Why do these two operations (append() resp. +) give different results?

>>> c = [1, 2, 3]
>>> c
[1, 2, 3]
>>> c += c
>>> c
[1, 2, 3, 1, 2, 3]
>>> c = [1, 2, 3]
>>> c.append(c)
>>> c
[1, 2, 3, [...]]
>>> 

In the last case there’s actually an infinite recursion. c[-1] and c are the same. Why is it different with the + operation?

To explain “why”:

The + operation adds the array elements to the original array. The array.append operation inserts the array (or any object) into the end of the original array, which results in a reference to self in that spot (hence the infinite recursion).

The difference here is that the + operation acts specific when you add an array (it’s overloaded like others, see this chapter on sequences) by concatenating the element. The append-method however does literally what you ask: append the object on the right-hand side that you give it (the array or any other object), instead of taking its elements.

An alternative

Use extend() if you want to use a function that acts similar to the + operator (as others have shown here as well). It’s not wise to do the opposite: to try to mimic append with the + operator for lists (see my earlier link on why).

Little history

For fun, a little history: the birth of the array module in Python in February 1993. it might surprise you, but arrays were added way after sequences and lists came into existence.

The concatenation operator + is a binary infix operator which, when applied to lists, returns a new list containing all the elements of each of its two operands. The list.append() method is a mutator on list which appends its single object argument (in your specific example the list c) to the subject list. In your example this results in c appending a reference to itself (hence the infinite recursion).

An alternative to ‘+’ concatenation

The list.extend() method is also a mutator method which concatenates its sequence argument with the subject list. Specifically, it appends each of the elements of sequence in iteration order.

An aside

Being an operator, + returns the result of the expression as a new value. Being a non-chaining mutator method, list.extend() modifies the subject list in-place and returns nothing.

Arrays

I’ve added this due to the potential confusion which the Abel’s answer above may cause by mixing the discussion of lists, sequences and arrays. Arrays were added to Python after sequences and lists, as a more efficient way of storing arrays of integral data types. Do not confuse arrays with lists. They are not the same.

From the array docs:

Arrays are sequence types and behave very much like lists, except that the type of objects stored in them is constrained. The type is specified at object creation time by using a type code, which is a single character.

append is appending an element to a list. if you want to extend the list with the new list you need to use extend.

>>> c = [1, 2, 3]
>>> c.extend(c)
>>> c
[1, 2, 3, 1, 2, 3]

Python lists are heterogeneous that is the elements in the same list can be any type of object. The expression: c.append(c) appends the object c what ever it may be to the list. In the case it makes the list itself a member of the list.

The expression c += c adds two lists together and assigns the result to the variable c. The overloaded + operator is defined on lists to create a new list whose contents are the elements in the first list and the elements in the second list.

So these are really just different expressions used to do different things by design.

The method you’re looking for is extend(). From the Python documentation:

list.append(x)
    Add an item to the end of the list; equivalent to a[len(a):] = [x].

list.extend(L)
    Extend the list by appending all the items in the given list; equivalent to a[len(a):] = L.

list.insert(i, x)
    Insert an item at a given position. The first argument is the index of the element before which to insert, so a.insert(0, x) inserts at the front of the list, and a.insert(len(a), x) is equivalent to a.append(x).

you should use extend()

>>> c=[1,2,3]
>>> c.extend(c)
>>> c
[1, 2, 3, 1, 2, 3]

other info: append vs. extend

See the documentation:

list.append(x)

• Add an item to the end of the list; equivalent to a[len(a):] = [x].

list.extend(L) – Extend the list by appending all the items in the given list; equivalent to a[len(a):] = L.

c.append(c) “appends” c to itself as an element. Since a list is a reference type, this creates a recursive data structure.

c += c is equivalent to extend(c), which appends the elements of c to c.