问题:在Python的调用者线程中捕获线程的异常
我对Python和多线程编程非常陌生。基本上,我有一个脚本可以将文件复制到另一个位置。我希望将其放置在另一个线程中,以便可以输出....
以指示脚本仍在运行。
我遇到的问题是,如果无法复制文件,它将引发异常。如果在主线程中运行,这没关系;但是,具有以下代码不起作用:
try:
threadClass = TheThread(param1, param2, etc.)
threadClass.start() ##### **Exception takes place here**
except:
print "Caught an exception"
在线程类本身中,我试图重新引发异常,但是它不起作用。我已经看到这里的人问类似的问题,但是他们似乎都在做比我想做的事情更具体的事情(而且我不太了解所提供的解决方案)。我见过有人提到的用法sys.exc_info()
,但是我不知道在哪里或如何使用它。
非常感谢所有帮助!
编辑:线程类的代码如下:
class TheThread(threading.Thread):
def __init__(self, sourceFolder, destFolder):
threading.Thread.__init__(self)
self.sourceFolder = sourceFolder
self.destFolder = destFolder
def run(self):
try:
shul.copytree(self.sourceFolder, self.destFolder)
except:
raise
回答 0
问题是thread_obj.start()
立即返回。您产生的子线程在其自己的上下文中执行,并带有自己的堆栈。在那里发生的任何异常都在子线程的上下文中,并且在其自己的堆栈中。我现在可以想到的一种将此信息传达给父线程的方法是使用某种消息传递,因此您可能会对此进行研究。
尝试以下尺寸:
import sys
import threading
import Queue
class ExcThread(threading.Thread):
def __init__(self, bucket):
threading.Thread.__init__(self)
self.bucket = bucket
def run(self):
try:
raise Exception('An error occured here.')
except Exception:
self.bucket.put(sys.exc_info())
def main():
bucket = Queue.Queue()
thread_obj = ExcThread(bucket)
thread_obj.start()
while True:
try:
exc = bucket.get(block=False)
except Queue.Empty:
pass
else:
exc_type, exc_obj, exc_trace = exc
# deal with the exception
print exc_type, exc_obj
print exc_trace
thread_obj.join(0.1)
if thread_obj.isAlive():
continue
else:
break
if __name__ == '__main__':
main()
回答 1
通过该concurrent.futures
模块,可以轻松地在单独的线程(或进程)中进行工作并处理任何导致的异常:
import concurrent.futures
import shutil
def copytree_with_dots(src_path, dst_path):
with concurrent.futures.ThreadPoolExecutor(max_workers=1) as executor:
# Execute the copy on a separate thread,
# creating a future object to track progress.
future = executor.submit(shutil.copytree, src_path, dst_path)
while future.running():
# Print pretty dots here.
pass
# Return the value returned by shutil.copytree(), None.
# Raise any exceptions raised during the copy process.
return future.result()
concurrent.futures
包含在Python 3.2中,并且可以作为早期版本的向后移植futures
模块。
回答 2
这个问题有很多非常复杂的答案。我是否对此简化了,因为这对我来说大多数事情似乎已经足够。
from threading import Thread
class PropagatingThread(Thread):
def run(self):
self.exc = None
try:
if hasattr(self, '_Thread__target'):
# Thread uses name mangling prior to Python 3.
self.ret = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
else:
self.ret = self._target(*self._args, **self._kwargs)
except BaseException as e:
self.exc = e
def join(self):
super(PropagatingThread, self).join()
if self.exc:
raise self.exc
return self.ret
如果确定只能在一个或另一个版本的Python上运行,则可以将该run()
方法缩减为仅损坏的版本(如果仅在3之前的Python版本上运行),或者只是干净的版本(如果您只能在以3开头的Python版本上运行)。
用法示例:
def f(*args, **kwargs):
print(args)
print(kwargs)
raise Exception('I suck at this')
t = PropagatingThread(target=f, args=(5,), kwargs={'hello':'world'})
t.start()
t.join()
当您加入时,您将看到另一个线程引发的异常。
如果仅使用six
Python 3或仅在Python 3上使用,则可以改善重新引发异常时所获得的堆栈跟踪信息。您可以将内部异常包装在新的外部异常中,而不是仅在连接时使用堆栈,并使用
six.raise_from(RuntimeError('Exception in thread'),self.exc)
要么
raise RuntimeError('Exception in thread') from self.exc
回答 3
尽管不可能直接捕获在不同线程中引发的异常,但是这里的代码可以透明地获取与该功能非常接近的内容。在等待线程完成其工作时,您的子线程必须ExThread
代替该类的子类,threading.Thread
并且父线程必须调用该child_thread.join_with_exception()
方法,而不是调用该方法child_thread.join()
。
此实现的技术细节:当子线程引发异常时,它将通过a传递给Queue
父线程,然后再次在父线程中引发。请注意,这种方法无需等待。
#!/usr/bin/env python
import sys
import threading
import Queue
class ExThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.__status_queue = Queue.Queue()
def run_with_exception(self):
"""This method should be overriden."""
raise NotImplementedError
def run(self):
"""This method should NOT be overriden."""
try:
self.run_with_exception()
except BaseException:
self.__status_queue.put(sys.exc_info())
self.__status_queue.put(None)
def wait_for_exc_info(self):
return self.__status_queue.get()
def join_with_exception(self):
ex_info = self.wait_for_exc_info()
if ex_info is None:
return
else:
raise ex_info[1]
class MyException(Exception):
pass
class MyThread(ExThread):
def __init__(self):
ExThread.__init__(self)
def run_with_exception(self):
thread_name = threading.current_thread().name
raise MyException("An error in thread '{}'.".format(thread_name))
def main():
t = MyThread()
t.start()
try:
t.join_with_exception()
except MyException as ex:
thread_name = threading.current_thread().name
print "Caught a MyException in thread '{}': {}".format(thread_name, ex)
if __name__ == '__main__':
main()
回答 4
如果线程中发生异常,最好的方法是在期间在调用者线程中重新引发它join
。您可以使用该sys.exc_info()
函数获取有关当前正在处理的异常的信息。该信息可以简单地存储为线程对象的属性,直到join
被调用为止,此时可以重新引发该信息。
请注意,Queue.Queue
在这种简单的情况下,线程最多引发1个异常,并在引发异常后立即完成,因此不需要(如其他答案中所建议的)。我们只需等待线程完成即可避免出现竞争情况。
例如,扩展ExcThread
(在下面),覆盖excRun
(而不是run
)。
Python 2.x:
import threading
class ExcThread(threading.Thread):
def excRun(self):
pass
def run(self):
self.exc = None
try:
# Possibly throws an exception
self.excRun()
except:
import sys
self.exc = sys.exc_info()
# Save details of the exception thrown but don't rethrow,
# just complete the function
def join(self):
threading.Thread.join(self)
if self.exc:
msg = "Thread '%s' threw an exception: %s" % (self.getName(), self.exc[1])
new_exc = Exception(msg)
raise new_exc.__class__, new_exc, self.exc[2]
Python 3.x:
的3参数形式raise
在Python 3中消失了,因此将最后一行更改为:
raise new_exc.with_traceback(self.exc[2])
回答 5
concurrent.futures.as_completed
https://docs.python.org/3.7/library/concurrent.futures.html#concurrent.futures.as_completed
以下解决方法:
- 调用异常后立即返回主线程
- 不需要额外的用户定义类,因为它不需要:
- 明确的
Queue
- 在工作线程周围添加一个else
- 明确的
资源:
#!/usr/bin/env python3
import concurrent.futures
import time
def func_that_raises(do_raise):
for i in range(3):
print(i)
time.sleep(0.1)
if do_raise:
raise Exception()
for i in range(3):
print(i)
time.sleep(0.1)
with concurrent.futures.ThreadPoolExecutor(max_workers=2) as executor:
futures = []
futures.append(executor.submit(func_that_raises, False))
futures.append(executor.submit(func_that_raises, True))
for future in concurrent.futures.as_completed(futures):
print(repr(future.exception()))
可能的输出:
0
0
1
1
2
2
0
Exception()
1
2
None
不幸的是,由于一个交易失败,不可能杀死期货以取消其他交易:
concurrent.features
; Python:current.futures如何使其取消?threading
:有什么方法可以杀死线程?- C pthread:杀死Pthread库中的线程
如果您执行以下操作:
for future in concurrent.futures.as_completed(futures):
if future.exception() is not None:
raise future.exception()
然后with
捕获它,并等待第二个线程完成后再继续。以下行为类似:
for future in concurrent.futures.as_completed(futures):
future.result()
因为future.result()
如果发生一个异常,则会重新引发异常。
如果您想退出整个Python过程,则可以使用os._exit(0)
,但是这可能意味着您需要重构。
具有完美异常语义的自定义类
我最终在以下方面为自己编写了一个完美的接口:限制一次运行的最大线程数的正确方法?部分“带有错误处理的队列示例”。该类旨在既方便,又使您可以完全控制提交和结果/错误处理。
在Python 3.6.7,Ubuntu 18.04上进行了测试。
回答 6
这是一个令人讨厌的小问题,我想提出自己的解决方案。我发现的其他一些解决方案(例如async.io)看起来很有希望,但也有一些黑匣子。队列/事件循环方法将您与特定实现联系在一起。但是,并发的期货源代码大约只有1000行,并且很容易理解。它使我可以轻松地解决我的问题:无需进行过多设置即可创建临时工作线程,并能够捕获主线程中的异常。
我的解决方案使用并发的期货API和线程API。它允许您创建一个工作线程,为您提供线程和未来。这样,您可以加入线程以等待结果:
worker = Worker(test)
thread = worker.start()
thread.join()
print(worker.future.result())
…或者您可以让工作人员在完成后仅发送回调:
worker = Worker(test)
thread = worker.start(lambda x: print('callback', x))
…或者您可以循环播放直到事件结束:
worker = Worker(test)
thread = worker.start()
while True:
print("waiting")
if worker.future.done():
exc = worker.future.exception()
print('exception?', exc)
result = worker.future.result()
print('result', result)
break
time.sleep(0.25)
这是代码:
from concurrent.futures import Future
import threading
import time
class Worker(object):
def __init__(self, fn, args=()):
self.future = Future()
self._fn = fn
self._args = args
def start(self, cb=None):
self._cb = cb
self.future.set_running_or_notify_cancel()
thread = threading.Thread(target=self.run, args=())
thread.daemon = True #this will continue thread execution after the main thread runs out of code - you can still ctrl + c or kill the process
thread.start()
return thread
def run(self):
try:
self.future.set_result(self._fn(*self._args))
except BaseException as e:
self.future.set_exception(e)
if(self._cb):
self._cb(self.future.result())
…以及测试功能:
def test(*args):
print('args are', args)
time.sleep(2)
raise Exception('foo')
回答 7
作为Threading的入门者,我花了很长时间了解如何实现Mateusz Kobos的代码(上述)。这是一个澄清的版本,可帮助您了解如何使用它。
#!/usr/bin/env python
import sys
import threading
import Queue
class ExThread(threading.Thread):
def __init__(self):
threading.Thread.__init__(self)
self.__status_queue = Queue.Queue()
def run_with_exception(self):
"""This method should be overriden."""
raise NotImplementedError
def run(self):
"""This method should NOT be overriden."""
try:
self.run_with_exception()
except Exception:
self.__status_queue.put(sys.exc_info())
self.__status_queue.put(None)
def wait_for_exc_info(self):
return self.__status_queue.get()
def join_with_exception(self):
ex_info = self.wait_for_exc_info()
if ex_info is None:
return
else:
raise ex_info[1]
class MyException(Exception):
pass
class MyThread(ExThread):
def __init__(self):
ExThread.__init__(self)
# This overrides the "run_with_exception" from class "ExThread"
# Note, this is where the actual thread to be run lives. The thread
# to be run could also call a method or be passed in as an object
def run_with_exception(self):
# Code will function until the int
print "sleeping 5 seconds"
import time
for i in 1, 2, 3, 4, 5:
print i
time.sleep(1)
# Thread should break here
int("str")
# I'm honestly not sure why these appear here? So, I removed them.
# Perhaps Mateusz can clarify?
# thread_name = threading.current_thread().name
# raise MyException("An error in thread '{}'.".format(thread_name))
if __name__ == '__main__':
# The code lives in MyThread in this example. So creating the MyThread
# object set the code to be run (but does not start it yet)
t = MyThread()
# This actually starts the thread
t.start()
print
print ("Notice 't.start()' is considered to have completed, although"
" the countdown continues in its new thread. So you code "
"can tinue into new processing.")
# Now that the thread is running, the join allows for monitoring of it
try:
t.join_with_exception()
# should be able to be replace "Exception" with specific error (untested)
except Exception, e:
print
print "Exceptioon was caught and control passed back to the main thread"
print "Do some handling here...or raise a custom exception "
thread_name = threading.current_thread().name
e = ("Caught a MyException in thread: '" +
str(thread_name) +
"' [" + str(e) + "]")
raise Exception(e) # Or custom class of exception, such as MyException
回答 8
类似于RickardSjogren的没有Queue,sys等的方式,但是也没有一些信号侦听器:直接执行与except块相对应的异常处理程序。
#!/usr/bin/env python3
import threading
class ExceptionThread(threading.Thread):
def __init__(self, callback=None, *args, **kwargs):
"""
Redirect exceptions of thread to an exception handler.
:param callback: function to handle occured exception
:type callback: function(thread, exception)
:param args: arguments for threading.Thread()
:type args: tuple
:param kwargs: keyword arguments for threading.Thread()
:type kwargs: dict
"""
self._callback = callback
super().__init__(*args, **kwargs)
def run(self):
try:
if self._target:
self._target(*self._args, **self._kwargs)
except BaseException as e:
if self._callback is None:
raise e
else:
self._callback(self, e)
finally:
# Avoid a refcycle if the thread is running a function with
# an argument that has a member that points to the thread.
del self._target, self._args, self._kwargs, self._callback
仅self._callback和run()中的except块是普通threading.Thread的附加项。
回答 9
我知道我在这里参加聚会有点晚了,但是我遇到了一个非常类似的问题,但是它包括使用tkinter作为GUI,并且mainloop使得无法使用任何依赖.join()的解决方案。因此,我改编了原始问题的EDIT中给出的解决方案,但使其变得更笼统,以使其他人易于理解。
这是正在使用的新线程类:
import threading
import traceback
import logging
class ExceptionThread(threading.Thread):
def __init__(self, *args, **kwargs):
threading.Thread.__init__(self, *args, **kwargs)
def run(self):
try:
if self._target:
self._target(*self._args, **self._kwargs)
except Exception:
logging.error(traceback.format_exc())
def test_function_1(input):
raise IndexError(input)
if __name__ == "__main__":
input = 'useful'
t1 = ExceptionThread(target=test_function_1, args=[input])
t1.start()
当然,从日志记录中,您总是可以用其他方法来处理异常,例如将其打印出来或将其输出到控制台。
这使您可以像完全使用Thread类一样使用ExceptionThread类,而无需进行任何特殊修改。
回答 10
我喜欢的一种方法是基于观察者模式。我定义了一个信号类,我的线程使用该信号类向侦听器发出异常。它也可以用于从线程返回值。例:
import threading
class Signal:
def __init__(self):
self._subscribers = list()
def emit(self, *args, **kwargs):
for func in self._subscribers:
func(*args, **kwargs)
def connect(self, func):
self._subscribers.append(func)
def disconnect(self, func):
try:
self._subscribers.remove(func)
except ValueError:
raise ValueError('Function {0} not removed from {1}'.format(func, self))
class WorkerThread(threading.Thread):
def __init__(self, *args, **kwargs):
super(WorkerThread, self).__init__(*args, **kwargs)
self.Exception = Signal()
self.Result = Signal()
def run(self):
if self._Thread__target is not None:
try:
self._return_value = self._Thread__target(*self._Thread__args, **self._Thread__kwargs)
except Exception as e:
self.Exception.emit(e)
else:
self.Result.emit(self._return_value)
if __name__ == '__main__':
import time
def handle_exception(exc):
print exc.message
def handle_result(res):
print res
def a():
time.sleep(1)
raise IOError('a failed')
def b():
time.sleep(2)
return 'b returns'
t = WorkerThread(target=a)
t2 = WorkerThread(target=b)
t.Exception.connect(handle_exception)
t2.Result.connect(handle_result)
t.start()
t2.start()
print 'Threads started'
t.join()
t2.join()
print 'Done'
我没有使用线程的足够经验来宣称这是一种完全安全的方法。但这对我有用,我喜欢这种灵活性。
回答 11
使用裸露的exceptions不是一个好习惯,因为您通常会收获比讨价还价更多的东西。
我建议修改,except
使其仅捕获您要处理的异常。我认为提高它并没有达到预期的效果,因为当您TheThread
在外部实例化时try
,如果它引发异常,则分配将永远不会发生。
相反,您可能只想提醒它并继续前进,例如:
def run(self):
try:
shul.copytree(self.sourceFolder, self.destFolder)
except OSError, err:
print err
然后,当该异常被捕获时,您可以在那里处理它。然后,当外部程序try
从中捕获到异常时TheThread
,您就会知道它不会是您已经处理过的异常,它将帮助您隔离处理流程。
回答 12
捕获线程异常并将其传递回调用方方法的一种简单方法是将字典或列表传递给worker
方法。
示例(将字典传递给worker方法):
import threading
def my_method(throw_me):
raise Exception(throw_me)
def worker(shared_obj, *args, **kwargs):
try:
shared_obj['target'](*args, **kwargs)
except Exception as err:
shared_obj['err'] = err
shared_obj = {'err':'', 'target': my_method}
throw_me = "Test"
th = threading.Thread(target=worker, args=(shared_obj, throw_me), kwargs={})
th.start()
th.join()
if shared_obj['err']:
print(">>%s" % shared_obj['err'])
回答 13
用异常存储包装线程。
import threading
import sys
class ExcThread(threading.Thread):
def __init__(self, target, args = None):
self.args = args if args else []
self.target = target
self.exc = None
threading.Thread.__init__(self)
def run(self):
try:
self.target(*self.args)
raise Exception('An error occured here.')
except Exception:
self.exc=sys.exc_info()
def main():
def hello(name):
print(!"Hello, {name}!")
thread_obj = ExcThread(target=hello, args=("Jack"))
thread_obj.start()
thread_obj.join()
exc = thread_obj.exc
if exc:
exc_type, exc_obj, exc_trace = exc
print(exc_type, ':',exc_obj, ":", exc_trace)
main()
回答 14
pygolang提供sync.WorkGroup,尤其是将异常从生成的工作线程传播到主线程。例如:
#!/usr/bin/env python
"""This program demostrates how with sync.WorkGroup an exception raised in
spawned thread is propagated into main thread which spawned the worker."""
from __future__ import print_function
from golang import sync, context
def T1(ctx, *argv):
print('T1: run ... %r' % (argv,))
raise RuntimeError('T1: problem')
def T2(ctx):
print('T2: ran ok')
def main():
wg = sync.WorkGroup(context.background())
wg.go(T1, [1,2,3])
wg.go(T2)
try:
wg.wait()
except Exception as e:
print('Tmain: caught exception: %r\n' %e)
# reraising to see full traceback
raise
if __name__ == '__main__':
main()
运行时给出以下内容:
T1: run ... ([1, 2, 3],)
T2: ran ok
Tmain: caught exception: RuntimeError('T1: problem',)
Traceback (most recent call last):
File "./x.py", line 28, in <module>
main()
File "./x.py", line 21, in main
wg.wait()
File "golang/_sync.pyx", line 198, in golang._sync.PyWorkGroup.wait
pyerr_reraise(pyerr)
File "golang/_sync.pyx", line 178, in golang._sync.PyWorkGroup.go.pyrunf
f(pywg._pyctx, *argv, **kw)
File "./x.py", line 10, in T1
raise RuntimeError('T1: problem')
RuntimeError: T1: problem
该问题的原始代码就是:
wg = sync.WorkGroup(context.background())
def _(ctx):
shul.copytree(sourceFolder, destFolder)
wg.go(_)
# waits for spawned worker to complete and, on error, reraises
# its exception on the main thread.
wg.wait()