使用SMTP从Python发送邮件

问题:使用SMTP从Python发送邮件

我正在使用以下方法使用SMTP从Python发送邮件。这是使用的正确方法,还是我想念的陷阱?

from smtplib import SMTP
import datetime

debuglevel = 0

smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('USERNAME@DOMAIN', 'PASSWORD')

from_addr = "John Doe <john@doe.net>"
to_addr = "foo@bar.com"

subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )

message_text = "Hello\nThis is a mail from your server\n\nBye\n"

msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s" 
        % ( from_addr, to_addr, subj, date, message_text )

smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()

I’m using the following method to send mail from Python using SMTP. Is it the right method to use or are there gotchas I’m missing ?

from smtplib import SMTP
import datetime

debuglevel = 0

smtp = SMTP()
smtp.set_debuglevel(debuglevel)
smtp.connect('YOUR.MAIL.SERVER', 26)
smtp.login('USERNAME@DOMAIN', 'PASSWORD')

from_addr = "John Doe <john@doe.net>"
to_addr = "foo@bar.com"

subj = "hello"
date = datetime.datetime.now().strftime( "%d/%m/%Y %H:%M" )

message_text = "Hello\nThis is a mail from your server\n\nBye\n"

msg = "From: %s\nTo: %s\nSubject: %s\nDate: %s\n\n%s" 
        % ( from_addr, to_addr, subj, date, message_text )

smtp.sendmail(from_addr, to_addr, msg)
smtp.quit()

回答 0

我使用的脚本非常相似。我将其张贴在此处,作为如何使用email。*模块生成MIME消息的示例。因此可以轻松修改此脚本以附加图片等。

我依靠我的ISP添加日期时间标头。

我的ISP要求我使用安全的smtp连接发送邮件,我依靠smtplib模块(可从http://www1.cs.columbia.edu/~db2501/ssmtplib.py下载)

就像在脚本中一样,用于在SMTP服务器上进行身份验证的用户名和密码(下面提供了伪值)在源中为纯文本格式。这是一个安全漏洞。但是最好的选择取决于您对这些保护有多认真(想要?)。

======================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message

The script I use is quite similar; I post it here as an example of how to use the email.* modules to generate MIME messages; so this script can be easily modified to attach pictures, etc.

I rely on my ISP to add the date time header.

My ISP requires me to use a secure smtp connection to send mail, I rely on the smtplib module (downloadable at http://www1.cs.columbia.edu/~db2501/ssmtplib.py)

As in your script, the username and password, (given dummy values below), used to authenticate on the SMTP server, are in plain text in the source. This is a security weakness; but the best alternative depends on how careful you need (want?) to be about protecting these.

=======================================

#! /usr/local/bin/python


SMTPserver = 'smtp.att.yahoo.com'
sender =     'me@my_email_domain.net'
destination = ['recipient@her_email_domain.com']

USERNAME = "USER_NAME_FOR_INTERNET_SERVICE_PROVIDER"
PASSWORD = "PASSWORD_INTERNET_SERVICE_PROVIDER"

# typical values for text_subtype are plain, html, xml
text_subtype = 'plain'


content="""\
Test message
"""

subject="Sent from Python"

import sys
import os
import re

from smtplib import SMTP_SSL as SMTP       # this invokes the secure SMTP protocol (port 465, uses SSL)
# from smtplib import SMTP                  # use this for standard SMTP protocol   (port 25, no encryption)

# old version
# from email.MIMEText import MIMEText
from email.mime.text import MIMEText

try:
    msg = MIMEText(content, text_subtype)
    msg['Subject']=       subject
    msg['From']   = sender # some SMTP servers will do this automatically, not all

    conn = SMTP(SMTPserver)
    conn.set_debuglevel(False)
    conn.login(USERNAME, PASSWORD)
    try:
        conn.sendmail(sender, destination, msg.as_string())
    finally:
        conn.quit()

except:
    sys.exit( "mail failed; %s" % "CUSTOM_ERROR" ) # give an error message

回答 1

我通常使用的方法…没什么大的不同

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')

mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())

mailserver.quit()

而已

The method I commonly use…not much different but a little bit

import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEText import MIMEText

msg = MIMEMultipart()
msg['From'] = 'me@gmail.com'
msg['To'] = 'you@gmail.com'
msg['Subject'] = 'simple email in python'
message = 'here is the email'
msg.attach(MIMEText(message))

mailserver = smtplib.SMTP('smtp.gmail.com',587)
# identify ourselves to smtp gmail client
mailserver.ehlo()
# secure our email with tls encryption
mailserver.starttls()
# re-identify ourselves as an encrypted connection
mailserver.ehlo()
mailserver.login('me@gmail.com', 'mypassword')

mailserver.sendmail('me@gmail.com','you@gmail.com',msg.as_string())

mailserver.quit()

That’s it


回答 2

另外,如果您想使用TLS(而不是SSL)执行smtp身份验证,则只需更改端口(使用587)并执行smtp.starttls()。这对我有用:

...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
...

Also if you want to do smtp auth with TLS as opposed to SSL then you just have to change the port (use 587) and do smtp.starttls(). This worked for me:

...
smtp.connect('YOUR.MAIL.SERVER', 587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login('USERNAME@DOMAIN', 'PASSWORD')
...

回答 3

我看到的主要问题是,您没有处理任何错误:.login()和.sendmail()都记录了可以抛出的异常,而且看来.connect()必须有某种方式表明它是无法连接-可能是底层套接字代码引发的异常。

The main gotcha I see is that you’re not handling any errors: .login() and .sendmail() both have documented exceptions that they can throw, and it seems like .connect() must have some way to indicate that it was unable to connect – probably an exception thrown by the underlying socket code.


回答 4

确保您没有任何阻止SMTP的防火墙。我第一次尝试发送电子邮件时,它同时被Windows防火墙和McAfee阻止-花费了很多时间才能找到它们。

Make sure you don’t have any firewalls blocking SMTP. The first time I tried to send an email, it was blocked both by Windows Firewall and McAfee – took forever to find them both.


回答 5

那这个呢?

import smtplib

SERVER = "localhost"

FROM = "sender@example.com"
TO = ["user@example.com"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()

What about this?

import smtplib

SERVER = "localhost"

FROM = "sender@example.com"
TO = ["user@example.com"] # must be a list

SUBJECT = "Hello!"

TEXT = "This message was sent with Python's smtplib."

# Prepare actual message

message = """\
From: %s
To: %s
Subject: %s

%s
""" % (FROM, ", ".join(TO), SUBJECT, TEXT)

# Send the mail

server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()

回答 6

以下代码对我来说很好用:

import smtplib

to = 'mkyong2002@yahoo.com'
gmail_user = 'mkyong2002@gmail.com'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()

参考:http : //www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/

following code is working fine for me:

import smtplib

to = 'mkyong2002@yahoo.com'
gmail_user = 'mkyong2002@gmail.com'
gmail_pwd = 'yourpassword'
smtpserver = smtplib.SMTP("smtp.gmail.com",587)
smtpserver.ehlo()
smtpserver.starttls()
smtpserver.ehlo() # extra characters to permit edit
smtpserver.login(gmail_user, gmail_pwd)
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:testing \n'
print header
msg = header + '\n this is test msg from mkyong.com \n\n'
smtpserver.sendmail(gmail_user, to, msg)
print 'done!'
smtpserver.quit()

Ref: http://www.mkyong.com/python/how-do-send-email-in-python-via-smtplib/


回答 7

您应该确保以正确的格式RFC2822格式化日期。

You should make sure you format the date in the correct format – RFC2822.


回答 8

我使用SMTP发送邮件的示例代码。

import smtplib, ssl

smtp_server = "smtp.gmail.com"
port = 587  # For starttls
sender_email = "sender@email"
receiver_email = "receiver@email"
password = "<your password here>"
message = """ Subject: Hi there

This message is sent from Python."""


# Create a secure SSL context
context = ssl.create_default_context()

# Try to log in to server and send email
server = smtplib.SMTP(smtp_server,port)

try:
    server.ehlo() # Can be omitted
    server.starttls(context=context) # Secure the connection
    server.ehlo() # Can be omitted
    server.login(sender_email, password)
    server.sendmail(sender_email, receiver_email, message)
except Exception as e:
    # Print any error messages to stdout
    print(e)
finally:
    server.quit()

The example code which i did for send mail using SMTP.

import smtplib, ssl

smtp_server = "smtp.gmail.com"
port = 587  # For starttls
sender_email = "sender@email"
receiver_email = "receiver@email"
password = "<your password here>"
message = """ Subject: Hi there

This message is sent from Python."""


# Create a secure SSL context
context = ssl.create_default_context()

# Try to log in to server and send email
server = smtplib.SMTP(smtp_server,port)

try:
    server.ehlo() # Can be omitted
    server.starttls(context=context) # Secure the connection
    server.ehlo() # Can be omitted
    server.login(sender_email, password)
    server.sendmail(sender_email, receiver_email, message)
except Exception as e:
    # Print any error messages to stdout
    print(e)
finally:
    server.quit()

回答 9

查看所有这些宽大的答案?请允许我通过几行来自我推广。

导入并连接:

import yagmail
yag = yagmail.SMTP('john@doe.net', host = 'YOUR.MAIL.SERVER', port = 26)

然后,它只是一线:

yag.send('foo@bar.com', 'hello', 'Hello\nThis is a mail from your server\n\nBye\n')

当它超出范围时,它将实际上关闭(或可以手动关闭)。此外,它将允许您在密钥环中注册用户名,从而不必在脚本中写出密码(在写之前,这确实困扰了我yagmail!)

有关软件包/安装,提示和技巧,请查看gitpip,它们可用于Python 2和3。

See all those lenghty answers? Please allow me to self promote by doing it all in a couple of lines.

Import and Connect:

import yagmail
yag = yagmail.SMTP('john@doe.net', host = 'YOUR.MAIL.SERVER', port = 26)

Then it is just a one-liner:

yag.send('foo@bar.com', 'hello', 'Hello\nThis is a mail from your server\n\nBye\n')

It will actually close when it goes out of scope (or can be closed manually). Furthermore, it will allow you to register your username in your keyring such that you do not have to write out your password in your script (it really bothered me prior to writing yagmail!)

For the package/installation, tips and tricks please look at git or pip, available for both Python 2 and 3.


回答 10

你可以那样做

import smtplib
from email.mime.text import MIMEText
from email.header import Header


server = smtplib.SMTP('mail.servername.com', 25)
server.ehlo()
server.starttls()

server.login('username', 'password')
from = 'me@servername.com'
to = 'mygfriend@servername.com'
body = 'That A Message For My Girl Friend For tell Him If We will go to eat Something This Nigth'
subject = 'Invite to A Diner'
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
message = msg.as_string()
server.sendmail(from, to, message)

you can do like that

import smtplib
from email.mime.text import MIMEText
from email.header import Header


server = smtplib.SMTP('mail.servername.com', 25)
server.ehlo()
server.starttls()

server.login('username', 'password')
from = 'me@servername.com'
to = 'mygfriend@servername.com'
body = 'That A Message For My Girl Friend For tell Him If We will go to eat Something This Nigth'
subject = 'Invite to A Diner'
msg = MIMEText(body,'plain','utf-8')
msg['Subject'] = Header(subject, 'utf-8')
msg['From'] = Header(from, 'utf-8')
msg['To'] = Header(to, 'utf-8')
message = msg.as_string()
server.sendmail(from, to, message)

回答 11

这是Python 3.x的工作示例

#!/usr/bin/env python3

from email.message import EmailMessage
from getpass import getpass
from smtplib import SMTP_SSL
from sys import exit

smtp_server = 'smtp.gmail.com'
username = 'your_email_address@gmail.com'
password = getpass('Enter Gmail password: ')

sender = 'your_email_address@gmail.com'
destination = 'recipient_email_address@gmail.com'
subject = 'Sent from Python 3.x'
content = 'Hello! This was sent to you via Python 3.x!'

# Create a text/plain message
msg = EmailMessage()
msg.set_content(content)

msg['Subject'] = subject
msg['From'] = sender
msg['To'] = destination

try:
    s = SMTP_SSL(smtp_server)
    s.login(username, password)
    try:
        s.send_message(msg)
    finally:
        s.quit()

except Exception as E:
    exit('Mail failed: {}'.format(str(E)))

Here’s a working example for Python 3.x

#!/usr/bin/env python3

from email.message import EmailMessage
from getpass import getpass
from smtplib import SMTP_SSL
from sys import exit

smtp_server = 'smtp.gmail.com'
username = 'your_email_address@gmail.com'
password = getpass('Enter Gmail password: ')

sender = 'your_email_address@gmail.com'
destination = 'recipient_email_address@gmail.com'
subject = 'Sent from Python 3.x'
content = 'Hello! This was sent to you via Python 3.x!'

# Create a text/plain message
msg = EmailMessage()
msg.set_content(content)

msg['Subject'] = subject
msg['From'] = sender
msg['To'] = destination

try:
    s = SMTP_SSL(smtp_server)
    s.login(username, password)
    try:
        s.send_message(msg)
    finally:
        s.quit()

except Exception as E:
    exit('Mail failed: {}'.format(str(E)))

回答 12

基于此示例,我做了以下功能:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def send_email(host, port, user, pwd, recipients, subject, body, html=None, from_=None):
    """ copied and adapted from
        /programming/10147455/how-to-send-an-email-with-gmail-as-provider-using-python#12424439
    returns None if all ok, but if problem then returns exception object
    """

    PORT_LIST = (25, 587, 465)

    FROM = from_ if from_ else user 
    TO = recipients if isinstance(recipients, (list, tuple)) else [recipients]
    SUBJECT = subject
    TEXT = body.encode("utf8") if isinstance(body, unicode) else body
    HTML = html.encode("utf8") if isinstance(html, unicode) else html

    if not html:
        # Prepare actual message
        message = """From: %s\nTo: %s\nSubject: %s\n\n%s
        """ % (FROM, ", ".join(TO), SUBJECT, TEXT)
    else:
                # /programming/882712/sending-html-email-using-python#882770
        msg = MIMEMultipart('alternative')
        msg['Subject'] = SUBJECT
        msg['From'] = FROM
        msg['To'] = ", ".join(TO)

        # Record the MIME types of both parts - text/plain and text/html.
        # utf-8 -> /programming/5910104/python-how-to-send-utf-8-e-mail#5910530
        part1 = MIMEText(TEXT, 'plain', "utf-8")
        part2 = MIMEText(HTML, 'html', "utf-8")

        # Attach parts into message container.
        # According to RFC 2046, the last part of a multipart message, in this case
        # the HTML message, is best and preferred.
        msg.attach(part1)
        msg.attach(part2)

        message = msg.as_string()


    try:
        if port not in PORT_LIST: 
            raise Exception("Port %s not one of %s" % (port, PORT_LIST))

        if port in (465,):
            server = smtplib.SMTP_SSL(host, port)
        else:
            server = smtplib.SMTP(host, port)

        # optional
        server.ehlo()

        if port in (587,): 
            server.starttls()

        server.login(user, pwd)
        server.sendmail(FROM, TO, message)
        server.close()
        # logger.info("SENT_EMAIL to %s: %s" % (recipients, subject))
    except Exception, ex:
        return ex

    return None

如果仅通过,body则将发送纯文本邮件,但是,如果将html论点与论点一起传递body,则将发送html电子邮件(对于不支持html / mime类型的电子邮件客户端,将回退到文本内容)。

用法示例:

ex = send_email(
      host        = 'smtp.gmail.com'
   #, port        = 465 # OK
    , port        = 587  #OK
    , user        = "xxx@gmail.com"
    , pwd         = "xxx"
    , from_       = 'xxx@gmail.com'
    , recipients  = ['yyy@gmail.com']
    , subject     = "Test from python"
    , body        = "Test from python - body"
    )
if ex: 
    print("Mail sending failed: %s" % ex)
else:
    print("OK - mail sent"

顺便说一句。如果要将gmail用作测试或生产SMTP服务器,请启用对安全性较低的应用程序的临时访问或永久访问:

Based on this example I made following function:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

def send_email(host, port, user, pwd, recipients, subject, body, html=None, from_=None):
    """ copied and adapted from
        https://stackoverflow.com/questions/10147455/how-to-send-an-email-with-gmail-as-provider-using-python#12424439
    returns None if all ok, but if problem then returns exception object
    """

    PORT_LIST = (25, 587, 465)

    FROM = from_ if from_ else user 
    TO = recipients if isinstance(recipients, (list, tuple)) else [recipients]
    SUBJECT = subject
    TEXT = body.encode("utf8") if isinstance(body, unicode) else body
    HTML = html.encode("utf8") if isinstance(html, unicode) else html

    if not html:
        # Prepare actual message
        message = """From: %s\nTo: %s\nSubject: %s\n\n%s
        """ % (FROM, ", ".join(TO), SUBJECT, TEXT)
    else:
                # https://stackoverflow.com/questions/882712/sending-html-email-using-python#882770
        msg = MIMEMultipart('alternative')
        msg['Subject'] = SUBJECT
        msg['From'] = FROM
        msg['To'] = ", ".join(TO)

        # Record the MIME types of both parts - text/plain and text/html.
        # utf-8 -> https://stackoverflow.com/questions/5910104/python-how-to-send-utf-8-e-mail#5910530
        part1 = MIMEText(TEXT, 'plain', "utf-8")
        part2 = MIMEText(HTML, 'html', "utf-8")

        # Attach parts into message container.
        # According to RFC 2046, the last part of a multipart message, in this case
        # the HTML message, is best and preferred.
        msg.attach(part1)
        msg.attach(part2)

        message = msg.as_string()


    try:
        if port not in PORT_LIST: 
            raise Exception("Port %s not one of %s" % (port, PORT_LIST))

        if port in (465,):
            server = smtplib.SMTP_SSL(host, port)
        else:
            server = smtplib.SMTP(host, port)

        # optional
        server.ehlo()

        if port in (587,): 
            server.starttls()

        server.login(user, pwd)
        server.sendmail(FROM, TO, message)
        server.close()
        # logger.info("SENT_EMAIL to %s: %s" % (recipients, subject))
    except Exception, ex:
        return ex

    return None

if you pass only body then plain text mail will be sent, but if you pass html argument along with body argument, html email will be sent (with fallback to text content for email clients that don’t support html/mime types).

Example usage:

ex = send_email(
      host        = 'smtp.gmail.com'
   #, port        = 465 # OK
    , port        = 587  #OK
    , user        = "xxx@gmail.com"
    , pwd         = "xxx"
    , from_       = 'xxx@gmail.com'
    , recipients  = ['yyy@gmail.com']
    , subject     = "Test from python"
    , body        = "Test from python - body"
    )
if ex: 
    print("Mail sending failed: %s" % ex)
else:
    print("OK - mail sent"

Btw. If you want to use gmail as testing or production SMTP server, enable temp or permanent access to less secured apps: