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如何将逗号分隔的字符串转换为Python中的列表？

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问题：如何将逗号分隔的字符串转换为Python中的列表？
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5
回答 6

问题：如何将逗号分隔的字符串转换为Python中的列表？

给定一个字符串，该字符串是由逗号分隔的多个值的序列：

mStr = 'A,B,C,D,E'

如何将字符串转换为列表？

mList = ['A', 'B', 'C', 'D', 'E']
点击查看英文原文

Given a string that is a sequence of several values separated by a commma:

mStr = 'A,B,C,D,E'

How do I convert the string to a list?

mList = ['A', 'B', 'C', 'D', 'E']

回答 0

您可以使用str.split方法。

>>> my_string = 'A,B,C,D,E'
>>> my_list = my_string.split(",")
>>> print my_list
['A', 'B', 'C', 'D', 'E']

如果要将其转换为元组，只需

>>> print tuple(my_list)
('A', 'B', 'C', 'D', 'E')

如果您希望追加到列表，请尝试以下操作：

>>> my_list.append('F')
>>> print my_list
['A', 'B', 'C', 'D', 'E', 'F']
点击查看英文原文

You can use the str.split method.

>>> my_string = 'A,B,C,D,E'
>>> my_list = my_string.split(",")
>>> print my_list
['A', 'B', 'C', 'D', 'E']

If you want to convert it to a tuple, just

>>> print tuple(my_list)
('A', 'B', 'C', 'D', 'E')

If you are looking to append to a list, try this:

>>> my_list.append('F')
>>> print my_list
['A', 'B', 'C', 'D', 'E', 'F']

回答 1

对于字符串中包含的整数，如果要避免将它们int分别转换为整数，可以执行以下操作：

mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]

这称为列表理解，它基于集合构建器符号。

例如： 

>>> mStr = "1,A,B,3,4"
>>> mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
>>> mList
>>> [1,'A','B',3,4]
点击查看英文原文

In the case of integers that are included at the string, if you want to avoid casting them to int individually you can do:

mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]

It is called list comprehension, and it is based on set builder notation.

ex: 

>>> mStr = "1,A,B,3,4"
>>> mList = [int(e) if e.isdigit() else e for e in mStr.split(',')]
>>> mList
>>> [1,'A','B',3,4]

回答 2

>>> some_string='A,B,C,D,E'
>>> new_tuple= tuple(some_string.split(','))
>>> new_tuple
('A', 'B', 'C', 'D', 'E')
点击查看英文原文 
>>> some_string='A,B,C,D,E'
>>> new_tuple= tuple(some_string.split(','))
>>> new_tuple
('A', 'B', 'C', 'D', 'E')

回答 3

您可以使用此功能将以逗号分隔的单个字符串转换为list-

def stringtolist(x):
    mylist=[]
    for i in range(0,len(x),2):
        mylist.append(x[i])
    return mylist
点击查看英文原文

You can use this function to convert comma-delimited single character strings to list-

def stringtolist(x):
    mylist=[]
    for i in range(0,len(x),2):
        mylist.append(x[i])
    return mylist

回答 4

#splits string according to delimeters 
'''
Let's make a function that can split a string
into list according the given delimeters. 
example data: cat;dog:greff,snake/
example delimeters: ,;- /|:
'''
def string_to_splitted_array(data,delimeters):
    #result list
    res = []
    # we will add chars into sub_str until
    # reach a delimeter
    sub_str = ''
    for c in data: #iterate over data char by char
        # if we reached a delimeter, we store the result 
        if c in delimeters: 
            # avoid empty strings
            if len(sub_str)>0:
                # looks like a valid string.
                res.append(sub_str)
                # reset sub_str to start over
                sub_str = ''
        else:
            # c is not a deilmeter. then it is 
            # part of the string.
            sub_str += c
    # there may not be delimeter at end of data. 
    # if sub_str is not empty, we should att it to list. 
    if len(sub_str)>0:
        res.append(sub_str)
    # result is in res 
    return res

# test the function. 
delimeters = ',;- /|:'
# read the csv data from console. 
csv_string = input('csv string:')
#lets check if working. 
splitted_array = string_to_splitted_array(csv_string,delimeters)
print(splitted_array)
点击查看英文原文 
#splits string according to delimeters 
'''
Let's make a function that can split a string
into list according the given delimeters. 
example data: cat;dog:greff,snake/
example delimeters: ,;- /|:
'''
def string_to_splitted_array(data,delimeters):
    #result list
    res = []
    # we will add chars into sub_str until
    # reach a delimeter
    sub_str = ''
    for c in data: #iterate over data char by char
        # if we reached a delimeter, we store the result 
        if c in delimeters: 
            # avoid empty strings
            if len(sub_str)>0:
                # looks like a valid string.
                res.append(sub_str)
                # reset sub_str to start over
                sub_str = ''
        else:
            # c is not a deilmeter. then it is 
            # part of the string.
            sub_str += c
    # there may not be delimeter at end of data. 
    # if sub_str is not empty, we should att it to list. 
    if len(sub_str)>0:
        res.append(sub_str)
    # result is in res 
    return res

# test the function. 
delimeters = ',;- /|:'
# read the csv data from console. 
csv_string = input('csv string:')
#lets check if working. 
splitted_array = string_to_splitted_array(csv_string,delimeters)
print(splitted_array)

回答 5

考虑以下内容以处理空字符串的情况：

>>> my_string = 'A,B,C,D,E'
>>> my_string.split(",") if my_string else []
['A', 'B', 'C', 'D', 'E']
>>> my_string = ""
>>> my_string.split(",") if my_string else []
[]
点击查看英文原文

Consider the following in order to handle the case of an empty string:

>>> my_string = 'A,B,C,D,E'
>>> my_string.split(",") if my_string else []
['A', 'B', 'C', 'D', 'E']
>>> my_string = ""
>>> my_string.split(",") if my_string else []
[]

回答 6

您可以拆分该字符串,并直接获取列表：

mStr = 'A,B,C,D,E'
list1 = mStr.split(',')
print(list1)

输出：

['A', 'B', 'C', 'D', 'E']

您还可以将其转换为n元组：

print(tuple(list1))

输出：

('A', 'B', 'C', 'D', 'E')

点击查看英文原文

You can split that string on , and directly get a list:

mStr = 'A,B,C,D,E'
list1 = mStr.split(',')
print(list1)

Output:

['A', 'B', 'C', 'D', 'E']

You can also convert it to an n-tuple:

print(tuple(list1))

Output:

('A', 'B', 'C', 'D', 'E')