问题：如何在python中将集合转换为列表？
我正在尝试将一组转换为Python 2.6中的列表。我正在使用以下语法：
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
但是，我得到以下堆栈跟踪：
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: 'set' object is not callable
我怎样才能解决这个问题？
I am trying to convert a set to a list in Python 2.6. I’m using this syntax:
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
However, I get the following stack trace:
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: 'set' object is not callable
How can I fix this?
回答 0
已经是清单了
type(my_set)
>>> <type 'list'>
你想要类似的东西吗
my_set = set([1,2,3,4])
my_list = list(my_set)
print my_list
>> [1, 2, 3, 4]
编辑：您的最后评论的输出
>>> my_list = [1,2,3,4]
>>> my_set = set(my_list)
>>> my_new_list = list(my_set)
>>> print my_new_list
[1, 2, 3, 4]
我想知道您是否做了这样的事情：
>>> set=set()
>>> set([1,2])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
It is already a list
type(my_set)
>>> <type 'list'>
Do you want something like
my_set = set([1,2,3,4])
my_list = list(my_set)
print my_list
>> [1, 2, 3, 4]
EDIT :
Output of your last comment
>>> my_list = [1,2,3,4]
>>> my_set = set(my_list)
>>> my_new_list = list(my_set)
>>> print my_new_list
[1, 2, 3, 4]
I’m wondering if you did something like this :
>>> set=set()
>>> set([1,2])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
回答 1
代替：
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
为什么不简化该过程：
my_list = list(set([1,2,3,4])
这将从您的列表中删除重复对象，并将列表返回给您。
Instead of:
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
Why not shortcut the process:
my_list = list(set([1,2,3,4])
This will remove the dupes from you list and return a list back to you.
回答 2
[编辑]似乎您之前已经重新定义了“列表”，将其用作变量名，如下所示：
list = set([1,2,3,4]) # oops
#...
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
你会得到
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: 'set' object is not callable
[EDITED]
It’s seems you earlier have redefined “list”, using it as a variable name, like this:
list = set([1,2,3,4]) # oops
#...
first_list = [1,2,3,4]
my_set=set(first_list)
my_list = list(my_set)
And you’l get
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: 'set' object is not callable
回答 3
每当遇到此类问题时，请尝试使用以下方法查找要首先转换的元素的数据类型：
type(my_set)
然后，使用：
list(my_set)
将其转换为列表。您现在可以像使用python中的任何普通列表一样使用新建列表。
Whenever you are stuck in such type of problems, try to find the datatype of the element you want to convert first by using :
type(my_set)
Then, Use:
list(my_set)
to convert it to a list. You can use the newly built list like any normal list in python now.
回答 4
只需键入：
list(my_set)
这会将格式为{‘1’，’2’}的集合转换为格式为[‘1’，’2’]的列表。
Simply type:
list(my_set)
This will turn a set in the form {‘1′,’2’} into a list in the form [‘1′,’2’].
回答 5
查看您的第一行。您的堆栈跟踪信息显然不是来自您在此处粘贴的代码，因此我不知道您到底做了什么。
>>> my_set=([1,2,3,4])
>>> my_set
[1, 2, 3, 4]
>>> type(my_set)
<type 'list'>
>>> list(my_set)
[1, 2, 3, 4]
>>> type(_)
<type 'list'>
你想要的是set([1, 2, 3, 4])。
>>> my_set = set([1, 2, 3, 4])
>>> my_set
set([1, 2, 3, 4])
>>> type(my_set)
<type 'set'>
>>> list(my_set)
[1, 2, 3, 4]
>>> type(_)
<type 'list'>
“不可调用”异常表示您正在执行类似操作set()()-尝试调用set实例。
Review your first line. Your stack trace is clearly not from the code you’ve pasted here, so I don’t know precisely what you’ve done.
>>> my_set=([1,2,3,4])
>>> my_set
[1, 2, 3, 4]
>>> type(my_set)
<type 'list'>
>>> list(my_set)
[1, 2, 3, 4]
>>> type(_)
<type 'list'>
What you wanted was set([1, 2, 3, 4]).
>>> my_set = set([1, 2, 3, 4])
>>> my_set
set([1, 2, 3, 4])
>>> type(my_set)
<type 'set'>
>>> list(my_set)
[1, 2, 3, 4]
>>> type(_)
<type 'list'>
The “not callable” exception means you were doing something like set()() – attempting to call a set instance.
回答 6
我不确定您是否正在使用此([1, 2])语法创建一个集合，而不是一个列表。要创建集合，您应该使用set([1, 2])。
这些括号只是包裹住您的表达方式，就像您会写的那样：
if (condition1
and condition2 == 3):
print something
并没有真正被忽略，但是对您的表情什么也不做。
注意：(something, something_else)将创建一个元组（但仍然没有列表）。
I’m not sure that you’re creating a set with this ([1, 2]) syntax, rather a list. To create a set, you should use set([1, 2]).
These brackets are just envelopping your expression, as if you would have written:
if (condition1
and condition2 == 3):
print something
There’re not really ignored, but do nothing to your expression.
Note: (something, something_else) will create a tuple (but still no list).
回答 7
Python是一种动态类型化的语言，这意味着您不能像在C或C ++中那样定义变量的类型：
type variable = value
要么
type variable(value)
在Python中，如果更改类型或类型的初始化函数（构造函数）来声明类型的变量，则可以使用强制转换：
my_set = set([1,2,3])
type my_set
会给你<type 'set'>答案。
如果有列表，请执行以下操作：
my_list = [1,2,3]
my_set = set(my_list)
Python is a dynamically typed language, which means that you cannot define the type of the variable as you do in C or C++:
type variable = value
or
type variable(value)
In Python, you use coercing if you change types, or the init functions (constructors) of the types to declare a variable of a type:
my_set = set([1,2,3])
type my_set
will give you <type 'set'> for an answer.
If you have a list, do this:
my_list = [1,2,3]
my_set = set(my_list)
回答 8
嗯，我敢打赌，在前面的几行中，您会看到以下内容：
list = set(something)
我错了吗 ？
Hmmm I bet that in some previous lines you have something like:
list = set(something)
Am I wrong ?
