Python日期字符串到日期对象

问题:Python日期字符串到日期对象

如何在python中将字符串转换为日期对象?

该字符串是:"24052010"(对应于格式:"%d%m%Y"

我不想要datetime.datetime对象,而是想要datetime.date。

How do I convert a string to a date object in python?

The string would be: "24052010" (corresponding to the format: "%d%m%Y")

I don’t want a datetime.datetime object, but rather a datetime.date.


回答 0

您可以strptimedatetimePython包中使用:

>>> import datetime
>>> datetime.datetime.strptime('24052010', "%d%m%Y").date()
datetime.date(2010, 5, 24)

You can use strptime in the datetime package of Python:

>>> import datetime
>>> datetime.datetime.strptime('24052010', "%d%m%Y").date()
datetime.date(2010, 5, 24)

回答 1

import datetime
datetime.datetime.strptime('24052010', '%d%m%Y').date()
import datetime
datetime.datetime.strptime('24052010', '%d%m%Y').date()

回答 2

直接相关的问题:

如果有的话

datetime.datetime.strptime("2015-02-24T13:00:00-08:00", "%Y-%B-%dT%H:%M:%S-%H:%M").date()

你会得到:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/_strptime.py", line 308, in _strptime
    format_regex = _TimeRE_cache.compile(format)
  File "/usr/local/lib/python2.7/_strptime.py", line 265, in compile
    return re_compile(self.pattern(format), IGNORECASE)
  File "/usr/local/lib/python2.7/re.py", line 194, in compile
    return _compile(pattern, flags)
  File "/usr/local/lib/python2.7/re.py", line 251, in _compile
    raise error, v # invalid expression
sre_constants.error: redefinition of group name 'H' as group 7; was group 4

并且您尝试了:

<-24T13:00:00-08:00", "%Y-%B-%dT%HH:%MM:%SS-%HH:%MM").date()

但是您仍然可以得到上面的追溯。

回答:

>>> from dateutil.parser import parse
>>> from datetime import datetime
>>> parse("2015-02-24T13:00:00-08:00")
datetime.datetime(2015, 2, 24, 13, 0, tzinfo=tzoffset(None, -28800))

Directly related question:

What if you have

datetime.datetime.strptime("2015-02-24T13:00:00-08:00", "%Y-%B-%dT%H:%M:%S-%H:%M").date()

and you get:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python2.7/_strptime.py", line 308, in _strptime
    format_regex = _TimeRE_cache.compile(format)
  File "/usr/local/lib/python2.7/_strptime.py", line 265, in compile
    return re_compile(self.pattern(format), IGNORECASE)
  File "/usr/local/lib/python2.7/re.py", line 194, in compile
    return _compile(pattern, flags)
  File "/usr/local/lib/python2.7/re.py", line 251, in _compile
    raise error, v # invalid expression
sre_constants.error: redefinition of group name 'H' as group 7; was group 4

and you tried:

<-24T13:00:00-08:00", "%Y-%B-%dT%HH:%MM:%SS-%HH:%MM").date()

but you still get the traceback above.

Answer:

>>> from dateutil.parser import parse
>>> from datetime import datetime
>>> parse("2015-02-24T13:00:00-08:00")
datetime.datetime(2015, 2, 24, 13, 0, tzinfo=tzoffset(None, -28800))

回答 3

如果您懒惰并且不想与字符串文字打架,则可以使用该parser模块。

from dateutil import parser
dt = parser.parse("Jun 1 2005  1:33PM")
print(dt.year, dt.month, dt.day,dt.hour, dt.minute, dt.second)
>2005 6 1 13 33 0

只是一点说明,我们在尝试匹配any字符串表示形式时,它的速度比10倍慢strptime

If you are lazy and don’t want to fight with string literals, you can just go with the parser module.

from dateutil import parser
dt = parser.parse("Jun 1 2005  1:33PM")
print(dt.year, dt.month, dt.day,dt.hour, dt.minute, dt.second)
>2005 6 1 13 33 0

Just a side note, as we are trying to match any string representation, it is 10x slower than strptime


回答 4

您有一个像这样的日期字符串“ 24052010”,并且您想要这个日期对象,

from datetime import datetime
cus_date = datetime.strptime("24052010", "%d%m%Y").date()

此cus_date将为您提供日期对象。

您可以使用此方法从日期对象中检索日期字符串,

cus_date.strftime("%d%m%Y")

you have a date string like this, “24052010” and you want date object for this,

from datetime import datetime
cus_date = datetime.strptime("24052010", "%d%m%Y").date()

this cus_date will give you date object.

you can retrieve date string from your date object using this,

cus_date.strftime("%d%m%Y")

回答 5

还有一个叫做arrowpython的很棒的库,可以对python日期进行操作。

import arrow
import datetime

a = arrow.get('24052010', 'DMYYYY').date()
print(isinstance(a, datetime.date)) # True

There is another library called arrow really great to make manipulation on python date.

import arrow
import datetime

a = arrow.get('24052010', 'DMYYYY').date()
print(isinstance(a, datetime.date)) # True

回答 6

使用时间模块转换数据。

程式码片段:

import time 
tring='20150103040500'
var = int(time.mktime(time.strptime(tring, '%Y%m%d%H%M%S')))
print var

Use time module to convert data.

Code snippet:

import time 
tring='20150103040500'
var = int(time.mktime(time.strptime(tring, '%Y%m%d%H%M%S')))
print var