Python 十个加快编程效率的技巧(tricks)

x, y = 10, 20
print(x, y) 
x, y = y, x 
print(x, y) 

10 20
20 10

a ="GeeksForGeeks"
print("Reverse is", a[::-1]) 

Reverse is skeeGroFskeeG

a = ["Geeks", "For", "Geeks"] 
print(" ".join(a)) 

Geeks For Geeks

n = 10
result = 1 < n < 20 
print(result)  
result = 1 > n <= 9
print(result) 

True
False

import os; 
import socket; 

print(os) 
print(socket) 

<module 'os' from '/usr/lib/python3.5/os.py'>
<module 'socket' from '/usr/lib/python3.5/socket.py'>

class MyName: 
    Geeks, For, Geeks = range(3) 

print(MyName.Geeks) 
print(MyName.For) 
print(MyName.Geeks) 

2
1
2

def x(): 
    return 1, 2, 3, 4
a, b, c, d = x() 
print(a, b, c, d) 

1 2 3 4

test = [1, 2, 3, 4, 2, 2, 3, 1, 4, 4, 4] 
print(max(set(test), key = test.count)) 

4

import sys 
x = 1
print(sys.getsizeof(x)) 

28

from collections import Counter 
def is_anagram(str1, str2): 
    return Counter(str1) == Counter(str2) 
print(is_anagram('geek', 'eegk')) 
  
print(is_anagram('geek', 'peek'))   

True
False