问题：如何在Linux和Windows中的Python中使用“ /”（目录分隔符）？
我已经在python中编写了一个代码，该代码使用/在文件夹中创建特定文件，如果我想在Windows中使用该代码将无法正常工作，有没有一种方法可以在Windows和Linux中使用该代码。
在python中，我使用以下代码：
pathfile=os.path.dirname(templateFile)
rootTree.write(''+pathfile+'/output/log.txt')
当我在Windows计算机中使用我的代码时，我的代码将无法工作。
在Linux和Windows中如何使用“ /”（目录分隔符）？
I have written a code in python which uses / to make a particular file in a folder, if I want to use the code in windows it will not work, is there a way by which I can use the code in Windows and Linux.
In python I am using this code:
pathfile=os.path.dirname(templateFile)
rootTree.write(''+pathfile+'/output/log.txt')
When I will use my code in suppose windows machine my code will not work.
How do I use “/” (directory separator) in both Linux and Windows?
回答 0
使用os.path.join()。范例：os.path.join(pathfile,"output","log.txt")。
在您的代码中将是： rootTree.write(os.path.join(pathfile,"output","log.txt"))
Use os.path.join().
Example: os.path.join(pathfile,"output","log.txt").
In your code that would be: rootTree.write(os.path.join(pathfile,"output","log.txt"))
回答 1
用：
import os
print os.sep
查看分隔符在当前操作系统上的外观。
在您的代码中，您可以使用：
import os
path = os.path.join('folder_name', 'file_name')
Use:
import os
print os.sep
to see how separator looks on a current OS.
In your code you can use:
import os
path = os.path.join('folder_name', 'file_name')
回答 2
您可以使用os.sep：
>>> import os
>>> os.sep
'/'
You can use os.sep:
>>> import os
>>> os.sep
'/'
回答 3
os.path.normpath(pathname)还应提及，因为它将Windows上的/路径分隔符转换为\分隔符。它还折叠冗余uplevel引用…即，A/B与A/foo/../B和A/./B一切变得A/B。如果您使用的是Windows，那么所有这些都将变为A\B。
os.path.normpath(pathname) should also be mentioned as it converts / path separators into \ separators on Windows. It also collapses redundant uplevel references… i.e., A/B and A/foo/../B and A/./B all become A/B. And if you are Windows, these all become A\B.
回答 4
如果您有幸能够运行Python 3.4+，则可以使用pathlib：
from pathlib import Path
path = Path(dir, subdir, filename) # returns a path of the system's path flavour
或者，等效地，
path = Path(dir) / subdir / filename
If you are fortunate enough to be running Python 3.4+, you can use pathlib:
from pathlib import Path
path = Path(dir, subdir, filename) # returns a path of the system's path flavour
or, equivalently,
path = Path(dir) / subdir / filename
回答 5
Some useful links that will help you:
回答 6
Do a import os and then use os.sep
回答 7
您可以使用“ os.sep ”
import os
pathfile=os.path.dirname(templateFile)
directory = str(pathfile)+os.sep+'output'+os.sep+'log.txt'
rootTree.write(directory)
You can use “os.sep “
import os
pathfile=os.path.dirname(templateFile)
directory = str(pathfile)+os.sep+'output'+os.sep+'log.txt'
rootTree.write(directory)
回答 8
不要自行建立目录和文件名，请使用python随附的库。
在这种情况下，相关的是os.path。特别是join，它从目录和文件名或目录创建一个新的路径名，然后从完整路径中获取文件名。
你的例子是
pathfile=os.path.dirname(templateFile)
p = os.path.join(pathfile, 'output')
p = os.path.join( p, 'log.txt')
rootTree.write(p)
Don’t build directory and file names your self, use python’s included libraries.
In this case the relevant one is os.path. Especially join which creates a new pathname from a directory and a file name or directory and split that gets the filename from a full path.
Your example would be
pathfile=os.path.dirname(templateFile)
p = os.path.join(pathfile, 'output')
p = os.path.join( p, 'log.txt')
rootTree.write(p)
