问题:在共享内存中使用numpy数组进行多处理
我想在共享内存中使用一个numpy数组,以便与多处理模块一起使用。困难是像numpy数组一样使用它,而不仅仅是ctypes数组。
from multiprocessing import Process, Array
import scipy
def f(a):
a[0] = -a[0]
if __name__ == '__main__':
# Create the array
N = int(10)
unshared_arr = scipy.rand(N)
arr = Array('d', unshared_arr)
print "Originally, the first two elements of arr = %s"%(arr[:2])
# Create, start, and finish the child processes
p = Process(target=f, args=(arr,))
p.start()
p.join()
# Printing out the changed values
print "Now, the first two elements of arr = %s"%arr[:2]
这将产生如下输出:
Originally, the first two elements of arr = [0.3518653236697369, 0.517794725524976]
Now, the first two elements of arr = [-0.3518653236697369, 0.517794725524976]
可以ctypes方式访问该数组,例如arr[i]
说得通。但是,它不是一个numpy数组,因此我无法执行-1*arr
,或arr.sum()
。我想一个解决方案是将ctypes数组转换为numpy数组。但是(除了无法完成这项工作之外),我不相信会再共享它。
对于必须解决的常见问题,似乎将有一个标准解决方案。
回答 0
要添加到@unutbu(不再可用)和@Henry Gomersall的答案中。您可以shared_arr.get_lock()
在需要时使用来同步访问:
shared_arr = mp.Array(ctypes.c_double, N)
# ...
def f(i): # could be anything numpy accepts as an index such another numpy array
with shared_arr.get_lock(): # synchronize access
arr = np.frombuffer(shared_arr.get_obj()) # no data copying
arr[i] = -arr[i]
例
import ctypes
import logging
import multiprocessing as mp
from contextlib import closing
import numpy as np
info = mp.get_logger().info
def main():
logger = mp.log_to_stderr()
logger.setLevel(logging.INFO)
# create shared array
N, M = 100, 11
shared_arr = mp.Array(ctypes.c_double, N)
arr = tonumpyarray(shared_arr)
# fill with random values
arr[:] = np.random.uniform(size=N)
arr_orig = arr.copy()
# write to arr from different processes
with closing(mp.Pool(initializer=init, initargs=(shared_arr,))) as p:
# many processes access the same slice
stop_f = N // 10
p.map_async(f, [slice(stop_f)]*M)
# many processes access different slices of the same array
assert M % 2 # odd
step = N // 10
p.map_async(g, [slice(i, i + step) for i in range(stop_f, N, step)])
p.join()
assert np.allclose(((-1)**M)*tonumpyarray(shared_arr), arr_orig)
def init(shared_arr_):
global shared_arr
shared_arr = shared_arr_ # must be inherited, not passed as an argument
def tonumpyarray(mp_arr):
return np.frombuffer(mp_arr.get_obj())
def f(i):
"""synchronized."""
with shared_arr.get_lock(): # synchronize access
g(i)
def g(i):
"""no synchronization."""
info("start %s" % (i,))
arr = tonumpyarray(shared_arr)
arr[i] = -1 * arr[i]
info("end %s" % (i,))
if __name__ == '__main__':
mp.freeze_support()
main()
如果您不需要同步访问或创建自己的锁,则mp.Array()
没有必要。mp.sharedctypes.RawArray
在这种情况下,您可以使用。
回答 1
该Array
对象具有get_obj()
与之关联的方法,该方法返回呈现缓冲区接口的ctypes数组。我认为以下应该起作用…
from multiprocessing import Process, Array
import scipy
import numpy
def f(a):
a[0] = -a[0]
if __name__ == '__main__':
# Create the array
N = int(10)
unshared_arr = scipy.rand(N)
a = Array('d', unshared_arr)
print "Originally, the first two elements of arr = %s"%(a[:2])
# Create, start, and finish the child process
p = Process(target=f, args=(a,))
p.start()
p.join()
# Print out the changed values
print "Now, the first two elements of arr = %s"%a[:2]
b = numpy.frombuffer(a.get_obj())
b[0] = 10.0
print a[0]
运行时,它将打印出现在的第一个元素a
10.0,显示a
并b
只是进入同一内存的两个视图。
为了确保它仍然是多处理器安全的,我相信您将必须使用对象acquire
和release
上存在的方法,以及其内置的锁以确保可以安全地访问所有对象(尽管我不是专家)多处理器模块)。Array
a
回答 2
尽管已经给出了很好的答案,但是只要满足两个条件,就可以轻松解决此问题:
- 您使用的是POSIX兼容的操作系统(例如Linux,Mac OSX);和
- 您的子进程需要对共享阵列的只读访问权限。
在这种情况下,您无需费心地显式地使变量共享,因为将使用派生来创建子进程。分叉的孩子会自动共享父母的内存空间。在Python多处理的上下文中,这意味着它共享所有模块级变量;请注意,这不适用于您显式传递给子进程或传递给a multiprocessing.Pool
或此类函数的参数。
一个简单的例子:
import multiprocessing
import numpy as np
# will hold the (implicitly mem-shared) data
data_array = None
# child worker function
def job_handler(num):
# built-in id() returns unique memory ID of a variable
return id(data_array), np.sum(data_array)
def launch_jobs(data, num_jobs=5, num_worker=4):
global data_array
data_array = data
pool = multiprocessing.Pool(num_worker)
return pool.map(job_handler, range(num_jobs))
# create some random data and execute the child jobs
mem_ids, sumvals = zip(*launch_jobs(np.random.rand(10)))
# this will print 'True' on POSIX OS, since the data was shared
print(np.all(np.asarray(mem_ids) == id(data_array)))
回答 3
我编写了一个小的python模块,该模块使用POSIX共享内存在python解释器之间共享numpy数组。也许您会发现它很方便。
https://pypi.python.org/pypi/SharedArray
运作方式如下:
import numpy as np
import SharedArray as sa
# Create an array in shared memory
a = sa.create("test1", 10)
# Attach it as a different array. This can be done from another
# python interpreter as long as it runs on the same computer.
b = sa.attach("test1")
# See how they are actually sharing the same memory block
a[0] = 42
print(b[0])
# Destroying a does not affect b.
del a
print(b[0])
# See how "test1" is still present in shared memory even though we
# destroyed the array a.
sa.list()
# Now destroy the array "test1" from memory.
sa.delete("test1")
# The array b is not affected, but once you destroy it then the
# data are lost.
print(b[0])
回答 4
您可以使用以下sharedmem
模块:https : //bitbucket.org/cleemesser/numpy-sharedmem
然后,这是您的原始代码,这一次使用行为类似于NumPy数组的共享内存(请注意调用NumPy sum()
函数的其他最后一条语句):
from multiprocessing import Process
import sharedmem
import scipy
def f(a):
a[0] = -a[0]
if __name__ == '__main__':
# Create the array
N = int(10)
unshared_arr = scipy.rand(N)
arr = sharedmem.empty(N)
arr[:] = unshared_arr.copy()
print "Originally, the first two elements of arr = %s"%(arr[:2])
# Create, start, and finish the child process
p = Process(target=f, args=(arr,))
p.start()
p.join()
# Print out the changed values
print "Now, the first two elements of arr = %s"%arr[:2]
# Perform some NumPy operation
print arr.sum()