问题:如何记录带有调试信息的Python错误?
我正在使用以下命令将Python异常消息打印到日志文件中logging.error
:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.error(e) # ERROR:root:division by zero
除了异常字符串以外,是否可以打印有关异常及其生成代码的更多详细信息?行号或堆栈跟踪之类的东西会很棒。
I am printing Python exception messages to a log file with logging.error
:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.error(e) # ERROR:root:division by zero
Is it possible to print more detailed information about the exception and the code that generated it than just the exception string? Things like line numbers or stack traces would be great.
回答 0
logger.exception
将在错误消息旁边输出堆栈跟踪。
例如:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.exception("message")
输出:
ERROR:root:message
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
@Paulo Check指出:“请注意,在Python 3中,您必须logging.exception
在except
零件内部调用该方法。如果在任意位置调用此方法,则可能会遇到奇怪的异常。文档对此有所提示。”
logger.exception
will output a stack trace alongside the error message.
For example:
import logging
try:
1/0
except ZeroDivisionError as e:
logging.exception("message")
Output:
ERROR:root:message
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
@Paulo Cheque notes, “be aware that in Python 3 you must call the logging.exception
method just inside the except
part. If you call this method in an arbitrary place you may get a bizarre exception. The docs alert about that.”
回答 1
约一个好处logging.exception
是SiggyF的回答并没有显示的是,你可以在任意的消息传递和记录仍然会显示完整的回溯与所有异常的详细信息:
import logging
try:
1/0
except ZeroDivisionError:
logging.exception("Deliberate divide by zero traceback")
在默认情况下(在最新版本中),仅将错误打印到的日志记录行为sys.stderr
如下所示:
>>> import logging
>>> try:
... 1/0
... except ZeroDivisionError:
... logging.exception("Deliberate divide by zero traceback")
...
ERROR:root:Deliberate divide by zero traceback
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
One nice thing about logging.exception
that SiggyF’s answer doesn’t show is that you can pass in an arbitrary message, and logging will still show the full traceback with all the exception details:
import logging
try:
1/0
except ZeroDivisionError:
logging.exception("Deliberate divide by zero traceback")
With the default (in recent versions) logging behaviour of just printing errors to sys.stderr
, it looks like this:
>>> import logging
>>> try:
... 1/0
... except ZeroDivisionError:
... logging.exception("Deliberate divide by zero traceback")
...
ERROR:root:Deliberate divide by zero traceback
Traceback (most recent call last):
File "<stdin>", line 2, in <module>
ZeroDivisionError: integer division or modulo by zero
回答 2
使用exc_info
选项可能更好,允许您选择错误级别(如果使用exception
,它将始终处于错误error
级别):
try:
# do something here
except Exception as e:
logging.critical(e, exc_info=True) # log exception info at CRITICAL log level
Using exc_info
options may be better, to allow you to choose the error level (if you use exception
, it will always be at the error
level):
try:
# do something here
except Exception as e:
logging.critical(e, exc_info=True) # log exception info at CRITICAL log level
回答 3
报价单
如果您的应用程序以其他方式记录日志而不使用logging
模块怎么办?
现在,traceback
可以在这里使用。
import traceback
def log_traceback(ex, ex_traceback=None):
if ex_traceback is None:
ex_traceback = ex.__traceback__
tb_lines = [ line.rstrip('\n') for line in
traceback.format_exception(ex.__class__, ex, ex_traceback)]
exception_logger.log(tb_lines)
在Python 2中使用它:
try:
# your function call is here
except Exception as ex:
_, _, ex_traceback = sys.exc_info()
log_traceback(ex, ex_traceback)
在Python 3中使用它:
try:
x = get_number()
except Exception as ex:
log_traceback(ex)
Quoting
What if your application does logging some other way – not using the logging
module?
Now, traceback
could be used here.
import traceback
def log_traceback(ex, ex_traceback=None):
if ex_traceback is None:
ex_traceback = ex.__traceback__
tb_lines = [ line.rstrip('\n') for line in
traceback.format_exception(ex.__class__, ex, ex_traceback)]
exception_logger.log(tb_lines)
Use it in Python 2:
try:
# your function call is here
except Exception as ex:
_, _, ex_traceback = sys.exc_info()
log_traceback(ex, ex_traceback)
Use it in Python 3:
try:
x = get_number()
except Exception as ex:
log_traceback(ex)
回答 4
如果您使用纯日志-您的所有日志记录都应符合以下规则:one record = one line
。遵循此规则,您可以使用grep
和其他工具来处理日志文件。
但是回溯信息是多行的。因此,我的答案是zangw在此线程中提出的解决方案的扩展版本。问题是回溯线可能在\n
内部,因此我们需要做一些额外的工作来消除该行的结尾:
import logging
logger = logging.getLogger('your_logger_here')
def log_app_error(e: BaseException, level=logging.ERROR) -> None:
e_traceback = traceback.format_exception(e.__class__, e, e.__traceback__)
traceback_lines = []
for line in [line.rstrip('\n') for line in e_traceback]:
traceback_lines.extend(line.splitlines())
logger.log(level, traceback_lines.__str__())
之后(当您要分析日志时),您可以从日志文件中复制/粘贴所需的回溯行,然后执行以下操作:
ex_traceback = ['line 1', 'line 2', ...]
for line in ex_traceback:
print(line)
利润!
If you use plain logs – all your log records should correspond this rule: one record = one line
. Following this rule you can use grep
and other tools to process your log files.
But traceback information is multi-line. So my answer is an extended version of solution proposed by zangw above in this thread. The problem is that traceback lines could have \n
inside, so we need to do an extra work to get rid of this line endings:
import logging
logger = logging.getLogger('your_logger_here')
def log_app_error(e: BaseException, level=logging.ERROR) -> None:
e_traceback = traceback.format_exception(e.__class__, e, e.__traceback__)
traceback_lines = []
for line in [line.rstrip('\n') for line in e_traceback]:
traceback_lines.extend(line.splitlines())
logger.log(level, traceback_lines.__str__())
After that (when you’ll be analyzing your logs) you could copy / paste required traceback lines from your log file and do this:
ex_traceback = ['line 1', 'line 2', ...]
for line in ex_traceback:
print(line)
Profit!
回答 5
这个答案是建立在上述优秀答案之上的。
在大多数应用程序中,您不会直接调用logging.exception(e)。您很可能已经定义了特定于您的应用程序或模块的自定义记录器,如下所示:
# Set the name of the app or module
my_logger = logging.getLogger('NEM Sequencer')
# Set the log level
my_logger.setLevel(logging.INFO)
# Let's say we want to be fancy and log to a graylog2 log server
graylog_handler = graypy.GELFHandler('some_server_ip', 12201)
graylog_handler.setLevel(logging.INFO)
my_logger.addHandler(graylog_handler)
在这种情况下,只需使用记录器调用异常(e),如下所示:
try:
1/0
except ZeroDivisionError, e:
my_logger.exception(e)
This answer builds up from the above excellent ones.
In most applications, you won’t be calling logging.exception(e) directly. Most likely you have defined a custom logger specific for your application or module like this:
# Set the name of the app or module
my_logger = logging.getLogger('NEM Sequencer')
# Set the log level
my_logger.setLevel(logging.INFO)
# Let's say we want to be fancy and log to a graylog2 log server
graylog_handler = graypy.GELFHandler('some_server_ip', 12201)
graylog_handler.setLevel(logging.INFO)
my_logger.addHandler(graylog_handler)
In this case, just use the logger to call the exception(e) like this:
try:
1/0
except ZeroDivisionError, e:
my_logger.exception(e)
回答 6
您可以毫无exceptions地记录堆栈跟踪。
https://docs.python.org/3/library/logging.html#logging.Logger.debug
第二个可选的关键字参数是stack_info,默认为False。如果为true,则将堆栈信息添加到日志消息中,包括实际的日志调用。请注意,这与通过指定exc_info显示的堆栈信息不同:前者是从堆栈底部到当前线程中的日志记录调用的堆栈帧,而后者是有关已取消缠绕的堆栈帧的信息,在搜索异常处理程序时跟踪异常。
例:
>>> import logging
>>> logging.basicConfig(level=logging.DEBUG)
>>> logging.getLogger().info('This prints the stack', stack_info=True)
INFO:root:This prints the stack
Stack (most recent call last):
File "<stdin>", line 1, in <module>
>>>
You can log the stack trace without an exception.
https://docs.python.org/3/library/logging.html#logging.Logger.debug
The second optional keyword argument is stack_info, which defaults to False. If true, stack information is added to the logging message, including the actual logging call. Note that this is not the same stack information as that displayed through specifying exc_info: The former is stack frames from the bottom of the stack up to the logging call in the current thread, whereas the latter is information about stack frames which have been unwound, following an exception, while searching for exception handlers.
Example:
>>> import logging
>>> logging.basicConfig(level=logging.DEBUG)
>>> logging.getLogger().info('This prints the stack', stack_info=True)
INFO:root:This prints the stack
Stack (most recent call last):
File "<stdin>", line 1, in <module>
>>>
回答 7
一点点装饰器处理(受Maybe monad和举重的启发很松散)。您可以安全地删除Python 3.6类型注释,并使用较旧的消息格式样式。
fallable.py
from functools import wraps
from typing import Callable, TypeVar, Optional
import logging
A = TypeVar('A')
def fallible(*exceptions, logger=None) \
-> Callable[[Callable[..., A]], Callable[..., Optional[A]]]:
"""
:param exceptions: a list of exceptions to catch
:param logger: pass a custom logger; None means the default logger,
False disables logging altogether.
"""
def fwrap(f: Callable[..., A]) -> Callable[..., Optional[A]]:
@wraps(f)
def wrapped(*args, **kwargs):
try:
return f(*args, **kwargs)
except exceptions:
message = f'called {f} with *args={args} and **kwargs={kwargs}'
if logger:
logger.exception(message)
if logger is None:
logging.exception(message)
return None
return wrapped
return fwrap
演示:
In [1] from fallible import fallible
In [2]: @fallible(ArithmeticError)
...: def div(a, b):
...: return a / b
...:
...:
In [3]: div(1, 2)
Out[3]: 0.5
In [4]: res = div(1, 0)
ERROR:root:called <function div at 0x10d3c6ae8> with *args=(1, 0) and **kwargs={}
Traceback (most recent call last):
File "/Users/user/fallible.py", line 17, in wrapped
return f(*args, **kwargs)
File "<ipython-input-17-e056bd886b5c>", line 3, in div
return a / b
In [5]: repr(res)
'None'
您还可以修改此解决方案来回报比的东西更有意义一点None
从except
部分(甚至使溶液一般,通过指定该返回值fallible
的论点)。
A little bit of decorator treatment (very loosely inspired by the Maybe monad and lifting). You can safely remove Python 3.6 type annotations and use an older message formatting style.
fallible.py
from functools import wraps
from typing import Callable, TypeVar, Optional
import logging
A = TypeVar('A')
def fallible(*exceptions, logger=None) \
-> Callable[[Callable[..., A]], Callable[..., Optional[A]]]:
"""
:param exceptions: a list of exceptions to catch
:param logger: pass a custom logger; None means the default logger,
False disables logging altogether.
"""
def fwrap(f: Callable[..., A]) -> Callable[..., Optional[A]]:
@wraps(f)
def wrapped(*args, **kwargs):
try:
return f(*args, **kwargs)
except exceptions:
message = f'called {f} with *args={args} and **kwargs={kwargs}'
if logger:
logger.exception(message)
if logger is None:
logging.exception(message)
return None
return wrapped
return fwrap
Demo:
In [1] from fallible import fallible
In [2]: @fallible(ArithmeticError)
...: def div(a, b):
...: return a / b
...:
...:
In [3]: div(1, 2)
Out[3]: 0.5
In [4]: res = div(1, 0)
ERROR:root:called <function div at 0x10d3c6ae8> with *args=(1, 0) and **kwargs={}
Traceback (most recent call last):
File "/Users/user/fallible.py", line 17, in wrapped
return f(*args, **kwargs)
File "<ipython-input-17-e056bd886b5c>", line 3, in div
return a / b
In [5]: repr(res)
'None'
You can also modify this solution to return something a bit more meaningful than None
from the except
part (or even make the solution generic, by specifying this return value in fallible
‘s arguments).
回答 8
在您的日志记录模块(如果是自定义模块)中,只需启用stack_info即可。
api_logger.exceptionLog("*Input your Custom error message*",stack_info=True)
In your logging module(if custom module) just enable stack_info.
api_logger.exceptionLog("*Input your Custom error message*",stack_info=True)
回答 9
如果您可以处理额外的依赖关系,则可以使用twisted.log,您不必显式记录错误,而且它会将整个回溯和时间返回到文件或流。
If you can cope with the extra dependency then use twisted.log, you don’t have to explicitly log errors and also it returns the entire traceback and time to the file or stream.
回答 10
一种干净的方法是使用format_exc()
,然后解析输出以获取相关部分:
from traceback import format_exc
try:
1/0
except Exception:
print 'the relevant part is: '+format_exc().split('\n')[-2]
问候
A clean way to do it is using format_exc()
and then parse the output to get the relevant part:
from traceback import format_exc
try:
1/0
except Exception:
print 'the relevant part is: '+format_exc().split('\n')[-2]
Regards
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