问题:将Python datetime.datetime对象插入MySQL
我在MySQL表中有一个日期列。我想在datetime.datetime()
此列中插入一个对象。我应该在execute语句中使用什么?
我努力了:
now = datetime.datetime(2009,5,5)
cursor.execute("INSERT INTO table
(name, id, datecolumn) VALUES (%s, %s
, %s)",("name", 4,now))
我收到以下错误消息:"TypeError: not all arguments converted during string formatting"
应该用什么代替%s
?
I have a date column in a MySQL table. I want to insert a datetime.datetime()
object into this column. What should I be using in the execute statement?
I have tried:
now = datetime.datetime(2009,5,5)
cursor.execute("INSERT INTO table
(name, id, datecolumn) VALUES (%s, %s
, %s)",("name", 4,now))
I am getting an error as: "TypeError: not all arguments converted during string formatting"
What should I use instead of %s
?
回答 0
对于时间字段,请使用:
import time
time.strftime('%Y-%m-%d %H:%M:%S')
我认为strftime也适用于日期时间。
For a time field, use:
import time
time.strftime('%Y-%m-%d %H:%M:%S')
I think strftime also applies to datetime.
回答 1
您最有可能收到TypeError,因为您需要在datecolumn值前后加上引号。
尝试:
now = datetime.datetime(2009, 5, 5)
cursor.execute("INSERT INTO table (name, id, datecolumn) VALUES (%s, %s, '%s')",
("name", 4, now))
关于格式,我成功使用了上面的命令(包括毫秒)和以下命令:
now.strftime('%Y-%m-%d %H:%M:%S')
希望这可以帮助。
You are most likely getting the TypeError because you need quotes around the datecolumn value.
Try:
now = datetime.datetime(2009, 5, 5)
cursor.execute("INSERT INTO table (name, id, datecolumn) VALUES (%s, %s, '%s')",
("name", 4, now))
With regards to the format, I had success with the above command (which includes the milliseconds) and with:
now.strftime('%Y-%m-%d %H:%M:%S')
Hope this helps.
回答 2
尝试使用now.date()
获取Date
对象而不是获取对象DateTime
。
如果那不起作用,那么将其转换为字符串应该起作用:
now = datetime.datetime(2009,5,5)
str_now = now.date().isoformat()
cursor.execute('INSERT INTO table (name, id, datecolumn) VALUES (%s,%s,%s)', ('name',4,str_now))
Try using now.date()
to get a Date
object rather than a DateTime
.
If that doesn’t work, then converting that to a string should work:
now = datetime.datetime(2009,5,5)
str_now = now.date().isoformat()
cursor.execute('INSERT INTO table (name, id, datecolumn) VALUES (%s,%s,%s)', ('name',4,str_now))
回答 3
使用Python方法,其中format = '%Y-%m-%d %H:%M:%S'
。
import datetime
now = datetime.datetime.utcnow()
cursor.execute("INSERT INTO table (name, id, datecolumn) VALUES (%s, %s, %s)",
("name", 4, now.strftime('%Y-%m-%d %H:%M:%S')))
时区
如果需要考虑时区,则可以按如下所示为UTC设置MySQL时区:
cursor.execute("SET time_zone = '+00:00'")
时区可以在Python中设置:
now = datetime.datetime.utcnow().replace(tzinfo=datetime.timezone.utc)
MySQL可以使用以下格式识别DATETIME和TIMESTAMP值:
作为任一字符串 ‘YYYY-MM-DD HH:MM:SS’或‘YY-MM-DD HH:MM:SS’ 格式。这里也允许使用“宽松”语法:任何标点符号都可以用作日期部分或时间部分之间的分隔符。例如,“ 2012-12-31 11:30:45”,“ 2012 ^ 12 ^ 31 11 + 30 + 45”,“ 2012/12/31 11 * 30 * 45”和“ 2012 @ 12 @ 31 11” ^ 30 ^ 45’是等效的。
在日期和时间部分与小数秒部分之间唯一识别的分隔符是小数点。
日期和时间部分可以用T分隔而不是空格。例如,“ 2012-12-31 11:30:45”与“ 2012-12-31T11:30:45”等效。
如果字符串不带分隔符,则格式为“ YYYYMMDDHHMMSS”或“ YYMMDDHHMMSS”,但前提是该字符串应作为日期使用。例如,“ 20070523091528”和“ 070523091528”被解释为“ 2007-05-23 09:15:28”,但“ 071122129015”是非法的(具有无意义的分钟部分),并变为“ 0000-00-00 00”: 00:00’。
如果数字是日期,则以YYYYMMDDHHMMSS或YYMMDDHHMMSS格式表示。例如,将19830905132800和830905132800解释为“ 1983-09-05 13:28:00”。
Use Python method , where format = '%Y-%m-%d %H:%M:%S'
.
import datetime
now = datetime.datetime.utcnow()
cursor.execute("INSERT INTO table (name, id, datecolumn) VALUES (%s, %s, %s)",
("name", 4, now.strftime('%Y-%m-%d %H:%M:%S')))
Timezones
If timezones are a concern, the MySQL timezone can be set for UTC as follows:
cursor.execute("SET time_zone = '+00:00'")
And the timezone can be set in Python:
now = datetime.datetime.utcnow().replace(tzinfo=datetime.timezone.utc)
MySQL recognizes DATETIME and TIMESTAMP values in these formats:
As a string in either ‘YYYY-MM-DD HH:MM:SS’ or ‘YY-MM-DD HH:MM:SS’ format. A “relaxed” syntax is permitted here, too: Any punctuation character may be used as the delimiter between date parts or time parts. For example, ‘2012-12-31 11:30:45’, ‘2012^12^31 11+30+45’, ‘2012/12/31 11*30*45’, and ‘2012@12@31 11^30^45’ are equivalent.
The only delimiter recognized between a date and time part and a fractional seconds part is the decimal point.
The date and time parts can be separated by T rather than a space. For example, ‘2012-12-31 11:30:45’ ‘2012-12-31T11:30:45’ are equivalent.
As a string with no delimiters in either ‘YYYYMMDDHHMMSS’ or ‘YYMMDDHHMMSS’ format, provided that the string makes sense as a date. For example, ‘20070523091528’ and ‘070523091528’ are interpreted as ‘2007-05-23 09:15:28’, but ‘071122129015’ is illegal (it has a nonsensical minute part) and becomes ‘0000-00-00 00:00:00’.
As a number in either YYYYMMDDHHMMSS or YYMMDDHHMMSS format, provided that the number makes sense as a date. For example, 19830905132800 and 830905132800 are interpreted as ‘1983-09-05 13:28:00’.
回答 4
您要连接到哪个数据库?我知道Oracle对日期格式可能很挑剔,并且喜欢ISO 8601格式。
**注意:糟糕,我刚读过您在MySQL上。只需格式化日期并尝试将其作为单独的直接SQL调用进行测试即可。
在Python中,您可以获得一个ISO日期,例如
now.isoformat()
例如,Oracle喜欢日期,例如
insert into x values(99, '31-may-09');
根据您的数据库,如果是Oracle,则可能需要TO_DATE它:
insert into x
values(99, to_date('2009/05/31:12:00:00AM', 'yyyy/mm/dd:hh:mi:ssam'));
TO_DATE的一般用法是:
TO_DATE(<string>, '<format>')
如果使用另一个数据库(我看到了光标并认为是Oracle;可能是错误的),请检查其日期格式工具。对于MySQL,它是DATE_FORMAT(),对于SQL Server,它是CONVERT。
另外,使用SQLAlchemy之类的工具将消除此类差异,并使您的生活变得轻松。
What database are you connecting to? I know Oracle can be picky about date formats and likes ISO 8601 format.
**Note: Oops, I just read you are on MySQL. Just format the date and try it as a separate direct SQL call to test.
In Python, you can get an ISO date like
now.isoformat()
For instance, Oracle likes dates like
insert into x values(99, '31-may-09');
Depending on your database, if it is Oracle you might need to TO_DATE it:
insert into x
values(99, to_date('2009/05/31:12:00:00AM', 'yyyy/mm/dd:hh:mi:ssam'));
The general usage of TO_DATE is:
TO_DATE(<string>, '<format>')
If using another database (I saw the cursor and thought Oracle; I could be wrong) then check their date format tools. For MySQL it is DATE_FORMAT() and SQL Server it is CONVERT.
Also using a tool like SQLAlchemy will remove differences like these and make your life easy.
回答 5
如果您仅使用python datetime.date(而不是完整的datetime.datetime),则将日期转换为字符串。这非常简单,对我有用(mysql,python 2.7,Ubuntu)。该列published_date
是一个MySQL日期字段,python变量publish_date
是datetime.date
。
# make the record for the passed link info
sql_stmt = "INSERT INTO snippet_links (" + \
"link_headline, link_url, published_date, author, source, coco_id, link_id)" + \
"VALUES(%s, %s, %s, %s, %s, %s, %s) ;"
sql_data = ( title, link, str(publish_date), \
author, posted_by, \
str(coco_id), str(link_id) )
try:
dbc.execute(sql_stmt, sql_data )
except Exception, e:
...
If you’re just using a python datetime.date (not a full datetime.datetime), just cast the date as a string. This is very simple and works for me (mysql, python 2.7, Ubuntu). The column published_date
is a MySQL date field, the python variable publish_date
is datetime.date
.
# make the record for the passed link info
sql_stmt = "INSERT INTO snippet_links (" + \
"link_headline, link_url, published_date, author, source, coco_id, link_id)" + \
"VALUES(%s, %s, %s, %s, %s, %s, %s) ;"
sql_data = ( title, link, str(publish_date), \
author, posted_by, \
str(coco_id), str(link_id) )
try:
dbc.execute(sql_stmt, sql_data )
except Exception, e:
...
回答 6
当烦恼到T-SQL
这失败了:
select CONVERT(datetime,'2019-09-13 09:04:35.823312',21)
这有效:
select CONVERT(datetime,'2019-09-13 09:04:35.823',21)
简单的方法:
regexp = re.compile(r'\.(\d{6})')
def to_splunk_iso(dt):
"""Converts the datetime object to Splunk isoformat string."""
# 6-digits string.
microseconds = regexp.search(dt).group(1)
return regexp.sub('.%d' % round(float(microseconds) / 1000), dt)
when iserting into t-sql
this fails:
select CONVERT(datetime,'2019-09-13 09:04:35.823312',21)
this works:
select CONVERT(datetime,'2019-09-13 09:04:35.823',21)
easy way:
regexp = re.compile(r'\.(\d{6})')
def to_splunk_iso(dt):
"""Converts the datetime object to Splunk isoformat string."""
# 6-digits string.
microseconds = regexp.search(dt).group(1)
return regexp.sub('.%d' % round(float(microseconds) / 1000), dt)
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