问题:部分字符串格式
是否可以使用类似于字符串模板safe_substitute()
功能的高级字符串格式化方法来进行部分字符串格式化?
例如:
s = '{foo} {bar}'
s.format(foo='FOO') #Problem: raises KeyError 'bar'
回答 0
您可以通过覆盖映射将其欺骗为部分格式:
import string
class FormatDict(dict):
def __missing__(self, key):
return "{" + key + "}"
s = '{foo} {bar}'
formatter = string.Formatter()
mapping = FormatDict(foo='FOO')
print(formatter.vformat(s, (), mapping))
印刷
FOO {bar}
当然,此基本实现仅适用于基本情况。
回答 1
如果您知道要格式化的顺序:
s = '{foo} {{bar}}'
像这样使用它:
ss = s.format(foo='FOO')
print ss
>>> 'FOO {bar}'
print ss.format(bar='BAR')
>>> 'FOO BAR'
您不能指定foo
,并bar
在同一时间-你必须按顺序做。
回答 2
您可以使用简短易读的partial
函数functools
,并描述编码器的意图:
from functools import partial
s = partial("{foo} {bar}".format, foo="FOO")
print s(bar="BAR")
# FOO BAR
回答 3
这种局限性.format()
-无法进行部分替换-使我烦恼。
在评估了编写一个自定义Formatter
类(如此处许多答案所述)之后,甚至考虑使用第三方包(例如lazy_format),我发现了一个更简单的内置解决方案:模板字符串
它提供了相似的功能,但也提供了部分替代彻底的safe_substitute()
方法。模板字符串需要有一个$
前缀(感觉有些奇怪-但我认为总体解决方案更好)。
import string
template = string.Template('${x} ${y}')
try:
template.substitute({'x':1}) # raises KeyError
except KeyError:
pass
# but the following raises no error
partial_str = template.safe_substitute({'x':1}) # no error
# partial_str now contains a string with partial substitution
partial_template = string.Template(partial_str)
substituted_str = partial_template.safe_substitute({'y':2}) # no error
print substituted_str # prints '12'
基于此形成了一个便捷包装器:
class StringTemplate(object):
def __init__(self, template):
self.template = string.Template(template)
self.partial_substituted_str = None
def __repr__(self):
return self.template.safe_substitute()
def format(self, *args, **kws):
self.partial_substituted_str = self.template.safe_substitute(*args, **kws)
self.template = string.Template(self.partial_substituted_str)
return self.__repr__()
>>> s = StringTemplate('${x}${y}')
>>> s
'${x}${y}'
>>> s.format(x=1)
'1${y}'
>>> s.format({'y':2})
'12'
>>> print s
12
同样,基于Sven的答案的包装器使用默认的字符串格式:
class StringTemplate(object):
class FormatDict(dict):
def __missing__(self, key):
return "{" + key + "}"
def __init__(self, template):
self.substituted_str = template
self.formatter = string.Formatter()
def __repr__(self):
return self.substituted_str
def format(self, *args, **kwargs):
mapping = StringTemplate.FormatDict(*args, **kwargs)
self.substituted_str = self.formatter.vformat(self.substituted_str, (), mapping)
回答 4
不知道这是否可以作为一种快速的解决方法,但是如何解决
s = '{foo} {bar}'
s.format(foo='FOO', bar='{bar}')
?:)
回答 5
如果您定义自己Formatter
的get_value
方法,则可以使用该方法将未定义的字段名称映射到所需的任何内容:
http://docs.python.org/library/string.html#string.Formatter.get_value
例如,您可以映射bar
到"{bar}"
如果bar
不在kwargs中。
但是,这需要使用format()
Formatter对象的format()
方法,而不是字符串的方法。
回答 6
>>> 'fd:{uid}:{{topic_id}}'.format(uid=123)
'fd:123:{topic_id}'
试试看
回答 7
感谢Amber的评论,我想到了这一点:
import string
try:
# Python 3
from _string import formatter_field_name_split
except ImportError:
formatter_field_name_split = str._formatter_field_name_split
class PartialFormatter(string.Formatter):
def get_field(self, field_name, args, kwargs):
try:
val = super(PartialFormatter, self).get_field(field_name, args, kwargs)
except (IndexError, KeyError, AttributeError):
first, _ = formatter_field_name_split(field_name)
val = '{' + field_name + '}', first
return val
回答 8
对我来说这已经足够了:
>>> ss = 'dfassf {} dfasfae efaef {} fds'
>>> nn = ss.format('f1', '{}')
>>> nn
'dfassf f1 dfasfae efaef {} fds'
>>> n2 = nn.format('whoa')
>>> n2
'dfassf f1 dfasfae efaef whoa fds'
回答 9
我发现的所有解决方案似乎在使用更高级的规格或转换选项方面均存在问题。@SvenMarnach的FormatPlaceholder非常聪明,但是它不能与强制(例如{a!s:>2s}
)一起正常使用,因为它调用了__str__
方法(在此示例中),而不是调用该方法,__format__
并且您丢失了任何其他格式。
这是我最终得到的结果,以及其中的一些关键功能:
sformat('The {} is {}', 'answer')
'The answer is {}'
sformat('The answer to {question!r} is {answer:0.2f}', answer=42)
'The answer to {question!r} is 42.00'
sformat('The {} to {} is {:0.{p}f}', 'answer', 'everything', p=4)
'The answer to everything is {:0.4f}'
- 提供类似的界面
str.format
(不只是映射) - 支持更复杂的格式选项:
- 强迫
{k!s}
{!r}
- 套料
{k:>{size}}
- getattr
{k.foo}
- getitem
{k[0]}
- 强制+格式
{k!s:>{size}}
- 强迫
import string
class SparseFormatter(string.Formatter):
"""
A modified string formatter that handles a sparse set of format
args/kwargs.
"""
# re-implemented this method for python2/3 compatibility
def vformat(self, format_string, args, kwargs):
used_args = set()
result, _ = self._vformat(format_string, args, kwargs, used_args, 2)
self.check_unused_args(used_args, args, kwargs)
return result
def _vformat(self, format_string, args, kwargs, used_args, recursion_depth,
auto_arg_index=0):
if recursion_depth < 0:
raise ValueError('Max string recursion exceeded')
result = []
for literal_text, field_name, format_spec, conversion in \
self.parse(format_string):
orig_field_name = field_name
# output the literal text
if literal_text:
result.append(literal_text)
# if there's a field, output it
if field_name is not None:
# this is some markup, find the object and do
# the formatting
# handle arg indexing when empty field_names are given.
if field_name == '':
if auto_arg_index is False:
raise ValueError('cannot switch from manual field '
'specification to automatic field '
'numbering')
field_name = str(auto_arg_index)
auto_arg_index += 1
elif field_name.isdigit():
if auto_arg_index:
raise ValueError('cannot switch from manual field '
'specification to automatic field '
'numbering')
# disable auto arg incrementing, if it gets
# used later on, then an exception will be raised
auto_arg_index = False
# given the field_name, find the object it references
# and the argument it came from
try:
obj, arg_used = self.get_field(field_name, args, kwargs)
except (IndexError, KeyError):
# catch issues with both arg indexing and kwarg key errors
obj = orig_field_name
if conversion:
obj += '!{}'.format(conversion)
if format_spec:
format_spec, auto_arg_index = self._vformat(
format_spec, args, kwargs, used_args,
recursion_depth, auto_arg_index=auto_arg_index)
obj += ':{}'.format(format_spec)
result.append('{' + obj + '}')
else:
used_args.add(arg_used)
# do any conversion on the resulting object
obj = self.convert_field(obj, conversion)
# expand the format spec, if needed
format_spec, auto_arg_index = self._vformat(
format_spec, args, kwargs,
used_args, recursion_depth-1,
auto_arg_index=auto_arg_index)
# format the object and append to the result
result.append(self.format_field(obj, format_spec))
return ''.join(result), auto_arg_index
def sformat(s, *args, **kwargs):
# type: (str, *Any, **Any) -> str
"""
Sparse format a string.
Parameters
----------
s : str
args : *Any
kwargs : **Any
Examples
--------
>>> sformat('The {} is {}', 'answer')
'The answer is {}'
>>> sformat('The answer to {question!r} is {answer:0.2f}', answer=42)
'The answer to {question!r} is 42.00'
>>> sformat('The {} to {} is {:0.{p}f}', 'answer', 'everything', p=4)
'The answer to everything is {:0.4f}'
Returns
-------
str
"""
return SparseFormatter().format(s, *args, **kwargs)
在编写了一些有关如何使此方法运行的测试之后,我发现了各种实现的问题。如果有人发现他们有见识,它们就会在下面。
import pytest
def test_auto_indexing():
# test basic arg auto-indexing
assert sformat('{}{}', 4, 2) == '42'
assert sformat('{}{} {}', 4, 2) == '42 {}'
def test_manual_indexing():
# test basic arg indexing
assert sformat('{0}{1} is not {1} or {0}', 4, 2) == '42 is not 2 or 4'
assert sformat('{0}{1} is {3} {1} or {0}', 4, 2) == '42 is {3} 2 or 4'
def test_mixing_manualauto_fails():
# test mixing manual and auto args raises
with pytest.raises(ValueError):
assert sformat('{!r} is {0}{1}', 4, 2)
def test_kwargs():
# test basic kwarg
assert sformat('{base}{n}', base=4, n=2) == '42'
assert sformat('{base}{n}', base=4, n=2, extra='foo') == '42'
assert sformat('{base}{n} {key}', base=4, n=2) == '42 {key}'
def test_args_and_kwargs():
# test mixing args/kwargs with leftovers
assert sformat('{}{k} {v}', 4, k=2) == '42 {v}'
# test mixing with leftovers
r = sformat('{}{} is the {k} to {!r}', 4, 2, k='answer')
assert r == '42 is the answer to {!r}'
def test_coercion():
# test coercion is preserved for skipped elements
assert sformat('{!r} {k!r}', '42') == "'42' {k!r}"
def test_nesting():
# test nesting works with or with out parent keys
assert sformat('{k:>{size}}', k=42, size=3) == ' 42'
assert sformat('{k:>{size}}', size=3) == '{k:>3}'
@pytest.mark.parametrize(
('s', 'expected'),
[
('{a} {b}', '1 2.0'),
('{z} {y}', '{z} {y}'),
('{a} {a:2d} {a:04d} {y:2d} {z:04d}', '1 1 0001 {y:2d} {z:04d}'),
('{a!s} {z!s} {d!r}', '1 {z!s} {\'k\': \'v\'}'),
('{a!s:>2s} {z!s:>2s}', ' 1 {z!s:>2s}'),
('{a!s:>{a}s} {z!s:>{z}s}', '1 {z!s:>{z}s}'),
('{a.imag} {z.y}', '0 {z.y}'),
('{e[0]:03d} {z[0]:03d}', '042 {z[0]:03d}'),
],
ids=[
'normal',
'none',
'formatting',
'coercion',
'formatting+coercion',
'nesting',
'getattr',
'getitem',
]
)
def test_sformat(s, expected):
# test a bunch of random stuff
data = dict(
a=1,
b=2.0,
c='3',
d={'k': 'v'},
e=[42],
)
assert expected == sformat(s, **data)
回答 10
我的建议如下(使用Python3.6测试):
class Lazymap(object):
def __init__(self, **kwargs):
self.dict = kwargs
def __getitem__(self, key):
return self.dict.get(key, "".join(["{", key, "}"]))
s = '{foo} {bar}'
s.format_map(Lazymap(bar="FOO"))
# >>> '{foo} FOO'
s.format_map(Lazymap(bar="BAR"))
# >>> '{foo} BAR'
s.format_map(Lazymap(bar="BAR", foo="FOO", baz="BAZ"))
# >>> 'FOO BAR'
更新:此处显示了
更优雅的方式(子类化dict
和重载__missing__(self, key)
):https : //stackoverflow.com/a/17215533/333403
回答 11
假设在字符串完全填写之前不使用它,您可以执行类似此类的操作:
class IncrementalFormatting:
def __init__(self, string):
self._args = []
self._kwargs = {}
self._string = string
def add(self, *args, **kwargs):
self._args.extend(args)
self._kwargs.update(kwargs)
def get(self):
return self._string.format(*self._args, **self._kwargs)
例:
template = '#{a}:{}/{}?{c}'
message = IncrementalFormatting(template)
message.add('abc')
message.add('xyz', a=24)
message.add(c='lmno')
assert message.get() == '#24:abc/xyz?lmno'
回答 12
还有另一种方法可以实现这一目标,即使用format
和%
替换变量。例如:
>>> s = '{foo} %(bar)s'
>>> s = s.format(foo='my_foo')
>>> s
'my_foo %(bar)s'
>>> s % {'bar': 'my_bar'}
'my_foo my_bar'
回答 13
对我来说,一个非常丑陋但最简单的解决方案是:
tmpl = '{foo}, {bar}'
tmpl.replace('{bar}', 'BAR')
Out[3]: '{foo}, BAR'
这样,您仍然可以tmpl
用作常规模板并仅在需要时执行部分格式化。我觉得这个问题太微不足道了,无法使用像Mohan Raj’s这样的过分解决方案。
回答 14
测试从最有前途的解决方案后,在这里和那里,我认识到,没有一个是满足下列要求:
- 严格遵守
str.format_map()
模板可识别的语法; - 能够保留复杂的格式,即完全支持Format Mini-Language
因此,我编写了自己的解决方案,该解决方案可以满足上述要求。(编辑:现在@SvenMarnach的版本-如这个答案所报道-似乎处理了我需要的一些特殊情况)。
基本上,我最终解析了模板字符串,找到了匹配的嵌套{.*?}
组(使用find_all()
辅助函数),并逐步并直接使用格式化的字符串,str.format_map()
同时捕捉了任何潜在的可能性KeyError
。
def find_all(
text,
pattern,
overlap=False):
"""
Find all occurrencies of the pattern in the text.
Args:
text (str|bytes|bytearray): The input text.
pattern (str|bytes|bytearray): The pattern to find.
overlap (bool): Detect overlapping patterns.
Yields:
position (int): The position of the next finding.
"""
len_text = len(text)
offset = 1 if overlap else (len(pattern) or 1)
i = 0
while i < len_text:
i = text.find(pattern, i)
if i >= 0:
yield i
i += offset
else:
break
def matching_delimiters(
text,
l_delim,
r_delim,
including=True):
"""
Find matching delimiters in a sequence.
The delimiters are matched according to nesting level.
Args:
text (str|bytes|bytearray): The input text.
l_delim (str|bytes|bytearray): The left delimiter.
r_delim (str|bytes|bytearray): The right delimiter.
including (bool): Include delimeters.
yields:
result (tuple[int]): The matching delimiters.
"""
l_offset = len(l_delim) if including else 0
r_offset = len(r_delim) if including else 0
stack = []
l_tokens = set(find_all(text, l_delim))
r_tokens = set(find_all(text, r_delim))
positions = l_tokens.union(r_tokens)
for pos in sorted(positions):
if pos in l_tokens:
stack.append(pos + 1)
elif pos in r_tokens:
if len(stack) > 0:
prev = stack.pop()
yield (prev - l_offset, pos + r_offset, len(stack))
else:
raise ValueError(
'Found `{}` unmatched right token(s) `{}` (position: {}).'
.format(len(r_tokens) - len(l_tokens), r_delim, pos))
if len(stack) > 0:
raise ValueError(
'Found `{}` unmatched left token(s) `{}` (position: {}).'
.format(
len(l_tokens) - len(r_tokens), l_delim, stack.pop() - 1))
def safe_format_map(
text,
source):
"""
Perform safe string formatting from a mapping source.
If a value is missing from source, this is simply ignored, and no
`KeyError` is raised.
Args:
text (str): Text to format.
source (Mapping|None): The mapping to use as source.
If None, uses caller's `vars()`.
Returns:
result (str): The formatted text.
"""
stack = []
for i, j, depth in matching_delimiters(text, '{', '}'):
if depth == 0:
try:
replacing = text[i:j].format_map(source)
except KeyError:
pass
else:
stack.append((i, j, replacing))
result = ''
i, j = len(text), 0
while len(stack) > 0:
last_i = i
i, j, replacing = stack.pop()
result = replacing + text[j:last_i] + result
if i > 0:
result = text[0:i] + result
return result
(此代码也可在FlyingCircus中使用 -免责声明:我是它的主要作者。)
该代码的用法是:
print(safe_format_map('{a} {b} {c}', dict(a=-A-)))
# -A- {b} {c}
让我们比较这对我最喜欢的溶液(@SvenMarnach谁亲切地分享他的代码在这里和那里):
import string
class FormatPlaceholder:
def __init__(self, key):
self.key = key
def __format__(self, spec):
result = self.key
if spec:
result += ":" + spec
return "{" + result + "}"
def __getitem__(self, index):
self.key = "{}[{}]".format(self.key, index)
return self
def __getattr__(self, attr):
self.key = "{}.{}".format(self.key, attr)
return self
class FormatDict(dict):
def __missing__(self, key):
return FormatPlaceholder(key)
def safe_format_alt(text, source):
formatter = string.Formatter()
return formatter.vformat(text, (), FormatDict(source))
以下是一些测试:
test_texts = (
'{b} {f}', # simple nothing useful in source
'{a} {b}', # simple
'{a} {b} {c:5d}', # formatting
'{a} {b} {c!s}', # coercion
'{a} {b} {c!s:>{a}s}', # formatting and coercion
'{a} {b} {c:0{a}d}', # nesting
'{a} {b} {d[x]}', # dicts (existing in source)
'{a} {b} {e.index}', # class (existing in source)
'{a} {b} {f[g]}', # dict (not existing in source)
'{a} {b} {f.values}', # class (not existing in source)
)
source = dict(a=4, c=101, d=dict(x='FOO'), e=[])
以及使其运行的代码:
funcs = safe_format_map, safe_format_alt
n = 18
for text in test_texts:
full_source = {**dict(b='---', f=dict(g='Oh yes!')), **source}
print('{:>{n}s} : OK : '.format('str.format_map', n=n) + text.format_map(full_source))
for func in funcs:
try:
print(f'{func.__name__:>{n}s} : OK : ' + func(text, source))
except:
print(f'{func.__name__:>{n}s} : FAILED : {text}')
导致:
str.format_map : OK : --- {'g': 'Oh yes!'}
safe_format_map : OK : {b} {f}
safe_format_alt : OK : {b} {f}
str.format_map : OK : 4 ---
safe_format_map : OK : 4 {b}
safe_format_alt : OK : 4 {b}
str.format_map : OK : 4 --- 101
safe_format_map : OK : 4 {b} 101
safe_format_alt : OK : 4 {b} 101
str.format_map : OK : 4 --- 101
safe_format_map : OK : 4 {b} 101
safe_format_alt : OK : 4 {b} 101
str.format_map : OK : 4 --- 101
safe_format_map : OK : 4 {b} 101
safe_format_alt : OK : 4 {b} 101
str.format_map : OK : 4 --- 0101
safe_format_map : OK : 4 {b} 0101
safe_format_alt : OK : 4 {b} 0101
str.format_map : OK : 4 --- FOO
safe_format_map : OK : 4 {b} FOO
safe_format_alt : OK : 4 {b} FOO
str.format_map : OK : 4 --- <built-in method index of list object at 0x7f7a485666c8>
safe_format_map : OK : 4 {b} <built-in method index of list object at 0x7f7a485666c8>
safe_format_alt : OK : 4 {b} <built-in method index of list object at 0x7f7a485666c8>
str.format_map : OK : 4 --- Oh yes!
safe_format_map : OK : 4 {b} {f[g]}
safe_format_alt : OK : 4 {b} {f[g]}
str.format_map : OK : 4 --- <built-in method values of dict object at 0x7f7a485da090>
safe_format_map : OK : 4 {b} {f.values}
safe_format_alt : OK : 4 {b} {f.values}
如您所见,更新的版本现在似乎可以很好地处理早期版本曾经失败的情况。
在时间上,它们在大约范围内。彼此之间的50%取决于实际text
格式化的格式(可能还有实际的格式source
),但safe_format_map()
在我执行的大多数测试中似乎都具有优势(当然,无论它们是什么意思):
for text in test_texts:
print(f' {text}')
%timeit safe_format(text * 1000, source)
%timeit safe_format_alt(text * 1000, source)
{b} {f}
3.93 ms ± 153 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
6.35 ms ± 51.9 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b}
4.37 ms ± 57.1 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
5.2 ms ± 159 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {c:5d}
7.15 ms ± 91.9 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
7.76 ms ± 69.5 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {c!s}
7.04 ms ± 138 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
7.56 ms ± 161 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {c!s:>{a}s}
8.91 ms ± 113 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
10.5 ms ± 181 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {c:0{a}d}
8.84 ms ± 147 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
10.2 ms ± 202 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {d[x]}
7.01 ms ± 197 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
7.35 ms ± 106 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {e.index}
11 ms ± 68.8 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
8.78 ms ± 405 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {f[g]}
6.55 ms ± 88.6 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
9.12 ms ± 159 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
{a} {b} {f.values}
6.61 ms ± 55.9 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
9.92 ms ± 98.8 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
回答 15
如果您想解开字典以将参数传递给format
,如本相关问题所示,则可以使用以下方法。
首先假设字符串s
与此问题相同:
s = '{foo} {bar}'
值由以下字典给出:
replacements = {'foo': 'FOO'}
显然这是行不通的:
s.format(**replacements)
#---------------------------------------------------------------------------
#KeyError Traceback (most recent call last)
#<ipython-input-29-ef5e51de79bf> in <module>()
#----> 1 s.format(**replacements)
#
#KeyError: 'bar'
但是,您可以首先从中获取set
所有命名参数,s
然后创建一个字典,将参数映射到用大括号括起来的自身:
from string import Formatter
args = {x[1]:'{'+x[1]+'}' for x in Formatter().parse(s)}
print(args)
#{'foo': '{foo}', 'bar': '{bar}'}
现在,使用args
字典来填写中缺少的键replacements
。对于python 3.5+,您可以在单个表达式中执行此操作:
new_s = s.format(**{**args, **replacements}}
print(new_s)
#'FOO {bar}'
对于旧版本的python,您可以调用update
:
args.update(replacements)
print(s.format(**args))
#'FOO {bar}'
回答 16
我喜欢@ sven-marnach的答案。我的答案只是它的扩展版本。它允许非关键字格式,并忽略多余的键。以下是用法示例(函数名称是对python 3.6 f字符串格式的引用):
# partial string substitution by keyword
>>> f('{foo} {bar}', foo="FOO")
'FOO {bar}'
# partial string substitution by argument
>>> f('{} {bar}', 1)
'1 {bar}'
>>> f('{foo} {}', 1)
'{foo} 1'
# partial string substitution with arguments and keyword mixed
>>> f('{foo} {} {bar} {}', '|', bar='BAR')
'{foo} | BAR {}'
# partial string substitution with extra keyword
>>> f('{foo} {bar}', foo="FOO", bro="BRO")
'FOO {bar}'
# you can simply 'pour out' your dictionary to format function
>>> kwargs = {'foo': 'FOO', 'bro': 'BRO'}
>>> f('{foo} {bar}', **kwargs)
'FOO {bar}'
这是我的代码:
from string import Formatter
class FormatTuple(tuple):
def __getitem__(self, key):
if key + 1 > len(self):
return "{}"
return tuple.__getitem__(self, key)
class FormatDict(dict):
def __missing__(self, key):
return "{" + key + "}"
def f(string, *args, **kwargs):
"""
String safe substitute format method.
If you pass extra keys they will be ignored.
If you pass incomplete substitute map, missing keys will be left unchanged.
:param string:
:param kwargs:
:return:
>>> f('{foo} {bar}', foo="FOO")
'FOO {bar}'
>>> f('{} {bar}', 1)
'1 {bar}'
>>> f('{foo} {}', 1)
'{foo} 1'
>>> f('{foo} {} {bar} {}', '|', bar='BAR')
'{foo} | BAR {}'
>>> f('{foo} {bar}', foo="FOO", bro="BRO")
'FOO {bar}'
"""
formatter = Formatter()
args_mapping = FormatTuple(args)
mapping = FormatDict(kwargs)
return formatter.vformat(string, args_mapping, mapping)
回答 17
回答 18
阅读@Sam Bourne的注释,我修改了@SvenMarnach的代码
以正确地使用强制(如{a!s:>2s}
),而无需编写自定义解析器。基本思想不是转换为字符串,而是将带有强制标签的缺失键连接起来。
import string
class MissingKey(object):
def __init__(self, key):
self.key = key
def __str__(self): # Supports {key!s}
return MissingKeyStr("".join([self.key, "!s"]))
def __repr__(self): # Supports {key!r}
return MissingKeyStr("".join([self.key, "!r"]))
def __format__(self, spec): # Supports {key:spec}
if spec:
return "".join(["{", self.key, ":", spec, "}"])
return "".join(["{", self.key, "}"])
def __getitem__(self, i): # Supports {key[i]}
return MissingKey("".join([self.key, "[", str(i), "]"]))
def __getattr__(self, name): # Supports {key.name}
return MissingKey("".join([self.key, ".", name]))
class MissingKeyStr(MissingKey, str):
def __init__(self, key):
if isinstance(key, MissingKey):
self.key = "".join([key.key, "!s"])
else:
self.key = key
class SafeFormatter(string.Formatter):
def __init__(self, default=lambda k: MissingKey(k)):
self.default=default
def get_value(self, key, args, kwds):
if isinstance(key, str):
return kwds.get(key, self.default(key))
else:
return super().get_value(key, args, kwds)
像这样使用(例如)
SafeFormatter().format("{a:<5} {b:<10}", a=10)
以下测试(受@ norok2测试的启发)在两种情况下检查传统类format_map
和a safe_format_map
类的输出:提供正确的关键字或不提供关键字。
def safe_format_map(text, source):
return SafeFormatter().format(text, **source)
test_texts = (
'{a} ', # simple nothing useful in source
'{a:5d}', # formatting
'{a!s}', # coercion
'{a!s:>{a}s}', # formatting and coercion
'{a:0{a}d}', # nesting
'{d[x]}', # indexing
'{d.values}', # member
)
source = dict(a=10,d=dict(x='FOO'))
funcs = [safe_format_map,
str.format_map
#safe_format_alt # Version based on parsing (See @norok2)
]
n = 18
for text in test_texts:
# full_source = {**dict(b='---', f=dict(g='Oh yes!')), **source}
# print('{:>{n}s} : OK : '.format('str.format_map', n=n) + text.format_map(full_source))
print("Testing:", text)
for func in funcs:
try:
print(f'{func.__name__:>{n}s} : OK\t\t\t: ' + func(text, dict()))
except:
print(f'{func.__name__:>{n}s} : FAILED')
try:
print(f'{func.__name__:>{n}s} : OK\t\t\t: ' + func(text, source))
except:
print(f'{func.__name__:>{n}s} : FAILED')
哪些输出
Testing: {a}
safe_format_map : OK : {a}
safe_format_map : OK : 10
format_map : FAILED
format_map : OK : 10
Testing: {a:5d}
safe_format_map : OK : {a:5d}
safe_format_map : OK : 10
format_map : FAILED
format_map : OK : 10
Testing: {a!s}
safe_format_map : OK : {a!s}
safe_format_map : OK : 10
format_map : FAILED
format_map : OK : 10
Testing: {a!s:>{a}s}
safe_format_map : OK : {a!s:>{a}s}
safe_format_map : OK : 10
format_map : FAILED
format_map : OK : 10
Testing: {a:0{a}d}
safe_format_map : OK : {a:0{a}d}
safe_format_map : OK : 0000000010
format_map : FAILED
format_map : OK : 0000000010
Testing: {d[x]}
safe_format_map : OK : {d[x]}
safe_format_map : OK : FOO
format_map : FAILED
format_map : OK : FOO
Testing: {d.values}
safe_format_map : OK : {d.values}
safe_format_map : OK : <built-in method values of dict object at 0x7fe61e230af8>
format_map : FAILED
format_map : OK : <built-in method values of dict object at 0x7fe61e230af8>
回答 19
您可以将其包装在带有默认参数的函数中:
def print_foo_bar(foo='', bar=''):
s = '{foo} {bar}'
return s.format(foo=foo, bar=bar)
print_foo_bar(bar='BAR') # ' BAR'