问题:字符串格式:%与.format

Python 2.6引入的方法与现有%运算符的语法略有不同。哪个更好,什么情况下适合?

  1. 以下使用每种方法并具有相同的结果,那么有什么区别?

    #!/usr/bin/python
    sub1 = "python string!"
    sub2 = "an arg"
    
    a = "i am a %s" % sub1
    b = "i am a {0}".format(sub1)
    
    c = "with %(kwarg)s!" % {'kwarg':sub2}
    d = "with {kwarg}!".format(kwarg=sub2)
    
    print a    # "i am a python string!"
    print b    # "i am a python string!"
    print c    # "with an arg!"
    print d    # "with an arg!"
    
  2. 此外,何时在Python中进行字符串格式化?例如,如果我的日志记录级别设置为HIGH,那么执行以下%操作是否还会对我有所帮助?如果是这样,有办法避免这种情况吗?

    log.debug("some debug info: %s" % some_info)

Python 2.6 introduced the method with a slightly different syntax from the existing % operator. Which is better and for what situations?

  1. The following uses each method and has the same outcome, so what is the difference?

    #!/usr/bin/python
    sub1 = "python string!"
    sub2 = "an arg"
    
    a = "i am a %s" % sub1
    b = "i am a {0}".format(sub1)
    
    c = "with %(kwarg)s!" % {'kwarg':sub2}
    d = "with {kwarg}!".format(kwarg=sub2)
    
    print a    # "i am a python string!"
    print b    # "i am a python string!"
    print c    # "with an arg!"
    print d    # "with an arg!"
    
  2. Furthermore when does string formatting occur in Python? For example, if my logging level is set to HIGH will I still take a hit for performing the following % operation? And if so, is there a way to avoid this?

    log.debug("some debug info: %s" % some_info)
    

回答 0

要回答您的第一个问题… .format在许多方面似乎都更加复杂。令人烦恼的%是它如何可以采用变量或元组。您会认为以下各项将始终有效:

"hi there %s" % name

但是,如果name碰巧(1, 2, 3),它将抛出一个TypeError。为了确保它始终打印,您需要执行

"hi there %s" % (name,)   # supply the single argument as a single-item tuple

真丑。.format没有那些问题。同样在您给出的第二个示例中,该.format示例看起来更加简洁。

为什么不使用它?

  • 不知道(我在阅读本文之前)
  • 必须与Python 2.5兼容

为了回答您的第二个问题,字符串格式化与其他任何操作都同时发生-计算字符串格式化表达式时。而且,Python并不是一种惰性语言,它会在调用函数之前先对表达式求值,因此在您的log.debug示例中,表达式"some debug info: %s"%some_info将首先求值,例如"some debug info: roflcopters are active",然后将该字符串传递给log.debug()

To answer your first question… .format just seems more sophisticated in many ways. An annoying thing about % is also how it can either take a variable or a tuple. You’d think the following would always work:

"hi there %s" % name

yet, if name happens to be (1, 2, 3), it will throw a TypeError. To guarantee that it always prints, you’d need to do

"hi there %s" % (name,)   # supply the single argument as a single-item tuple

which is just ugly. .format doesn’t have those issues. Also in the second example you gave, the .format example is much cleaner looking.

Why would you not use it?

  • not knowing about it (me before reading this)
  • having to be compatible with Python 2.5

To answer your second question, string formatting happens at the same time as any other operation – when the string formatting expression is evaluated. And Python, not being a lazy language, evaluates expressions before calling functions, so in your log.debug example, the expression "some debug info: %s"%some_infowill first evaluate to, e.g. "some debug info: roflcopters are active", then that string will be passed to log.debug().


回答 1

afaik,模运算符(%)无法做到的事情:

tu = (12,45,22222,103,6)
print '{0} {2} {1} {2} {3} {2} {4} {2}'.format(*tu)

结果

12 22222 45 22222 103 22222 6 22222

很有用。

另一点:format()作为函数,可以用作其他函数的参数:

li = [12,45,78,784,2,69,1254,4785,984]
print map('the number is {}'.format,li)   

print

from datetime import datetime,timedelta

once_upon_a_time = datetime(2010, 7, 1, 12, 0, 0)
delta = timedelta(days=13, hours=8,  minutes=20)

gen =(once_upon_a_time +x*delta for x in xrange(20))

print '\n'.join(map('{:%Y-%m-%d %H:%M:%S}'.format, gen))

结果是:

['the number is 12', 'the number is 45', 'the number is 78', 'the number is 784', 'the number is 2', 'the number is 69', 'the number is 1254', 'the number is 4785', 'the number is 984']

2010-07-01 12:00:00
2010-07-14 20:20:00
2010-07-28 04:40:00
2010-08-10 13:00:00
2010-08-23 21:20:00
2010-09-06 05:40:00
2010-09-19 14:00:00
2010-10-02 22:20:00
2010-10-16 06:40:00
2010-10-29 15:00:00
2010-11-11 23:20:00
2010-11-25 07:40:00
2010-12-08 16:00:00
2010-12-22 00:20:00
2011-01-04 08:40:00
2011-01-17 17:00:00
2011-01-31 01:20:00
2011-02-13 09:40:00
2011-02-26 18:00:00
2011-03-12 02:20:00

Something that the modulo operator ( % ) can’t do, afaik:

tu = (12,45,22222,103,6)
print '{0} {2} {1} {2} {3} {2} {4} {2}'.format(*tu)

result

12 22222 45 22222 103 22222 6 22222

Very useful.

Another point: format(), being a function, can be used as an argument in other functions:

li = [12,45,78,784,2,69,1254,4785,984]
print map('the number is {}'.format,li)   

print

from datetime import datetime,timedelta

once_upon_a_time = datetime(2010, 7, 1, 12, 0, 0)
delta = timedelta(days=13, hours=8,  minutes=20)

gen =(once_upon_a_time +x*delta for x in xrange(20))

print '\n'.join(map('{:%Y-%m-%d %H:%M:%S}'.format, gen))

Results in:

['the number is 12', 'the number is 45', 'the number is 78', 'the number is 784', 'the number is 2', 'the number is 69', 'the number is 1254', 'the number is 4785', 'the number is 984']

2010-07-01 12:00:00
2010-07-14 20:20:00
2010-07-28 04:40:00
2010-08-10 13:00:00
2010-08-23 21:20:00
2010-09-06 05:40:00
2010-09-19 14:00:00
2010-10-02 22:20:00
2010-10-16 06:40:00
2010-10-29 15:00:00
2010-11-11 23:20:00
2010-11-25 07:40:00
2010-12-08 16:00:00
2010-12-22 00:20:00
2011-01-04 08:40:00
2011-01-17 17:00:00
2011-01-31 01:20:00
2011-02-13 09:40:00
2011-02-26 18:00:00
2011-03-12 02:20:00

回答 2

假设您正在使用Python的logging模块,则可以将字符串格式参数作为参数传递给.debug()方法,而不必自己进行格式设置:

log.debug("some debug info: %s", some_info)

除非记录器实际记录某些内容,否则可以避免进行格式化。

Assuming you’re using Python’s logging module, you can pass the string formatting arguments as arguments to the .debug() method rather than doing the formatting yourself:

log.debug("some debug info: %s", some_info)

which avoids doing the formatting unless the logger actually logs something.


回答 3

从Python 3.6(2016)开始,您可以使用f字符串替换变量:

>>> origin = "London"
>>> destination = "Paris"
>>> f"from {origin} to {destination}"
'from London to Paris'

注意f"前缀。如果您在Python 3.5或更早版本中尝试此操作,则会看到一个SyntaxError

参见https://docs.python.org/3.6/reference/lexical_analysis.html#f-strings

As of Python 3.6 (2016) you can use f-strings to substitute variables:

>>> origin = "London"
>>> destination = "Paris"
>>> f"from {origin} to {destination}"
'from London to Paris'

Note the f" prefix. If you try this in Python 3.5 or earlier, you’ll get a SyntaxError.

See https://docs.python.org/3.6/reference/lexical_analysis.html#f-strings


回答 4

PEP 3101提议%用Python 3中新的高级字符串格式替换运算符,这将是默认格式。

PEP 3101 proposes the replacement of the % operator with the new, advanced string formatting in Python 3, where it would be the default.


回答 5

但是请小心,刚才我在尝试%.format现有代码替换所有内容时发现了一个问题:'{}'.format(unicode_string)将尝试对unicode_string进行编码,并且可能会失败。

只需查看以下Python交互式会话日志即可:

Python 2.7.2 (default, Aug 27 2012, 19:52:55) 
[GCC 4.1.2 20080704 (Red Hat 4.1.2-48)] on linux2
; s='й'
; u=u'й'
; s
'\xd0\xb9'
; u
u'\u0439'

s只是一个字符串(在Python3中称为“字节数组”),并且u是Unicode字符串(在Python3中称为“字符串”):

; '%s' % s
'\xd0\xb9'
; '%s' % u
u'\u0439'

当将Unicode对象作为%运算符的参数时,即使原始字符串不是Unicode,它也会产生一个Unicode字符串:

; '{}'.format(s)
'\xd0\xb9'
; '{}'.format(u)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
UnicodeEncodeError: 'latin-1' codec can't encode character u'\u0439' in position 0: ordinal not in range(256)

但该.format函数将引发“ UnicodeEncodeError”:

; u'{}'.format(s)
u'\xd0\xb9'
; u'{}'.format(u)
u'\u0439'

并且仅当原始字符串为Unicode时,它才可以与Unicode参数一起使用。

; '{}'.format(u'i')
'i'

或者参数字符串可以转换为字符串(所谓的“字节数组”)

But please be careful, just now I’ve discovered one issue when trying to replace all % with .format in existing code: '{}'.format(unicode_string) will try to encode unicode_string and will probably fail.

Just look at this Python interactive session log:

Python 2.7.2 (default, Aug 27 2012, 19:52:55) 
[GCC 4.1.2 20080704 (Red Hat 4.1.2-48)] on linux2
; s='й'
; u=u'й'
; s
'\xd0\xb9'
; u
u'\u0439'

s is just a string (called ‘byte array’ in Python3) and u is a Unicode string (called ‘string’ in Python3):

; '%s' % s
'\xd0\xb9'
; '%s' % u
u'\u0439'

When you give a Unicode object as a parameter to % operator it will produce a Unicode string even if the original string wasn’t Unicode:

; '{}'.format(s)
'\xd0\xb9'
; '{}'.format(u)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
UnicodeEncodeError: 'latin-1' codec can't encode character u'\u0439' in position 0: ordinal not in range(256)

but the .format function will raise “UnicodeEncodeError”:

; u'{}'.format(s)
u'\xd0\xb9'
; u'{}'.format(u)
u'\u0439'

and it will work with a Unicode argument fine only if the original string was Unicode.

; '{}'.format(u'i')
'i'

or if argument string can be converted to a string (so called ‘byte array’)


回答 6

的另一个优点.format(我没有在答案中看到):它可以具有对象属性。

In [12]: class A(object):
   ....:     def __init__(self, x, y):
   ....:         self.x = x
   ....:         self.y = y
   ....:         

In [13]: a = A(2,3)

In [14]: 'x is {0.x}, y is {0.y}'.format(a)
Out[14]: 'x is 2, y is 3'

或者,作为关键字参数:

In [15]: 'x is {a.x}, y is {a.y}'.format(a=a)
Out[15]: 'x is 2, y is 3'

%据我所知,这是不可能的。

Yet another advantage of .format (which I don’t see in the answers): it can take object properties.

In [12]: class A(object):
   ....:     def __init__(self, x, y):
   ....:         self.x = x
   ....:         self.y = y
   ....:         

In [13]: a = A(2,3)

In [14]: 'x is {0.x}, y is {0.y}'.format(a)
Out[14]: 'x is 2, y is 3'

Or, as a keyword argument:

In [15]: 'x is {a.x}, y is {a.y}'.format(a=a)
Out[15]: 'x is 2, y is 3'

This is not possible with % as far as I can tell.


回答 7

%format我的测试提供更好的性能。

测试代码:

Python 2.7.2:

import timeit
print 'format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')")
print '%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')")

结果:

> format: 0.470329046249
> %: 0.357107877731

Python 3.5.2

import timeit
print('format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')"))
print('%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')"))

结果

> format: 0.5864730989560485
> %: 0.013593495357781649

它在Python2中看起来很小,而在Python3中%则比快得多format

感谢@Chris Cogdon提供示例代码。

编辑1:

2019年7月在Python 3.7.2中再次测试。

结果:

> format: 0.86600608
> %: 0.630180146

没有太大的区别。我想Python正在逐步完善。

编辑2:

在有人在评论中提到python 3的f字符串后,我在python 3.7.2下对以下代码进行了测试:

import timeit
print('format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')"))
print('%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')"))
print('f-string:', timeit.timeit("f'{1}{1.23}{\"hello\"}'"))

结果:

format: 0.8331376779999999
%: 0.6314778750000001
f-string: 0.766649943

看来f-string仍然比慢,%但比慢format

% gives better performance than format from my test.

Test code:

Python 2.7.2:

import timeit
print 'format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')")
print '%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')")

Result:

> format: 0.470329046249
> %: 0.357107877731

Python 3.5.2

import timeit
print('format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')"))
print('%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')"))

Result

> format: 0.5864730989560485
> %: 0.013593495357781649

It looks in Python2, the difference is small whereas in Python3, % is much faster than format.

Thanks @Chris Cogdon for the sample code.

Edit 1:

Tested again in Python 3.7.2 in July 2019.

Result:

> format: 0.86600608
> %: 0.630180146

There is not much difference. I guess Python is improving gradually.

Edit 2:

After someone mentioned python 3’s f-string in comment, I did a test for the following code under python 3.7.2 :

import timeit
print('format:', timeit.timeit("'{}{}{}'.format(1, 1.23, 'hello')"))
print('%:', timeit.timeit("'%s%s%s' % (1, 1.23, 'hello')"))
print('f-string:', timeit.timeit("f'{1}{1.23}{\"hello\"}'"))

Result:

format: 0.8331376779999999
%: 0.6314778750000001
f-string: 0.766649943

It seems f-string is still slower than % but better than format.


回答 8

正如我今天发现的那样,通过格式化字符串的旧方法%不支持Decimalpython的用于十进制定点和浮点算术的模块。

示例(使用Python 3.3.5):

#!/usr/bin/env python3

from decimal import *

getcontext().prec = 50
d = Decimal('3.12375239e-24') # no magic number, I rather produced it by banging my head on my keyboard

print('%.50f' % d)
print('{0:.50f}'.format(d))

输出:

0.00000000000000000000000312375239000000009907464850 0.00000000000000000000000312312239239000000000000000000

当然可能有解决方法,但是您仍然可以考虑立即使用该format()方法。

As I discovered today, the old way of formatting strings via % doesn’t support Decimal, Python’s module for decimal fixed point and floating point arithmetic, out of the box.

Example (using Python 3.3.5):

#!/usr/bin/env python3

from decimal import *

getcontext().prec = 50
d = Decimal('3.12375239e-24') # no magic number, I rather produced it by banging my head on my keyboard

print('%.50f' % d)
print('{0:.50f}'.format(d))

Output:

0.00000000000000000000000312375239000000009907464850 0.00000000000000000000000312375239000000000000000000

There surely might be work-arounds but you still might consider using the format() method right away.


回答 9

如果您的python> = 3.6,则F字符串格式的文字是您的新朋友。

它更简单,更干净,性能更好。

In [1]: params=['Hello', 'adam', 42]

In [2]: %timeit "%s %s, the answer to everything is %d."%(params[0],params[1],params[2])
448 ns ± 1.48 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [3]: %timeit "{} {}, the answer to everything is {}.".format(*params)
449 ns ± 1.42 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [4]: %timeit f"{params[0]} {params[1]}, the answer to everything is {params[2]}."
12.7 ns ± 0.0129 ns per loop (mean ± std. dev. of 7 runs, 100000000 loops each)

If your python >= 3.6, F-string formatted literal is your new friend.

It’s more simple, clean, and better performance.

In [1]: params=['Hello', 'adam', 42]

In [2]: %timeit "%s %s, the answer to everything is %d."%(params[0],params[1],params[2])
448 ns ± 1.48 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [3]: %timeit "{} {}, the answer to everything is {}.".format(*params)
449 ns ± 1.42 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

In [4]: %timeit f"{params[0]} {params[1]}, the answer to everything is {params[2]}."
12.7 ns ± 0.0129 ns per loop (mean ± std. dev. of 7 runs, 100000000 loops each)

回答 10

附带说明,您不必为了提高性能而在日志记录中使用新样式格式。您可以将任何实现了magic方法的对象传递给logging.debuglogging.info等等__str__。当日志记录模块决定必须发出您的消息对象(无论它是什么)时,它将str(message_object)在发出消息之前先进行调用。因此,您可以执行以下操作:

import logging


class NewStyleLogMessage(object):
    def __init__(self, message, *args, **kwargs):
        self.message = message
        self.args = args
        self.kwargs = kwargs

    def __str__(self):
        args = (i() if callable(i) else i for i in self.args)
        kwargs = dict((k, v() if callable(v) else v) for k, v in self.kwargs.items())

        return self.message.format(*args, **kwargs)

N = NewStyleLogMessage

# Neither one of these messages are formatted (or calculated) until they're
# needed

# Emits "Lazily formatted log entry: 123 foo" in log
logging.debug(N('Lazily formatted log entry: {0} {keyword}', 123, keyword='foo'))


def expensive_func():
    # Do something that takes a long time...
    return 'foo'

# Emits "Expensive log entry: foo" in log
logging.debug(N('Expensive log entry: {keyword}', keyword=expensive_func))

所有这些都在Python 3文档(https://docs.python.org/3/howto/logging-cookbook.html#formatting-styles)中进行了描述。但是,它也可以在Python 2.6中使用(https://docs.python.org/2.6/library/logging.html#using-arbitrary-objects-as-messages)。

使用该技术的优点之一是它允许使用惰性值,例如expensive_func上面的函数,这是事实,除了格式风格不可知。这为Python文档中的建议提供了更优雅的替代方法:https : //docs.python.org/2.6/library/logging.html#optimization

As a side note, you don’t have to take a performance hit to use new style formatting with logging. You can pass any object to logging.debug, logging.info, etc. that implements the __str__ magic method. When the logging module has decided that it must emit your message object (whatever it is), it calls str(message_object) before doing so. So you could do something like this:

import logging


class NewStyleLogMessage(object):
    def __init__(self, message, *args, **kwargs):
        self.message = message
        self.args = args
        self.kwargs = kwargs

    def __str__(self):
        args = (i() if callable(i) else i for i in self.args)
        kwargs = dict((k, v() if callable(v) else v) for k, v in self.kwargs.items())

        return self.message.format(*args, **kwargs)

N = NewStyleLogMessage

# Neither one of these messages are formatted (or calculated) until they're
# needed

# Emits "Lazily formatted log entry: 123 foo" in log
logging.debug(N('Lazily formatted log entry: {0} {keyword}', 123, keyword='foo'))


def expensive_func():
    # Do something that takes a long time...
    return 'foo'

# Emits "Expensive log entry: foo" in log
logging.debug(N('Expensive log entry: {keyword}', keyword=expensive_func))

This is all described in the Python 3 documentation (https://docs.python.org/3/howto/logging-cookbook.html#formatting-styles). However, it will work with Python 2.6 as well (https://docs.python.org/2.6/library/logging.html#using-arbitrary-objects-as-messages).

One of the advantages of using this technique, other than the fact that it’s formatting-style agnostic, is that it allows for lazy values e.g. the function expensive_func above. This provides a more elegant alternative to the advice being given in the Python docs here: https://docs.python.org/2.6/library/logging.html#optimization.


回答 11

一种%可能有用的情况是格式化正则表达式时。例如,

'{type_names} [a-z]{2}'.format(type_names='triangle|square')

加薪IndexError。在这种情况下,您可以使用:

'%(type_names)s [a-z]{2}' % {'type_names': 'triangle|square'}

这样可以避免将正则表达式写为'{type_names} [a-z]{{2}}'。当您有两个正则表达式时,这很有用,其中一个正则表达式单独使用而没有格式,但是两个正则表达式的连接都已格式化。

One situation where % may help is when you are formatting regex expressions. For example,

'{type_names} [a-z]{2}'.format(type_names='triangle|square')

raises IndexError. In this situation, you can use:

'%(type_names)s [a-z]{2}' % {'type_names': 'triangle|square'}

This avoids writing the regex as '{type_names} [a-z]{{2}}'. This can be useful when you have two regexes, where one is used alone without format, but the concatenation of both is formatted.


回答 12

我要补充一点,从3.6版开始,我们可以像下面这样使用fstrings

foo = "john"
bar = "smith"
print(f"My name is {foo} {bar}")

哪个给

我叫约翰·史密斯

一切都转换为字符串

mylist = ["foo", "bar"]
print(f"mylist = {mylist}")

结果:

mylist = [‘foo’,’bar’]

您可以像其他格式一样传递函数

print(f'Hello, here is the date : {time.strftime("%d/%m/%Y")}')

举个例子

您好,这是日期:16/04/2018

I would add that since version 3.6, we can use fstrings like the following

foo = "john"
bar = "smith"
print(f"My name is {foo} {bar}")

Which give

My name is john smith

Everything is converted to strings

mylist = ["foo", "bar"]
print(f"mylist = {mylist}")

Result:

mylist = [‘foo’, ‘bar’]

you can pass function, like in others formats method

print(f'Hello, here is the date : {time.strftime("%d/%m/%Y")}')

Giving for example

Hello, here is the date : 16/04/2018


回答 13

对于python版本> = 3.6(请参阅PEP 498

s1='albha'
s2='beta'

f'{s1}{s2:>10}'

#output
'albha      beta'

For python version >= 3.6 (see PEP 498)

s1='albha'
s2='beta'

f'{s1}{s2:>10}'

#output
'albha      beta'

回答 14

Python 3.6.7比较:

#!/usr/bin/env python
import timeit

def time_it(fn):
    """
    Measure time of execution of a function
    """
    def wrapper(*args, **kwargs):
        t0 = timeit.default_timer()
        fn(*args, **kwargs)
        t1 = timeit.default_timer()
        print("{0:.10f} seconds".format(t1 - t0))
    return wrapper


@time_it
def new_new_format(s):
    print("new_new_format:", f"{s[0]} {s[1]} {s[2]} {s[3]} {s[4]}")


@time_it
def new_format(s):
    print("new_format:", "{0} {1} {2} {3} {4}".format(*s))


@time_it
def old_format(s):
    print("old_format:", "%s %s %s %s %s" % s)


def main():
    samples = (("uno", "dos", "tres", "cuatro", "cinco"), (1,2,3,4,5), (1.1, 2.1, 3.1, 4.1, 5.1), ("uno", 2, 3.14, "cuatro", 5.5),) 
    for s in samples:
        new_new_format(s)
        new_format(s)
        old_format(s)
        print("-----")


if __name__ == '__main__':
    main()

输出:

new_new_format: uno dos tres cuatro cinco
0.0000170280 seconds
new_format: uno dos tres cuatro cinco
0.0000046750 seconds
old_format: uno dos tres cuatro cinco
0.0000034820 seconds
-----
new_new_format: 1 2 3 4 5
0.0000043980 seconds
new_format: 1 2 3 4 5
0.0000062590 seconds
old_format: 1 2 3 4 5
0.0000041730 seconds
-----
new_new_format: 1.1 2.1 3.1 4.1 5.1
0.0000092650 seconds
new_format: 1.1 2.1 3.1 4.1 5.1
0.0000055340 seconds
old_format: 1.1 2.1 3.1 4.1 5.1
0.0000052130 seconds
-----
new_new_format: uno 2 3.14 cuatro 5.5
0.0000053380 seconds
new_format: uno 2 3.14 cuatro 5.5
0.0000047570 seconds
old_format: uno 2 3.14 cuatro 5.5
0.0000045320 seconds
-----

Python 3.6.7 comparative:

#!/usr/bin/env python
import timeit

def time_it(fn):
    """
    Measure time of execution of a function
    """
    def wrapper(*args, **kwargs):
        t0 = timeit.default_timer()
        fn(*args, **kwargs)
        t1 = timeit.default_timer()
        print("{0:.10f} seconds".format(t1 - t0))
    return wrapper


@time_it
def new_new_format(s):
    print("new_new_format:", f"{s[0]} {s[1]} {s[2]} {s[3]} {s[4]}")


@time_it
def new_format(s):
    print("new_format:", "{0} {1} {2} {3} {4}".format(*s))


@time_it
def old_format(s):
    print("old_format:", "%s %s %s %s %s" % s)


def main():
    samples = (("uno", "dos", "tres", "cuatro", "cinco"), (1,2,3,4,5), (1.1, 2.1, 3.1, 4.1, 5.1), ("uno", 2, 3.14, "cuatro", 5.5),) 
    for s in samples:
        new_new_format(s)
        new_format(s)
        old_format(s)
        print("-----")


if __name__ == '__main__':
    main()

Output:

new_new_format: uno dos tres cuatro cinco
0.0000170280 seconds
new_format: uno dos tres cuatro cinco
0.0000046750 seconds
old_format: uno dos tres cuatro cinco
0.0000034820 seconds
-----
new_new_format: 1 2 3 4 5
0.0000043980 seconds
new_format: 1 2 3 4 5
0.0000062590 seconds
old_format: 1 2 3 4 5
0.0000041730 seconds
-----
new_new_format: 1.1 2.1 3.1 4.1 5.1
0.0000092650 seconds
new_format: 1.1 2.1 3.1 4.1 5.1
0.0000055340 seconds
old_format: 1.1 2.1 3.1 4.1 5.1
0.0000052130 seconds
-----
new_new_format: uno 2 3.14 cuatro 5.5
0.0000053380 seconds
new_format: uno 2 3.14 cuatro 5.5
0.0000047570 seconds
old_format: uno 2 3.14 cuatro 5.5
0.0000045320 seconds
-----

回答 15

但是有一件事是,如果您嵌套了花括号,则不能使用格式但%可以使用。

例:

>>> '{{0}, {1}}'.format(1,2)
Traceback (most recent call last):
  File "<pyshell#3>", line 1, in <module>
    '{{0}, {1}}'.format(1,2)
ValueError: Single '}' encountered in format string
>>> '{%s, %s}'%(1,2)
'{1, 2}'
>>> 

But one thing is that also if you have nested curly-braces, won’t work for format but % will work.

Example:

>>> '{{0}, {1}}'.format(1,2)
Traceback (most recent call last):
  File "<pyshell#3>", line 1, in <module>
    '{{0}, {1}}'.format(1,2)
ValueError: Single '}' encountered in format string
>>> '{%s, %s}'%(1,2)
'{1, 2}'
>>> 

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