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获取总计熊猫列

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问题：获取总计熊猫列
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回答 1
回答 2
回答 3
回答 4

问题：获取总计熊猫列

目标

我有一个Pandas数据框，如下所示，具有多个列，并希望获取列的总数MyColumn。

数据框 –df：

print df

           X           MyColumn  Y              Z   
0          A           84        13.0           69.0   
1          B           76         77.0          127.0   
2          C           28         69.0           16.0   
3          D           28         28.0           31.0   
4          E           19         20.0           85.0   
5          F           84        193.0           70.0

我的尝试：

我试图使用groupby和获得列的总和.sum()：

Total = df.groupby['MyColumn'].sum()

print Total

这将导致以下错误：

TypeError: 'instancemethod' object has no attribute '__getitem__'

预期Yield

我期望输出如下：

319

或者，我想df用一个包含总数的新row标题进行编辑TOTAL：

           X           MyColumn  Y              Z   
0          A           84        13.0           69.0   
1          B           76         77.0          127.0   
2          C           28         69.0           16.0   
3          D           28         28.0           31.0   
4          E           19         20.0           85.0   
5          F           84        193.0           70.0   
TOTAL                  319
点击查看英文原文

Target

I have a Pandas data frame, as shown below, with multiple columns and would like to get the total of column, MyColumn.

Data Frame – df:

print df

           X           MyColumn  Y              Z   
0          A           84        13.0           69.0   
1          B           76         77.0          127.0   
2          C           28         69.0           16.0   
3          D           28         28.0           31.0   
4          E           19         20.0           85.0   
5          F           84        193.0           70.0

My attempt:

I have attempted to get the sum of the column using groupby and .sum():

Total = df.groupby['MyColumn'].sum()

print Total

This causes the following error:

TypeError: 'instancemethod' object has no attribute '__getitem__'

Expected Output

I’d have expected the output to be as followed:

319

Or alternatively, I would like df to be edited with a new row entitled TOTAL containing the total: 

           X           MyColumn  Y              Z   
0          A           84        13.0           69.0   
1          B           76         77.0          127.0   
2          C           28         69.0           16.0   
3          D           28         28.0           31.0   
4          E           19         20.0           85.0   
5          F           84        193.0           70.0   
TOTAL                  319

回答 0

您应该使用sum：

Total = df['MyColumn'].sum()
print (Total)
319

然后loc与一起使用Series，在这种情况下，索引应设置为与您需要求和的特定列相同：

df.loc['Total'] = pd.Series(df['MyColumn'].sum(), index = ['MyColumn'])
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN

因为如果传递标量，则将填充所有行的值：

df.loc['Total'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A        84   13.0   69.0
1        B        76   77.0  127.0
2        C        28   69.0   16.0
3        D        28   28.0   31.0
4        E        19   20.0   85.0
5        F        84  193.0   70.0
Total  319       319  319.0  319.0

另有两个解决方案at，ix请参见下面的应用程序：

df.at['Total', 'MyColumn'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN
df.ix['Total', 'MyColumn'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN

注意：自Pandas v0.20起，ix已弃用。使用loc或iloc代替。

点击查看英文原文

You should use sum:

Total = df['MyColumn'].sum()
print (Total)
319

Then you use loc with Series, in that case the index should be set as the same as the specific column you need to sum:

df.loc['Total'] = pd.Series(df['MyColumn'].sum(), index = ['MyColumn'])
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN

because if you pass scalar, the values of all rows will be filled:

df.loc['Total'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A        84   13.0   69.0
1        B        76   77.0  127.0
2        C        28   69.0   16.0
3        D        28   28.0   31.0
4        E        19   20.0   85.0
5        F        84  193.0   70.0
Total  319       319  319.0  319.0

Two other solutions are with at, and ix see the applications below:

df.at['Total', 'MyColumn'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN

df.ix['Total', 'MyColumn'] = df['MyColumn'].sum()
print (df)
         X  MyColumn      Y      Z
0        A      84.0   13.0   69.0
1        B      76.0   77.0  127.0
2        C      28.0   69.0   16.0
3        D      28.0   28.0   31.0
4        E      19.0   20.0   85.0
5        F      84.0  193.0   70.0
Total  NaN     319.0    NaN    NaN

Note: Since Pandas v0.20, ix has been deprecated. Use loc or iloc instead.

回答 1

您可以在此处使用的另一种选择：

df.loc["Total", "MyColumn"] = df.MyColumn.sum()

#         X  MyColumn      Y       Z
#0        A     84.0    13.0    69.0
#1        B     76.0    77.0   127.0
#2        C     28.0    69.0    16.0
#3        D     28.0    28.0    31.0
#4        E     19.0    20.0    85.0
#5        F     84.0   193.0    70.0
#Total  NaN    319.0     NaN     NaN

您也可以使用append()方法：

df.append(pd.DataFrame(df.MyColumn.sum(), index = ["Total"], columns=["MyColumn"]))

更新：

如果需要为所有数字列追加总和，则可以执行以下操作之一：

用于append以功能性方式执行此操作（不更改原始数据帧）：

# select numeric columns and calculate the sums
sums = df.select_dtypes(pd.np.number).sum().rename('total')

# append sums to the data frame
df.append(sums)
#         X  MyColumn      Y      Z
#0        A      84.0   13.0   69.0
#1        B      76.0   77.0  127.0
#2        C      28.0   69.0   16.0
#3        D      28.0   28.0   31.0
#4        E      19.0   20.0   85.0
#5        F      84.0  193.0   70.0
#total  NaN     319.0  400.0  398.0

用于loc在适当位置更改数据框：

df.loc['total'] = df.select_dtypes(pd.np.number).sum()
df
#         X  MyColumn      Y      Z
#0        A      84.0   13.0   69.0
#1        B      76.0   77.0  127.0
#2        C      28.0   69.0   16.0
#3        D      28.0   28.0   31.0
#4        E      19.0   20.0   85.0
#5        F      84.0  193.0   70.0
#total  NaN     638.0  800.0  796.0
点击查看英文原文

Another option you can go with here:

df.loc["Total", "MyColumn"] = df.MyColumn.sum()

#         X  MyColumn      Y       Z
#0        A     84.0    13.0    69.0
#1        B     76.0    77.0   127.0
#2        C     28.0    69.0    16.0
#3        D     28.0    28.0    31.0
#4        E     19.0    20.0    85.0
#5        F     84.0   193.0    70.0
#Total  NaN    319.0     NaN     NaN

You can also use append() method:

df.append(pd.DataFrame(df.MyColumn.sum(), index = ["Total"], columns=["MyColumn"]))

Update:

In case you need to append sum for all numeric columns, you can do one of the followings:

Use append to do this in a functional manner (doesn’t change the original data frame):

# select numeric columns and calculate the sums
sums = df.select_dtypes(pd.np.number).sum().rename('total')

# append sums to the data frame
df.append(sums)
#         X  MyColumn      Y      Z
#0        A      84.0   13.0   69.0
#1        B      76.0   77.0  127.0
#2        C      28.0   69.0   16.0
#3        D      28.0   28.0   31.0
#4        E      19.0   20.0   85.0
#5        F      84.0  193.0   70.0
#total  NaN     319.0  400.0  398.0

Use loc to mutate data frame in place:

df.loc['total'] = df.select_dtypes(pd.np.number).sum()
df
#         X  MyColumn      Y      Z
#0        A      84.0   13.0   69.0
#1        B      76.0   77.0  127.0
#2        C      28.0   69.0   16.0
#3        D      28.0   28.0   31.0
#4        E      19.0   20.0   85.0
#5        F      84.0  193.0   70.0
#total  NaN     638.0  800.0  796.0

回答 2

与获取数据框的长度类似len(df)，以下内容适用于熊猫和大火：

Total = sum(df['MyColumn'])

或者

Total = sum(df.MyColumn)
print Total
点击查看英文原文

Similar to getting the length of a dataframe, len(df), the following worked for pandas and blaze:

Total = sum(df['MyColumn'])

or alternatively

Total = sum(df.MyColumn)
print Total

回答 3

列求和有两种方法

数据集= pd.read_csv（“ data.csv”）

1：总和（dataset.Column_name）

2：数据集[‘Column_Name’]。sum（）

如果有任何问题，请纠正我。

点击查看英文原文

There are two ways to sum of a column

dataset = pd.read_csv(“data.csv”)

1: sum(dataset.Column_name)

2: dataset[‘Column_Name’].sum()

If there is any issue in this the please correct me..

回答 4

作为其他选择，您可以执行以下操作 

Group   Valuation   amount
    0   BKB Tube    156
    1   BKB Tube    143
    2   BKB Tube    67
    3   BAC Tube    176
    4   BAC Tube    39
    5   JDK Tube    75
    6   JDK Tube    35
    7   JDK Tube    155
    8   ETH Tube    38
    9   ETH Tube    56

下面的脚本，您可以用于上面的数据

import pandas as pd    
data = pd.read_csv("daata1.csv")
bytreatment = data.groupby('Group')
bytreatment['amount'].sum()
点击查看英文原文

As other option, you can do something like below 

Group   Valuation   amount
    0   BKB Tube    156
    1   BKB Tube    143
    2   BKB Tube    67
    3   BAC Tube    176
    4   BAC Tube    39
    5   JDK Tube    75
    6   JDK Tube    35
    7   JDK Tube    155
    8   ETH Tube    38
    9   ETH Tube    56

Below script, you can use for above data

import pandas as pd    
data = pd.read_csv("daata1.csv")
bytreatment = data.groupby('Group')
bytreatment['amount'].sum()