如何检查字典中是否存在值（Python）

I have the following dictionary in python:

d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'}

I need a way to find if a value such as “one” or “two” exists in this dictionary.

For example, if I wanted to know if the index “1” existed I would simply have to type:

"1" in d

And then python would tell me if that is true or false, however I need to do that same exact thing except to find if a value exists.

>>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'}
>>> 'one' in d.values()
True

Out of curiosity, some comparative timing:

>>> T(lambda : 'one' in d.itervalues()).repeat()
[0.28107285499572754, 0.29107213020324707, 0.27941107749938965]
>>> T(lambda : 'one' in d.values()).repeat()
[0.38303399085998535, 0.37257885932922363, 0.37096405029296875]
>>> T(lambda : 'one' in d.viewvalues()).repeat()
[0.32004380226135254, 0.31716084480285645, 0.3171098232269287]

EDIT: And in case you wonder why… the reason is that each of the above returns a different type of object, which may or may not be well suited for lookup operations:

>>> type(d.viewvalues())
<type 'dict_values'>
>>> type(d.values())
<type 'list'>
>>> type(d.itervalues())
<type 'dictionary-valueiterator'>

EDIT2: As per request in comments…

>>> T(lambda : 'four' in d.itervalues()).repeat()
[0.41178202629089355, 0.3959040641784668, 0.3970959186553955]
>>> T(lambda : 'four' in d.values()).repeat()
[0.4631338119506836, 0.43541407585144043, 0.4359898567199707]
>>> T(lambda : 'four' in d.viewvalues()).repeat()
[0.43414998054504395, 0.4213531017303467, 0.41684913635253906]

You can use

"one" in d.itervalues()

to test if "one" is among the values of your dictionary.

Python dictionary has get(key) funcion

>>> d.get(key)

For Example,

>>> d = {'1': 'one', '3': 'three', '2': 'two', '5': 'five', '4': 'four'}
>>> d.get('3')
'three'
>>> d.get('10')
none

If your key does’nt exist, will return none value.

foo = d[key] # raise error if key doesn't exist
foo = d.get(key) # return none if key doesn't exist

Content relevant to versions less than 3.0 and greater than 5.0. .

Use dictionary views:

if x in d.viewvalues():
    dosomething()..

Different types to check the values exists

d = {"key1":"value1", "key2":"value2"}
"value10" in d.values() 
>> False

What if list of values

test = {'key1': ['value4', 'value5', 'value6'], 'key2': ['value9'], 'key3': ['value6']}
"value4" in [x for v in test.values() for x in v]
>>True

What if list of values with string values

test = {'key1': ['value4', 'value5', 'value6'], 'key2': ['value9'], 'key3': ['value6'], 'key5':'value10'}
values = test.values()
"value10" in [x for v in test.values() for x in v] or 'value10' in values
>>True

In Python 3 you can use the values() function of the dictionary. It returns a view object of the values. This, in turn, can be passed to the iter function which returns an iterator object. The iterator can be checked using in, like this,

'one' in iter(d.values())

Or you can use the view object directly since it is similar to a list

'one' in d.values()