问题:在Python中创建单例
这个问题不是为了讨论是否需要单例设计模式,是否是反模式,还是针对任何宗教战争,而是要讨论如何以最pythonic的方式在Python中最好地实现此模式。在这种情况下,我将“最pythonic”定义为表示它遵循“最少惊讶的原理”。
我有多个将成为单例的类(我的用例用于记录器,但这并不重要)。当我可以简单地继承或修饰时,我不希望增加gumph来使几个类杂乱无章。
最佳方法:
方法1:装饰器
def singleton(class_):
instances = {}
def getinstance(*args, **kwargs):
if class_ not in instances:
instances[class_] = class_(*args, **kwargs)
return instances[class_]
return getinstance
@singleton
class MyClass(BaseClass):
pass
优点
缺点
- 使用MyClass()创建的对象将是真正的单例对象,而MyClass本身是一个函数,而不是类,因此您不能从中调用类方法。也就
m = MyClass(); n = MyClass(); o = type(n)();
这样m == n && m != o && n != o
方法2:一个基类
class Singleton(object):
_instance = None
def __new__(class_, *args, **kwargs):
if not isinstance(class_._instance, class_):
class_._instance = object.__new__(class_, *args, **kwargs)
return class_._instance
class MyClass(Singleton, BaseClass):
pass
优点
缺点
- 多重继承-好!
__new__
从第二个基类继承期间可能被覆盖?人们必须思考的超出了必要。
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
#Python2
class MyClass(BaseClass):
__metaclass__ = Singleton
#Python3
class MyClass(BaseClass, metaclass=Singleton):
pass
优点
- 这是一个真正的课堂
- 自动神奇地涵盖继承
- 利用
__metaclass__
它的正确用途(使我意识到这一点)
缺点
方法4:装饰器返回具有相同名称的类
def singleton(class_):
class class_w(class_):
_instance = None
def __new__(class_, *args, **kwargs):
if class_w._instance is None:
class_w._instance = super(class_w,
class_).__new__(class_,
*args,
**kwargs)
class_w._instance._sealed = False
return class_w._instance
def __init__(self, *args, **kwargs):
if self._sealed:
return
super(class_w, self).__init__(*args, **kwargs)
self._sealed = True
class_w.__name__ = class_.__name__
return class_w
@singleton
class MyClass(BaseClass):
pass
优点
缺点
- 创建每个新类没有开销吗?在这里,我们为希望创建单例的每个类创建两个类。虽然这对我来说很好,但我担心这可能无法扩展。当然,要扩展这种模式是否太容易了还有争议。
_sealed
属性的重点是什么
- 无法使用调用基类上同名的方法,
super()
因为它们会递归。这意味着您无法自定义__new__
,也无法将需要调用的类作为子类__init__
。
方法5:一个模块
一个模块文件 singleton.py
优点
缺点
This question is not for the discussion of whether or not the singleton design pattern is desirable, is an anti-pattern, or for any religious wars, but to discuss how this pattern is best implemented in Python in such a way that is most pythonic. In this instance I define ‘most pythonic’ to mean that it follows the ‘principle of least astonishment’.
I have multiple classes which would become singletons (my use-case is for a logger, but this is not important). I do not wish to clutter several classes with added gumph when I can simply inherit or decorate.
Best methods:
Method 1: A decorator
def singleton(class_):
instances = {}
def getinstance(*args, **kwargs):
if class_ not in instances:
instances[class_] = class_(*args, **kwargs)
return instances[class_]
return getinstance
@singleton
class MyClass(BaseClass):
pass
Pros
- Decorators are additive in a way that is often more intuitive than multiple inheritance.
Cons
- While objects created using MyClass() would be true singleton objects, MyClass itself is a a function, not a class, so you cannot call class methods from it. Also for
m = MyClass(); n = MyClass(); o = type(n)();
then m == n && m != o && n != o
Method 2: A base class
class Singleton(object):
_instance = None
def __new__(class_, *args, **kwargs):
if not isinstance(class_._instance, class_):
class_._instance = object.__new__(class_, *args, **kwargs)
return class_._instance
class MyClass(Singleton, BaseClass):
pass
Pros
Cons
- Multiple inheritance – eugh!
__new__
could be overwritten during inheritance from a second base class? One has to think more than is necessary.
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
#Python2
class MyClass(BaseClass):
__metaclass__ = Singleton
#Python3
class MyClass(BaseClass, metaclass=Singleton):
pass
Pros
- It’s a true class
- Auto-magically covers inheritance
- Uses
__metaclass__
for its proper purpose (and made me aware of it)
Cons
Method 4: decorator returning a class with the same name
def singleton(class_):
class class_w(class_):
_instance = None
def __new__(class_, *args, **kwargs):
if class_w._instance is None:
class_w._instance = super(class_w,
class_).__new__(class_,
*args,
**kwargs)
class_w._instance._sealed = False
return class_w._instance
def __init__(self, *args, **kwargs):
if self._sealed:
return
super(class_w, self).__init__(*args, **kwargs)
self._sealed = True
class_w.__name__ = class_.__name__
return class_w
@singleton
class MyClass(BaseClass):
pass
Pros
- It’s a true class
- Auto-magically covers inheritance
Cons
- Is there not an overhead for creating each new class? Here we are creating two classes for each class we wish to make a singleton. While this is fine in my case, I worry that this might not scale. Of course there is a matter of debate as to whether it aught to be too easy to scale this pattern…
- What is the point of the
_sealed
attribute
- Can’t call methods of the same name on base classes using
super()
because they will recurse. This means you can’t customize __new__
and can’t subclass a class that needs you to call up to __init__
.
Method 5: a module
a module file singleton.py
Pros
- Simple is better than complex
Cons
回答 0
使用元类
我建议使用方法2,但最好使用元类而不是基类。这是一个示例实现:
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
class Logger(object):
__metaclass__ = Singleton
或在Python3中
class Logger(metaclass=Singleton):
pass
如果要在__init__
每次调用类时运行,请添加
else:
cls._instances[cls].__init__(*args, **kwargs)
对中的if
陈述Singleton.__call__
。
关于元类的几句话。元类是类的类 ; 也就是说,类是其元类的实例。您可以使用来找到Python中对象的元类type(obj)
。普通的新式类是类型type
。Logger
上面代码中的将会是type class 'your_module.Singleton'
,就像的(唯一的)实例Logger
将是type一样class 'your_module.Logger'
。当你调用记录仪与Logger()
,Python的首先要求的元类Logger
,Singleton
,做什么,允许实例创建要捷足先登。此过程与Python __getattr__
通过执行以下操作引用类的一个属性时调用类来询问类的方法相同:myclass.attribute
。
元类从本质上决定了类定义的含义以及如何实现该定义。参见例如http://code.activestate.com/recipes/498149/,它实质上是struct
使用元类在Python中重新创建C风格的。线程元类的一些(具体)用例是什么?还提供了一些示例,它们通常似乎与声明性编程有关,尤其是在ORM中使用的声明性编程。
在这种情况下,如果您使用方法2,并且子类定义了一个__new__
方法,则每次调用时都会执行SubClassOfSingleton()
该方法-因为它负责调用返回存储实例的方法。对于元类,仅在创建唯一实例时才调用一次。您想自定义调用类的含义,该类由类的类型决定。
通常,使用元类实现单例是有意义的。单例很特别,因为它只能创建一次,而元类是自定义类创建的方式。如果需要以其他方式自定义单例类定义,则使用元类可以提供更多控制权。
您的单例不需要多重继承(因为元类不是基类),但是对于使用多重继承的已创建类的子类,您需要确保单例类是第一个/最左边的一个具有重新定义的元类的类。__call__
这不太可能成为问题。实例dict 不在实例的命名空间中,因此不会意外覆盖它。
您还将听到单例模式违反了“单一责任原则”-每个类只能做一件事。这样,您就不必担心如果需要更改另一代码,便会弄乱代码要做的一件事,因为它们是分开封装的。元类实现通过了此测试。元类负责执行模式,创建的类和子类无需知道它们是单例。正如您在“ MyClass本身是一个函数而不是一个类,因此您无法从中调用类方法”中指出的那样,方法#1未能通过该测试。
Python 2和3兼容版本
编写适用于Python2和3的东西需要使用稍微复杂一些的方案。由于元类通常是type的子类type
,因此可以使用一个在运行时动态创建中介基类并将其作为元类,然后将其用作公共Singleton
基类的基类。如下所示,这比做起来难解释。
# works in Python 2 & 3
class _Singleton(type):
""" A metaclass that creates a Singleton base class when called. """
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(_Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
class Singleton(_Singleton('SingletonMeta', (object,), {})): pass
class Logger(Singleton):
pass
具有讽刺意味的是,这种方法使用子类来实现元类。一个可能的优点是,与纯元类不同,isinstance(inst, Singleton)
它将返回True
。
更正
在另一个主题上,您可能已经注意到了这一点,但是原始文章中的基类实现是错误的。_instances
需要在类上引用,您需要使用super()
或递归,并且__new__
实际上是一个静态方法,您必须将类传递给,而不是类方法,因为尚未在其上创建实际的类叫做。所有这些对于元类实现也是正确的。
class Singleton(object):
_instances = {}
def __new__(class_, *args, **kwargs):
if class_ not in class_._instances:
class_._instances[class_] = super(Singleton, class_).__new__(class_, *args, **kwargs)
return class_._instances[class_]
class MyClass(Singleton):
pass
c = MyClass()
室内设计师返校
我本来是在写评论,但评论太长了,因此我将在此处添加。方法4比其他装饰器版本更好,但是它的代码比单例所需的代码更多,并且不清楚它的功能。
主要问题源于该类是它自己的基类。首先,让一个类成为几乎完全相同的类的子类不是很奇怪__class__
吗?这也意味着你不能定义调用同名的方法对它们的基类的任何方法用super()
,因为他们会重复。这意味着您的类无法自定义__new__
,并且不能从需要对其__init__
调用的任何类派生。
何时使用单例模式
您的用例是想要使用单例的更好示例之一。您在其中一项评论中说:“对我而言,伐木一直是Singletons的自然选择。” 你说的对。
人们说单身人士很糟糕,最常见的原因是他们是隐性的共享状态。虽然全局变量和顶级模块导入是显式共享状态,但通常会实例化传递的其他对象。这是一个好点,但有两个exceptions。
第一个,并且在各个地方都被提及的,是单例是恒定的。全局常数(尤其是枚举)的使用已被广泛接受,并被认为是明智的,因为无论如何,任何用户都无法为其他任何用户弄乱它们。对于恒定的单例也同样如此。
第二个exceptions(相反,它被忽略了)是相反的-当单例仅仅是数据接收器,而不是数据源(直接或间接)时。这就是为什么记录器感觉单例的“自然”使用。由于各种用户没有以其他用户关心的方式更改记录器,因此并没有真正的共享状态。这消除了反对单例模式的主要论点,并使其成为合理的选择,因为它们易于执行任务。
这是来自http://googletesting.blogspot.com/2008/08/root-cause-of-singletons.html的报价:
现在,有一种Singleton可以。那是所有可达对象都是不可变的单例。如果所有对象都是不可变的,则Singleton没有全局状态,因为一切都是恒定的。但是将这种单身人士变成易变的人是如此容易,这是很滑的坡度。因此,我也反对这些Singleton,不是因为它们不好,而是因为它们很容易变坏。(作为一个附带说明,Java枚举就是这些单例。只要您不将状态放入枚举中就可以,所以请不要这样做。)
另一种半可接受的单例是那些不影响代码执行的单例,它们没有“副作用”。日志记录就是一个很好的例子。它加载了Singletons和全局状态。这是可以接受的(因为它不会伤害您),因为无论是否启用给定的记录器,您的应用程序的行为都没有任何不同。此处的信息以一种方式流动:从您的应用程序进入记录器。甚至认为记录器是全局状态,因为没有信息从记录器流入您的应用程序,所以记录器是可以接受的。如果您想让测试断言某些东西正在被记录,那么您仍然应该注入记录器,但是一般来说,记录器即使处于满状态也不会有害。
Use a Metaclass
I would recommend Method #2, but you’re better off using a metaclass than a base class. Here is a sample implementation:
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
class Logger(object):
__metaclass__ = Singleton
Or in Python3
class Logger(metaclass=Singleton):
pass
If you want to run __init__
every time the class is called, add
else:
cls._instances[cls].__init__(*args, **kwargs)
to the if
statement in Singleton.__call__
.
A few words about metaclasses. A metaclass is the class of a class; that is, a class is an instance of its metaclass. You find the metaclass of an object in Python with type(obj)
. Normal new-style classes are of type type
. Logger
in the code above will be of type class 'your_module.Singleton'
, just as the (only) instance of Logger
will be of type class 'your_module.Logger'
. When you call logger with Logger()
, Python first asks the metaclass of Logger
, Singleton
, what to do, allowing instance creation to be pre-empted. This process is the same as Python asking a class what to do by calling __getattr__
when you reference one of it’s attributes by doing myclass.attribute
.
A metaclass essentially decides what the definition of a class means and how to implement that definition. See for example http://code.activestate.com/recipes/498149/, which essentially recreates C-style struct
s in Python using metaclasses. The thread What are some (concrete) use-cases for metaclasses? also provides some examples, they generally seem to be related to declarative programming, especially as used in ORMs.
In this situation, if you use your Method #2, and a subclass defines a __new__
method, it will be executed every time you call SubClassOfSingleton()
— because it is responsible for calling the method that returns the stored instance. With a metaclass, it will only be called once, when the only instance is created. You want to customize what it means to call the class, which is decided by it’s type.
In general, it makes sense to use a metaclass to implement a singleton. A singleton is special because is created only once, and a metaclass is the way you customize the creation of a class. Using a metaclass gives you more control in case you need to customize the singleton class definitions in other ways.
Your singletons won’t need multiple inheritance (because the metaclass is not a base class), but for subclasses of the created class that use multiple inheritance, you need to make sure the singleton class is the first / leftmost one with a metaclass that redefines __call__
This is very unlikely to be an issue. The instance dict is not in the instance’s namespace so it won’t accidentally overwrite it.
You will also hear that the singleton pattern violates the “Single Responsibility Principle” — each class should do only one thing. That way you don’t have to worry about messing up one thing the code does if you need to change another, because they are separate and encapsulated. The metaclass implementation passes this test. The metaclass is responsible for enforcing the pattern and the created class and subclasses need not be aware that they are singletons. Method #1 fails this test, as you noted with “MyClass itself is a a function, not a class, so you cannot call class methods from it.”
Python 2 and 3 Compatible Version
Writing something that works in both Python2 and 3 requires using a slightly more complicated scheme. Since metaclasses are usually subclasses of type type
, it’s possible to use one to dynamically create an intermediary base class at run time with it as its metaclass and then use that as the baseclass of the public Singleton
base class. It’s harder to explain than to do, as illustrated next:
# works in Python 2 & 3
class _Singleton(type):
""" A metaclass that creates a Singleton base class when called. """
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(_Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
class Singleton(_Singleton('SingletonMeta', (object,), {})): pass
class Logger(Singleton):
pass
An ironic aspect of this approach is that it’s using subclassing to implement a metaclass. One possible advantage is that, unlike with a pure metaclass, isinstance(inst, Singleton)
will return True
.
Corrections
On another topic, you’ve probably already noticed this, but the base class implementation in your original post is wrong. _instances
needs to be referenced on the class, you need to use super()
or you’re recursing, and __new__
is actually a static method that you have to pass the class to, not a class method, as the actual class hasn’t been created yet when it is called. All of these things will be true for a metaclass implementation as well.
class Singleton(object):
_instances = {}
def __new__(class_, *args, **kwargs):
if class_ not in class_._instances:
class_._instances[class_] = super(Singleton, class_).__new__(class_, *args, **kwargs)
return class_._instances[class_]
class MyClass(Singleton):
pass
c = MyClass()
Decorator Returning A Class
I originally was writing a comment but it was too long, so I’ll add this here. Method #4 is better than the other decorator version, but it’s more code than needed for a singleton, and it’s not as clear what it does.
The main problems stem from the class being it’s own base class. First, isn’t it weird to have a class be a subclass of a nearly identical class with the same name that exists only in its __class__
attribute? This also means that you can’t define any methods that call the method of the same name on their base class with super()
because they will recurse. This means your class can’t customize __new__
, and can’t derive from any classes that need __init__
called on them.
When to use the singleton pattern
Your use case is one of the better examples of wanting to use a singleton. You say in one of the comments “To me logging has always seemed a natural candidate for Singletons.” You’re absolutely right.
When people say singletons are bad, the most common reason is they are implicit shared state. While with global variables and top-level module imports are explicit shared state, other objects that are passed around are generally instantiated. This is a good point, with two exceptions.
The first, and one that gets mentioned in various places, is when the singletons are constant. Use of global constants, especially enums, is widely accepted, and considered sane because no matter what, none of the users can mess them up for any other user. This is equally true for a constant singleton.
The second exception, which get mentioned less, is the opposite — when the singleton is only a data sink, not a data source (directly or indirectly). This is why loggers feel like a “natural” use for singletons. As the various users are not changing the loggers in ways other users will care about, there is not really shared state. This negates the primary argument against the singleton pattern, and makes them a reasonable choice because of their ease of use for the task.
Here is a quote from http://googletesting.blogspot.com/2008/08/root-cause-of-singletons.html:
Now, there is one kind of Singleton which is OK. That is a singleton where all of the reachable objects are immutable. If all objects are immutable than Singleton has no global state, as everything is constant. But it is so easy to turn this kind of singleton into mutable one, it is very slippery slope. Therefore, I am against these Singletons too, not because they are bad, but because it is very easy for them to go bad. (As a side note Java enumeration are just these kind of singletons. As long as you don’t put state into your enumeration you are OK, so please don’t.)
The other kind of Singletons, which are semi-acceptable are those which don’t effect the execution of your code, They have no “side effects”. Logging is perfect example. It is loaded with Singletons and global state. It is acceptable (as in it will not hurt you) because your application does not behave any different whether or not a given logger is enabled. The information here flows one way: From your application into the logger. Even thought loggers are global state since no information flows from loggers into your application, loggers are acceptable. You should still inject your logger if you want your test to assert that something is getting logged, but in general Loggers are not harmful despite being full of state.
回答 1
class Foo(object):
pass
some_global_variable = Foo()
模块仅导入一次,其他一切都考虑不周。不要使用单例并且不要使用全局。
class Foo(object):
pass
some_global_variable = Foo()
Modules are imported only once, everything else is overthinking. Don’t use singletons and try not to use globals.
回答 2
使用模块。它仅导入一次。在其中定义一些全局变量-它们将是单例的“属性”。添加一些功能-单例的“方法”。
Use a module. It is imported only once. Define some global variables in it – they will be singleton’s ‘attributes’. Add some functions – the singleton’s ‘methods’.
回答 3
您可能永远不需要Python中的单例。只需在一个模块中定义所有数据和功能,便拥有事实上的单例。
如果您真的绝对必须要有一个单例类,那么我可以考虑:
class My_Singleton(object):
def foo(self):
pass
my_singleton = My_Singleton()
使用方法:
from mysingleton import my_singleton
my_singleton.foo()
其中mysingleton.py是定义My_Singleton的文件名。之所以起作用,是因为第一次导入文件后,Python不会重新执行代码。
You probably never need a singleton in Python. Just define all your data and functions in a module and you have a de-facto singleton.
If you really absolutely have to have a singleton class then I’d go with:
class My_Singleton(object):
def foo(self):
pass
my_singleton = My_Singleton()
To use:
from mysingleton import my_singleton
my_singleton.foo()
where mysingleton.py is your filename that My_Singleton is defined in. This works because after the first time a file is imported, Python doesn’t re-execute the code.
回答 4
这是您的一线客:
singleton = lambda c: c()
使用方法如下:
@singleton
class wat(object):
def __init__(self): self.x = 1
def get_x(self): return self.x
assert wat.get_x() == 1
您的对象会被实例化。这可能是您想要的,也可能不是。
Here’s a one-liner for you:
singleton = lambda c: c()
Here’s how you use it:
@singleton
class wat(object):
def __init__(self): self.x = 1
def get_x(self): return self.x
assert wat.get_x() == 1
Your object gets instantiated eagerly. This may or may not be what you want.
回答 5
回答 6
这是我自己的单例实现。您所要做的就是装饰教室。要获得单例,则必须使用该Instance
方法。这是一个例子:
@Singleton
class Foo:
def __init__(self):
print 'Foo created'
f = Foo() # Error, this isn't how you get the instance of a singleton
f = Foo.Instance() # Good. Being explicit is in line with the Python Zen
g = Foo.Instance() # Returns already created instance
print f is g # True
这是代码:
class Singleton:
"""
A non-thread-safe helper class to ease implementing singletons.
This should be used as a decorator -- not a metaclass -- to the
class that should be a singleton.
The decorated class can define one `__init__` function that
takes only the `self` argument. Other than that, there are
no restrictions that apply to the decorated class.
To get the singleton instance, use the `Instance` method. Trying
to use `__call__` will result in a `TypeError` being raised.
Limitations: The decorated class cannot be inherited from.
"""
def __init__(self, decorated):
self._decorated = decorated
def Instance(self):
"""
Returns the singleton instance. Upon its first call, it creates a
new instance of the decorated class and calls its `__init__` method.
On all subsequent calls, the already created instance is returned.
"""
try:
return self._instance
except AttributeError:
self._instance = self._decorated()
return self._instance
def __call__(self):
raise TypeError('Singletons must be accessed through `Instance()`.')
def __instancecheck__(self, inst):
return isinstance(inst, self._decorated)
Here’s my own implementation of singletons. All you have to do is decorate the class; to get the singleton, you then have to use the Instance
method. Here’s an example:
@Singleton
class Foo:
def __init__(self):
print 'Foo created'
f = Foo() # Error, this isn't how you get the instance of a singleton
f = Foo.Instance() # Good. Being explicit is in line with the Python Zen
g = Foo.Instance() # Returns already created instance
print f is g # True
And here’s the code:
class Singleton:
"""
A non-thread-safe helper class to ease implementing singletons.
This should be used as a decorator -- not a metaclass -- to the
class that should be a singleton.
The decorated class can define one `__init__` function that
takes only the `self` argument. Other than that, there are
no restrictions that apply to the decorated class.
To get the singleton instance, use the `Instance` method. Trying
to use `__call__` will result in a `TypeError` being raised.
Limitations: The decorated class cannot be inherited from.
"""
def __init__(self, decorated):
self._decorated = decorated
def Instance(self):
"""
Returns the singleton instance. Upon its first call, it creates a
new instance of the decorated class and calls its `__init__` method.
On all subsequent calls, the already created instance is returned.
"""
try:
return self._instance
except AttributeError:
self._instance = self._decorated()
return self._instance
def __call__(self):
raise TypeError('Singletons must be accessed through `Instance()`.')
def __instancecheck__(self, inst):
return isinstance(inst, self._decorated)
回答 7
方法3看起来很整洁,但是如果您希望程序同时在Python 2和Python 3中运行,那么它将无法正常工作。即使使用Python版本的测试来保护单独的变体也失败了,因为Python 3版本在Python 2中给出了语法错误。
感谢Mike Watkins:http : //mikewatkins.ca/2008/11/29/python-2-and-3-metaclasses/。如果要使程序在Python 2和Python 3中都能工作,则需要执行以下操作:
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
MC = Singleton('MC', (object), {})
class MyClass(MC):
pass # Code for the class implementation
我认为作业中的“对象”需要替换为“ BaseClass”,但是我还没有尝试过(我尝试了如图所示的代码)。
Method 3 seems to be very neat, but if you want your program to run in both Python 2 and Python 3, it doesn’t work. Even protecting the separate variants with tests for the Python version fails, because the Python 3 version gives a syntax error in Python 2.
Thanks to Mike Watkins: http://mikewatkins.ca/2008/11/29/python-2-and-3-metaclasses/. If you want the program to work in both Python 2 and Python 3, you need to do something like:
class Singleton(type):
_instances = {}
def __call__(cls, *args, **kwargs):
if cls not in cls._instances:
cls._instances[cls] = super(Singleton, cls).__call__(*args, **kwargs)
return cls._instances[cls]
MC = Singleton('MC', (object), {})
class MyClass(MC):
pass # Code for the class implementation
I presume that ‘object’ in the assignment needs to be replaced with the ‘BaseClass’, but I haven’t tried that (I have tried code as illustrated).
回答 8
好吧,除了同意关于模块级全局的Pythonic通用建议外,如何做到这一点:
def singleton(class_):
class class_w(class_):
_instance = None
def __new__(class2, *args, **kwargs):
if class_w._instance is None:
class_w._instance = super(class_w, class2).__new__(class2, *args, **kwargs)
class_w._instance._sealed = False
return class_w._instance
def __init__(self, *args, **kwargs):
if self._sealed:
return
super(class_w, self).__init__(*args, **kwargs)
self._sealed = True
class_w.__name__ = class_.__name__
return class_w
@singleton
class MyClass(object):
def __init__(self, text):
print text
@classmethod
def name(class_):
print class_.__name__
x = MyClass(111)
x.name()
y = MyClass(222)
print id(x) == id(y)
输出为:
111 # the __init__ is called only on the 1st time
MyClass # the __name__ is preserved
True # this is actually the same instance
Well, other than agreeing with the general Pythonic suggestion on having module-level global, how about this:
def singleton(class_):
class class_w(class_):
_instance = None
def __new__(class2, *args, **kwargs):
if class_w._instance is None:
class_w._instance = super(class_w, class2).__new__(class2, *args, **kwargs)
class_w._instance._sealed = False
return class_w._instance
def __init__(self, *args, **kwargs):
if self._sealed:
return
super(class_w, self).__init__(*args, **kwargs)
self._sealed = True
class_w.__name__ = class_.__name__
return class_w
@singleton
class MyClass(object):
def __init__(self, text):
print text
@classmethod
def name(class_):
print class_.__name__
x = MyClass(111)
x.name()
y = MyClass(222)
print id(x) == id(y)
Output is:
111 # the __init__ is called only on the 1st time
MyClass # the __name__ is preserved
True # this is actually the same instance
回答 9
这个怎么样:
def singleton(cls):
instance=cls()
cls.__new__ = cls.__call__= lambda cls: instance
cls.__init__ = lambda self: None
return instance
将其用作应该为单例的类上的装饰器。像这样:
@singleton
class MySingleton:
#....
这类似于singleton = lambda c: c()
另一个答案中的装饰器。与其他解决方案一样,唯一的实例具有类(MySingleton
)的名称。但是,使用此解决方案,您仍然可以通过执行从类“创建”实例(实际上是唯一的实例)MySingleton()
。它还会阻止您这样做来创建其他实例type(MySingleton)()
(这也会返回相同的实例)。
How about this:
def singleton(cls):
instance=cls()
cls.__new__ = cls.__call__= lambda cls: instance
cls.__init__ = lambda self: None
return instance
Use it as a decorator on a class that should be a singleton. Like this:
@singleton
class MySingleton:
#....
This is similar to the singleton = lambda c: c()
decorator in another answer. Like the other solution, the only instance has name of the class (MySingleton
). However, with this solution you can still “create” instances (actually get the only instance) from the class, by doing MySingleton()
. It also prevents you from creating additional instances by doing type(MySingleton)()
(that also returns the same instance).
回答 10
我将我扔进戒指。这是一个简单的装饰器。
from abc import ABC
def singleton(real_cls):
class SingletonFactory(ABC):
instance = None
def __new__(cls, *args, **kwargs):
if not cls.instance:
cls.instance = real_cls(*args, **kwargs)
return cls.instance
SingletonFactory.register(real_cls)
return SingletonFactory
# Usage
@singleton
class YourClass:
... # Your normal implementation, no special requirements.
我认为它具有一些其他解决方案的好处:
- 这是简洁明了的(在我看来; D)。
- 它的作用被完全封装。您无需更改的实现的任何事情
YourClass
。这包括不需要为您的类使用元类(请注意,上面的元类在工厂中,而不是“真实”类)。
- 它不依赖于Monkey修补任何东西。
- 对调用方法透明:
- 调用者仍然简单地import
YourClass
,它看起来像一个类(因为是),并且可以正常使用它。无需使调用者适应工厂功能。
- 什么
YourClass()
实例仍是的一个真正的实例YourClass
您实现的,没有任何形式的代理,所以没有副作用的几率从产生。
isinstance(instance, YourClass)
并且类似的操作仍然可以按预期进行(尽管此位确实需要abc,因此排除了Python <2.6)。
我确实有一个缺点:实类的类方法和静态方法不能通过隐藏它的工厂类透明地调用。我已经很少使用了它,以至从未碰到过这种需求,但是通过在工厂上使用实现__getattr__()
将所有属性访问权限委派给真实类的自定义元类,可以很容易地对其进行纠正。
我实际上发现的一个相关模式更有用(并不是说我经常需要这些东西)是“唯一”模式,其中使用相同的参数实例化该类会导致返回相同的实例。即“每个参数单”。上面的内容很好地适应了这一点,并且变得更加简洁:
def unique(real_cls):
class UniqueFactory(ABC):
@functools.lru_cache(None) # Handy for 3.2+, but use any memoization decorator you like
def __new__(cls, *args, **kwargs):
return real_cls(*args, **kwargs)
UniqueFactory.register(real_cls)
return UniqueFactory
综上所述,我确实同意以下一般性建议:如果您认为自己需要这些东西之一,则可能应该停一会儿,问问自己是否确实需要。YAGNI 99%的时间。
I’ll toss mine into the ring. It’s a simple decorator.
from abc import ABC
def singleton(real_cls):
class SingletonFactory(ABC):
instance = None
def __new__(cls, *args, **kwargs):
if not cls.instance:
cls.instance = real_cls(*args, **kwargs)
return cls.instance
SingletonFactory.register(real_cls)
return SingletonFactory
# Usage
@singleton
class YourClass:
... # Your normal implementation, no special requirements.
Benefits I think it has over some of the other solutions:
- It’s clear and concise (to my eye ;D).
- Its action is completely encapsulated. You don’t need to change a single thing about the implementation of
YourClass
. This includes not needing to use a metaclass for your class (note that the metaclass above is on the factory, not the “real” class).
- It doesn’t rely on monkey-patching anything.
- It’s transparent to callers:
- Callers still simply import
YourClass
, it looks like a class (because it is), and they use it normally. No need to adapt callers to a factory function.
- What
YourClass()
instantiates is still a true instance of the YourClass
you implemented, not a proxy of any kind, so no chance of side effects resulting from that.
isinstance(instance, YourClass)
and similar operations still work as expected (though this bit does require abc so precludes Python <2.6).
One downside does occur to me: classmethods and staticmethods of the real class are not transparently callable via the factory class hiding it. I’ve used this rarely enough that I’ve never happen to run into that need, but it would be easily rectified by using a custom metaclass on the factory that implements __getattr__()
to delegate all-ish attribute access to the real class.
A related pattern I’ve actually found more useful (not that I’m saying these kinds of things are required very often at all) is a “Unique” pattern where instantiating the class with the same arguments results in getting back the same instance. I.e. a “singleton per arguments”. The above adapts to this well and becomes even more concise:
def unique(real_cls):
class UniqueFactory(ABC):
@functools.lru_cache(None) # Handy for 3.2+, but use any memoization decorator you like
def __new__(cls, *args, **kwargs):
return real_cls(*args, **kwargs)
UniqueFactory.register(real_cls)
return UniqueFactory
All that said, I do agree with the general advice that if you think you need one of these things, you really should probably stop for a moment and ask yourself if you really do. 99% of the time, YAGNI.
回答 11
基于Tolli的答案的代码。
#decorator, modyfies new_cls
def _singleton(new_cls):
instance = new_cls() #2
def new(cls):
if isinstance(instance, cls): #4
return instance
else:
raise TypeError("I can only return instance of {}, caller wanted {}".format(new_cls, cls))
new_cls.__new__ = new #3
new_cls.__init__ = lambda self: None #5
return new_cls
#decorator, creates new class
def singleton(cls):
new_cls = type('singleton({})'.format(cls.__name__), (cls,), {} ) #1
return _singleton(new_cls)
#metaclass
def meta_singleton(name, bases, attrs):
new_cls = type(name, bases, attrs) #1
return _singleton(new_cls)
说明:
创建新类,继承自给定的类cls
(cls
例如,在有人想要的情况下,它不会进行修改singleton(list)
)
创建实例。覆盖之前__new__
是如此简单。
- 现在,当我们轻松创建实例后,请
__new__
使用之前定义的方法进行覆盖。
该函数instance
仅在调用者期望的时候返回,否则抛出TypeError
。
当有人尝试从装饰类继承时,不满足该条件。
如果__new__()
返回的实例cls
,那么新实例的__init__()
方法将被调用一样__init__(self[, ...])
,这里的自我是新实例,其余参数都一样传递给__new__()
。
instance
已经被初始化,所以__init__
功能被什么都不做的功能所取代。
看到它在线上工作
Code based on Tolli’s answer.
#decorator, modyfies new_cls
def _singleton(new_cls):
instance = new_cls() #2
def new(cls):
if isinstance(instance, cls): #4
return instance
else:
raise TypeError("I can only return instance of {}, caller wanted {}".format(new_cls, cls))
new_cls.__new__ = new #3
new_cls.__init__ = lambda self: None #5
return new_cls
#decorator, creates new class
def singleton(cls):
new_cls = type('singleton({})'.format(cls.__name__), (cls,), {} ) #1
return _singleton(new_cls)
#metaclass
def meta_singleton(name, bases, attrs):
new_cls = type(name, bases, attrs) #1
return _singleton(new_cls)
Explanation:
Create new class, inheriting from given cls
(it doesn’t modify cls
in case someone wants for example singleton(list)
)
Create instance. Before overriding __new__
it’s so easy.
- Now, when we have easily created instance, overrides
__new__
using method defined moment ago.
The function returns instance
only when it’s what the caller expects, otherwise raises TypeError
.
The condition is not met when someone attempts to inherit from decorated class.
If __new__()
returns an instance of cls
, then the new instance’s __init__()
method will be invoked like __init__(self[, ...])
, where self is the new instance and the remaining arguments are the same as were passed to __new__()
.
instance
is already initialized, so function replaces __init__
with function doing nothing.
See it working online
回答 12
它与晶圆厂的答案有些相似,但并不完全相同。
该单合同并不要求我们能够多次调用构造函数。作为一个单例应该仅创建一次,是否不应该将其视为仅创建一次?“欺骗”构造函数无疑会损害可读性。
所以我的建议是这样的:
class Elvis():
def __init__(self):
if hasattr(self.__class__, 'instance'):
raise Exception()
self.__class__.instance = self
# initialisation code...
@staticmethod
def the():
if hasattr(Elvis, 'instance'):
return Elvis.instance
return Elvis()
这不排除instance
用户代码对构造函数或字段的使用:
if Elvis() is King.instance:
…如果您确定Elvis
还没有创建,那就已经创建了King
。
但它鼓励用户the
普遍使用该方法:
Elvis.the().leave(Building.the())
为了完成此操作,__delattr__()
如果尝试删除instance
,也可以重写以引发Exception ,并重写__del__()
以引发Exception(除非我们知道程序正在结束…)
进一步的改进
感谢那些为评论和编辑提供帮助的人,我们欢迎其中的更多内容。当我使用Jython时,这应该更通用,并且是线程安全的。
try:
# This is jython-specific
from synchronize import make_synchronized
except ImportError:
# This should work across different python implementations
def make_synchronized(func):
import threading
func.__lock__ = threading.Lock()
def synced_func(*args, **kws):
with func.__lock__:
return func(*args, **kws)
return synced_func
class Elvis(object): # NB must be subclass of object to use __new__
instance = None
@classmethod
@make_synchronized
def __new__(cls, *args, **kwargs):
if cls.instance is not None:
raise Exception()
cls.instance = object.__new__(cls, *args, **kwargs)
return cls.instance
def __init__(self):
pass
# initialisation code...
@classmethod
@make_synchronized
def the(cls):
if cls.instance is not None:
return cls.instance
return cls()
注意事项:
- 如果您不从python2.x中的对象继承子类,则将获得一个老式的类,该类不使用
__new__
- 装饰时,
__new__
您必须使用@classmethod装饰,否则__new__
它将是未绑定的实例方法
- 可以通过使用元类来改善这一点,因为这将使您能够创建
the
类级别的属性,并将其重命名为instance
It is slightly similar to the answer by fab but not exactly the same.
The singleton contract does not require that we be able to call the constructor multiple times. As a singleton should be created once and once only, shouldn’t it be seen to be created just once? “Spoofing” the constructor arguably impairs legibility.
So my suggestion is just this:
class Elvis():
def __init__(self):
if hasattr(self.__class__, 'instance'):
raise Exception()
self.__class__.instance = self
# initialisation code...
@staticmethod
def the():
if hasattr(Elvis, 'instance'):
return Elvis.instance
return Elvis()
This does not rule out the use of the constructor or the field instance
by user code:
if Elvis() is King.instance:
… if you know for sure that Elvis
has not yet been created, and that King
has.
But it encourages users to use the the
method universally:
Elvis.the().leave(Building.the())
To make this complete you could also override __delattr__()
to raise an Exception if an attempt is made to delete instance
, and override __del__()
so that it raises an Exception (unless we know the program is ending…)
Further improvements
My thanks to those who have helped with comments and edits, of which more are welcome. While I use Jython, this should work more generally, and be thread-safe.
try:
# This is jython-specific
from synchronize import make_synchronized
except ImportError:
# This should work across different python implementations
def make_synchronized(func):
import threading
func.__lock__ = threading.Lock()
def synced_func(*args, **kws):
with func.__lock__:
return func(*args, **kws)
return synced_func
class Elvis(object): # NB must be subclass of object to use __new__
instance = None
@classmethod
@make_synchronized
def __new__(cls, *args, **kwargs):
if cls.instance is not None:
raise Exception()
cls.instance = object.__new__(cls, *args, **kwargs)
return cls.instance
def __init__(self):
pass
# initialisation code...
@classmethod
@make_synchronized
def the(cls):
if cls.instance is not None:
return cls.instance
return cls()
Points of note:
- If you don’t subclass from object in python2.x you will get an old-style class, which does not use
__new__
- When decorating
__new__
you must decorate with @classmethod or __new__
will be an unbound instance method
- This could possibly be improved by way of use of a metaclass, as this would allow you to make
the
a class-level property, possibly renaming it to instance
回答 13
一名班轮(我不为此感到自豪,但确实能胜任):
class Myclass:
def __init__(self):
# do your stuff
globals()[type(self).__name__] = lambda: self # singletonify
One liner (I am not proud, but it does the job):
class Myclass:
def __init__(self):
# do your stuff
globals()[type(self).__name__] = lambda: self # singletonify
回答 14
如果您不需要懒惰地初始化Singleton实例,则以下操作应该很容易且线程安全:
class A:
instance = None
# Methods and variables of the class/object A follow
A.instance = A()
这种方式A
是在模块导入时初始化的单例。
If you don’t need lazy initialization of the instance of the Singleton, then the following should be easy and thread-safe:
class A:
instance = None
# Methods and variables of the class/object A follow
A.instance = A()
This way A
is a singleton initialized at module import.
回答 15
- 如果一个人想拥有多个相同类的实例,但是只有当args或kwargs不同时,才可以使用它
- 例如
- 如果您有类处理
serial
通信,并且要创建一个实例,并且希望将串行端口作为参数发送,那么使用传统方法将无法正常工作
- 使用上述装饰器,如果args不同,则可以创建该类的多个实例。
- 对于相同的参数,装饰器将返回已经创建的相同实例。
>>> from decorators import singleton
>>>
>>> @singleton
... class A:
... def __init__(self, *args, **kwargs):
... pass
...
>>>
>>> a = A(name='Siddhesh')
>>> b = A(name='Siddhesh', lname='Sathe')
>>> c = A(name='Siddhesh', lname='Sathe')
>>> a is b # has to be different
False
>>> b is c # has to be same
True
>>>
- If one wants to have multiple number of instances of the same class, but only if the args or kwargs are different, one can use this
- Ex.
- If you have a class handling
serial
communication, and to create an instance you want to send the serial port as an argument, then with traditional approach won’t work
- Using the above mentioned decorators, one can create multiple instances of the class if the args are different.
- For same args, the decorator will return the same instance which is already been created.
>>> from decorators import singleton
>>>
>>> @singleton
... class A:
... def __init__(self, *args, **kwargs):
... pass
...
>>>
>>> a = A(name='Siddhesh')
>>> b = A(name='Siddhesh', lname='Sathe')
>>> c = A(name='Siddhesh', lname='Sathe')
>>> a is b # has to be different
False
>>> b is c # has to be same
True
>>>
回答 16
也许我误解了单例模式,但是我的解决方案是这个简单而实用的(pythonic?)。该代码实现了两个目标
- 使实例可在
Foo
任何地方(全局)访问。
- 只能
Foo
存在一个实例。
这是代码。
#!/usr/bin/env python3
class Foo:
me = None
def __init__(self):
if Foo.me != None:
raise Exception('Instance of Foo still exists!')
Foo.me = self
if __name__ == '__main__':
Foo()
Foo()
输出量
Traceback (most recent call last):
File "./x.py", line 15, in <module>
Foo()
File "./x.py", line 8, in __init__
raise Exception('Instance of Foo still exists!')
Exception: Instance of Foo still exists!
Maybe I missunderstand the singleton pattern but my solution is this simple and pragmatic (pythonic?). This code fullfills two goals
- Make the instance of
Foo
accessiable everywhere (global).
- Only one instance of
Foo
can exist.
This is the code.
#!/usr/bin/env python3
class Foo:
me = None
def __init__(self):
if Foo.me != None:
raise Exception('Instance of Foo still exists!')
Foo.me = self
if __name__ == '__main__':
Foo()
Foo()
Output
Traceback (most recent call last):
File "./x.py", line 15, in <module>
Foo()
File "./x.py", line 8, in __init__
raise Exception('Instance of Foo still exists!')
Exception: Instance of Foo still exists!
回答 17
经过一段时间的努力,我最终想到了以下内容,以便从单独的模块中调用配置对象时,它只会被加载一次。元类允许将全局类实例存储在内置指令中,这在当前看来是存储适当程序全局的最简洁的方法。
import builtins
# -----------------------------------------------------------------------------
# So..... you would expect that a class would be "global" in scope, however
# when different modules use this,
# EACH ONE effectively has its own class namespace.
# In order to get around this, we use a metaclass to intercept
# "new" and provide the "truly global metaclass instance" if it already exists
class MetaConfig(type):
def __new__(cls, name, bases, dct):
try:
class_inst = builtins.CONFIG_singleton
except AttributeError:
class_inst = super().__new__(cls, name, bases, dct)
builtins.CONFIG_singleton = class_inst
class_inst.do_load()
return class_inst
# -----------------------------------------------------------------------------
class Config(metaclass=MetaConfig):
config_attr = None
@classmethod
def do_load(cls):
...<load-cfg-from-file>...
After struggling with this for some time I eventually came up with the following, so that the config object would only be loaded once, when called up from separate modules. The metaclass allows a global class instance to be stored in the builtins dict, which at present appears to be the neatest way of storing a proper program global.
import builtins
# -----------------------------------------------------------------------------
# So..... you would expect that a class would be "global" in scope, however
# when different modules use this,
# EACH ONE effectively has its own class namespace.
# In order to get around this, we use a metaclass to intercept
# "new" and provide the "truly global metaclass instance" if it already exists
class MetaConfig(type):
def __new__(cls, name, bases, dct):
try:
class_inst = builtins.CONFIG_singleton
except AttributeError:
class_inst = super().__new__(cls, name, bases, dct)
builtins.CONFIG_singleton = class_inst
class_inst.do_load()
return class_inst
# -----------------------------------------------------------------------------
class Config(metaclass=MetaConfig):
config_attr = None
@classmethod
def do_load(cls):
...<load-cfg-from-file>...
回答 18
我不记得在哪里找到该解决方案,但是从我的非Python专家的角度来看,它是最“优雅”的:
class SomeSingleton(dict):
__instance__ = None
def __new__(cls, *args,**kwargs):
if SomeSingleton.__instance__ is None:
SomeSingleton.__instance__ = dict.__new__(cls)
return SomeSingleton.__instance__
def __init__(self):
pass
def some_func(self,arg):
pass
我为什么喜欢这个?没有装饰器,没有元类,没有多重继承…,如果您决定不再希望它成为Singleton,只需删除该__new__
方法。由于我是Python(和OOP的新手)的新手,所以我希望有人能使我明白为什么这是一种糟糕的方法?
I can’t remember where I found this solution, but I find it to be the most ‘elegant’ from my non-Python-expert point of view:
class SomeSingleton(dict):
__instance__ = None
def __new__(cls, *args,**kwargs):
if SomeSingleton.__instance__ is None:
SomeSingleton.__instance__ = dict.__new__(cls)
return SomeSingleton.__instance__
def __init__(self):
pass
def some_func(self,arg):
pass
Why do I like this? No decorators, no meta classes, no multiple inheritance…and if you decide you don’t want it to be a Singleton anymore, just delete the __new__
method. As I am new to Python (and OOP in general) I expect someone will set me straight about why this is a terrible approach?
回答 19
这是我实现单例的首选方式:
class Test(object):
obj = None
def __init__(self):
if Test.obj is not None:
raise Exception('A Test Singleton instance already exists')
# Initialization code here
@classmethod
def get_instance(cls):
if cls.obj is None:
cls.obj = Test()
return cls.obj
@classmethod
def custom_method(cls):
obj = cls.get_instance()
# Custom Code here
This is my preferred way of implementing singletons:
class Test(object):
obj = None
def __init__(self):
if Test.obj is not None:
raise Exception('A Test Singleton instance already exists')
# Initialization code here
@classmethod
def get_instance(cls):
if cls.obj is None:
cls.obj = Test()
return cls.obj
@classmethod
def custom_method(cls):
obj = cls.get_instance()
# Custom Code here
回答 20
这个答案可能不是您想要的。我想要一个单例,因为只有那个对象才具有其身份,以便进行比较。就我而言,它被用作前哨值。答案很简单,mything = object()
根据python的性质制作任何对象,只有该对象才具有其标识。
#!python
MyNone = object() # The singleton
for item in my_list:
if item is MyNone: # An Example identity comparison
raise StopIteration
This answer is likely not what you’re looking for. I wanted a singleton in the sense that only that object had its identity, for comparison to. In my case it was being used as a Sentinel Value. To which the answer is very simple, make any object mything = object()
and by python’s nature, only that thing will have its identity.
#!python
MyNone = object() # The singleton
for item in my_list:
if item is MyNone: # An Example identity comparison
raise StopIteration
回答 21
该解决方案在模块级别上导致了一些命名空间污染(三个定义,而不仅仅是一个定义),但是我发现很容易遵循。
我希望能够编写这样的内容(延迟初始化),但不幸的是,类在其自身的定义中不可用。
# wouldn't it be nice if we could do this?
class Foo(object):
instance = None
def __new__(cls):
if cls.instance is None:
cls.instance = object()
cls.instance.__class__ = Foo
return cls.instance
由于这是不可能的,因此我们可以在其中分解初始化和静态实例
急切的初始化:
import random
class FooMaker(object):
def __init__(self, *args):
self._count = random.random()
self._args = args
class Foo(object):
def __new__(self):
return foo_instance
foo_instance = FooMaker()
foo_instance.__class__ = Foo
延迟初始化:
急切的初始化:
import random
class FooMaker(object):
def __init__(self, *args):
self._count = random.random()
self._args = args
class Foo(object):
def __new__(self):
global foo_instance
if foo_instance is None:
foo_instance = FooMaker()
return foo_instance
foo_instance = None
This solution causes some namespace pollution at the module level (three definitions rather than just one), but I find it easy to follow.
I’d like to be able to write something like this (lazy initialization), but unfortunately classes are not available in the body of their own definitions.
# wouldn't it be nice if we could do this?
class Foo(object):
instance = None
def __new__(cls):
if cls.instance is None:
cls.instance = object()
cls.instance.__class__ = Foo
return cls.instance
Since that isn’t possible, we can break out the initialization and the static instance in
Eager Initialization:
import random
class FooMaker(object):
def __init__(self, *args):
self._count = random.random()
self._args = args
class Foo(object):
def __new__(self):
return foo_instance
foo_instance = FooMaker()
foo_instance.__class__ = Foo
Lazy initialization:
Eager Initialization:
import random
class FooMaker(object):
def __init__(self, *args):
self._count = random.random()
self._args = args
class Foo(object):
def __new__(self):
global foo_instance
if foo_instance is None:
foo_instance = FooMaker()
return foo_instance
foo_instance = None