I am looking to format a number like 188518982.18 to £188,518,982.18 using Python.

How can I do this?

See the locale module.

This does currency (and date) formatting.

>>> import locale
>>> locale.setlocale( locale.LC_ALL, '' )
'English_United States.1252'
>>> locale.currency( 188518982.18 )
'$188518982.18'
>>> locale.currency( 188518982.18, grouping=True )
'$188,518,982.18'

New in 2.7

>>> '{:20,.2f}'.format(18446744073709551616.0)
'18,446,744,073,709,551,616.00'

http://docs.python.org/dev/whatsnew/2.7.html#pep-0378

Not quite sure why it’s not mentioned more online (or on this thread), but the Babel package (and Django utilities) from the Edgewall guys is awesome for currency formatting (and lots of other i18n tasks). It’s nice because it doesn’t suffer from the need to do everything globally like the core Python locale module.

The example the OP gave would simply be:

>>> import babel.numbers
>>> import decimal
>>> babel.numbers.format_currency( decimal.Decimal( "188518982.18" ), "GBP" )
£188,518,982.18

This is an ancient post, but I just implemented the following solution which:

• Doesn’t require external modules
• Doesn’t require creating a new function
• Can be done in-line
• Handles multiple variables
• Handles negative dollar amounts

Code:

num1 = 4153.53
num2 = -23159.398598

print 'This: ${:0,.0f} and this: ${:0,.2f}'.format(num1, num2).replace('$-','-$')

Output:

This: $4,154 and this: -$23,159.40

And for the original poster, obviously, just switch $ for £

My locale settings seemed incomplete, so I had too look beyond this SO answer and found:

http://docs.python.org/library/decimal.html#recipes

OS-independent

Just wanted to share here.

If you are using OSX and have yet to set your locale module setting this first answer will not work you will receive the following error:

Traceback (most recent call last):File "<stdin>", line 1, in <module> File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/locale.py", line 221, in currency
raise ValueError("Currency formatting is not possible using "ValueError: Currency formatting is not possible using the 'C' locale.

To remedy this you will have to do use the following:

locale.setlocale(locale.LC_ALL, 'en_US')

"{:0,.2f}".format(float(your_numeric_value)) in Python 3 does the job; it gives out something like one of the following lines:

10,938.29
10,899.00
10,898.99
2,328.99

If I were you, I would use BABEL: http://babel.pocoo.org/en/latest/index.html

from babel.numbers import format_decimal


format_decimal(188518982.18, locale='en_US')

Oh, that’s an interesting beast.

I’ve spent considerable time of getting that right, there are three main issues that differs from locale to locale: – currency symbol and direction – thousand separator – decimal point

I’ve written my own rather extensive implementation of this which is part of the kiwi python framework, check out the LGPL:ed source here:

http://svn.async.com.br/cgi-bin/viewvc.cgi/kiwi/trunk/kiwi/currency.py?view=markup

The code is slightly Linux/Glibc specific, but shouldn’t be too difficult to adopt to windows or other unixes.

Once you have that installed you can do the following:

>>> from kiwi.datatypes import currency
>>> v = currency('10.5').format()

Which will then give you:

'$10.50'

or

'10,50 kr'

Depending on the currently selected locale.

The main point this post has over the other is that it will work with older versions of python. locale.currency was introduced in python 2.5.

#printing the variable ‘Total:’ in a format that looks like this ‘9,348.237’

print ('Total:',   '{:7,.3f}'.format(zum1))

where the ‘{:7,.3f}’ es the number of spaces for formatting the number in this case is a million with 3 decimal points. Then you add the ‘.format(zum1). The zum1 is tha variable that has the big number for the sum of all number in my particular program. Variable can be anything that you decide to use.

Inspired by the code above :D

def money_format(value):
    value = str(value).split('.')
    money = ''
    count = 1

    for digit in value[0][::-1]:
        if count != 3:
            money += digit
            count += 1
        else:
            money += f'{digit},'
            count = 1

    if len(value) == 1:
        money = ('$' + money[::-1]).replace('$-','-$')
    else:
        money = ('$' + money[::-1] + '.' + value[1]).replace('$-','-$')

    return money

I’ve come to look at the same thing and found python-money not really used it yet but maybe a mix of the two would be good

A lambda for calculating it inside a function, with help from @Nate’s answer

converter = lambda amount, currency: "%s%s%s" %(
    "-" if amount < 0 else "", 
    currency, 
    ('{:%d,.2f}'%(len(str(amount))+3)).format(abs(amount)).lstrip())

and then,

>>> converter(123132132.13, "$")
'$123,132,132.13'

>>> converter(-123132132.13, "$")
'-$123,132,132.13'

Simple python code!

def format_us_currency(value):
    value=str(value)
    if value.count(',')==0:
        b,n,v='',1,value
        value=value[:value.rfind('.')]
        for i in value[::-1]:
            b=','+i+b if n==3 else i+b
            n=1 if n==3 else n+1
        b=b[1:] if b[0]==',' else b
        value=b+v[v.rfind('.'):]
    return '$'+(value.rstrip('0').rstrip('.') if '.' in value else value)