如何在python函数中打印换行符？

I have a list of strings in my code;

A = ['a1', 'a2', 'a3' ...]
B = ['b1', 'b2', 'b3' ...]

and I want to print them separated by a linebreak, like this:

>a1
b1
>a2
b2
>a3
b3

I’ve tried:

print '>' + A + '/n' + B

But /n isn’t recognized like a line break.

You have your slash backwards, it should be "\n"

The newline character is actually '\n'.

>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']

>>> for x in A:
        for i in B:
            print ">" + x + "\n" + i

Outputs:

>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3

Notice that you are using /n which is not correct!

for pair in zip(A, B):
    print ">"+'\n'.join(pair)

All three way you can use for newline character :

'\n'

"\n"

"""\n"""

\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.

You can print a native linebreak using the standard os library

import os
with open('test.txt','w') as f:
    f.write(os.linesep)

Also if you’re making it a console program, you can do: print(" ") and continue your program. I’ve found it the easiest way to separate my text.