问题:如何使用matplotlib为多个子图制作一个图例?
我正在绘制相同类型的信息,但针对不同的国家,使用matplotlib具有多个子图。也就是说,我在3×3网格上有9个图,所有图线都相同(当然,每条线的值不同)。
但是,我还没有想出如何仅在图上放置一个图例(因为所有9个子图都有相同的行)。
我怎么做?
回答 0
get_legend_handles_labels()
您还可以在最后一个轴上调用一个不错的函数(如果对其进行迭代),该label=
函数将从参数中收集所需的所有信息:
handles, labels = ax.get_legend_handles_labels()
fig.legend(handles, labels, loc='upper center')
回答 1
figlegend可能就是您要寻找的东西:http ://matplotlib.org/api/pyplot_api.html#matplotlib.pyplot.figlegend
此处的示例:http : //matplotlib.org/examples/pylab_examples/figlegend_demo.html
另一个例子:
plt.figlegend( lines, labels, loc = 'lower center', ncol=5, labelspacing=0. )
要么:
fig.legend( lines, labels, loc = (0.5, 0), ncol=5 )
回答 2
为了自动将单个图例定位在figure
具有多个轴的轴上(如通过所获得的轴),subplots()
以下解决方案非常有效:
plt.legend( lines, labels, loc = 'lower center', bbox_to_anchor = (0,-0.1,1,1),
bbox_transform = plt.gcf().transFigure )
使用bbox_to_anchor
和,bbox_transform=plt.gcf().transFigure
您将定义一个与您的大小相同的新边框figure
作为的参考loc
。使用(0,-0.1,1,1)
此装订线框稍微向下移动,以防止将图例放置在其他艺术家的上方。
OBS:使用之后fig.set_size_inches()
和使用之前,请使用此解决方案fig.tight_layout()
回答 3
您只需要在循环外询问一次图例。
例如,在这种情况下,我有4个子图,它们具有相同的行和一个图例。
from matplotlib.pyplot import *
ficheiros = ['120318.nc', '120319.nc', '120320.nc', '120321.nc']
fig = figure()
fig.suptitle('concentration profile analysis')
for a in range(len(ficheiros)):
# dados is here defined
level = dados.variables['level'][:]
ax = fig.add_subplot(2,2,a+1)
xticks(range(8), ['0h','3h','6h','9h','12h','15h','18h','21h'])
ax.set_xlabel('time (hours)')
ax.set_ylabel('CONC ($\mu g. m^{-3}$)')
for index in range(len(level)):
conc = dados.variables['CONC'][4:12,index] * 1e9
ax.plot(conc,label=str(level[index])+'m')
dados.close()
ax.legend(bbox_to_anchor=(1.05, 0), loc='lower left', borderaxespad=0.)
# it will place the legend on the outer right-hand side of the last axes
show()
回答 4
我注意到没有答案显示带有单个图例的图像,该图例引用了不同子图中的许多曲线,因此我必须向您展示一个……让您感到好奇……
现在,您想看一下代码,不是吗?
from numpy import linspace
import matplotlib.pyplot as plt
# Calling the axes.prop_cycle returns an itertoools.cycle
color_cycle = plt.rcParams['axes.prop_cycle']()
# I need some curves to plot
x = linspace(0, 1, 51)
f1 = x*(1-x) ; lab1 = 'x - x x'
f2 = 0.25-f1 ; lab2 = '1/4 - x + x x'
f3 = x*x*(1-x) ; lab3 = 'x x - x x x'
f4 = 0.25-f3 ; lab4 = '1/4 - x x + x x x'
# let's plot our curves (note the use of color cycle, otherwise the curves colors in
# the two subplots will be repeated and a single legend becomes difficult to read)
fig, (a13, a24) = plt.subplots(2)
a13.plot(x, f1, label=lab1, **next(color_cycle))
a13.plot(x, f3, label=lab3, **next(color_cycle))
a24.plot(x, f2, label=lab2, **next(color_cycle))
a24.plot(x, f4, label=lab4, **next(color_cycle))
# so far so good, now the trick
lines_labels = [ax.get_legend_handles_labels() for ax in fig.axes]
lines, labels = [sum(lol, []) for lol in zip(*lines_labels)]
# finally we invoke the legend (that you probably would like to customize...)
fig.legend(lines, labels)
plt.show()
两条线
lines_labels = [ax.get_legend_handles_labels() for ax in fig.axes]
lines, labels = [sum(lol, []) for lol in zip(*lines_labels)]
值得解释-为此,我将棘手的部分封装在一个函数中,仅用4行代码,但注释严重
def fig_legend(fig, **kwdargs):
# generate a sequence of tuples, each contains
# - a list of handles (lohand) and
# - a list of labels (lolbl)
tuples_lohand_lolbl = (ax.get_legend_handles_labels() for ax in fig.axes)
# e.g. a figure with two axes, ax0 with two curves, ax1 with one curve
# yields: ([ax0h0, ax0h1], [ax0l0, ax0l1]) and ([ax1h0], [ax1l0])
# legend needs a list of handles and a list of labels,
# so our first step is to transpose our data,
# generating two tuples of lists of homogeneous stuff(tolohs), i.e
# we yield ([ax0h0, ax0h1], [ax1h0]) and ([ax0l0, ax0l1], [ax1l0])
tolohs = zip(*tuples_lohand_lolbl)
# finally we need to concatenate the individual lists in the two
# lists of lists: [ax0h0, ax0h1, ax1h0] and [ax0l0, ax0l1, ax1l0]
# a possible solution is to sum the sublists - we use unpacking
handles, labels = (sum(list_of_lists, []) for list_of_lists in tolohs)
# call fig.legend with the keyword arguments, return the legend object
return fig.legend(handles, labels, **kwdargs)
PS我认识到这sum(list_of_lists, [])
是一种平整列表列表的方法,实际上是一种效率很低的方法,但是①我喜欢它的紧凑性,②通常在几个子图中有一些曲线,并且③Matplotlib和效率高吗?;-)
回答 5
虽然游戏时间比较晚,但我将在此处提供另一种解决方案,因为这仍然是显示在Google上的第一个链接之一。使用matplotlib 2.2.2,可以使用gridspec功能来实现。在下面的示例中,目标是以2×2的方式排列四个子图,图例显示在底部。在底部创建一个“人造”轴,以将图例放置在固定位置。然后关闭“人造”轴,因此仅显示图例。结果:https : //i.stack.imgur.com/5LUWM.png。
import matplotlib.pyplot as plt
import matplotlib.gridspec as gridspec
#Gridspec demo
fig = plt.figure()
fig.set_size_inches(8,9)
fig.set_dpi(100)
rows = 17 #the larger the number here, the smaller the spacing around the legend
start1 = 0
end1 = int((rows-1)/2)
start2 = end1
end2 = int(rows-1)
gspec = gridspec.GridSpec(ncols=4, nrows=rows)
axes = []
axes.append(fig.add_subplot(gspec[start1:end1,0:2]))
axes.append(fig.add_subplot(gspec[start2:end2,0:2]))
axes.append(fig.add_subplot(gspec[start1:end1,2:4]))
axes.append(fig.add_subplot(gspec[start2:end2,2:4]))
axes.append(fig.add_subplot(gspec[end2,0:4]))
line, = axes[0].plot([0,1],[0,1],'b') #add some data
axes[-1].legend((line,),('Test',),loc='center') #create legend on bottommost axis
axes[-1].set_axis_off() #don't show bottommost axis
fig.tight_layout()
plt.show()
回答 6
如果您将子图与条形图一起使用,则每个条形具有不同的颜色。自己动手制作艺术品可能会更快mpatches
假设您有四个颜色不同的条形图,r
m
c
k
可以按如下所示设置图例
import matplotlib.patches as mpatches
import matplotlib.pyplot as plt
labels = ['Red Bar', 'Magenta Bar', 'Cyan Bar', 'Black Bar']
#####################################
# insert code for the subplots here #
#####################################
# now, create an artist for each color
red_patch = mpatches.Patch(facecolor='r', edgecolor='#000000') #this will create a red bar with black borders, you can leave out edgecolor if you do not want the borders
black_patch = mpatches.Patch(facecolor='k', edgecolor='#000000')
magenta_patch = mpatches.Patch(facecolor='m', edgecolor='#000000')
cyan_patch = mpatches.Patch(facecolor='c', edgecolor='#000000')
fig.legend(handles = [red_patch, magenta_patch, cyan_patch, black_patch],labels=labels,
loc="center right",
borderaxespad=0.1)
plt.subplots_adjust(right=0.85) #adjust the subplot to the right for the legend
回答 7
此答案是@Evert在图例位置的补充。
由于图例和子图标题的重叠,我对@Evert解决方案的首次尝试失败。
实际上,重叠是由引起的fig.tight_layout()
,这会更改子图的布局而无需考虑图形图例。但是,这fig.tight_layout()
是必需的。
为了避免重叠,我们可以通过告知fig.tight_layout()
为人物的图例保留空格fig.tight_layout(rect=(0,0,1,0.9))
。
回答 8
要建立在@gboffi和Ben Usman的答案之上:
在不同的子图中具有相同颜色和标签的不同线条的情况下,可以沿
labels_handles = {
label: handle for ax in fig.axes for handle, label in zip(*ax.get_legend_handles_labels())
}
fig.legend(
labels_handles.values(),
labels_handles.keys(),
loc="upper center",
bbox_to_anchor=(0.5, 0),
bbox_transform=plt.gcf().transFigure,
)