内容 隐藏
问题：str.startswith带有要测试的字符串列表
回答 0
回答 1

问题：str.startswith带有要测试的字符串列表

我试图避免使用那么多的if语句和比较，而只使用一个列表，但不确定如何将其用于str.startswith：

if link.lower().startswith("js/") or link.lower().startswith("catalog/") or link.lower().startswith("script/") or link.lower().startswith("scripts/") or link.lower().startswith("katalog/"):
    # then "do something"

我希望它是：

if link.lower().startswith() in ["js","catalog","script","scripts","katalog"]:
    # then "do something"

任何帮助，将不胜感激。

点击查看英文原文

I’m trying to avoid using so many if statements and comparisons and simply use a list, but not sure how to use it with str.startswith:

if link.lower().startswith("js/") or link.lower().startswith("catalog/") or link.lower().startswith("script/") or link.lower().startswith("scripts/") or link.lower().startswith("katalog/"):
    # then "do something"

What I would like it to be is:

if link.lower().startswith() in ["js","catalog","script","scripts","katalog"]:
    # then "do something"

Any help would be appreciated.

回答 0

str.startswith 允许您提供一个字符串元组来测试：

if link.lower().startswith(("js", "catalog", "script", "katalog")):

从文档：

str.startswith(prefix[, start[, end]])

返回True如果字符串开始用prefix，否则返回False。prefix也可以是要查找的前缀的元组。

下面是一个演示：

>>> "abcde".startswith(("xyz", "abc"))
True
>>> prefixes = ["xyz", "abc"]
>>> "abcde".startswith(tuple(prefixes)) # You must use a tuple though
True
>>>
点击查看英文原文

str.startswith allows you to supply a tuple of strings to test for:

if link.lower().startswith(("js", "catalog", "script", "katalog")):

From the docs:

str.startswith(prefix[, start[, end]])

Return True if string starts with the prefix, otherwise return False. prefix can also be a tuple of prefixes to look for.

Below is a demonstration:

>>> "abcde".startswith(("xyz", "abc"))
True
>>> prefixes = ["xyz", "abc"]
>>> "abcde".startswith(tuple(prefixes)) # You must use a tuple though
True
>>>

回答 1

你也可以使用any()，map()就像这样：

if any(map(l.startswith, x)):
    pass # Do something

或者，使用生成器表达式：

if any(l.startswith(s) for s in x)
    pass # Do something
点击查看英文原文

You can also use any(), map() like so:

if any(map(l.startswith, x)):
    pass # Do something

Or alternatively, using a generator expression:

if any(l.startswith(s) for s in x)
    pass # Do something
声明：本站所有文章，如无特殊说明或标注，均为本站原创发布。任何个人或组织，在未征得本站同意时，禁止复制、盗用、采集、发布本站内容到任何网站、书籍等各类媒体平台。如若本站内容侵犯了原著者的合法权益，可联系我们进行处理。