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问题：如何获得Flask请求网址的不同部分？
回答 0
回答 1
回答 2
回答 3

问题：如何获得Flask请求网址的不同部分？

我想检测请求是否来自localhost:5000或foo.herokuapp.com主机以及请求的路径。如何获得有关Flask请求的信息？

点击查看英文原文

I want to detect if the request came from the localhost:5000 or foo.herokuapp.com host and what path was requested. How do I get this information about a Flask request?

回答 0

您可以通过以下几个Request字段检查网址：

用户请求以下URL：

    http://www.example.com/myapplication/page.html?x=y

在这种情况下，上述属性的值如下：

    path             /page.html
    script_root      /myapplication
    base_url         http://www.example.com/myapplication/page.html
    url              http://www.example.com/myapplication/page.html?x=y
    url_root         http://www.example.com/myapplication/

您可以通过适当的拆分轻松提取主体部分。

点击查看英文原文

You can examine the url through several Request fields:

Imagine your application is listening on the following application root:

http://www.example.com/myapplication

And a user requests the following URI:

http://www.example.com/myapplication/foo/page.html?x=y

In this case the values of the above mentioned attributes would be the following:

    path             /foo/page.html
    full_path        /foo/page.html?x=y
    script_root      /myapplication
    base_url         http://www.example.com/myapplication/foo/page.html
    url              http://www.example.com/myapplication/foo/page.html?x=y
    url_root         http://www.example.com/myapplication/

You can easily extract the host part with the appropriate splits.

回答 1

另一个例子：

请求：

curl -XGET http://127.0.0.1:5000/alert/dingding/test?x=y

然后：

request.method:              GET
request.url:                 http://127.0.0.1:5000/alert/dingding/test?x=y
request.base_url:            http://127.0.0.1:5000/alert/dingding/test
request.url_charset:         utf-8
request.url_root:            http://127.0.0.1:5000/
str(request.url_rule):       /alert/dingding/test
request.host_url:            http://127.0.0.1:5000/
request.host:                127.0.0.1:5000
request.script_root:
request.path:                /alert/dingding/test
request.full_path:           /alert/dingding/test?x=y

request.args:                ImmutableMultiDict([('x', 'y')])
request.args.get('x'):       y
点击查看英文原文

another example:

request:

curl -XGET http://127.0.0.1:5000/alert/dingding/test?x=y

then:

request.method:              GET
request.url:                 http://127.0.0.1:5000/alert/dingding/test?x=y
request.base_url:            http://127.0.0.1:5000/alert/dingding/test
request.url_charset:         utf-8
request.url_root:            http://127.0.0.1:5000/
str(request.url_rule):       /alert/dingding/test
request.host_url:            http://127.0.0.1:5000/
request.host:                127.0.0.1:5000
request.script_root:
request.path:                /alert/dingding/test
request.full_path:           /alert/dingding/test?x=y

request.args:                ImmutableMultiDict([('x', 'y')])
request.args.get('x'):       y

回答 2

你应该试试：

request.url

它假设即使在localhost上也可以一直工作（只是这样做了）。

点击查看英文原文

you should try:

request.url

It suppose to work always, even on localhost (just did it).

回答 3

如果您使用的是Python，建议您浏览请求对象：

dir(request)

由于对象支持方法dict：

request.__dict__

可以打印或保存。我用它来在Flask中记录404代码：

@app.errorhandler(404)
def not_found(e):
    with open("./404.csv", "a") as f:
        f.write(f'{datetime.datetime.now()},{request.__dict__}\n')
    return send_file('static/images/Darknet-404-Page-Concept.png', mimetype='image/png')
点击查看英文原文

If you are using Python, I would suggest by exploring the request object:

dir(request)

Since the object support the method dict:

request.__dict__

It can be printed or saved. I use it to log 404 codes in Flask:

@app.errorhandler(404)
def not_found(e):
    with open("./404.csv", "a") as f:
        f.write(f'{datetime.datetime.now()},{request.__dict__}\n')
    return send_file('static/images/Darknet-404-Page-Concept.png', mimetype='image/png')
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