问题:在Django中,如何检查用户是否在某个组中?

我在Django的管理站点中创建了一个自定义组。

在我的代码中,我想检查用户是否在该组中。我怎么做?

I created a custom group in Django’s admin site.

In my code, I want to check if a user is in this group. How do I do that?


回答 0

您只需通过上的groups属性即可访问组User

from django.contrib.auth.models import User, Group

group = Group(name = "Editor")
group.save()                    # save this new group for this example
user = User.objects.get(pk = 1) # assuming, there is one initial user 
user.groups.add(group)          # user is now in the "Editor" group

然后user.groups.all()返回[<Group: Editor>]

另外,更直接地,您可以通过以下方式检查用户是否在群组中:

if django_user.groups.filter(name = groupname).exists():

    ...

注意,groupname可以是实际的Django组对象。

You can access the groups simply through the groups attribute on User.

from django.contrib.auth.models import User, Group

group = Group(name = "Editor")
group.save()                    # save this new group for this example
user = User.objects.get(pk = 1) # assuming, there is one initial user 
user.groups.add(group)          # user is now in the "Editor" group

then user.groups.all() returns [<Group: Editor>].

Alternatively, and more directly, you can check if a a user is in a group by:

if django_user.groups.filter(name = groupname).exists():

    ...

Note that groupname can also be the actual Django Group object.


回答 1

您的User对象通过ManyToMany关系链接到Group对象。

因此,您可以将filter方法应用于user.groups

因此,要检查给定的用户是否在某个组中(例如“成员”),只需执行以下操作:

def is_member(user):
    return user.groups.filter(name='Member').exists()

如果要检查给定用户是否属于多个给定组,请使用__in运算符,如下所示:

def is_in_multiple_groups(user):
    return user.groups.filter(name__in=['group1', 'group2']).exists()

请注意,这些功能可以与@user_passes_test装饰器一起使用,以管理对视图的访问:

from django.contrib.auth.decorators import login_required, user_passes_test
@login_required
@user_passes_test(is_member) # or @user_passes_test(is_in_multiple_groups)
def myview(request):
    # Do your processing

希望有帮助

Your User object is linked to the Group object through a ManyToMany relationship.

You can thereby apply the filter method to user.groups.

So, to check if a given User is in a certain group (“Member” for the example), just do this :

def is_member(user):
    return user.groups.filter(name='Member').exists()

If you want to check if a given user belongs to more than one given groups, use the __in operator like so :

def is_in_multiple_groups(user):
    return user.groups.filter(name__in=['group1', 'group2']).exists()

Note that those functions can be used with the @user_passes_test decorator to manage access to your views :

from django.contrib.auth.decorators import login_required, user_passes_test
@login_required
@user_passes_test(is_member) # or @user_passes_test(is_in_multiple_groups)
def myview(request):
    # Do your processing

Hope this help


回答 2

如果需要组中的用户列表,则可以改为:

from django.contrib.auth.models import Group
users_in_group = Group.objects.get(name="group name").user_set.all()

然后检查

 if user in users_in_group:
     # do something

检查用户是否在组中。

If you need the list of users that are in a group, you can do this instead:

from django.contrib.auth.models import Group
users_in_group = Group.objects.get(name="group name").user_set.all()

and then check

 if user in users_in_group:
     # do something

to check if the user is in the group.


回答 3

如果您不需要网站上的用户实例(就像我一样),可以使用

User.objects.filter(pk=userId, groups__name='Editor').exists()

这只会对数据库产生一个请求,并返回一个布尔值。

If you don’t need the user instance on site (as I did), you can do it with

User.objects.filter(pk=userId, groups__name='Editor').exists()

This will produce only one request to the database and return a boolean.


回答 4

如果用户属于某个组,则可以使用以下方法在Django模板中进行检查:

{% if group in request.user.groups.all %} "some action" {% endif %}

If a user belongs to a certain group or not, can be checked in django templates using:

{% if group in request.user.groups.all %} "some action" {% endif %}


回答 5

您只需要一行:

from django.contrib.auth.decorators import user_passes_test  

@user_passes_test(lambda u: u.groups.filter(name='companyGroup').exists())
def you_view():
    return HttpResponse("Since you're logged in, you can see this text!")

You just need one line:

from django.contrib.auth.decorators import user_passes_test  

@user_passes_test(lambda u: u.groups.filter(name='companyGroup').exists())
def you_view():
    return HttpResponse("Since you're logged in, you can see this text!")

回答 6

万一您想检查用户的组是否属于预定义的组列表,以防万一:

def is_allowed(user):
    allowed_group = set(['admin', 'lead', 'manager'])
    usr = User.objects.get(username=user)
    groups = [ x.name for x in usr.groups.all()]
    if allowed_group.intersection(set(groups)):
       return True
    return False

Just in case if you wanna check user’s group belongs to a predefined group list:

def is_allowed(user):
    allowed_group = set(['admin', 'lead', 'manager'])
    usr = User.objects.get(username=user)
    groups = [ x.name for x in usr.groups.all()]
    if allowed_group.intersection(set(groups)):
       return True
    return False

回答 7

我有类似的情况,我想测试用户是否在某个组中。因此,我创建了新文件utils.py,在其中放置了所有有助于整个应用程序的小型实用程序。在那里,我有这个定义:

utils.py

def is_company_admin(user):
    return user.groups.filter(name='company_admin').exists()

所以基本上我正在测试用户是否在company_admin组中,为了清楚起见,我将此函数称为is_company_admin

当我要检查用户是否在company_admin中时,只需执行以下操作:

views.py

from .utils import *

if is_company_admin(request.user):
        data = Company.objects.all().filter(id=request.user.company.id)

现在,如果您希望在模板中进行测试,则可以在上下文中添加is_user_admin,如下所示:

views.py

return render(request, 'admin/users.html', {'data': data, 'is_company_admin': is_company_admin(request.user)})

现在,您可以在模板中评估您的响应:

users.html

{% if is_company_admin %}
     ... do something ...
{% endif %}

简单而干净的解决方案,基于可以在该线程的较早版本中找到的答案,但是以不同的方式进行。希望它会帮助某人。

在Django 3.0.4中测试。

I have similar situation, I wanted to test if the user is in a certain group. So, I’ve created new file utils.py where I put all my small utilities that help me through entire application. There, I’ve have this definition:

utils.py

def is_company_admin(user):
    return user.groups.filter(name='company_admin').exists()

so basically I am testing if the user is in the group company_admin and for clarity I’ve called this function is_company_admin.

When I want to check if the user is in the company_admin I just do this:

views.py

from .utils import *

if is_company_admin(request.user):
        data = Company.objects.all().filter(id=request.user.company.id)

Now, if you wish to test same in your template, you can add is_user_admin in your context, something like this:

views.py

return render(request, 'admin/users.html', {'data': data, 'is_company_admin': is_company_admin(request.user)})

Now you can evaluate you response in a template:

users.html

{% if is_company_admin %}
     ... do something ...
{% endif %}

Simple and clean solution, based on answers that can be found earlier in this thread, but done differently. Hope it will help someone.

Tested in Django 3.0.4.


回答 8

一行:

'Groupname' in user.groups.values_list('name', flat=True)

这等于TrueFalse

In one line:

'Groupname' in user.groups.values_list('name', flat=True)

This evaluates to either True or False.


回答 9

我已经按照以下方式完成了。似乎效率低下,但我心中没有其他选择:

@login_required
def list_track(request):

usergroup = request.user.groups.values_list('name', flat=True).first()
if usergroup in 'appAdmin':
    tracks = QuestionTrack.objects.order_by('pk')
    return render(request, 'cmit/appadmin/list_track.html', {'tracks': tracks})

else:
    return HttpResponseRedirect('/cmit/loggedin')

I have done it the following way. Seems inefficient but I had no other way in my mind:

@login_required
def list_track(request):

usergroup = request.user.groups.values_list('name', flat=True).first()
if usergroup in 'appAdmin':
    tracks = QuestionTrack.objects.order_by('pk')
    return render(request, 'cmit/appadmin/list_track.html', {'tracks': tracks})

else:
    return HttpResponseRedirect('/cmit/loggedin')

回答 10

User.objects.filter(username='tom', groups__name='admin').exists()

该查询将通知您用户:“ tom”是否属于“ admin”组

User.objects.filter(username='tom', groups__name='admin').exists()

That query will inform you user : “tom” whether belong to group “admin ” or not


回答 11

我是这样做的。对于名为的组Editor

# views.py
def index(request):
    current_user_groups = request.user.groups.values_list("name", flat=True)
    context = {
        "is_editor": "Editor" in current_user_groups,
    }
    return render(request, "index.html", context)

模板

# index.html
{% if is_editor %}
  <h1>Editor tools</h1>
{% endif %}

I did it like this. For group named Editor.

# views.py
def index(request):
    current_user_groups = request.user.groups.values_list("name", flat=True)
    context = {
        "is_editor": "Editor" in current_user_groups,
    }
    return render(request, "index.html", context)

template

# index.html
{% if is_editor %}
  <h1>Editor tools</h1>
{% endif %}

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