问题:来自对象字段的Python字典
您是否知道是否有内置函数可以从任意对象构建字典?我想做这样的事情:
>>> class Foo:
...     bar = 'hello'
...     baz = 'world'
...
>>> f = Foo()
>>> props(f)
{ 'bar' : 'hello', 'baz' : 'world' }
注意:它不应包含方法。仅字段。
 
        
        
            
            
            
                
                    Do you know if there is a built-in function to build a dictionary from an arbitrary object? I’d like to do something like this:
>>> class Foo:
...     bar = 'hello'
...     baz = 'world'
...
>>> f = Foo()
>>> props(f)
{ 'bar' : 'hello', 'baz' : 'world' }
NOTE: It should not include methods. Only fields.
                 
             
            
         
        
        
回答 0
请注意,Python 2.7中的最佳实践是使用新型类(Python 3不需要),即
class Foo(object):
   ...
同样,“对象”和“类”之间也存在差异。要从任意对象构建字典,只需使用即可__dict__。通常,您将在类级别声明您的方法,并在实例级别声明您的属性,因此__dict__应该没问题。例如:
>>> class A(object):
...   def __init__(self):
...     self.b = 1
...     self.c = 2
...   def do_nothing(self):
...     pass
...
>>> a = A()
>>> a.__dict__
{'c': 2, 'b': 1}
更好的方法(由robert建议在注释中使用)是内置vars函数:
>>> vars(a)
{'c': 2, 'b': 1}
另外,根据您要执行的操作,最好继承自dict。然后,您的Class已经是字典,并且如果您愿意,可以覆盖getattr和/或setattr调用并设置字典。例如:
class Foo(dict):
    def __init__(self):
        pass
    def __getattr__(self, attr):
        return self[attr]
    # etc...
 
        
        
            
            
            
                
                    Note that best practice in Python 2.7 is to use new-style classes (not needed with Python 3), i.e.
class Foo(object):
   ...
Also, there’s a difference between an ‘object’ and a ‘class’. To build a dictionary from an arbitrary object, it’s sufficient to use __dict__. Usually, you’ll declare your methods at class level and your attributes at instance level, so __dict__ should be fine. For example:
>>> class A(object):
...   def __init__(self):
...     self.b = 1
...     self.c = 2
...   def do_nothing(self):
...     pass
...
>>> a = A()
>>> a.__dict__
{'c': 2, 'b': 1}
A better approach (suggested by robert in comments) is the builtin vars function:
>>> vars(a)
{'c': 2, 'b': 1}
Alternatively, depending on what you want to do, it might be nice to inherit from dict. Then your class is already a dictionary, and if you want you can override getattr and/or setattr to call through and set the dict. For example:
class Foo(dict):
    def __init__(self):
        pass
    def __getattr__(self, attr):
        return self[attr]
    # etc...
                 
             
            
         
        
        
回答 1
取而代之的是x.__dict__,它实际上更具有Pythonic的用法vars(x)。
 
        
        
            
            
            
                
                    Instead of x.__dict__, it’s actually more pythonic to use vars(x).
                 
             
            
         
        
        
回答 2
该dir内置会给你对象的所有属性,包括特殊的方法,如__str__,__dict__和一大堆人,你可能不希望的。但是您可以执行以下操作:
>>> class Foo(object):
...     bar = 'hello'
...     baz = 'world'
...
>>> f = Foo()
>>> [name for name in dir(f) if not name.startswith('__')]
[ 'bar', 'baz' ]
>>> dict((name, getattr(f, name)) for name in dir(f) if not name.startswith('__')) 
{ 'bar': 'hello', 'baz': 'world' }
因此可以通过定义如下props函数将其扩展为仅返回数据属性而不是方法:
import inspect
def props(obj):
    pr = {}
    for name in dir(obj):
        value = getattr(obj, name)
        if not name.startswith('__') and not inspect.ismethod(value):
            pr[name] = value
    return pr
 
        
        
            
            
            
                
                    The dir builtin will give you all the object’s attributes, including special methods like __str__, __dict__ and a whole bunch of others which you probably don’t want. But you can do something like:
>>> class Foo(object):
...     bar = 'hello'
...     baz = 'world'
...
>>> f = Foo()
>>> [name for name in dir(f) if not name.startswith('__')]
[ 'bar', 'baz' ]
>>> dict((name, getattr(f, name)) for name in dir(f) if not name.startswith('__')) 
{ 'bar': 'hello', 'baz': 'world' }
So can extend this to only return data attributes and not methods, by defining your props function like this:
import inspect
def props(obj):
    pr = {}
    for name in dir(obj):
        value = getattr(obj, name)
        if not name.startswith('__') and not inspect.ismethod(value):
            pr[name] = value
    return pr
                 
             
            
         
        
        
回答 3
我已经结合了两个答案:
dict((key, value) for key, value in f.__dict__.iteritems() 
    if not callable(value) and not key.startswith('__'))
 
        
        
            
            
            
                
                    I’ve settled with a combination of both answers:
dict((key, value) for key, value in f.__dict__.iteritems() 
    if not callable(value) and not key.startswith('__'))
                 
             
            
         
        
        
回答 4
我以为我会花些时间向您展示如何通过转换对象来决定字典dict(obj)。
class A(object):
    d = '4'
    e = '5'
    f = '6'
    def __init__(self):
        self.a = '1'
        self.b = '2'
        self.c = '3'
    def __iter__(self):
        # first start by grabbing the Class items
        iters = dict((x,y) for x,y in A.__dict__.items() if x[:2] != '__')
        # then update the class items with the instance items
        iters.update(self.__dict__)
        # now 'yield' through the items
        for x,y in iters.items():
            yield x,y
a = A()
print(dict(a)) 
# prints "{'a': '1', 'c': '3', 'b': '2', 'e': '5', 'd': '4', 'f': '6'}"
此代码的关键部分是 __iter__功能。
正如评论所解释的,我们要做的第一件事是获取Class项,并防止以’__’开头的任何东西。
一旦创建了它dict,就可以使用updatedict函数并传入实例__dict__。
这些将为您提供完整的成员类+实例字典。现在剩下的就是迭代它们并产生回报。
另外,如果您打算大量使用它,则可以创建一个@iterable类装饰器。
def iterable(cls):
    def iterfn(self):
        iters = dict((x,y) for x,y in cls.__dict__.items() if x[:2] != '__')
        iters.update(self.__dict__)
        for x,y in iters.items():
            yield x,y
    cls.__iter__ = iterfn
    return cls
@iterable
class B(object):
    d = 'd'
    e = 'e'
    f = 'f'
    def __init__(self):
        self.a = 'a'
        self.b = 'b'
        self.c = 'c'
b = B()
print(dict(b))
 
        
        
            
            
            
                
                    I thought I’d take some time to show you how you can translate an object to dict via dict(obj).
class A(object):
    d = '4'
    e = '5'
    f = '6'
    def __init__(self):
        self.a = '1'
        self.b = '2'
        self.c = '3'
    def __iter__(self):
        # first start by grabbing the Class items
        iters = dict((x,y) for x,y in A.__dict__.items() if x[:2] != '__')
        # then update the class items with the instance items
        iters.update(self.__dict__)
        # now 'yield' through the items
        for x,y in iters.items():
            yield x,y
a = A()
print(dict(a)) 
# prints "{'a': '1', 'c': '3', 'b': '2', 'e': '5', 'd': '4', 'f': '6'}"
The key section of this code is the __iter__ function. 
As the comments explain, the first thing we do is grab the Class items and prevent anything that starts with ‘__’.
Once you’ve created that dict, then you can use the update dict function and pass in the instance __dict__.
These will give you a complete class+instance dictionary of members. Now all that’s left is to iterate over them and yield the returns.
Also, if you plan on using this a lot, you can create an @iterable class decorator.
def iterable(cls):
    def iterfn(self):
        iters = dict((x,y) for x,y in cls.__dict__.items() if x[:2] != '__')
        iters.update(self.__dict__)
        for x,y in iters.items():
            yield x,y
    cls.__iter__ = iterfn
    return cls
@iterable
class B(object):
    d = 'd'
    e = 'e'
    f = 'f'
    def __init__(self):
        self.a = 'a'
        self.b = 'b'
        self.c = 'c'
b = B()
print(dict(b))
                 
             
            
         
        
        
回答 5
要从任意对象构建字典,只需使用即可__dict__。
这会错过对象从其类继承的属性。例如,
class c(object):
    x = 3
a = c()
hasattr(a,’x’)是true,但是’x’不会出现在a .__ dict__
 
        
        
            
            
            
                
                    
  To build a dictionary from an arbitrary object, it’s sufficient to use __dict__.
This misses attributes that the object inherits from its class. For example,
class c(object):
    x = 3
a = c()
hasattr(a, ‘x’) is true, but ‘x’ does not appear in a.__dict__
                 
             
            
         
        
        
回答 6
答案较晚,但提供了完整性和对Google员工的好处:
def props(x):
    return dict((key, getattr(x, key)) for key in dir(x) if key not in dir(x.__class__))
这不会显示在类中定义的方法,但仍会显示字段,包括分配给lambda的字段或以双下划线开头的字段。
 
        
        
            
            
            
                
                    Late answer but provided for completeness and the benefit of googlers:
def props(x):
    return dict((key, getattr(x, key)) for key in dir(x) if key not in dir(x.__class__))
This will not show methods defined in the class, but it will still show fields including those assigned to lambdas or those which start with a double underscore.
                 
             
            
         
        
        
回答 7
我认为最简单的方法是为该类创建一个getitem属性。如果需要写入对象,则可以创建一个自定义setattr。这是getitem的示例:
class A(object):
    def __init__(self):
        self.b = 1
        self.c = 2
    def __getitem__(self, item):
        return self.__dict__[item]
# Usage: 
a = A()
a.__getitem__('b')  # Outputs 1
a.__dict__  # Outputs {'c': 2, 'b': 1}
vars(a)  # Outputs {'c': 2, 'b': 1}
dict将对象属性生成到字典中,并且字典对象可用于获取所需的项目。
 
        
        
            
            
            
                
                    I think the easiest way is to create a getitem attribute for the class. If you need to write to the object, you can create a custom setattr . Here is an example for getitem:
class A(object):
    def __init__(self):
        self.b = 1
        self.c = 2
    def __getitem__(self, item):
        return self.__dict__[item]
# Usage: 
a = A()
a.__getitem__('b')  # Outputs 1
a.__dict__  # Outputs {'c': 2, 'b': 1}
vars(a)  # Outputs {'c': 2, 'b': 1}
dict generates the objects attributes into a dictionary and the dictionary object can be used to get the item you need.
                 
             
            
         
        
        
回答 8
使用的缺点 __dict__是它很浅。它不会将任何子类转换为字典。
如果您使用的是Python3.5或更高版本,则可以使用jsons:
>>> import jsons
>>> jsons.dump(f)
{'bar': 'hello', 'baz': 'world'}
 
        
        
            
            
            
                
                    A downside of using __dict__ is that it is shallow; it won’t convert any subclasses to dictionaries.
If you’re using Python3.5 or higher, you can use jsons:
>>> import jsons
>>> jsons.dump(f)
{'bar': 'hello', 'baz': 'world'}
                 
             
            
         
        
        
回答 9
如果要列出部分属性,请覆盖__dict__:
def __dict__(self):
    d = {
    'attr_1' : self.attr_1,
    ...
    }
    return d
# Call __dict__
d = instance.__dict__()
如果您instance获得了一些大块数据,并且想要d像消息队列一样推送到Redis ,这将很有帮助。
 
        
        
            
            
            
                
                    If you want to list part of your attributes, override __dict__:
def __dict__(self):
    d = {
    'attr_1' : self.attr_1,
    ...
    }
    return d
# Call __dict__
d = instance.__dict__()
This helps a lot if your instance get some large block data and you want to push d to Redis like message queue. 
                 
             
            
         
        
        
回答 10
PYTHON 3:
class DateTimeDecoder(json.JSONDecoder):
   def __init__(self, *args, **kargs):
        JSONDecoder.__init__(self, object_hook=self.dict_to_object,
                         *args, **kargs)
   def dict_to_object(self, d):
       if '__type__' not in d:
          return d
       type = d.pop('__type__')
       try:
          dateobj = datetime(**d)
          return dateobj
       except:
          d['__type__'] = type
          return d
def json_default_format(value):
    try:
        if isinstance(value, datetime):
            return {
                '__type__': 'datetime',
                'year': value.year,
                'month': value.month,
                'day': value.day,
                'hour': value.hour,
                'minute': value.minute,
                'second': value.second,
                'microsecond': value.microsecond,
            }
        if isinstance(value, decimal.Decimal):
            return float(value)
        if isinstance(value, Enum):
            return value.name
        else:
            return vars(value)
    except Exception as e:
        raise ValueError
现在,您可以在自己的类中使用上述代码:
class Foo():
  def toJSON(self):
        return json.loads(
            json.dumps(self, sort_keys=True, indent=4, separators=(',', ': '), default=json_default_format), cls=DateTimeDecoder)
Foo().toJSON() 
 
        
        
            
            
            
                
                    PYTHON 3:
class DateTimeDecoder(json.JSONDecoder):
   def __init__(self, *args, **kargs):
        JSONDecoder.__init__(self, object_hook=self.dict_to_object,
                         *args, **kargs)
   def dict_to_object(self, d):
       if '__type__' not in d:
          return d
       type = d.pop('__type__')
       try:
          dateobj = datetime(**d)
          return dateobj
       except:
          d['__type__'] = type
          return d
def json_default_format(value):
    try:
        if isinstance(value, datetime):
            return {
                '__type__': 'datetime',
                'year': value.year,
                'month': value.month,
                'day': value.day,
                'hour': value.hour,
                'minute': value.minute,
                'second': value.second,
                'microsecond': value.microsecond,
            }
        if isinstance(value, decimal.Decimal):
            return float(value)
        if isinstance(value, Enum):
            return value.name
        else:
            return vars(value)
    except Exception as e:
        raise ValueError
Now you can use above code inside your own class :
class Foo():
  def toJSON(self):
        return json.loads(
            json.dumps(self, sort_keys=True, indent=4, separators=(',', ': '), default=json_default_format), cls=DateTimeDecoder)
Foo().toJSON() 
                 
             
            
         
        
        
回答 11
vars() 很棒,但是不适用于对象的嵌套对象
将对象的嵌套对象转换为dict:
def to_dict(self):
    return json.loads(json.dumps(self, default=lambda o: o.__dict__))
 
        
        
            
            
            
                
                    vars() is great, but doesn’t work for nested objects of objects
Convert nested object of objects to dict:
def to_dict(self):
    return json.loads(json.dumps(self, default=lambda o: o.__dict__))
                 
             
            
         
        
        
	
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