问题：Python设置为列表
如何在Python中将集合转换为列表？使用
a = set(["Blah", "Hello"])
a = list(a)
不起作用。它给了我：
TypeError: 'set' object is not callable
How can I convert a set to a list in Python? Using
a = set(["Blah", "Hello"])
a = list(a)
doesn’t work. It gives me:
TypeError: 'set' object is not callable
回答 0
您的代码可以正常工作（在cpython 2.4、2.5、2.6、2.7、3.1和3.2上进行了测试）：
>>> a = set(["Blah", "Hello"])
>>> a = list(a) # You probably wrote a = list(a()) here or list = set() above
>>> a
['Blah', 'Hello']
检查您是否没有list意外覆盖：
>>> assert list == __builtins__.list
Your code does work (tested with cpython 2.4, 2.5, 2.6, 2.7, 3.1 and 3.2):
>>> a = set(["Blah", "Hello"])
>>> a = list(a) # You probably wrote a = list(a()) here or list = set() above
>>> a
['Blah', 'Hello']
Check that you didn’t overwrite list by accident:
>>> assert list == __builtins__.list
回答 1
您无意间使用了内置集作为变量名，从而掩盖了它，这是一种复制错误的简单方法
>>> set=set()
>>> set=set()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
第一行将set重新绑定到set的实例。第二行试图调用该实例，该实例当然会失败。
这是一个不太混乱的版本，每个变量使用不同的名称。使用新鲜的口译员
>>> a=set()
>>> b=a()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
希望很明显，调用a是一个错误
You’ve shadowed the builtin set by accidentally using it as a variable name, here is a simple way to replicate your error
>>> set=set()
>>> set=set()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
The first line rebinds set to an instance of set. The second line is trying to call the instance which of course fails.
Here is a less confusing version using different names for each variable. Using a fresh interpreter
>>> a=set()
>>> b=a()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'set' object is not callable
Hopefully it is obvious that calling a is an error
回答 2
在编写之前，set(XXXXX)
您已经使用“ set”作为变量，例如
set = 90 #you have used "set" as an object
…
…
a = set(["Blah", "Hello"])
a = list(a)
before you write set(XXXXX)
you have used “set” as a variable
e.g.
set = 90 #you have used "set" as an object
…
…
a = set(["Blah", "Hello"])
a = list(a)
回答 3
这将起作用：
>>> t = [1,1,2,2,3,3,4,5]
>>> print list(set(t))
[1,2,3,4,5]
但是，如果将“列表”或“集合”用作变量名，则会得到：
TypeError: 'set' object is not callable
例如：
>>> set = [1,1,2,2,3,3,4,5]
>>> print list(set(set))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
如果将“列表”用作变量名，则会发生相同的错误。
This will work:
>>> t = [1,1,2,2,3,3,4,5]
>>> print list(set(t))
[1,2,3,4,5]
However, if you have used “list” or “set” as a variable name you will get the:
TypeError: 'set' object is not callable
eg:
>>> set = [1,1,2,2,3,3,4,5]
>>> print list(set(set))
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable
Same error will occur if you have used “list” as a variable name.
回答 4
s = set([1,2,3])
print [ x for x in iter(s) ]
s = set([1,2,3])
print [ x for x in iter(s) ]
回答 5
您的代码在Win7 x64上与Python 3.2.1兼容
a = set(["Blah", "Hello"])
a = list(a)
type(a)
<class 'list'>
Your code works with Python 3.2.1 on Win7 x64
a = set(["Blah", "Hello"])
a = list(a)
type(a)
<class 'list'>
回答 6
尝试结合使用map和lambda函数：
aList = map( lambda x: x, set ([1, 2, 6, 9, 0]) )
如果您在字符串中有一组数字并将其转换为整数列表，则这是一种非常方便的方法：
aList = map( lambda x: int(x), set (['1', '2', '3', '7', '12']) )
Try using combination of map and lambda functions:
aList = map( lambda x: x, set ([1, 2, 6, 9, 0]) )
It is very convenient approach if you have a set of numbers in string and you want to convert it to list of integers:
aList = map( lambda x: int(x), set (['1', '2', '3', '7', '12']) )
