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如何在Python中找到与正则表达式的所有匹配项？

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问题：如何在Python中找到与正则表达式的所有匹配项？
回答 0

问题：如何在Python中找到与正则表达式的所有匹配项？

在我编写的程序中，我使用Python re.search()函数在文本块中查找匹配项并打印结果。但是，一旦找到文本块中的第一个匹配项，程序就会退出。

在找到所有匹配项之前程序不停止的情况下，如何重复执行此操作？是否有单独的功能来执行此操作？

点击查看英文原文

In a program I’m writing I have Python use the re.search() function to find matches in a block of text and print the results. However, the program exits once it finds the first match in the block of text.

How do I do this repeatedly where the program doesn’t stop until ALL matches have been found? Is there a separate function to do this?

回答 0

使用re.findall或re.finditer代替。

re.findall(pattern, string) 返回匹配字符串的列表。

re.finditer(pattern, string)返回MatchObject对象上的迭代器。

例：

re.findall( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')
# Output: ['cats', 'dogs']

[x.group() for x in re.finditer( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')]
# Output: ['all cats are', 'all dogs are']
点击查看英文原文

Use re.findall or re.finditer instead.

re.findall(pattern, string) returns a list of matching strings.

re.finditer(pattern, string) returns an iterator over MatchObject objects.

Example:

re.findall( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')
# Output: ['cats', 'dogs']

[x.group() for x in re.finditer( r'all (.*?) are', 'all cats are smarter than dogs, all dogs are dumber than cats')]
# Output: ['all cats are', 'all dogs are']