set the queryset on init in a similar manner.
回答 7
如果您需要django admin中的动态选择字段;这适用于Django> = 2.1。
class CarAdminForm(forms.ModelForm):
class Meta:
model = Car
def __init__(self, *args, **kwargs):
super(CarForm, self).__init__(*args, **kwargs)
# Now you can make it dynamic.
choices = (
('audi', 'Audi'),
('tesla', 'Tesla')
)
self.fields.get('car_field').choices = choices
car_field = forms.ChoiceField(choices=[])
@admin.register(Car)
class CarAdmin(admin.ModelAdmin):
form = CarAdminForm
希望这可以帮助。
If you need a dynamic choice field in django admin; This works for django >=2.1.
class CarAdminForm(forms.ModelForm):
class Meta:
model = Car
def __init__(self, *args, **kwargs):
super(CarForm, self).__init__(*args, **kwargs)
# Now you can make it dynamic.
choices = (
('audi', 'Audi'),
('tesla', 'Tesla')
)
self.fields.get('car_field').choices = choices
car_field = forms.ChoiceField(choices=[])
@admin.register(Car)
class CarAdmin(admin.ModelAdmin):
form = CarAdminForm
Hope this helps.
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