问题:熊猫可以绘制日期直方图吗?
我已经将我的Series系列产品,并将其强制为dtype =的datetime列datetime64[ns]
(尽管仅需要日期分辨率…不确定如何更改)。
import pandas as pd
df = pd.read_csv('somefile.csv')
column = df['date']
column = pd.to_datetime(column, coerce=True)
但是绘图不起作用:
ipdb> column.plot(kind='hist')
*** TypeError: ufunc add cannot use operands with types dtype('<M8[ns]') and dtype('float64')
我想绘制一个直方图,该直方图仅按周,月或年显示日期计数。
当然有办法做到pandas
吗?
I’ve taken my Series and coerced it to a datetime column of dtype=datetime64[ns]
(though only need day resolution…not sure how to change).
import pandas as pd
df = pd.read_csv('somefile.csv')
column = df['date']
column = pd.to_datetime(column, coerce=True)
but plotting doesn’t work:
ipdb> column.plot(kind='hist')
*** TypeError: ufunc add cannot use operands with types dtype('<M8[ns]') and dtype('float64')
I’d like to plot a histogram that just shows the count of dates by week, month, or year.
Surely there is a way to do this in pandas
?
回答 0
鉴于此df:
date
0 2001-08-10
1 2002-08-31
2 2003-08-29
3 2006-06-21
4 2002-03-27
5 2003-07-14
6 2004-06-15
7 2003-08-14
8 2003-07-29
并且,如果还不是这样的话:
df["date"] = df["date"].astype("datetime64")
要按月显示日期计数:
df.groupby(df["date"].dt.month).count().plot(kind="bar")
.dt
允许您访问datetime属性。
这会给你:
您可以按年,日等替换月份。
例如,如果要区分年份和月份,请执行以下操作:
df.groupby([df["date"].dt.year, df["date"].dt.month]).count().plot(kind="bar")
这使:
是您想要的吗?这清楚吗?
希望这可以帮助 !
Given this df:
date
0 2001-08-10
1 2002-08-31
2 2003-08-29
3 2006-06-21
4 2002-03-27
5 2003-07-14
6 2004-06-15
7 2003-08-14
8 2003-07-29
and, if it’s not already the case:
df["date"] = df["date"].astype("datetime64")
To show the count of dates by month:
df.groupby(df["date"].dt.month).count().plot(kind="bar")
.dt
allows you to access the datetime properties.
Which will give you:
You can replace month by year, day, etc..
If you want to distinguish year and month for instance, just do:
df.groupby([df["date"].dt.year, df["date"].dt.month]).count().plot(kind="bar")
Which gives:
Was it what you wanted ? Is this clear ?
Hope this helps !
回答 1
我认为重新采样可能是您想要的。对于您的情况,请执行以下操作:
df.set_index('date', inplace=True)
# for '1M' for 1 month; '1W' for 1 week; check documentation on offset alias
df.resample('1M', how='count')
它仅在进行计数而不是在进行图,因此您必须自己制作图。
有关重新采样熊猫重新采样文档的更多详细信息,请参见这篇文章。
我遇到了和您一样的类似问题。希望这可以帮助。
I think resample might be what you are looking for. In your case, do:
df.set_index('date', inplace=True)
# for '1M' for 1 month; '1W' for 1 week; check documentation on offset alias
df.resample('1M', how='count')
It is only doing the counting and not the plot, so you then have to make your own plots.
See this post for more details on the documentation of resample pandas resample documentation
I have ran into similar problems as you did. Hope this helps.
回答 2
渲染示例
范例程式码
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Create random datetime object."""
# core modules
from datetime import datetime
import random
# 3rd party modules
import pandas as pd
import matplotlib.pyplot as plt
def visualize(df, column_name='start_date', color='#494949', title=''):
"""
Visualize a dataframe with a date column.
Parameters
----------
df : Pandas dataframe
column_name : str
Column to visualize
color : str
title : str
"""
plt.figure(figsize=(20, 10))
ax = (df[column_name].groupby(df[column_name].dt.hour)
.count()).plot(kind="bar", color=color)
ax.set_facecolor('#eeeeee')
ax.set_xlabel("hour of the day")
ax.set_ylabel("count")
ax.set_title(title)
plt.show()
def create_random_datetime(from_date, to_date, rand_type='uniform'):
"""
Create random date within timeframe.
Parameters
----------
from_date : datetime object
to_date : datetime object
rand_type : {'uniform'}
Examples
--------
>>> random.seed(28041990)
>>> create_random_datetime(datetime(1990, 4, 28), datetime(2000, 12, 31))
datetime.datetime(1998, 12, 13, 23, 38, 0, 121628)
>>> create_random_datetime(datetime(1990, 4, 28), datetime(2000, 12, 31))
datetime.datetime(2000, 3, 19, 19, 24, 31, 193940)
"""
delta = to_date - from_date
if rand_type == 'uniform':
rand = random.random()
else:
raise NotImplementedError('Unknown random mode \'{}\''
.format(rand_type))
return from_date + rand * delta
def create_df(n=1000):
"""Create a Pandas dataframe with datetime objects."""
from_date = datetime(1990, 4, 28)
to_date = datetime(2000, 12, 31)
sales = [create_random_datetime(from_date, to_date) for _ in range(n)]
df = pd.DataFrame({'start_date': sales})
return df
if __name__ == '__main__':
import doctest
doctest.testmod()
df = create_df()
visualize(df)
Rendered example
Example Code
#!/usr/bin/env python
# -*- coding: utf-8 -*-
"""Create random datetime object."""
# core modules
from datetime import datetime
import random
# 3rd party modules
import pandas as pd
import matplotlib.pyplot as plt
def visualize(df, column_name='start_date', color='#494949', title=''):
"""
Visualize a dataframe with a date column.
Parameters
----------
df : Pandas dataframe
column_name : str
Column to visualize
color : str
title : str
"""
plt.figure(figsize=(20, 10))
ax = (df[column_name].groupby(df[column_name].dt.hour)
.count()).plot(kind="bar", color=color)
ax.set_facecolor('#eeeeee')
ax.set_xlabel("hour of the day")
ax.set_ylabel("count")
ax.set_title(title)
plt.show()
def create_random_datetime(from_date, to_date, rand_type='uniform'):
"""
Create random date within timeframe.
Parameters
----------
from_date : datetime object
to_date : datetime object
rand_type : {'uniform'}
Examples
--------
>>> random.seed(28041990)
>>> create_random_datetime(datetime(1990, 4, 28), datetime(2000, 12, 31))
datetime.datetime(1998, 12, 13, 23, 38, 0, 121628)
>>> create_random_datetime(datetime(1990, 4, 28), datetime(2000, 12, 31))
datetime.datetime(2000, 3, 19, 19, 24, 31, 193940)
"""
delta = to_date - from_date
if rand_type == 'uniform':
rand = random.random()
else:
raise NotImplementedError('Unknown random mode \'{}\''
.format(rand_type))
return from_date + rand * delta
def create_df(n=1000):
"""Create a Pandas dataframe with datetime objects."""
from_date = datetime(1990, 4, 28)
to_date = datetime(2000, 12, 31)
sales = [create_random_datetime(from_date, to_date) for _ in range(n)]
df = pd.DataFrame({'start_date': sales})
return df
if __name__ == '__main__':
import doctest
doctest.testmod()
df = create_df()
visualize(df)
回答 3
我可以通过以下方法解决此问题:(1)使用matplotlib进行绘制,而不是直接使用数据框,以及(2)使用values
属性。参见示例:
import matplotlib.pyplot as plt
ax = plt.gca()
ax.hist(column.values)
如果我不使用values
,这是行不通的,但是我不知道为什么行得通。
I was able to work around this by (1) plotting with matplotlib instead of using the dataframe directly and (2) using the values
attribute. See example:
import matplotlib.pyplot as plt
ax = plt.gca()
ax.hist(column.values)
This doesn’t work if I don’t use values
, but I don’t know why it does work.
回答 4
当您只想拥有期望的直方图时,这是一个解决方案。这不使用groupby,而是将日期时间值转换为整数并更改绘图上的标签。可以做一些改进以将刻度标签移动到均匀位置。同样,采用这种方法,内核密度估计图(和任何其他图)也是可能的。
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
df = pd.DataFrame({"datetime": pd.to_datetime(np.random.randint(1582800000000000000, 1583500000000000000, 100, dtype=np.int64))})
fig, ax = plt.subplots()
df["datetime"].astype(np.int64).plot.hist(ax=ax)
labels = ax.get_xticks().tolist()
labels = pd.to_datetime(labels)
ax.set_xticklabels(labels, rotation=90)
plt.show()
Here is a solution for when you just want to have a histogram like you expect it. This doesn’t use groupby, but converts datetime values to integers and changes labels on the plot. Some improvement could be done to move the tick labels to even locations. Also with approach a kernel density estimation plot (and any other plot) is also possible.
import pandas as pd
import numpy as np
import matplotlib.pyplot as plt
df = pd.DataFrame({"datetime": pd.to_datetime(np.random.randint(1582800000000000000, 1583500000000000000, 100, dtype=np.int64))})
fig, ax = plt.subplots()
df["datetime"].astype(np.int64).plot.hist(ax=ax)
labels = ax.get_xticks().tolist()
labels = pd.to_datetime(labels)
ax.set_xticklabels(labels, rotation=90)
plt.show()
回答 5
我认为要解决该问题,您可以使用以下代码,它将日期类型转换为int类型:
df['date'] = df['date'].astype(int)
df['date'] = pd.to_datetime(df['date'], unit='s')
仅用于获取日期,您可以添加以下代码:
pd.DatetimeIndex(df.date).normalize()
df['date'] = pd.DatetimeIndex(df.date).normalize()
I think for solving that problem, you can use this code, it converts date type to int types:
df['date'] = df['date'].astype(int)
df['date'] = pd.to_datetime(df['date'], unit='s')
for getting date only, you can add this code:
pd.DatetimeIndex(df.date).normalize()
df['date'] = pd.DatetimeIndex(df.date).normalize()
回答 6
我也有这个问题。我想像是因为您正在使用日期,所以您想要保留时间顺序(就像我一样)。
解决方法是
import matplotlib.pyplot as plt
counts = df['date'].value_counts(sort=False)
plt.bar(counts.index,counts)
plt.show()
请,如果有人知道更好的方法,请说出来。
编辑:对于上面的吉恩,这是数据示例[我从完整数据集中随机取样,因此是平凡的直方图数据。]
print dates
type(dates),type(dates[0])
dates.hist()
plt.show()
输出:
0 2001-07-10
1 2002-05-31
2 2003-08-29
3 2006-06-21
4 2002-03-27
5 2003-07-14
6 2004-06-15
7 2002-01-17
Name: Date, dtype: object
<class 'pandas.core.series.Series'> <type 'datetime.date'>
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-38-f39e334eece0> in <module>()
2 print dates
3 print type(dates),type(dates[0])
----> 4 dates.hist()
5 plt.show()
/anaconda/lib/python2.7/site-packages/pandas/tools/plotting.pyc in hist_series(self, by, ax, grid, xlabelsize, xrot, ylabelsize, yrot, figsize, bins, **kwds)
2570 values = self.dropna().values
2571
-> 2572 ax.hist(values, bins=bins, **kwds)
2573 ax.grid(grid)
2574 axes = np.array([ax])
/anaconda/lib/python2.7/site-packages/matplotlib/axes/_axes.pyc in hist(self, x, bins, range, normed, weights, cumulative, bottom, histtype, align, orientation, rwidth, log, color, label, stacked, **kwargs)
5620 for xi in x:
5621 if len(xi) > 0:
-> 5622 xmin = min(xmin, xi.min())
5623 xmax = max(xmax, xi.max())
5624 bin_range = (xmin, xmax)
TypeError: can't compare datetime.date to float
I was just having trouble with this as well. I imagine that since you’re working with dates you want to preserve chronological ordering (like I did.)
The workaround then is
import matplotlib.pyplot as plt
counts = df['date'].value_counts(sort=False)
plt.bar(counts.index,counts)
plt.show()
Please, if anyone knows of a better way please speak up.
EDIT: for jean above, here’s a sample of the data [I randomly sampled from the full dataset, hence the trivial histogram data.]
print dates
type(dates),type(dates[0])
dates.hist()
plt.show()
Output:
0 2001-07-10
1 2002-05-31
2 2003-08-29
3 2006-06-21
4 2002-03-27
5 2003-07-14
6 2004-06-15
7 2002-01-17
Name: Date, dtype: object
<class 'pandas.core.series.Series'> <type 'datetime.date'>
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-38-f39e334eece0> in <module>()
2 print dates
3 print type(dates),type(dates[0])
----> 4 dates.hist()
5 plt.show()
/anaconda/lib/python2.7/site-packages/pandas/tools/plotting.pyc in hist_series(self, by, ax, grid, xlabelsize, xrot, ylabelsize, yrot, figsize, bins, **kwds)
2570 values = self.dropna().values
2571
-> 2572 ax.hist(values, bins=bins, **kwds)
2573 ax.grid(grid)
2574 axes = np.array([ax])
/anaconda/lib/python2.7/site-packages/matplotlib/axes/_axes.pyc in hist(self, x, bins, range, normed, weights, cumulative, bottom, histtype, align, orientation, rwidth, log, color, label, stacked, **kwargs)
5620 for xi in x:
5621 if len(xi) > 0:
-> 5622 xmin = min(xmin, xi.min())
5623 xmax = max(xmax, xi.max())
5624 bin_range = (xmin, xmax)
TypeError: can't compare datetime.date to float
回答 7
所有这些答案似乎都过于复杂,至少对于“现代”熊猫来说,这是两行。
df.set_index('date', inplace=True)
df.resample('M').size().plot.bar()
All of these answers seem overly complex, as least with ‘modern’ pandas it’s two lines.
df.set_index('date', inplace=True)
df.resample('M').size().plot.bar()
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