问题:如何将秒转换为小时,分钟和秒?
我有一个以秒为单位返回信息的函数,但是我需要以小时:分钟:秒存储该信息。
有没有简单的方法可以在Python中将秒转换为这种格式?
I have a function that returns information in seconds, but I need to store that information in hours:minutes:seconds.
Is there an easy way to convert the seconds to this format in Python?
回答 0
您可以使用datetime.timedelta
功能:
>>> import datetime
>>> str(datetime.timedelta(seconds=666))
'0:11:06'
You can use datetime.timedelta
function:
>>> import datetime
>>> str(datetime.timedelta(seconds=666))
'0:11:06'
回答 1
通过使用divmod()
仅执行一个除法运算就可以得到商和余数的函数,您只需执行两个数学运算就可以很快得出结果:
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
然后使用字符串格式将结果转换为所需的输出:
print('{:d}:{:02d}:{:02d}'.format(h, m, s)) # Python 3
print(f'{h:d}:{m:02d}:{s:02d}') # Python 3.6+
By using the divmod()
function, which does only a single division to produce both the quotient and the remainder, you can have the result very quickly with only two mathematical operations:
m, s = divmod(seconds, 60)
h, m = divmod(m, 60)
And then use string formatting to convert the result into your desired output:
print('{:d}:{:02d}:{:02d}'.format(h, m, s)) # Python 3
print(f'{h:d}:{m:02d}:{s:02d}') # Python 3.6+
回答 2
我很难说出这种简单的方法(至少我不记得语法),但是可以使用time.strftime,它提供了对格式的更多控制:
from time import strftime
from time import gmtime
strftime("%H:%M:%S", gmtime(666))
'00:11:06'
strftime("%H:%M:%S", gmtime(60*60*24))
'00:00:00'
gmtime用于将秒转换为所需的特殊元组格式strftime()
。
注意:在23:59:59之后截断
I can hardly name that an easy way (at least I can’t remember the syntax), but it is possible to use time.strftime, which gives more control over formatting:
from time import strftime
from time import gmtime
strftime("%H:%M:%S", gmtime(666))
'00:11:06'
strftime("%H:%M:%S", gmtime(60*60*24))
'00:00:00'
gmtime is used to convert seconds to special tuple format that strftime()
requires.
Note: Truncates after 23:59:59
回答 3
使用datetime
:
使用':0>8'
格式:
from datetime import timedelta
"{:0>8}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{:0>8}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{:0>8}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
没有':0>8'
格式:
"{}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
使用time
:
from time import gmtime
from time import strftime
# NOTE: The following resets if it goes over 23:59:59!
strftime("%H:%M:%S", gmtime(125))
# Result: '00:02:05'
strftime("%H:%M:%S", gmtime(60*60*24-1))
# Result: '23:59:59'
strftime("%H:%M:%S", gmtime(60*60*24))
# Result: '00:00:00'
strftime("%H:%M:%S", gmtime(666777))
# Result: '17:12:57'
# Wrong
Using datetime
:
With the ':0>8'
format:
from datetime import timedelta
"{:0>8}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{:0>8}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{:0>8}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Without the ':0>8'
format:
"{}".format(str(timedelta(seconds=66)))
# Result: '00:01:06'
"{}".format(str(timedelta(seconds=666777)))
# Result: '7 days, 17:12:57'
"{}".format(str(timedelta(seconds=60*60*49+109)))
# Result: '2 days, 1:01:49'
Using time
:
from time import gmtime
from time import strftime
# NOTE: The following resets if it goes over 23:59:59!
strftime("%H:%M:%S", gmtime(125))
# Result: '00:02:05'
strftime("%H:%M:%S", gmtime(60*60*24-1))
# Result: '23:59:59'
strftime("%H:%M:%S", gmtime(60*60*24))
# Result: '00:00:00'
strftime("%H:%M:%S", gmtime(666777))
# Result: '17:12:57'
# Wrong
回答 4
回答 5
如果您需要获取datetime.time
价值,可以使用以下技巧:
my_time = (datetime(1970,1,1) + timedelta(seconds=my_seconds)).time()
您不能添加timedelta
到time
,但可以将其添加到datetime
。
UPD:同一技术的另一种变化:
my_time = (datetime.fromordinal(1) + timedelta(seconds=my_seconds)).time()
而不是1
可以使用大于0的任何数字。在这里,我们使用这样的事实,即datetime.fromordinal
始终返回组件为零的datetime
对象time
。
If you need to get datetime.time
value, you can use this trick:
my_time = (datetime(1970,1,1) + timedelta(seconds=my_seconds)).time()
You cannot add timedelta
to time
, but can add it to datetime
.
UPD: Yet another variation of the same technique:
my_time = (datetime.fromordinal(1) + timedelta(seconds=my_seconds)).time()
Instead of 1
you can use any number greater than 0. Here we use the fact that datetime.fromordinal
will always return datetime
object with time
component being zero.
回答 6
这就是我的方法。
def sec2time(sec, n_msec=3):
''' Convert seconds to 'D days, HH:MM:SS.FFF' '''
if hasattr(sec,'__len__'):
return [sec2time(s) for s in sec]
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
d, h = divmod(h, 24)
if n_msec > 0:
pattern = '%%02d:%%02d:%%0%d.%df' % (n_msec+3, n_msec)
else:
pattern = r'%02d:%02d:%02d'
if d == 0:
return pattern % (h, m, s)
return ('%d days, ' + pattern) % (d, h, m, s)
一些例子:
$ sec2time(10, 3)
Out: '00:00:10.000'
$ sec2time(1234567.8910, 0)
Out: '14 days, 06:56:07'
$ sec2time(1234567.8910, 4)
Out: '14 days, 06:56:07.8910'
$ sec2time([12, 345678.9], 3)
Out: ['00:00:12.000', '4 days, 00:01:18.900']
This is how I got it.
def sec2time(sec, n_msec=3):
''' Convert seconds to 'D days, HH:MM:SS.FFF' '''
if hasattr(sec,'__len__'):
return [sec2time(s) for s in sec]
m, s = divmod(sec, 60)
h, m = divmod(m, 60)
d, h = divmod(h, 24)
if n_msec > 0:
pattern = '%%02d:%%02d:%%0%d.%df' % (n_msec+3, n_msec)
else:
pattern = r'%02d:%02d:%02d'
if d == 0:
return pattern % (h, m, s)
return ('%d days, ' + pattern) % (d, h, m, s)
Some examples:
$ sec2time(10, 3)
Out: '00:00:10.000'
$ sec2time(1234567.8910, 0)
Out: '14 days, 06:56:07'
$ sec2time(1234567.8910, 4)
Out: '14 days, 06:56:07.8910'
$ sec2time([12, 345678.9], 3)
Out: ['00:00:12.000', '4 days, 00:01:18.900']
回答 7
以下设置对我有用。
def sec_to_hours(seconds):
a=str(seconds//3600)
b=str((seconds%3600)//60)
c=str((seconds%3600)%60)
d=["{} hours {} mins {} seconds".format(a, b, c)]
return d
print(sec_to_hours(10000))
# ['2 hours 46 mins 40 seconds']
print(sec_to_hours(60*60*24+105))
# ['24 hours 1 mins 45 seconds']
The following set worked for me.
def sec_to_hours(seconds):
a=str(seconds//3600)
b=str((seconds%3600)//60)
c=str((seconds%3600)%60)
d=["{} hours {} mins {} seconds".format(a, b, c)]
return d
print(sec_to_hours(10000))
# ['2 hours 46 mins 40 seconds']
print(sec_to_hours(60*60*24+105))
# ['24 hours 1 mins 45 seconds']
回答 8
dateutil.relativedelta
如果您还需要访问浮点数的小时,分钟和秒,则非常方便。datetime.timedelta
没有提供类似的界面。
from dateutil.relativedelta import relativedelta
rt = relativedelta(seconds=5440)
print(rt.seconds)
print('{:02d}:{:02d}:{:02d}'.format(
int(rt.hours), int(rt.minutes), int(rt.seconds)))
版画
40.0
01:30:40
dateutil.relativedelta
is convenient if you need to access hours, minutes and seconds as floats as well. datetime.timedelta
does not provide a similar interface.
from dateutil.relativedelta import relativedelta
rt = relativedelta(seconds=5440)
print(rt.seconds)
print('{:02d}:{:02d}:{:02d}'.format(
int(rt.hours), int(rt.minutes), int(rt.seconds)))
Prints
40.0
01:30:40
回答 9
小时(h)由楼层的秒数(//)除以3600(60分钟/小时* 60秒/分钟)
分钟(m),以剩余秒数(小时计算的剩余百分比,%)除以60(60秒/分钟)计算得出
类似地,以小时和分钟的余数计算秒数。
其余只是字符串格式!
def hms(seconds):
h = seconds // 3600
m = seconds % 3600 // 60
s = seconds % 3600 % 60
return '{:02d}:{:02d}:{:02d}'.format(h, m, s)
print(hms(7500)) # Should print 02h05m00s
hours (h) calculated by floor division (by //) of seconds by 3600 (60 min/hr * 60 sec/min)
minutes (m) calculated by floor division of remaining seconds (remainder from hour calculation, by %) by 60 (60 sec/min)
similarly, seconds (s) by remainder of hour and minutes calculation.
Rest is just string formatting!
def hms(seconds):
h = seconds // 3600
m = seconds % 3600 // 60
s = seconds % 3600 % 60
return '{:02d}:{:02d}:{:02d}'.format(h, m, s)
print(hms(7500)) # Should print 02h05m00s
回答 10
您可以将秒除以60得到分钟
import time
seconds = time.time()
minutes = seconds / 60
print(minutes)
再次将其除以60,就可以得到小时
You can divide seconds by 60 to get the minutes
import time
seconds = time.time()
minutes = seconds / 60
print(minutes)
When you divide it by 60 again, you will get the hours
回答 11
division = 3623 // 3600 #to hours
division2 = 600 // 60 #to minutes
print (division) #write hours
print (division2) #write minutes
PS我的代码不专业
division = 3623 // 3600 #to hours
division2 = 600 // 60 #to minutes
print (division) #write hours
print (division2) #write minutes
PS My code is unprofessional
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