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如何为Popen指定工作目录

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问题：如何为Popen指定工作目录
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问题：如何为Popen指定工作目录

有没有一种方法可以在Python的目录中指定命令的运行目录subprocess.Popen()？

例如：

Popen('c:\mytool\tool.exe', workingdir='d:\test\local')

我的Python脚本位于 C:\programs\python

是否可以C:\mytool\tool.exe在目录中运行D:\test\local？

如何设置子流程的工作目录？

点击查看英文原文

Is there a way to specify the running directory of command in Python’s subprocess.Popen()?

For example:

Popen('c:\mytool\tool.exe', workingdir='d:\test\local')

My Python script is located in C:\programs\python

Is is possible to run C:\mytool\tool.exe in the directory D:\test\local?

How do I set the working directory for a sub-process?

回答 0

subprocess.Popen 接受一个cwd参数来设置当前工作目录；您还需要转义反斜杠（'d:\\test\\local'），或使用，r'd:\test\local'以便Python不会将反斜杠解释为转义序列。按照您编写的方式，\t零件将被翻译为tab。

因此，您的新行应如下所示：

subprocess.Popen(r'c:\mytool\tool.exe', cwd=r'd:\test\local')

要将Python脚本路径用作cwd，import os并使用以下命令定义cwd：

os.path.dirname(os.path.realpath(__file__))
点击查看英文原文

subprocess.Popen takes a cwd argument to set the Current Working Directory; you’ll also want to escape your backslashes ('d:\\test\\local'), or use r'd:\test\local' so that the backslashes aren’t interpreted as escape sequences by Python. The way you have it written, the \t part will be translated to a tab.

So, your new line should look like:

subprocess.Popen(r'c:\mytool\tool.exe', cwd=r'd:\test\local')

To use your Python script path as cwd, import os and define cwd using this:

os.path.dirname(os.path.realpath(__file__))