如何将日期时间转换为日期（在Python中）？

How do I convert a datetime.datetime object (e.g., the return value of datetime.datetime.now()) to a datetime.date object in Python?

Use the date() method:

datetime.datetime.now().date()

From the documentation:

datetime.datetime.date()

Return date object with same year, month and day.

You use the datetime.datetime.date() method:

datetime.datetime.now().date()

Obviously, the expression above can (and should IMHO :) be written as:

datetime.date.today()

You can convert a datetime object to a date with the date() method of the date time object, as follows:

<datetime_object>.date()

import time
import datetime

# use mktime to step by one day
# end - the last day, numdays - count of days to step back
def gen_dates_list(end, numdays):
  start = end - datetime.timedelta(days=numdays+1)
  end   = int(time.mktime(end.timetuple()))
  start = int(time.mktime(start.timetuple()))
  # 86400 s = 1 day
  return xrange(start, end, 86400)

# if you need reverse the list of dates
for dt in reversed(gen_dates_list(datetime.datetime.today(), 100)):
    print datetime.datetime.fromtimestamp(dt).date()

you could enter this code form for (today date & Names of the Day & hour) : datetime.datetime.now().strftime('%y-%m-%d %a %H:%M:%S')

’19-09-09 Mon 17:37:56′

and enter this code for (today date simply): datetime.date.today().strftime('%y-%m-%d') ’19-09-10′

for object : datetime.datetime.now().date() datetime.datetime.today().date() datetime.datetime.utcnow().date() datetime.datetime.today().time() datetime.datetime.utcnow().date() datetime.datetime.utcnow().time()