问题:如何在Python中获取实例变量?

Python中是否有内置方法来获取所有类的实例变量的数组?例如,如果我有以下代码:

class hi:
  def __init__(self):
    self.ii = "foo"
    self.kk = "bar"

有没有办法让我做到这一点:

>>> mystery_method(hi)
["ii", "kk"]

编辑:我最初是错误地要求类变量。

Is there a built-in method in Python to get an array of all a class’ instance variables? For example, if I have this code:

class hi:
  def __init__(self):
    self.ii = "foo"
    self.kk = "bar"

Is there a way for me to do this:

>>> mystery_method(hi)
["ii", "kk"]

Edit: I originally had asked for class variables erroneously.


回答 0

每个对象都有一个__dict__变量,其中包含所有变量及其值。

试试这个

>>> hi_obj = hi()
>>> hi_obj.__dict__.keys()

Every object has a __dict__ variable containing all the variables and its values in it.

Try this

>>> hi_obj = hi()
>>> hi_obj.__dict__.keys()

回答 1

使用vars()

class Foo(object):
    def __init__(self):
        self.a = 1
        self.b = 2

vars(Foo()) #==> {'a': 1, 'b': 2}
vars(Foo()).keys() #==> ['a', 'b']

Use vars()

class Foo(object):
    def __init__(self):
        self.a = 1
        self.b = 2

vars(Foo()) #==> {'a': 1, 'b': 2}
vars(Foo()).keys() #==> ['a', 'b']

回答 2

通常,仅给定一个类就不能获得实例属性,至少不能不实例化该类。但是,您可以获取给定实例的实例属性,也可以获取给定类的类属性。请参阅“检查”模块。您无法获得实例属性的列表,因为实例实际上可以将任何东西作为属性,而且-如您的示例中所示-创建它们的通常方法是只在__init__方法中对其进行分配。

exceptions是您的类使用插槽,插槽是类允许实例具有的固定属性列表。插槽在http://www.python.org/2.2.3/descrintro.html中进行了说明,但是插槽存在各种陷阱。它们会影响内存布局,因此多重继承可能会出现问题,并且一般而言,继承也必须考虑插槽。

You normally can’t get instance attributes given just a class, at least not without instantiating the class. You can get instance attributes given an instance, though, or class attributes given a class. See the ‘inspect’ module. You can’t get a list of instance attributes because instances really can have anything as attribute, and — as in your example — the normal way to create them is to just assign to them in the __init__ method.

An exception is if your class uses slots, which is a fixed list of attributes that the class allows instances to have. Slots are explained in http://www.python.org/2.2.3/descrintro.html, but there are various pitfalls with slots; they affect memory layout, so multiple inheritance may be problematic, and inheritance in general has to take slots into account, too.


回答 3

Vars()和dict方法都将适用于OP发布的示例,但不适用于“松散”定义的对象,例如:

class foo:
  a = 'foo'
  b = 'bar'

要打印所有不可调用的属性,可以使用以下功能:

def printVars(object):
    for i in [v for v in dir(object) if not callable(getattr(object,v))]:
        print '\n%s:' % i
        exec('print object.%s\n\n') % i

Both the Vars() and dict methods will work for the example the OP posted, but they won’t work for “loosely” defined objects like:

class foo:
  a = 'foo'
  b = 'bar'

To print all non-callable attributes, you can use the following function:

def printVars(object):
    for i in [v for v in dir(object) if not callable(getattr(object,v))]:
        print '\n%s:' % i
        exec('print object.%s\n\n') % i

回答 4

您还可以使用以下方法测试对象是否具有特定变量:

>>> hi_obj = hi()
>>> hasattr(hi_obj, "some attribute")

You can also test if an object has a specific variable with:

>>> hi_obj = hi()
>>> hasattr(hi_obj, "some attribute")

回答 5

您的示例显示了“实例变量”,而不是真正的类变量。

查找hi_obj.__class__.__dict__.items()类变量,以及其他其他类成员,例如成员函数和包含的模块。

class Hi( object ):
    class_var = ( 23, 'skidoo' ) # class variable
    def __init__( self ):
        self.ii = "foo" # instance variable
        self.jj = "bar"

类变量由该类的所有实例共享。

Your example shows “instance variables”, not really class variables.

Look in hi_obj.__class__.__dict__.items() for the class variables, along with other other class members like member functions and the containing module.

class Hi( object ):
    class_var = ( 23, 'skidoo' ) # class variable
    def __init__( self ):
        self.ii = "foo" # instance variable
        self.jj = "bar"

Class variables are shared by all instances of the class.


回答 6

建议

>>> print vars.__doc__
vars([object]) -> dictionary

Without arguments, equivalent to locals().
With an argument, equivalent to object.__dict__.

换句话说,它实际上只是包装__dict__

Suggest

>>> print vars.__doc__
vars([object]) -> dictionary

Without arguments, equivalent to locals().
With an argument, equivalent to object.__dict__.

In otherwords, it essentially just wraps __dict__


回答 7

尽管不是直接回答OP问题,但是有一种很不错的方法可以找出函数范围内的变量。看一下这段代码:

>>> def f(x, y):
    z = x**2 + y**2
    sqrt_z = z**.5
    return sqrt_z

>>> f.func_code.co_varnames
('x', 'y', 'z', 'sqrt_z')
>>> 

func_code属性中包含各种有趣的东西。它可以让您做一些很酷的事情。这是我如何使用此示例:

def exec_command(self, cmd, msg, sig):

    def message(msg):
        a = self.link.process(self.link.recieved_message(msg))
        self.exec_command(*a)

    def error(msg):
        self.printer.printInfo(msg)

    def set_usrlist(msg):
        self.client.connected_users = msg

    def chatmessage(msg):
        self.printer.printInfo(msg)

    if not locals().has_key(cmd): return
    cmd = locals()[cmd]

    try:
        if 'sig' in cmd.func_code.co_varnames and \
                       'msg' in cmd.func_code.co_varnames: 
            cmd(msg, sig)
        elif 'msg' in cmd.func_code.co_varnames: 
            cmd(msg)
        else:
            cmd()
    except Exception, e:
        print '\n-----------ERROR-----------'
        print 'error: ', e
        print 'Error proccessing: ', cmd.__name__
        print 'Message: ', msg
        print 'Sig: ', sig
        print '-----------ERROR-----------\n'

Although not directly an answer to the OP question, there is a pretty sweet way of finding out what variables are in scope in a function. take a look at this code:

>>> def f(x, y):
    z = x**2 + y**2
    sqrt_z = z**.5
    return sqrt_z

>>> f.func_code.co_varnames
('x', 'y', 'z', 'sqrt_z')
>>> 

The func_code attribute has all kinds of interesting things in it. It allows you todo some cool stuff. Here is an example of how I have have used this:

def exec_command(self, cmd, msg, sig):

    def message(msg):
        a = self.link.process(self.link.recieved_message(msg))
        self.exec_command(*a)

    def error(msg):
        self.printer.printInfo(msg)

    def set_usrlist(msg):
        self.client.connected_users = msg

    def chatmessage(msg):
        self.printer.printInfo(msg)

    if not locals().has_key(cmd): return
    cmd = locals()[cmd]

    try:
        if 'sig' in cmd.func_code.co_varnames and \
                       'msg' in cmd.func_code.co_varnames: 
            cmd(msg, sig)
        elif 'msg' in cmd.func_code.co_varnames: 
            cmd(msg)
        else:
            cmd()
    except Exception, e:
        print '\n-----------ERROR-----------'
        print 'error: ', e
        print 'Error proccessing: ', cmd.__name__
        print 'Message: ', msg
        print 'Sig: ', sig
        print '-----------ERROR-----------\n'

回答 8

建立在dmark的答案上以获取以下内容,如果您希望获得sprintf的等效功能,这将很有用,并希望能对某人有所帮助…

def sprint(object):
    result = ''
    for i in [v for v in dir(object) if not callable(getattr(object, v)) and v[0] != '_']:
        result += '\n%s:' % i + str(getattr(object, i, ''))
    return result

built on dmark’s answer to get the following, which is useful if you want the equiv of sprintf and hopefully will help someone…

def sprint(object):
    result = ''
    for i in [v for v in dir(object) if not callable(getattr(object, v)) and v[0] != '_']:
        result += '\n%s:' % i + str(getattr(object, i, ''))
    return result

回答 9

有时您想根据公共/私有变量来过滤列表。例如

def pub_vars(self):
    """Gives the variable names of our instance we want to expose
    """
    return [k for k in vars(self) if not k.startswith('_')]

Sometimes you want to filter the list based on public/private vars. E.g.

def pub_vars(self):
    """Gives the variable names of our instance we want to expose
    """
    return [k for k in vars(self) if not k.startswith('_')]

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