问题:遍历JSON对象
我正在尝试遍历JSON对象以导入数据,即标题和链接。我似乎无法掌握过去的内容:
。
JSON:
[
{
"title": "Baby (Feat. Ludacris) - Justin Bieber",
"description": "Baby (Feat. Ludacris) by Justin Bieber on Grooveshark",
"link": "http://listen.grooveshark.com/s/Baby+Feat+Ludacris+/2Bqvdq",
"pubDate": "Wed, 28 Apr 2010 02:37:53 -0400",
"pubTime": 1272436673,
"TinyLink": "http://tinysong.com/d3wI",
"SongID": "24447862",
"SongName": "Baby (Feat. Ludacris)",
"ArtistID": "1118876",
"ArtistName": "Justin Bieber",
"AlbumID": "4104002",
"AlbumName": "My World (Part II);\nhttp://tinysong.com/gQsw",
"LongLink": "11578982",
"GroovesharkLink": "11578982",
"Link": "http://tinysong.com/d3wI"
},
{
"title": "Feel Good Inc - Gorillaz",
"description": "Feel Good Inc by Gorillaz on Grooveshark",
"link": "http://listen.grooveshark.com/s/Feel+Good+Inc/1UksmI",
"pubDate": "Wed, 28 Apr 2010 02:25:30 -0400",
"pubTime": 1272435930
}
]
我尝试使用字典:
def getLastSong(user,limit):
base_url = 'http://gsuser.com/lastSong/'
user_url = base_url + str(user) + '/' + str(limit) + "/"
raw = urllib.urlopen(user_url)
json_raw= raw.readlines()
json_object = json.loads(json_raw[0])
#filtering and making it look good.
gsongs = []
print json_object
for song in json_object[0]:
print song
此代码仅在之前打印信息:
。(忽略贾斯汀·比伯的曲目:)
回答 0
您加载JSON数据有些脆弱。代替:
json_raw= raw.readlines()
json_object = json.loads(json_raw[0])
您实际上应该这样做:
json_object = json.load(raw)
您不应该将“ JSON对象”视为什么。您所拥有的是清单。该列表包含两个字典。字典包含各种键/值对,所有字符串。当您这样做时json_object[0]
,您将要求列表中的第一个字典。当您使用进行迭代时for song in json_object[0]:
,您将遍历字典的键。因为那是您遍历dict时得到的。如果要访问与该字典中的键关联的值,则可以使用json_object[0][song]
。
这些都不是特定于JSON的。这只是基本的Python类型,其基本操作如本教程所述。
回答 1
我相信您可能是说:
from __future__ import print_function
for song in json_object:
# now song is a dictionary
for attribute, value in song.items():
print(attribute, value) # example usage
注意:您可以在Python 2中使用if song.iteritems
代替song.items
。
回答 2
这个问题已经存在很长时间了,但是我想贡献我通常如何遍历JSON对象的方式。在下面的示例中,我显示了一个包含JSON的硬编码字符串,但是JSON字符串也可以很容易地来自Web服务或文件。
import json
def main():
# create a simple JSON array
jsonString = '{"key1":"value1","key2":"value2","key3":"value3"}'
# change the JSON string into a JSON object
jsonObject = json.loads(jsonString)
# print the keys and values
for key in jsonObject:
value = jsonObject[key]
print("The key and value are ({}) = ({})".format(key, value))
pass
if __name__ == '__main__':
main()
回答 3
反序列化JSON之后,您将拥有一个python对象。使用常规对象方法。
在这种情况下,您有一个由字典组成的列表:
json_object[0].items()
json_object[0]["title"]
等等
回答 4
我会这样解决这个问题
import json
import urllib2
def last_song(user, limit):
# Assembling strings with "foo" + str(bar) + "baz" + ... generally isn't
# as nice as using real string formatting. It can seem simpler at first,
# but leaves you less happy in the long run.
url = 'http://gsuser.com/lastSong/%s/%d/' % (user, limit)
# urllib.urlopen is deprecated in favour of urllib2.urlopen
site = urllib2.urlopen(url)
# The json module has a function load for loading from file-like objects,
# like the one you get from `urllib2.urlopen`. You don't need to turn
# your data into a string and use loads and you definitely don't need to
# use readlines or readline (there is seldom if ever reason to use a
# file-like object's readline(s) methods.)
songs = json.load(site)
# I don't know why "lastSong" stuff returns something like this, but
# your json thing was a JSON array of two JSON objects. This will
# deserialise as a list of two dicts, with each item representing
# each of those two songs.
#
# Since each of the songs is represented by a dict, it will iterate
# over its keys (like any other Python dict).
baby, feel_good = songs
# Rather than printing in a function, it's usually better to
# return the string then let the caller do whatever with it.
# You said you wanted to make the output pretty but you didn't
# mention *how*, so here's an example of a prettyish representation
# from the song information given.
return "%(SongName)s by %(ArtistName)s - listen at %(link)s" % baby
回答 5
通过JSON进行迭代,您可以使用以下代码:
json_object = json.loads(json_file)
for element in json_object:
for value in json_object['Name_OF_YOUR_KEY/ELEMENT']:
print(json_object['Name_OF_YOUR_KEY/ELEMENT']['INDEX_OF_VALUE']['VALUE'])
回答 6
对于Python 3,您必须解码从Web服务器获取的数据。例如,我将数据解码为utf8,然后对其进行处理:
# example of json data object group with two values of key id
jsonstufftest = '{'group':{'id':'2','id':'3'}}
# always set your headers
headers = {'User-Agent': 'Moz & Woz'}
# the url you are trying to load and get json from
url = 'http://www.cooljson.com/cooljson.json'
# in python 3 you can build the request using request.Request
req = urllib.request.Request(url,None,headers)
# try to connect or fail gracefully
try:
response = urllib.request.urlopen(req) # new python 3 code -jc
except:
exit('could not load page, check connection')
# read the response and DECODE
html=response.read().decode('utf8') # new python3 code
# now convert the decoded string into real JSON
loadedjson = json.loads(html)
# print to make sure it worked
print (loadedjson) # works like a charm
# iterate through each key value
for testdata in loadedjson['group']:
print (accesscount['id']) # should print 2 then 3 if using test json
如果不解码,Python 3中将得到字节与字符串错误。
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