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问题：如何将列表中的每个元素除以int？
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5

问题：如何将列表中的每个元素除以int？

我只想将一个列表中的每个元素都用一个int分隔。

myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = myList/myInt

这是错误：

TypeError: unsupported operand type(s) for /: 'list' and 'int'

我了解为什么收到此错误。但是我为找不到解决方案感到沮丧。

还尝试了：

newList = [ a/b for a, b in (myList,myInt)]

错误：

ValueError: too many values to unpack

预期结果：

newList = [1,2,3,4,5,6,7,8,9]


编辑：

以下代码给了我预期的结果：

newList = []
for x in myList:
    newList.append(x/myInt)

但是，有没有更容易/更快的方法来做到这一点？

点击查看英文原文

I just want to divide each element in a list by an int.

myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = myList/myInt

This is the error:

TypeError: unsupported operand type(s) for /: 'list' and 'int'

I understand why I am receiving this error. But I am frustrated that I can’t find a solution.

Also tried:

newList = [ a/b for a, b in (myList,myInt)]

Error:

ValueError: too many values to unpack

Expected Result:

newList = [1,2,3,4,5,6,7,8,9]


EDIT:

The following code gives me my expected result:

newList = []
for x in myList:
    newList.append(x/myInt)

But is there an easier/faster way to do this?

回答 0

惯用的方法是使用列表理解：

myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = [x / myInt for x in myList]

或者，如果您需要保留对原始列表的引用：

myList[:] = [x / myInt for x in myList]
点击查看英文原文

The idiomatic way would be to use list comprehension:

myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = [x / myInt for x in myList]

or, if you need to maintain the reference to the original list:

myList[:] = [x / myInt for x in myList]

回答 1

实际上，您首先可以使用numpy直接尝试：

import numpy
myArray = numpy.array([10,20,30,40,50,60,70,80,90])
myInt = 10
newArray = myArray/myInt

如果您使用长列表进行此类操作，尤其是在任何类型的科学计算项目中，我都会建议您使用numpy。

点击查看英文原文

The way you tried first is actually directly possible with numpy:

import numpy
myArray = numpy.array([10,20,30,40,50,60,70,80,90])
myInt = 10
newArray = myArray/myInt

If you do such operations with long lists and especially in any sort of scientific computing project, I would really advise using numpy.

回答 2

>>> myList = [10,20,30,40,50,60,70,80,90]
>>> myInt = 10
>>> newList = map(lambda x: x/myInt, myList)
>>> newList
[1, 2, 3, 4, 5, 6, 7, 8, 9]
点击查看英文原文 
>>> myList = [10,20,30,40,50,60,70,80,90]
>>> myInt = 10
>>> newList = map(lambda x: x/myInt, myList)
>>> newList
[1, 2, 3, 4, 5, 6, 7, 8, 9]

回答 3

myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = [i/myInt for i in myList]
点击查看英文原文 
myList = [10,20,30,40,50,60,70,80,90]
myInt = 10
newList = [i/myInt for i in myList]

回答 4

抽象版本可以是：

import numpy as np
myList = [10, 20, 30, 40, 50, 60, 70, 80, 90]
myInt = 10
newList  = np.divide(myList, myInt)
点击查看英文原文

The abstract version can be:

import numpy as np
myList = [10, 20, 30, 40, 50, 60, 70, 80, 90]
myInt = 10
newList  = np.divide(myList, myInt)

回答 5

myInt=10
myList=[tmpList/myInt for tmpList in range(10,100,10)]
点击查看英文原文 
myInt=10
myList=[tmpList/myInt for tmpList in range(10,100,10)]
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