基于正则表达式的Python拆分字符串

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问题：基于正则表达式的Python拆分字符串

"HELLO there HOW are YOU"用大写单词分割字符串的最佳方法是什么（在Python中）？

所以我最终得到一个像这样的数组： results = ['HELLO there', 'HOW are', 'YOU']

编辑：

我努力了：

p = re.compile("\b[A-Z]{2,}\b")
print p.split(page_text)

不过，它似乎不起作用。

What is the best way to split a string like "HELLO there HOW are YOU" by upper case words (in Python)?

So I’d end up with an array like such: results = ['HELLO there', 'HOW are', 'YOU']

EDIT:

I have tried:

p = re.compile("\b[A-Z]{2,}\b")
print p.split(page_text)

It doesn’t seem to work, though.

我建议

l = re.compile("(?<!^)\s+(?=[A-Z])(?!.\s)").split(s)

检查这个演示。

I suggest

l = re.compile("(?<!^)\s+(?=[A-Z])(?!.\s)").split(s)

Check this demo.

您可以先行使用：

re.split(r'[ ](?=[A-Z]+\b)', input)

这将在每个空格处分开，后跟一串大写字母，每个大写字母以单词边界结尾。

请注意，方括号仅出于可读性考虑，也可以省略。

如果一个单词的第一个字母大写就足够了（因此，如果您也想在其前面拆分Hello），它将变得更加容易：

re.split(r'[ ](?=[A-Z])', input)

现在，这会在每个空格处分开，后跟任何大写字母。

You could use a lookahead:

re.split(r'[ ](?=[A-Z]+\b)', input)

This will split at every space that is followed by a string of upper-case letters which end in a word-boundary.

Note that the square brackets are only for readability and could as well be omitted.

If it is enough that the first letter of a word is upper case (so if you would want to split in front of Hello as well) it gets even easier:

re.split(r'[ ](?=[A-Z])', input)

Now this splits at every space followed by any upper-case letter.

您的问题包含字符串文字"\b[A-Z]{2,}\b"，但是这\b意味着退格，因为没有r-修饰符。

试试：r"\b[A-Z]{2,}\b"。

Your question contains the string literal "\b[A-Z]{2,}\b", but that \b will mean backspace, because there is no r-modifier.

Try: r"\b[A-Z]{2,}\b".