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Python-使用列表作为函数参数

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问题：Python-使用列表作为函数参数
回答 0
回答 1
回答 2
回答 3

问题：Python-使用列表作为函数参数

如何使用Python列表（例如params = ['a',3.4,None]）作为函数的参数，例如：

def some_func(a_char,a_float,a_something):
   # do stuff
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How can I use a Python list (e.g. params = ['a',3.4,None]) as parameters to a function, e.g.:

def some_func(a_char,a_float,a_something):
   # do stuff

回答 0

您可以使用splat运算符执行此操作：

some_func(*params)

这使函数将每个列表项作为单独的参数接收。这里有一个描述：http : //docs.python.org/tutorial/controlflow.html#unpacking-argument-lists

点击查看英文原文

You can do this using the splat operator:

some_func(*params)

This causes the function to receive each list item as a separate parameter. There’s a description here: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists

回答 1

这已经得到了完美的答案，但是由于我刚进入本页并且不立即理解，所以我将添加一个简单但完整的示例。

def some_func(a_char, a_float, a_something):
    print a_char

params = ['a', 3.4, None]
some_func(*params)

>> a
点击查看英文原文

This has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example.

def some_func(a_char, a_float, a_something):
    print a_char

params = ['a', 3.4, None]
some_func(*params)

>> a

回答 2

使用星号：

some_func(*params)
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Use an asterisk:

some_func(*params)

回答 3

您需要参数解包运算符*。

点击查看英文原文

You want the argument unpacking operator *.