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Python中的字母范围

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问题：Python中的字母范围
回答 0
回答 1
回答 2
回答 3
回答 4
回答 5
回答 6

问题：Python中的字母范围

而不是像这样列出字母字符：

alpha = ['a', 'b', 'c', 'd'.........'z']

有什么办法可以将它分组到某个范围之内？例如，对于数字，可以使用进行分组range()：

range(1, 10)
点击查看英文原文

Instead of making a list of alphabet characters like this:

alpha = ['a', 'b', 'c', 'd'.........'z']

is there any way that we can group it to a range or something? For example, for numbers it can be grouped using range():

range(1, 10)

回答 0

>>> import string
>>> string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'

如果您确实需要列表：

>>> list(string.ascii_lowercase)
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

并做到这一点 range

>>> list(map(chr, range(97, 123))) #or list(map(chr, range(ord('a'), ord('z')+1)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

其他有用的string模块功能：

>>> help(string) # on Python 3
....
DATA
    ascii_letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
    ascii_lowercase = 'abcdefghijklmnopqrstuvwxyz'
    ascii_uppercase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    digits = '0123456789'
    hexdigits = '0123456789abcdefABCDEF'
    octdigits = '01234567'
    printable = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~ \t\n\r\x0b\x0c'
    punctuation = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'
    whitespace = ' \t\n\r\x0b\x0c'
点击查看英文原文 
>>> import string
>>> string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'

If you really need a list:

>>> list(string.ascii_lowercase)
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

And to do it with range

>>> list(map(chr, range(97, 123))) #or list(map(chr, range(ord('a'), ord('z')+1)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Other helpful string module features:

>>> help(string) # on Python 3
....
DATA
    ascii_letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
    ascii_lowercase = 'abcdefghijklmnopqrstuvwxyz'
    ascii_uppercase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'
    digits = '0123456789'
    hexdigits = '0123456789abcdefABCDEF'
    octdigits = '01234567'
    printable = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~ \t\n\r\x0b\x0c'
    punctuation = '!"#$%&\'()*+,-./:;<=>?@[\\]^_`{|}~'
    whitespace = ' \t\n\r\x0b\x0c'

回答 1

[chr(i) for i in range(ord('a'),ord('z')+1)]
点击查看英文原文 
[chr(i) for i in range(ord('a'),ord('z')+1)]

回答 2

在Python 2.7和3中，您可以使用以下代码：

import string
string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'

string.ascii_uppercase
'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

正如@Zaz所说： string.lowercase已弃用，不再在Python 3中string.ascii_lowercase工作，但在两者中都工作

点击查看英文原文

In Python 2.7 and 3 you can use this:

import string
string.ascii_lowercase
'abcdefghijklmnopqrstuvwxyz'

string.ascii_uppercase
'ABCDEFGHIJKLMNOPQRSTUVWXYZ'

As @Zaz says: string.lowercase is deprecated and no longer works in Python 3 but string.ascii_lowercase works in both

回答 3

这是一个简单的字母范围实现：

码

def letter_range(start, stop="{", step=1):
    """Yield a range of lowercase letters.""" 
    for ord_ in range(ord(start.lower()), ord(stop.lower()), step):
        yield chr(ord_)

演示版

list(letter_range("a", "f"))
# ['a', 'b', 'c', 'd', 'e']

list(letter_range("a", "f", step=2))
# ['a', 'c', 'e']
点击查看英文原文

Here is a simple letter-range implementation:

Code

def letter_range(start, stop="{", step=1):
    """Yield a range of lowercase letters.""" 
    for ord_ in range(ord(start.lower()), ord(stop.lower()), step):
        yield chr(ord_)

Demo

list(letter_range("a", "f"))
# ['a', 'b', 'c', 'd', 'e']

list(letter_range("a", "f", step=2))
# ['a', 'c', 'e']

回答 4

如果要查找letters[1:10]与R 相等的值，则可以使用：

 import string
 list(string.ascii_lowercase[0:10])
点击查看英文原文

If you are looking to an equivalent of letters[1:10] from R, you can use:

 import string
 list(string.ascii_lowercase[0:10])

回答 5

使用内置的range函数在python中打印大写和小写字母

def upperCaseAlphabets():
    print("Upper Case Alphabets")
    for i in range(65, 91):
        print(chr(i), end=" ")
    print()

def lowerCaseAlphabets():
    print("Lower Case Alphabets")
    for i in range(97, 123):
        print(chr(i), end=" ")

upperCaseAlphabets();
lowerCaseAlphabets();
点击查看英文原文

Print the Upper and Lower case alphabets in python using a built-in range function

def upperCaseAlphabets():
    print("Upper Case Alphabets")
    for i in range(65, 91):
        print(chr(i), end=" ")
    print()

def lowerCaseAlphabets():
    print("Lower Case Alphabets")
    for i in range(97, 123):
        print(chr(i), end=" ")

upperCaseAlphabets();
lowerCaseAlphabets();

回答 6

这是我能找出的最简单方法：

#!/usr/bin/python3 for i in range(97, 123): print("{:c}".format(i), end='')

因此，从97到122是与’a’和’z’等效的ASCII码。请注意，小写字母和放置123的需要，因为将不包括在内）。

在打印功能中，请确保设置{:c}（字符）格式，在这种情况下，我们希望它一起打印所有内容，甚至不让最后一行换行，这样end=''就可以了。

结果是这样的： abcdefghijklmnopqrstuvwxyz

点击查看英文原文

This is the easiest way I can figure out:

#!/usr/bin/python3 for i in range(97, 123): print("{:c}".format(i), end='')

So, 97 to 122 are the ASCII number equivalent to ‘a’ to and ‘z’. Notice the lowercase and the need to put 123, since it will not be included).

In print function make sure to set the {:c} (character) format, and, in this case, we want it to print it all together not even letting a new line at the end, so end=''would do the job.

The result is this: abcdefghijklmnopqrstuvwxyz