问题:如何将Django QueryDict更改为Python Dict?
假设我有以下QueryDict:
<QueryDict: {u'num': [0], u'var1': [u'value1', u'value2'], u'var2': [u'8']}>
我想要一本这样的字典,例如:
{'num': [0], 'var1':['value1', 'value2'], 'var2':['8']}
(我不在乎Unicode符号是否u
继续存在。)
如果我queryDict.dict()
按照django网站的建议进行操作,则会丢失属于的额外值var1
,例如:
{'num': [0], 'var1':['value2'], 'var2':['8']}
我正在考虑这样做:
myDict = {}
for key in queryDict.iterkeys():
myDict[key] = queryDict.getlist(key)
有没有更好的办法?
Let’s pretend I have the following QueryDict:
<QueryDict: {u'num': [0], u'var1': [u'value1', u'value2'], u'var2': [u'8']}>
I’d like to have a dictionary out of this, eg:
{'num': [0], 'var1':['value1', 'value2'], 'var2':['8']}
(I don’t care if the unicode symbol u
stays or goes.)
If I do queryDict.dict()
, as suggested by the django site, I lose the extra values belonging to var1
, eg:
{'num': [0], 'var1':['value2'], 'var2':['8']}
I was thinking of doing this:
myDict = {}
for key in queryDict.iterkeys():
myDict[key] = queryDict.getlist(key)
Is there a better way?
回答 0
这应该工作: myDict = dict(queryDict.iterlists())
This should work: myDict = dict(queryDict.iterlists())
回答 1
回答 2
这就是我最终使用的:
def qdict_to_dict(qdict):
"""Convert a Django QueryDict to a Python dict.
Single-value fields are put in directly, and for multi-value fields, a list
of all values is stored at the field's key.
"""
return {k: v[0] if len(v) == 1 else v for k, v in qdict.lists()}
根据我的用法,这似乎为您提供了一个列表,您可以将其发送回例如表单构造函数。
编辑:也许这不是最好的方法。看来,如果您QueryDict
出于某种疯狂的原因例如要写入文件,这是可行QueryDict.urlencode()
的方法。要重建QueryDict
您,只需要做QueryDict(urlencoded_data)
。
This is what I’ve ended up using:
def qdict_to_dict(qdict):
"""Convert a Django QueryDict to a Python dict.
Single-value fields are put in directly, and for multi-value fields, a list
of all values is stored at the field's key.
"""
return {k: v[0] if len(v) == 1 else v for k, v in qdict.lists()}
From my usage this seems to get you a list you can send back to e.g. a form constructor.
EDIT: maybe this isn’t the best method. It seems if you want to e.g. write QueryDict
to a file for whatever crazy reason, QueryDict.urlencode()
is the way to go. To reconstruct the QueryDict
you simply do QueryDict(urlencoded_data)
.
回答 3
from django.utils import six
post_dict = dict(six.iterlists(request.POST))
from django.utils import six
post_dict = dict(six.iterlists(request.POST))
回答 4
如果您不希望这些值作为数组,则可以执行以下操作:
# request = <QueryDict: {u'key': [u'123ABC']}>
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"123ABC" }
# Only work for single item lists
# request = <QueryDict: {u'key': [u'123ABC',U 'CDEF']}>
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"CDEF" }
zip是一种功能强大的工具,请在此处详细了解它http://docs.python.org/2/library/functions.html#zip
If you do not want the values as Arrays you can do the following:
# request = <QueryDict: {u'key': [u'123ABC']}>
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"123ABC" }
# Only work for single item lists
# request = <QueryDict: {u'key': [u'123ABC',U 'CDEF']}>
dict(zip(request.GET.keys(), request.GET.values()))
{u'key': u"CDEF" }
zip is a powerful tool read more about it here http://docs.python.org/2/library/functions.html#zip
回答 5
我遇到了类似的问题,想将表单中的任意值保存为序列化值。
我的回答避免了显式地迭代字典内容: dict(querydict.iterlists())
为了检索起原始作用的类似于字典的值,可使用反函数QueryDict.setlist()
来填充新QueryDict
值。在这种情况下,我认为显式迭代是不可避免的。
我的辅助函数如下所示:
from django.http import QueryDict
def querydict_dict(querydict):
"""
Converts a Django QueryDict value to a regular dictionary, preserving multiple items.
"""
return dict(querydict.iterlists())
def dict_querydict(dict_):
"""
Converts a value created by querydict_dict back into a Django QueryDict value.
"""
q = QueryDict("", mutable=True)
for k, v in dict_.iteritems():
q.setlist(k, v)
q._mutable = False
return q
I ran into a similar problem, wanting to save arbitrary values from a form as serialized values.
My answer avoids explicitly iterating the dictionary contents: dict(querydict.iterlists())
In order to retrieve a dictionary-like value that functions as the original, an inverse function uses QueryDict.setlist()
to populate a new QueryDict
value. In this case, I don’t think the explicit iteration is avoidable.
My helper functions look like this:
from django.http import QueryDict
def querydict_dict(querydict):
"""
Converts a Django QueryDict value to a regular dictionary, preserving multiple items.
"""
return dict(querydict.iterlists())
def dict_querydict(dict_):
"""
Converts a value created by querydict_dict back into a Django QueryDict value.
"""
q = QueryDict("", mutable=True)
for k, v in dict_.iteritems():
q.setlist(k, v)
q._mutable = False
return q
回答 6
更新:
myDict = dict(queryDict._iterlists())
请注意:_
的iterlists方法中的下划线queryDict
。Django版本:1.5.1
Update:
myDict = dict(queryDict._iterlists())
Please Note : underscore _
in iterlists method of queryDict
. Django version :1.5.1
回答 7
dict(request.POST)
返回带有数组包装值的怪异python字典。
{'start': ['2017-01-14T21:00'], 'stop': ['2017-01-14T22:00'], 'email': ['sandeep@sakethtech.com']}
作为{x:request.POST.get(x) for x in request.POST.keys()}
返回预期输出的位置。
{'start': '2017-01-14T21:00', 'stop': '2017-01-14T22:00', 'email': 'sandeep@sakethtech.com'}
dict(request.POST)
returns a weird python dictionary with array wrapped values.
{'start': ['2017-01-14T21:00'], 'stop': ['2017-01-14T22:00'], 'email': ['sandeep@sakethtech.com']}
where as {x:request.POST.get(x) for x in request.POST.keys()}
returns expected output.
{'start': '2017-01-14T21:00', 'stop': '2017-01-14T22:00', 'email': 'sandeep@sakethtech.com'}
回答 8
只需添加
queryDict=dict(request.GET)
要么 queryDict=dict(QueryDict)
在您的视图中,数据将以python Dict的形式保存在querDict中。
just simply add
queryDict=dict(request.GET)
or queryDict=dict(QueryDict)
In your view and data will be saved in querDict as python Dict.
回答 9
这就是我解决该问题的方法:
dict_ = {k: q.getlist(k) if len(q.getlist(k))>1 else v for k, v in q.items()}
This is how I solved that problem:
dict_ = {k: q.getlist(k) if len(q.getlist(k))>1 else v for k, v in q.items()}
回答 10
回答 11
随着Django 2.2
很少有干净的解决方案:
QueryDict.dict()
这是最简单的方法,但是会破坏QueryDict
列表作为值,例如:
from django.http.request import QueryDict, MultiValueDict
query_dict = QueryDict('', mutable=True)
query_dict.update(MultiValueDict({'a': ['one', 'two']}))
query_dict.update({'b': 'three'})
for key, value in query_dict.dict().items(): # ---> query_dict.dict()
print(key, value)
将输出
a two # <--- missed 'one'
b three
dict(QueryDict)
更好,因为它将使列表正确字典:
from django.http.request import QueryDict, MultiValueDict
query_dict = QueryDict('', mutable=True)
query_dict.update(MultiValueDict({'a': ['one', 'two']}))
query_dict.update({'b': 'three'})
for key, value in dict(query_dict).items(): # ---> dict(query_dict)
print(key, value)
将输出
a ['one', 'two']
b ['three']
哪个是正确的。
With Django 2.2
there are few clean solutions:
QueryDict.dict()
is simplest but it will broke QueryDict
with lists as values, e.g:
from django.http.request import QueryDict, MultiValueDict
query_dict = QueryDict('', mutable=True)
query_dict.update(MultiValueDict({'a': ['one', 'two']}))
query_dict.update({'b': 'three'})
for key, value in query_dict.dict().items(): # ---> query_dict.dict()
print(key, value)
will output
a two # <--- missed 'one'
b three
dict(QueryDict)
is better because it will make correct dictionary of lists:
from django.http.request import QueryDict, MultiValueDict
query_dict = QueryDict('', mutable=True)
query_dict.update(MultiValueDict({'a': ['one', 'two']}))
query_dict.update({'b': 'three'})
for key, value in dict(query_dict).items(): # ---> dict(query_dict)
print(key, value)
will output
a ['one', 'two']
b ['three']
which is correct.
回答 12
我尝试了两者dict(request.POST)
,request.POST.dict()
并意识到,如果您的list
值中'var1':['value1', 'value2']
嵌套了一些值request.POST
,则late(request.POST.dict()
)仅使我可以访问嵌套列表中的最后一项,而前一个(dict(request.POST)
)则允许我访问嵌套列表中的所有项目。
我希望这可以帮助别人。
I tried out both dict(request.POST)
and request.POST.dict()
and realised that if you have list
values for example 'var1':['value1', 'value2']
nested in your request.POST
, the later(request.POST.dict()
) only gave me access to the last item in a nested list while the former(dict(request.POST)
) allowed me to access all items in a nested list.
I hope this helps someone.
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