问题:Argparse:“可选参数”下列出了必需参数吗?

我使用下面的简单代码来解析一些参数。请注意,其中之一是必需的。不幸的是,当用户在不提供参数的情况下运行脚本时,显示的用法/帮助文本并不表示存在一个非可选的参数,我感到非常困惑。如何获取python以指示参数不是可选的?

这是代码:

import argparse
if __name__ == '__main__':
    parser = argparse.ArgumentParser(
        description='Foo')
    parser.add_argument('-i','--input', help='Input file name', required=True)
    parser.add_argument('-o','--output', help='Output file name', default="stdout")
    args = parser.parse_args()
    print ("Input file: %s" % args.input )
    print ("Output file: %s" % args.output )

在不提供必需参数的情况下运行上述代码时,得到以下输出:

usage: foo.py [-h] -i INPUT [-o OUTPUT]

Foo

optional arguments:
    -h, --help            show this help message and exit
    -i INPUT, --input INPUT
                          Input file name
    -o OUTPUT, --output OUTPUT
                          Output file name

I use the following simple code to parse some arguments; note that one of them is required. Unfortunately, when the user runs the script without providing the argument, the displayed usage/help text does not indicate that there is a non-optional argument, which I find very confusing. How can I get python to indicate that an argument is not optional?

Here is the code:

import argparse
if __name__ == '__main__':
    parser = argparse.ArgumentParser(
        description='Foo')
    parser.add_argument('-i','--input', help='Input file name', required=True)
    parser.add_argument('-o','--output', help='Output file name', default="stdout")
    args = parser.parse_args()
    print ("Input file: %s" % args.input )
    print ("Output file: %s" % args.output )

When running above code without providing the required argument, I get the following output:

usage: foo.py [-h] -i INPUT [-o OUTPUT]

Foo

optional arguments:
    -h, --help            show this help message and exit
    -i INPUT, --input INPUT
                          Input file name
    -o OUTPUT, --output OUTPUT
                          Output file name

回答 0

-或开头的参数--通常被认为是可选的。所有其他参数都是位置参数,因此是设计所必需的(例如位置函数自变量)。可能需要可选参数,但这有点违背其设计。由于它们仍然是非位置参数的一部分,因此即使需要它们,它们仍将列在令人困惑的标题“可选参数”下。但是,用法部分缺少的方括号表明确实需要它们。

另请参阅文档

通常,argparse模块假定-f和–bar之类的标志表示可选参数,在命令行中始终可以将其省略。

注意:必需的选项通常被认为是错误的格式,因为用户期望选项是可选的,因此应尽可能避免使用。

就是说,帮助中的标头“位置参数”“可选参数”是由两个参数组生成的,参数被自动分成两个。现在,您可以“破解”并更改可选参数的名称,但是一种更为优雅的解决方案是为“必需的命名参数”(或您要调用的任何参数)创建另一个组:

parser = argparse.ArgumentParser(description='Foo')
parser.add_argument('-o', '--output', help='Output file name', default='stdout')
requiredNamed = parser.add_argument_group('required named arguments')
requiredNamed.add_argument('-i', '--input', help='Input file name', required=True)
parser.parse_args(['-h'])
usage: [-h] [-o OUTPUT] -i INPUT

Foo

optional arguments:
  -h, --help            show this help message and exit
  -o OUTPUT, --output OUTPUT
                        Output file name

required named arguments:
  -i INPUT, --input INPUT
                        Input file name

Parameters starting with - or -- are usually considered optional. All other parameters are positional parameters and as such required by design (like positional function arguments). It is possible to require optional arguments, but this is a bit against their design. Since they are still part of the non-positional arguments, they will still be listed under the confusing header “optional arguments” even if they are required. The missing square brackets in the usage part however show that they are indeed required.

See also the documentation:

In general, the argparse module assumes that flags like -f and –bar indicate optional arguments, which can always be omitted at the command line.

Note: Required options are generally considered bad form because users expect options to be optional, and thus they should be avoided when possible.

That being said, the headers “positional arguments” and “optional arguments” in the help are generated by two argument groups in which the arguments are automatically separated into. Now, you could “hack into it” and change the name of the optional ones, but a far more elegant solution would be to create another group for “required named arguments” (or whatever you want to call them):

parser = argparse.ArgumentParser(description='Foo')
parser.add_argument('-o', '--output', help='Output file name', default='stdout')
requiredNamed = parser.add_argument_group('required named arguments')
requiredNamed.add_argument('-i', '--input', help='Input file name', required=True)
parser.parse_args(['-h'])
usage: [-h] [-o OUTPUT] -i INPUT

Foo

optional arguments:
  -h, --help            show this help message and exit
  -o OUTPUT, --output OUTPUT
                        Output file name

required named arguments:
  -i INPUT, --input INPUT
                        Input file name

回答 1

由于我倾向于在可选参数之前列出必需的参数,因此我通过以下方法解决了这个问题:

    parser = argparse.ArgumentParser()
    parser._action_groups.pop()
    required = parser.add_argument_group('required arguments')
    optional = parser.add_argument_group('optional arguments')
    required.add_argument('--required_arg', required=True)
    optional.add_argument('--optional_arg')
    return parser.parse_args()

并输出:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
               [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  --optional_arg OPTIONAL_ARG

我可以在可选参数组中不显示“帮助”的情况下生活。

Since I prefer to list required arguments before optional, I hack around it via:

    parser = argparse.ArgumentParser()
    parser._action_groups.pop()
    required = parser.add_argument_group('required arguments')
    optional = parser.add_argument_group('optional arguments')
    required.add_argument('--required_arg', required=True)
    optional.add_argument('--optional_arg')
    return parser.parse_args()

and this outputs:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
               [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  --optional_arg OPTIONAL_ARG

I can live without ‘help’ showing up in the optional arguments group.


回答 2

从@Karl Rosaen建造

parser = argparse.ArgumentParser()
optional = parser._action_groups.pop() # Edited this line
required = parser.add_argument_group('required arguments')
# remove this line: optional = parser...
required.add_argument('--required_arg', required=True)
optional.add_argument('--optional_arg')
parser._action_groups.append(optional) # added this line
return parser.parse_args()

并输出:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
           [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  -h, --help                    show this help message and exit
  --optional_arg OPTIONAL_ARG

Building off of @Karl Rosaen

parser = argparse.ArgumentParser()
optional = parser._action_groups.pop() # Edited this line
required = parser.add_argument_group('required arguments')
# remove this line: optional = parser...
required.add_argument('--required_arg', required=True)
optional.add_argument('--optional_arg')
parser._action_groups.append(optional) # added this line
return parser.parse_args()

and this outputs:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
           [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  -h, --help                    show this help message and exit
  --optional_arg OPTIONAL_ARG

回答 3

再过一次,以@RalphyZ为基础

这个不会破坏公开的API。

from argparse import ArgumentParser, SUPPRESS
# Disable default help
parser = ArgumentParser(add_help=False)
required = parser.add_argument_group('required arguments')
optional = parser.add_argument_group('optional arguments')

# Add back help 
optional.add_argument(
    '-h',
    '--help',
    action='help',
    default=SUPPRESS,
    help='show this help message and exit'
)
required.add_argument('--required_arg', required=True)
optional.add_argument('--optional_arg')

它将显示与上面相同的内容,并且应该在将来的版本中保留下来:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
           [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  -h, --help                    show this help message and exit
  --optional_arg OPTIONAL_ARG

One more time, building off of @RalphyZ

This one doesn’t break the exposed API.

from argparse import ArgumentParser, SUPPRESS
# Disable default help
parser = ArgumentParser(add_help=False)
required = parser.add_argument_group('required arguments')
optional = parser.add_argument_group('optional arguments')

# Add back help 
optional.add_argument(
    '-h',
    '--help',
    action='help',
    default=SUPPRESS,
    help='show this help message and exit'
)
required.add_argument('--required_arg', required=True)
optional.add_argument('--optional_arg')

Which will show the same as above and should survive future versions:

usage: main.py [-h] [--required_arg REQUIRED_ARG]
           [--optional_arg OPTIONAL_ARG]

required arguments:
  --required_arg REQUIRED_ARG

optional arguments:
  -h, --help                    show this help message and exit
  --optional_arg OPTIONAL_ARG

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