问题:将字典的字符串表示形式转换为字典?
如何将a的str
表示形式(dict
例如以下字符串)转换为a dict
?
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我宁愿不使用eval
。我还能使用什么?
这样做的主要原因是他写的我的同事类之一,将所有输入都转换为字符串。我不打算去修改他的类,以解决这个问题。
回答 0
从Python 2.6开始,您可以使用内置的ast.literal_eval
:
>>> import ast
>>> ast.literal_eval("{'muffin' : 'lolz', 'foo' : 'kitty'}")
{'muffin': 'lolz', 'foo': 'kitty'}
这比使用更为安全eval
。正如其文档所说:
>>>帮助(ast.literal_eval) 帮助ast模块中的literal_eval函数: literal_eval(node_or_string) 安全地评估表达式节点或包含Python的字符串 表达。提供的字符串或节点只能由以下内容组成 Python文字结构:字符串,数字,元组,列表,字典,布尔值, 和没有。
例如:
>>> eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<string>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 208, in rmtree
onerror(os.listdir, path, sys.exc_info())
File "/opt/Python-2.6.1/lib/python2.6/shutil.py", line 206, in rmtree
names = os.listdir(path)
OSError: [Errno 2] No such file or directory: 'mongo'
>>> ast.literal_eval("shutil.rmtree('mongo')")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 68, in literal_eval
return _convert(node_or_string)
File "/opt/Python-2.6.1/lib/python2.6/ast.py", line 67, in _convert
raise ValueError('malformed string')
ValueError: malformed string
回答 1
https://docs.python.org/3.8/library/json.html
JSON可以解决此问题,尽管其解码器希望在键和值周围使用双引号。如果您不介意更换骇客…
import json
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
json_acceptable_string = s.replace("'", "\"")
d = json.loads(json_acceptable_string)
# d = {u'muffin': u'lolz', u'foo': u'kitty'}
请注意,如果将单引号作为键或值的一部分,则由于字符替换不当而导致此操作失败。仅当您对评估解决方案强烈反对时,才建议使用此解决方案。
有关JSON单引号的更多信息:jQuery.parseJSON由于JSON中的单引号已转义而引发“无效JSON”错误
回答 2
使用json.loads
:
>>> import json
>>> h = '{"foo":"bar", "foo2":"bar2"}'
>>> d = json.loads(h)
>>> d
{u'foo': u'bar', u'foo2': u'bar2'}
>>> type(d)
<type 'dict'>
回答 3
以OP为例:
s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
我们可以使用Yaml处理字符串中的这种非标准json:
>>> import yaml
>>> s = "{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> s
"{'muffin' : 'lolz', 'foo' : 'kitty'}"
>>> yaml.load(s)
{'muffin': 'lolz', 'foo': 'kitty'}
回答 4
如果始终可以信任该字符串,则可以使用eval
(或literal_eval
按建议使用;无论该字符串是什么都是安全的。)否则,您需要一个解析器。如果JSON解析器(例如simplejson)仅存储符合JSON方案的内容,则该解析器将起作用。
回答 5
使用json
。该ast
库消耗大量内存,并且速度较慢。我有一个过程需要读取156Mb的文本文件。Ast
转换字典需要5分钟的延迟,json
而使用内存减少60%则需要1分钟!
回答 6
总结一下:
import ast, yaml, json, timeit
descs=['short string','long string']
strings=['{"809001":2,"848545":2,"565828":1}','{"2979":1,"30581":1,"7296":1,"127256":1,"18803":2,"41619":1,"41312":1,"16837":1,"7253":1,"70075":1,"3453":1,"4126":1,"23599":1,"11465":3,"19172":1,"4019":1,"4775":1,"64225":1,"3235":2,"15593":1,"7528":1,"176840":1,"40022":1,"152854":1,"9878":1,"16156":1,"6512":1,"4138":1,"11090":1,"12259":1,"4934":1,"65581":1,"9747":2,"18290":1,"107981":1,"459762":1,"23177":1,"23246":1,"3591":1,"3671":1,"5767":1,"3930":1,"89507":2,"19293":1,"92797":1,"32444":2,"70089":1,"46549":1,"30988":1,"4613":1,"14042":1,"26298":1,"222972":1,"2982":1,"3932":1,"11134":1,"3084":1,"6516":1,"486617":1,"14475":2,"2127":1,"51359":1,"2662":1,"4121":1,"53848":2,"552967":1,"204081":1,"5675":2,"32433":1,"92448":1}']
funcs=[json.loads,eval,ast.literal_eval,yaml.load]
for desc,string in zip(descs,strings):
print('***',desc,'***')
print('')
for func in funcs:
print(func.__module__+' '+func.__name__+':')
%timeit func(string)
print('')
结果:
*** short string ***
json loads:
4.47 µs ± 33.4 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
builtins eval:
24.1 µs ± 163 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
ast literal_eval:
30.4 µs ± 299 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
yaml load:
504 µs ± 1.29 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
*** long string ***
json loads:
29.6 µs ± 230 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each)
builtins eval:
219 µs ± 3.92 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
ast literal_eval:
331 µs ± 1.89 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
yaml load:
9.02 ms ± 92.2 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
结论:更喜欢json.loads
回答 7
string = "{'server1':'value','server2':'value'}"
#Now removing { and }
s = string.replace("{" ,"")
finalstring = s.replace("}" , "")
#Splitting the string based on , we get key value pairs
list = finalstring.split(",")
dictionary ={}
for i in list:
#Get Key Value pairs separately to store in dictionary
keyvalue = i.split(":")
#Replacing the single quotes in the leading.
m= keyvalue[0].strip('\'')
m = m.replace("\"", "")
dictionary[m] = keyvalue[1].strip('"\'')
print dictionary
回答 8
没有使用任何库:
dict_format_string = "{'1':'one', '2' : 'two'}"
d = {}
elems = filter(str.isalnum,dict_format_string.split("'"))
values = elems[1::2]
keys = elems[0::2]
d.update(zip(keys,values))
注意:由于已进行硬编码,split("'")
因此仅适用于“单引号”数据的字符串。
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