问题:有没有一种简单的方法可以在python中请求URL而不遵循重定向?
查看urllib2的源代码,看起来最简单的方法是将HTTPRedirectHandler子类化,然后使用build_opener覆盖默认的HTTPRedirectHandler,但这似乎需要很多(相对复杂的)工作来完成应有的工作很简单。
回答 0
这是请求的方式:
import requests
r = requests.get('http://github.com', allow_redirects=False)
print(r.status_code, r.headers['Location'])
回答 1
Dive Into Python有很好的章节介绍如何使用urllib2进行重定向。另一个解决方案是httplib。
>>> import httplib
>>> conn = httplib.HTTPConnection("www.bogosoft.com")
>>> conn.request("GET", "")
>>> r1 = conn.getresponse()
>>> print r1.status, r1.reason
301 Moved Permanently
>>> print r1.getheader('Location')
http://www.bogosoft.com/new/location
回答 2
这是一个不会跟随重定向的urllib2处理程序:
class NoRedirectHandler(urllib2.HTTPRedirectHandler):
def http_error_302(self, req, fp, code, msg, headers):
infourl = urllib.addinfourl(fp, headers, req.get_full_url())
infourl.status = code
infourl.code = code
return infourl
http_error_300 = http_error_302
http_error_301 = http_error_302
http_error_303 = http_error_302
http_error_307 = http_error_302
opener = urllib2.build_opener(NoRedirectHandler())
urllib2.install_opener(opener)
回答 3
request方法中的redirections
关键字httplib2
是红色鲱鱼。RedirectLimit
如果收到重定向状态代码,它将引发异常,而不是返回第一个请求。要返回初始响应,您需要在对象上设置follow_redirects
为:False
Http
import httplib2
h = httplib2.Http()
h.follow_redirects = False
(response, body) = h.request("http://example.com")
回答 4
我想这会有所帮助
from httplib2 import Http
def get_html(uri,num_redirections=0): # put it as 0 for not to follow redirects
conn = Http()
return conn.request(uri,redirections=num_redirections)
回答 5
我仅次于olt的Dive into Python指针。这是一个使用urllib2重定向处理程序的实现,比应做的工作还要多?也许,耸耸肩。
import sys
import urllib2
class RedirectHandler(urllib2.HTTPRedirectHandler):
def http_error_301(self, req, fp, code, msg, headers):
result = urllib2.HTTPRedirectHandler.http_error_301(
self, req, fp, code, msg, headers)
result.status = code
raise Exception("Permanent Redirect: %s" % 301)
def http_error_302(self, req, fp, code, msg, headers):
result = urllib2.HTTPRedirectHandler.http_error_302(
self, req, fp, code, msg, headers)
result.status = code
raise Exception("Temporary Redirect: %s" % 302)
def main(script_name, url):
opener = urllib2.build_opener(RedirectHandler)
urllib2.install_opener(opener)
print urllib2.urlopen(url).read()
if __name__ == "__main__":
main(*sys.argv)
回答 6
但是最短的方法是
class NoRedirect(urllib2.HTTPRedirectHandler):
def redirect_request(self, req, fp, code, msg, hdrs, newurl):
pass
noredir_opener = urllib2.build_opener(NoRedirect())