matplotlib中的日期刻度和旋转

问题:matplotlib中的日期刻度和旋转

我在尝试在matplotlib中旋转日期刻度时遇到问题。下面是一个小示例程序。如果我尝试最后旋转刻度线,则刻度线不会旋转。如果我尝试如注释“ crashes”下所示旋转刻度线,则matplot lib崩溃。

仅当x值为日期时,才会发生这种情况。如果我在的调用dates中将变量替换tavail_plot,则该xticks(rotation=70)调用在内部正常运行avail_plot

有任何想法吗?

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

def avail_plot(ax, x, y, label, lcolor):
    ax.plot(x,y,'b')
    ax.set_ylabel(label, rotation='horizontal', color=lcolor)
    ax.get_yaxis().set_ticks([])

    #crashes
    #plt.xticks(rotation=70)

    ax2 = ax.twinx()
    ax2.plot(x, [1 for a in y], 'b')
    ax2.get_yaxis().set_ticks([])
    ax2.set_ylabel('testing')

f, axs = plt.subplots(2, sharex=True, sharey=True)
t = np.arange(0.01, 5, 1)
s1 = np.exp(t)
start = dt.datetime.now()
dates=[]
for val in t:
    next_val = start + dt.timedelta(0,val)
    dates.append(next_val)
    start = next_val

avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')
plt.subplots_adjust(hspace=0, bottom=0.3)
plt.yticks([0.5,],("",""))
#doesn't crash, but does not rotate the xticks
#plt.xticks(rotation=70)
plt.show()

I am having an issue trying to get my date ticks rotated in matplotlib. A small sample program is below. If I try to rotate the ticks at the end, the ticks do not get rotated. If I try to rotate the ticks as shown under the comment ‘crashes’, then matplot lib crashes.

This only happens if the x-values are dates. If I replaces the variable dates with the variable t in the call to avail_plot, the xticks(rotation=70) call works just fine inside avail_plot.

Any ideas?

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

def avail_plot(ax, x, y, label, lcolor):
    ax.plot(x,y,'b')
    ax.set_ylabel(label, rotation='horizontal', color=lcolor)
    ax.get_yaxis().set_ticks([])

    #crashes
    #plt.xticks(rotation=70)

    ax2 = ax.twinx()
    ax2.plot(x, [1 for a in y], 'b')
    ax2.get_yaxis().set_ticks([])
    ax2.set_ylabel('testing')

f, axs = plt.subplots(2, sharex=True, sharey=True)
t = np.arange(0.01, 5, 1)
s1 = np.exp(t)
start = dt.datetime.now()
dates=[]
for val in t:
    next_val = start + dt.timedelta(0,val)
    dates.append(next_val)
    start = next_val

avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')
plt.subplots_adjust(hspace=0, bottom=0.3)
plt.yticks([0.5,],("",""))
#doesn't crash, but does not rotate the xticks
#plt.xticks(rotation=70)
plt.show()

回答 0

如果您喜欢非面向对象的方法,请在两个调用之前移至plt.xticks(rotation=70)右侧,例如avail_plot

plt.xticks(rotation=70)
avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')

这将在设置标签之前设置旋转属性。由于这里有两个轴,因此plt.xticks在绘制了两个图后会感到困惑。而此时点plt.xticks什么都不做,plt.gca()没有给你想要修改的轴等plt.xticks作用于当前坐标,是行不通的。

对于不使用的面向对象方法plt.xticks,可以使用

plt.setp( axs[1].xaxis.get_majorticklabels(), rotation=70 )

两次avail_plot通话之后。这样可以专门设置正确轴上的旋转。

If you prefer a non-object-oriented approach, move plt.xticks(rotation=70) to right before the two avail_plot calls, eg

plt.xticks(rotation=70)
avail_plot(axs[0], dates, s1, 'testing', 'green')
avail_plot(axs[1], dates, s1, 'testing2', 'red')

This sets the rotation property before setting up the labels. Since you have two axes here, plt.xticks gets confused after you’ve made the two plots. At the point when plt.xticks doesn’t do anything, plt.gca() does not give you the axes you want to modify, and so plt.xticks, which acts on the current axes, is not going to work.

For an object-oriented approach not using plt.xticks, you can use

plt.setp( axs[1].xaxis.get_majorticklabels(), rotation=70 )

after the two avail_plot calls. This sets the rotation on the correct axes specifically.


回答 1

解决方案适用于Matplotlib 2.1+

存在tick_params可以更改刻度属性的轴方法。它也作为轴方法存在set_tick_params

ax.tick_params(axis='x', rotation=45)

要么

ax.xaxis.set_tick_params(rotation=45)

附带说明一下,当前解决方案通过使用command将有状态接口(使用pyplot)与面向对象的接口混合在一起plt.xticks(rotation=70)。由于问题中的代码使用面向对象的方法,因此最好始终坚持使用该方法。该解决方案确实提供了一个很好的显式解决方案plt.setp( axs[1].xaxis.get_majorticklabels(), rotation=70 )

Solution works for matplotlib 2.1+

There exists an axes method tick_params that can change tick properties. It also exists as an axis method as set_tick_params

ax.tick_params(axis='x', rotation=45)

Or

ax.xaxis.set_tick_params(rotation=45)

As a side note, the current solution mixes the stateful interface (using pyplot) with the object-oriented interface by using the command plt.xticks(rotation=70). Since the code in the question uses the object-oriented approach, it’s best to stick to that approach throughout. The solution does give a good explicit solution with plt.setp( axs[1].xaxis.get_majorticklabels(), rotation=70 )


回答 2

一个简单的解决方案是使用

fig.autofmt_xdate()

该命令自动旋转xaxis标签并调整其位置。默认值为旋转角度30°和水平对齐“向右”。但是可以在函数调用中更改它们

fig.autofmt_xdate(bottom=0.2, rotation=30, ha='right')

附加bottom参数等效于setting plt.subplots_adjust(bottom=bottom),它允许将底部轴的padding设置为更大的值,以承载旋转的ticklabel。

因此,基本上,这里您具有所有需要的设置,只需一个命令即可拥有一个漂亮的日期轴。

在matplotlib页面上可以找到一个很好的例子

An easy solution which avoids looping over the ticklabes is to just use

fig.autofmt_xdate()

This command automatically rotates the xaxis labels and adjusts their position. The default values are a rotation angle 30° and horizontal alignment “right”. But they can be changed in the function call

fig.autofmt_xdate(bottom=0.2, rotation=30, ha='right')

The additional bottom argument is equivalent to setting plt.subplots_adjust(bottom=bottom), which allows to set the bottom axes padding to a larger value to host the rotated ticklabels.

So basically here you have all the settings you need to have a nice date axis in a single command.

A good example can be found on the matplotlib page.


回答 3

申请的另一种方式horizontalalignment,并rotation给每个刻度标签做for了你要更改的刻度标记循环:

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]
hours_value = np.random.random(len(hours))
days_value = np.random.random(len(days))

fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
axs[0].plot(hours,hours_value)
axs[1].plot(days,days_value)

for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
    label.set_rotation(30)
    label.set_horizontalalignment("right")

这是一个示例,如果您想控制主要和次要刻度线的位置:

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]

axs[0].plot(hours,np.random.random(len(hours)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.HourLocator(byhour = range(0,25,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[0].xaxis.set_major_locator(x_major_lct)
axs[0].xaxis.set_minor_locator(x_minor_lct)
axs[0].xaxis.set_major_formatter(x_fmt)
axs[0].set_xlabel("minor ticks set to every hour, major ticks start with 00:00")

axs[1].plot(days,np.random.random(len(days)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.DayLocator(bymonthday = range(0,32,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[1].xaxis.set_major_locator(x_major_lct)
axs[1].xaxis.set_minor_locator(x_minor_lct)
axs[1].xaxis.set_major_formatter(x_fmt)
axs[1].set_xlabel("minor ticks set to every day, major ticks show first day of month")
for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
    label.set_rotation(30)
    label.set_horizontalalignment("right")

Another way to applyhorizontalalignment and rotation to each tick label is doing a for loop over the tick labels you want to change:

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]
hours_value = np.random.random(len(hours))
days_value = np.random.random(len(days))

fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
axs[0].plot(hours,hours_value)
axs[1].plot(days,days_value)

for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
    label.set_rotation(30)
    label.set_horizontalalignment("right")

And here is an example if you want to control the location of major and minor ticks:

import numpy as np
import matplotlib.pyplot as plt
import datetime as dt

fig, axs = plt.subplots(2)
fig.subplots_adjust(hspace=0.75)
now = dt.datetime.now()
hours = [now + dt.timedelta(minutes=x) for x in range(0,24*60,10)]
days = [now + dt.timedelta(days=x) for x in np.arange(0,30,1/4.)]

axs[0].plot(hours,np.random.random(len(hours)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.HourLocator(byhour = range(0,25,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[0].xaxis.set_major_locator(x_major_lct)
axs[0].xaxis.set_minor_locator(x_minor_lct)
axs[0].xaxis.set_major_formatter(x_fmt)
axs[0].set_xlabel("minor ticks set to every hour, major ticks start with 00:00")

axs[1].plot(days,np.random.random(len(days)))
x_major_lct = mpl.dates.AutoDateLocator(minticks=2,maxticks=10, interval_multiples=True)
x_minor_lct = matplotlib.dates.DayLocator(bymonthday = range(0,32,1))
x_fmt = matplotlib.dates.AutoDateFormatter(x_major_lct)
axs[1].xaxis.set_major_locator(x_major_lct)
axs[1].xaxis.set_minor_locator(x_minor_lct)
axs[1].xaxis.set_major_formatter(x_fmt)
axs[1].set_xlabel("minor ticks set to every day, major ticks show first day of month")
for label in axs[0].get_xmajorticklabels() + axs[1].get_xmajorticklabels():
    label.set_rotation(30)
    label.set_horizontalalignment("right")


回答 4

只需使用

ax.set_xticklabels(label_list, rotation=45)

Simply use

ax.set_xticklabels(label_list, rotation=45)