问题:Python中的HTTP请求和JSON解析

我想通过Google Directions API动态查询Google Maps。例如,此请求计算通过伊利诺伊州芝加哥市到密苏里州乔普林市和俄克拉荷马州俄克拉荷马市的两个航路点的路线:

http://maps.googleapis.com/maps/api/directions/json?origin = Chicago,IL&destination = Los + Angeles,CA&waypoints = Joplin,MO |俄克拉荷马州+市,OK&sensor = false

以JSON格式返回结果。

如何在Python中执行此操作?我想发送这样的请求,接收结果并解析它。

I want to dynamically query Google Maps through the Google Directions API. As an example, this request calculates the route from Chicago, IL to Los Angeles, CA via two waypoints in Joplin, MO and Oklahoma City, OK:

http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false

It returns a result in the JSON format.

How can I do this in Python? I want to send such a request, receive the result and parse it.


回答 0

我建议使用很棒的请求库:

import requests

url = 'http://maps.googleapis.com/maps/api/directions/json'

params = dict(
    origin='Chicago,IL',
    destination='Los+Angeles,CA',
    waypoints='Joplin,MO|Oklahoma+City,OK',
    sensor='false'
)

resp = requests.get(url=url, params=params)
data = resp.json() # Check the JSON Response Content documentation below

JSON响应内容:https : //requests.readthedocs.io/en/master/user/quickstart/#json-response-content

I recommend using the awesome requests library:

import requests

url = 'http://maps.googleapis.com/maps/api/directions/json'

params = dict(
    origin='Chicago,IL',
    destination='Los+Angeles,CA',
    waypoints='Joplin,MO|Oklahoma+City,OK',
    sensor='false'
)

resp = requests.get(url=url, params=params)
data = resp.json() # Check the JSON Response Content documentation below

JSON Response Content: https://requests.readthedocs.io/en/master/user/quickstart/#json-response-content


回答 1

requestsPython模块负责的两个检索JSON数据和对其进行解码,由于其内建JSON解码器。这是来自模块文档的示例:

>>> import requests
>>> r = requests.get('https://github.com/timeline.json')
>>> r.json()
[{u'repository': {u'open_issues': 0, u'url': 'https://github.com/...

因此,无需使用一些单独的模块来解码JSON。

The requests Python module takes care of both retrieving JSON data and decoding it, due to its builtin JSON decoder. Here is an example taken from the module’s documentation:

>>> import requests
>>> r = requests.get('https://github.com/timeline.json')
>>> r.json()
[{u'repository': {u'open_issues': 0, u'url': 'https://github.com/...

So there is no use of having to use some separate module for decoding JSON.


回答 2

具有内置.json()方法

import requests
requests.get(url).json()

has built-in .json() method

import requests
requests.get(url).json()

回答 3

import urllib
import json

url = 'http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false'
result = json.load(urllib.urlopen(url))
import urllib
import json

url = 'http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false'
result = json.load(urllib.urlopen(url))

回答 4

使用请求库,漂亮地打印结果,以便您可以更好地定位要提取的键/值,然后使用嵌套的for循环来解析数据。在该示例中,我逐步提取了行车路线。

import json, requests, pprint

url = 'http://maps.googleapis.com/maps/api/directions/json?'

params = dict(
    origin='Chicago,IL',
    destination='Los+Angeles,CA',
    waypoints='Joplin,MO|Oklahoma+City,OK',
    sensor='false'
)


data = requests.get(url=url, params=params)
binary = data.content
output = json.loads(binary)

# test to see if the request was valid
#print output['status']

# output all of the results
#pprint.pprint(output)

# step-by-step directions
for route in output['routes']:
        for leg in route['legs']:
            for step in leg['steps']:
                print step['html_instructions']

Use the requests library, pretty print the results so you can better locate the keys/values you want to extract, and then use nested for loops to parse the data. In the example I extract step by step driving directions.

import json, requests, pprint

url = 'http://maps.googleapis.com/maps/api/directions/json?'

params = dict(
    origin='Chicago,IL',
    destination='Los+Angeles,CA',
    waypoints='Joplin,MO|Oklahoma+City,OK',
    sensor='false'
)


data = requests.get(url=url, params=params)
binary = data.content
output = json.loads(binary)

# test to see if the request was valid
#print output['status']

# output all of the results
#pprint.pprint(output)

# step-by-step directions
for route in output['routes']:
        for leg in route['legs']:
            for step in leg['steps']:
                print step['html_instructions']

回答 5

试试这个:

import requests
import json

# Goole Maps API.
link = 'http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false'

# Request data from link as 'str'
data = requests.get(link).text

# convert 'str' to Json
data = json.loads(data)

# Now you can access Json 
for i in data['routes'][0]['legs'][0]['steps']:
    lattitude = i['start_location']['lat']
    longitude = i['start_location']['lng']
    print('{}, {}'.format(lattitude, longitude))

Try this:

import requests
import json

# Goole Maps API.
link = 'http://maps.googleapis.com/maps/api/directions/json?origin=Chicago,IL&destination=Los+Angeles,CA&waypoints=Joplin,MO|Oklahoma+City,OK&sensor=false'

# Request data from link as 'str'
data = requests.get(link).text

# convert 'str' to Json
data = json.loads(data)

# Now you can access Json 
for i in data['routes'][0]['legs'][0]['steps']:
    lattitude = i['start_location']['lat']
    longitude = i['start_location']['lng']
    print('{}, {}'.format(lattitude, longitude))

回答 6

同样适用于控制台上漂亮的Json:

 json.dumps(response.json(), indent=2)

可以使用带有缩进的转储。(请导入json

Also for pretty Json on console:

 json.dumps(response.json(), indent=2)

possible to use dumps with indent. (Please import json)


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