标签归档:django-templates

遍历模板中的模型实例字段名称和值

问题:遍历模板中的模型实例字段名称和值

我正在尝试创建一个基本模板以显示所选实例的字段值及其名称。可以将其视为表格式的该实例的值的标准输出,第一列具有字段名称(如果在字段上指定,则为verbose_name),第二列具有该字段的值。

例如,假设我们具有以下模型定义:

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

我希望将其像这样在模板中输出(假定具有给定值的实例):

Field Name      Field Value
----------      -----------
Name            Wayne Koorts
E-mail          waynes@email.com

我要实现的目标是能够将模型的实例传递到模板,并能够在模板中动态地对其进行迭代,如下所示:

<table>
    {% for field in fields %}
        <tr>
            <td>{{ field.name }}</td>
            <td>{{ field.value }}</td>
        </tr>
    {% endfor %}
</table>

有没有一种经过Django批准的简洁方法?这似乎是一项非常普通的任务,对于这个特定项目,我将需要经常执行。

I’m trying to create a basic template to display the selected instance’s field values, along with their names. Think of it as just a standard output of the values of that instance in table format, with the field name (verbose_name specifically if specified on the field) in the first column and the value of that field in the second column.

For example, let’s say we have the following model definition:

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

I would want it to be output in the template like so (assume an instance with the given values):

Field Name      Field Value
----------      -----------
Name            Wayne Koorts
E-mail          waynes@email.com

What I’m trying to achieve is being able to pass an instance of the model to a template and be able to iterate over it dynamically in the template, something like this:

<table>
    {% for field in fields %}
        <tr>
            <td>{{ field.name }}</td>
            <td>{{ field.value }}</td>
        </tr>
    {% endfor %}
</table>

Is there a neat, “Django-approved” way to do this? It seems like a very common task, and I will need to do it often for this particular project.


回答 0

model._meta.get_all_field_names()将为您提供模型的所有字段名称,然后您就可以使用model._meta.get_field()该方法来获取详细名称,并getattr(model_instance, 'field_name')从模型中获取值。

注意:model._meta.get_all_field_names()在django 1.9中已弃用。而是使用model._meta.get_fields()获取模型的字段并field.name获取每个字段名称。

model._meta.get_all_field_names() will give you all the model’s field names, then you can use model._meta.get_field() to work your way to the verbose name, and getattr(model_instance, 'field_name') to get the value from the model.

NOTE: model._meta.get_all_field_names() is deprecated in django 1.9. Instead use model._meta.get_fields() to get the model’s fields and field.name to get each field name.


回答 1

您可以使用Django的to-python queryset序列化程序。

只需将以下代码放入您的视图中:

from django.core import serializers
data = serializers.serialize( "python", SomeModel.objects.all() )

然后在模板中:

{% for instance in data %}
    {% for field, value in instance.fields.items %}
        {{ field }}: {{ value }}
    {% endfor %}
{% endfor %}

它的巨大优点是它处理关系字段。

对于字段子集,请尝试:

data = serializers.serialize('python', SomeModel.objects.all(), fields=('name','size'))

You can use Django’s to-python queryset serializer.

Just put the following code in your view:

from django.core import serializers
data = serializers.serialize( "python", SomeModel.objects.all() )

And then in the template:

{% for instance in data %}
    {% for field, value in instance.fields.items %}
        {{ field }}: {{ value }}
    {% endfor %}
{% endfor %}

Its great advantage is the fact that it handles relation fields.

For the subset of fields try:

data = serializers.serialize('python', SomeModel.objects.all(), fields=('name','size'))

回答 2

终于在开发邮件列表中找到了一个很好的解决方案:

在视图中添加:

from django.forms.models import model_to_dict

def show(request, object_id):
    object = FooForm(data=model_to_dict(Foo.objects.get(pk=object_id)))
    return render_to_response('foo/foo_detail.html', {'object': object})

在模板中添加:

{% for field in object %}
    <li><b>{{ field.label }}:</b> {{ field.data }}</li>
{% endfor %}

Finally found a good solution to this on the dev mailing list:

In the view add:

from django.forms.models import model_to_dict

def show(request, object_id):
    object = FooForm(data=model_to_dict(Foo.objects.get(pk=object_id)))
    return render_to_response('foo/foo_detail.html', {'object': object})

in the template add:

{% for field in object %}
    <li><b>{{ field.label }}:</b> {{ field.data }}</li>
{% endfor %}

回答 3

鉴于Django 1.8的发布(以及Model _meta API的形式化,我认为我将使用更新的答案对此进行更新。

假设模型相同:

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

Django <= 1.7

fields = [(f.verbose_name, f.name) for f in Client._meta.fields]
>>> fields
[(u'ID', u'id'), (u'name', u'name'), (u'E-mail', u'email')]

Django 1.8+(正式的Model _meta API)

在Django 1.8中进行了更改:

Model _metaAPI一直是Django内部的,但尚未正式记录和支持。作为使此API公开的工作的一部分,一些已经存在的API入口点已稍作更改。提供了迁移指南,以帮助您转换代码以使用新的官方API。

在下面的例子中,我们将利用形式化方法检索模型的所有字段的实例通过Client._meta.get_fields()

fields = [(f.verbose_name, f.name) for f in Client._meta.get_fields()]
>>> fields
[(u'ID', u'id'), (u'name', u'name'), (u'E-mail', u'email')]

实际上,已经引起我注意的是,以上内容对于所需的内容来说有些过分了(我同意!)。简单胜于复杂。我将以上内容留作参考。但是,要在模板中显示,最好的方法是使用ModelForm并传入实例。您可以遍历表单(等同于遍历表单的每个字段),并使用label属性检索模型字段的verbose_name,并使用value方法检索值:

from django.forms import ModelForm
from django.shortcuts import get_object_or_404, render
from .models import Client

def my_view(request, pk):
    instance = get_object_or_404(Client, pk=pk)
    
    class ClientForm(ModelForm):
        class Meta:
            model = Client
            fields = ('name', 'email')

    form = ClientForm(instance=instance)

    return render(
        request, 
        template_name='template.html',
        {'form': form}
    )

现在,我们在模板中渲染字段:

<table>
    <thead>
        {% for field in form %}
            <th>{{ field.label }}</th>
        {% endfor %}
    </thead>
    <tbody>
        <tr>
            {% for field in form %}
                <td>{{ field.value|default_if_none:'' }}</td>
            {% endfor %}
        </tr>
    </tbody>
</table>
 

In light of Django 1.8’s release (and the formalization of the Model _meta API, I figured I would update this with a more recent answer.

Assuming the same model:

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

Django <= 1.7

fields = [(f.verbose_name, f.name) for f in Client._meta.fields]
>>> fields
[(u'ID', u'id'), (u'name', u'name'), (u'E-mail', u'email')]

Django 1.8+ (formalized Model _meta API)

Changed in Django 1.8:

The Model _meta API has always existed as a Django internal, but wasn’t formally documented and supported. As part of the effort to make this API public, some of the already existing API entry points have changed slightly. A migration guide has been provided to assist in converting your code to use the new, official API.

In the below example, we will utilize the formalized method for retrieving all field instances of a model via Client._meta.get_fields():

fields = [(f.verbose_name, f.name) for f in Client._meta.get_fields()]
>>> fields
[(u'ID', u'id'), (u'name', u'name'), (u'E-mail', u'email')]

Actually, it has been brought to my attention that the above is slightly overboard for what was needed (I agree!). Simple is better than complex. I am leaving the above for reference. However, to display in the template, the best method would be to use a ModelForm and pass in an instance. You can iterate over the form (equivalent of iterating over each of the form’s fields) and use the label attribute to retrieve the verbose_name of the model field, and use the value method to retrieve the value:

from django.forms import ModelForm
from django.shortcuts import get_object_or_404, render
from .models import Client

def my_view(request, pk):
    instance = get_object_or_404(Client, pk=pk)
    
    class ClientForm(ModelForm):
        class Meta:
            model = Client
            fields = ('name', 'email')

    form = ClientForm(instance=instance)

    return render(
        request, 
        template_name='template.html',
        {'form': form}
    )

Now, we render the fields in the template:

<table>
    <thead>
        {% for field in form %}
            <th>{{ field.label }}</th>
        {% endfor %}
    </thead>
    <tbody>
        <tr>
            {% for field in form %}
                <td>{{ field.value|default_if_none:'' }}</td>
            {% endfor %}
        </tr>
    </tbody>
</table>
 

回答 4

这是使用模型方法的另一种方法。此版本可解析选择列表/选择字段,跳过空字段,并允许您排除特定字段。

def get_all_fields(self):
    """Returns a list of all field names on the instance."""
    fields = []
    for f in self._meta.fields:

        fname = f.name        
        # resolve picklists/choices, with get_xyz_display() function
        get_choice = 'get_'+fname+'_display'
        if hasattr(self, get_choice):
            value = getattr(self, get_choice)()
        else:
            try:
                value = getattr(self, fname)
            except AttributeError:
                value = None

        # only display fields with values and skip some fields entirely
        if f.editable and value and f.name not in ('id', 'status', 'workshop', 'user', 'complete') :

            fields.append(
              {
               'label':f.verbose_name, 
               'name':f.name, 
               'value':value,
              }
            )
    return fields

然后在您的模板中:

{% for f in app.get_all_fields %}
  <dt>{{f.label|capfirst}}</dt>
    <dd>
      {{f.value|escape|urlize|linebreaks}}
    </dd>
{% endfor %}

Here’s another approach using a model method. This version resolves picklist/choice fields, skips empty fields, and lets you exclude specific fields.

def get_all_fields(self):
    """Returns a list of all field names on the instance."""
    fields = []
    for f in self._meta.fields:

        fname = f.name        
        # resolve picklists/choices, with get_xyz_display() function
        get_choice = 'get_'+fname+'_display'
        if hasattr(self, get_choice):
            value = getattr(self, get_choice)()
        else:
            try:
                value = getattr(self, fname)
            except AttributeError:
                value = None

        # only display fields with values and skip some fields entirely
        if f.editable and value and f.name not in ('id', 'status', 'workshop', 'user', 'complete') :

            fields.append(
              {
               'label':f.verbose_name, 
               'name':f.name, 
               'value':value,
              }
            )
    return fields

Then in your template:

{% for f in app.get_all_fields %}
  <dt>{{f.label|capfirst}}</dt>
    <dd>
      {{f.value|escape|urlize|linebreaks}}
    </dd>
{% endfor %}

回答 5

好的,我知道这有点晚了,但是由于我在找到正确答案之前偶然发现了这个,其他人也可能会发现。

Django文档中

# This list contains a Blog object.
>>> Blog.objects.filter(name__startswith='Beatles')
[<Blog: Beatles Blog>]

# This list contains a dictionary.
>>> Blog.objects.filter(name__startswith='Beatles').values()
[{'id': 1, 'name': 'Beatles Blog', 'tagline': 'All the latest Beatles news.'}]

Ok, I know this is a bit late, but since I stumbled upon this before finding the correct answer so might someone else.

From the django docs:

# This list contains a Blog object.
>>> Blog.objects.filter(name__startswith='Beatles')
[<Blog: Beatles Blog>]

# This list contains a dictionary.
>>> Blog.objects.filter(name__startswith='Beatles').values()
[{'id': 1, 'name': 'Beatles Blog', 'tagline': 'All the latest Beatles news.'}]

回答 6

您可以使用的values()方法,该方法queryset返回字典。此外,此方法接受要作为子集的字段列表。该values()方法不适用于get(),因此必须使用filter()(请参阅QuerySet API)。

view

def show(request, object_id):
   object = Foo.objects.filter(id=object_id).values()[0]
   return render_to_response('detail.html', {'object': object})

detail.html

<ul>
   {% for key, value in object.items %}
        <li><b>{{ key }}:</b> {{ value }}</li>
   {% endfor %}
</ul>

对于过滤器返回的实例集合

   object = Foo.objects.filter(id=object_id).values() # no [0]

detail.html

{% for instance in object %}
<h1>{{ instance.id }}</h1>
<ul>
    {% for key, value in instance.items %}
        <li><b>{{ key }}:</b>  {{ value }}</li>
    {% endfor %}
</ul>
{% endfor %}

You can use the values() method of a queryset, which returns a dictionary. Further, this method accepts a list of fields to subset on. The values() method will not work with get(), so you must use filter() (refer to the QuerySet API).

In view

def show(request, object_id):
   object = Foo.objects.filter(id=object_id).values()[0]
   return render_to_response('detail.html', {'object': object})

In detail.html

<ul>
   {% for key, value in object.items %}
        <li><b>{{ key }}:</b> {{ value }}</li>
   {% endfor %}
</ul>

For a collection of instances returned by filter:

   object = Foo.objects.filter(id=object_id).values() # no [0]

In detail.html

{% for instance in object %}
<h1>{{ instance.id }}</h1>
<ul>
    {% for key, value in instance.items %}
        <li><b>{{ key }}:</b>  {{ value }}</li>
    {% endfor %}
</ul>
{% endfor %}

回答 7

我使用了https://stackoverflow.com/a/3431104/2022534,但以此替换了Django的model_to_dict()以便能够处理ForeignKey:

def model_to_dict(instance):
    data = {}
    for field in instance._meta.fields:
        data[field.name] = field.value_from_object(instance)
        if isinstance(field, ForeignKey):
            data[field.name] = field.rel.to.objects.get(pk=data[field.name])
    return data

请注意,我已经删除了不需要的部分,从而大大简化了它。您可能要放回去。

I used https://stackoverflow.com/a/3431104/2022534 but replaced Django’s model_to_dict() with this to be able to handle ForeignKey:

def model_to_dict(instance):
    data = {}
    for field in instance._meta.fields:
        data[field.name] = field.value_from_object(instance)
        if isinstance(field, ForeignKey):
            data[field.name] = field.rel.to.objects.get(pk=data[field.name])
    return data

Please note that I have simplified it quite a bit by removing the parts of the original I didn’t need. You might want to put those back.


回答 8

您可以使用表格为您完成工作。

def my_model_view(request, mymodel_id):
    class MyModelForm(forms.ModelForm):
        class Meta:
            model = MyModel

    model = get_object_or_404(MyModel, pk=mymodel_id)
    form = MyModelForm(instance=model)
    return render(request, 'model.html', { 'form': form})

然后在模板中:

<table>
    {% for field in form %}
        <tr>
            <td>{{ field.name }}</td>
            <td>{{ field.value }}</td>
        </tr>
    {% endfor %}
</table>

You can have a form do the work for you.

def my_model_view(request, mymodel_id):
    class MyModelForm(forms.ModelForm):
        class Meta:
            model = MyModel

    model = get_object_or_404(MyModel, pk=mymodel_id)
    form = MyModelForm(instance=model)
    return render(request, 'model.html', { 'form': form})

Then in the template:

<table>
    {% for field in form %}
        <tr>
            <td>{{ field.name }}</td>
            <td>{{ field.value }}</td>
        </tr>
    {% endfor %}
</table>

回答 9

确实应该有一种内置方法来执行此操作。我编写了此实用程序build_pretty_data_view,该实用程序接受模型对象和表单实例(基于您的模型的表单)并返回SortedDict

该解决方案的优势包括:

  • 它使用Django的内置命令保留命令 SortedDict
  • 尝试获取标签/详细名称时,但如果未定义则回退到字段名称。
  • 也可以选择 exclude()字段名称列表以排除某些字段。
  • 如果您的表单类包含一个Meta: exclude(),但您仍想返回这些值,则将这些字段添加到可选append()列表中。

要使用此解决方案,请先将此文件/功能添加到某处,然后将其导入到中views.py

utils.py

#!/usr/bin/env python
# -*- coding: utf-8 -*-
# vim: ai ts=4 sts=4 et sw=4
from django.utils.datastructures import SortedDict


def build_pretty_data_view(form_instance, model_object, exclude=(), append=()):
    i=0
    sd=SortedDict()

    for j in append:
        try:
            sdvalue={'label':j.capitalize(),
                     'fieldvalue':model_object.__getattribute__(j)}
            sd.insert(i, j, sdvalue)
            i+=1
        except(AttributeError):
            pass

    for k,v in form_instance.fields.items():
        sdvalue={'label':"", 'fieldvalue':""}
        if not exclude.__contains__(k):
            if v.label is not None:
                sdvalue = {'label':v.label,
                           'fieldvalue': model_object.__getattribute__(k)}
            else:
                sdvalue = {'label':k,
                           'fieldvalue': model_object.__getattribute__(k)}
            sd.insert(i, k, sdvalue)
            i+=1
    return sd

因此,现在views.py您可以执行以下操作

from django.shortcuts import render_to_response
from django.template import RequestContext
from utils import build_pretty_data_view
from models import Blog
from forms import BlogForm
.
.
def my_view(request):
   b=Blog.objects.get(pk=1)
   bf=BlogForm(instance=b)
   data=build_pretty_data_view(form_instance=bf, model_object=b,
                        exclude=('number_of_comments', 'number_of_likes'),
                        append=('user',))

   return render_to_response('my-template.html',
                          RequestContext(request,
                                         {'data':data,}))

现在,您my-template.html可以在模板中像这样遍历数据…

{% for field,value in data.items %}

    <p>{{ field }} : {{value.label}}: {{value.fieldvalue}}</p>

{% endfor %}

祝好运。希望这对某人有帮助!

There should really be a built-in way to do this. I wrote this utility build_pretty_data_view that takes a model object and form instance (a form based on your model) and returns a SortedDict.

Benefits to this solution include:

  • It preserves order using Django’s built-in SortedDict.
  • When tries to get the label/verbose_name, but falls back to the field name if one is not defined.
  • It will also optionally take an exclude() list of field names to exclude certain fields.
  • If your form class includes a Meta: exclude(), but you still want to return the values, then add those fields to the optional append() list.

To use this solution, first add this file/function somewhere, then import it into your views.py.

utils.py

#!/usr/bin/env python
# -*- coding: utf-8 -*-
# vim: ai ts=4 sts=4 et sw=4
from django.utils.datastructures import SortedDict


def build_pretty_data_view(form_instance, model_object, exclude=(), append=()):
    i=0
    sd=SortedDict()

    for j in append:
        try:
            sdvalue={'label':j.capitalize(),
                     'fieldvalue':model_object.__getattribute__(j)}
            sd.insert(i, j, sdvalue)
            i+=1
        except(AttributeError):
            pass

    for k,v in form_instance.fields.items():
        sdvalue={'label':"", 'fieldvalue':""}
        if not exclude.__contains__(k):
            if v.label is not None:
                sdvalue = {'label':v.label,
                           'fieldvalue': model_object.__getattribute__(k)}
            else:
                sdvalue = {'label':k,
                           'fieldvalue': model_object.__getattribute__(k)}
            sd.insert(i, k, sdvalue)
            i+=1
    return sd

So now in your views.py you might do something like this

from django.shortcuts import render_to_response
from django.template import RequestContext
from utils import build_pretty_data_view
from models import Blog
from forms import BlogForm
.
.
def my_view(request):
   b=Blog.objects.get(pk=1)
   bf=BlogForm(instance=b)
   data=build_pretty_data_view(form_instance=bf, model_object=b,
                        exclude=('number_of_comments', 'number_of_likes'),
                        append=('user',))

   return render_to_response('my-template.html',
                          RequestContext(request,
                                         {'data':data,}))

Now in your my-template.html template you can iterate over the data like so…

{% for field,value in data.items %}

    <p>{{ field }} : {{value.label}}: {{value.fieldvalue}}</p>

{% endfor %}

Good Luck. Hope this helps someone!


回答 10

下面是我的,受到黑客的 启发get_all_fields。它获取一个模型实例的字典,如果遇到关系字段,则递归将字段值分配给字典。

def to_dict(obj, exclude=[]):
    """生成一个 dict, 递归包含一个 model instance 数据.
    """
    tree = {}
    for field in obj._meta.fields + obj._meta.many_to_many:
        if field.name in exclude or \
           '%s.%s' % (type(obj).__name__, field.name) in exclude:
            continue

        try :
            value = getattr(obj, field.name)
        except obj.DoesNotExist:
            value = None

        if type(field) in [ForeignKey, OneToOneField]:
            tree[field.name] = to_dict(value, exclude=exclude)
        elif isinstance(field, ManyToManyField):
            vs = []
            for v in value.all():
                vs.append(to_dict(v, exclude=exclude))
            tree[field.name] = vs
        elif isinstance(field, DateTimeField):
            tree[field.name] = str(value)
        elif isinstance(field, FileField):
            tree[field.name] = {'url': value.url}
        else:
            tree[field.name] = value

    return tree

此函数主要用于将模型实例转储到json数据:

def to_json(self):
    tree = to_dict(self, exclude=('id', 'User.password'))
    return json.dumps(tree, ensure_ascii=False)

Below is mine, inspired by shacker’s get_all_fields. It gets a dict of one model instance, if encounter relation field, then asign the field value a dict recursively.

def to_dict(obj, exclude=[]):
    """生成一个 dict, 递归包含一个 model instance 数据.
    """
    tree = {}
    for field in obj._meta.fields + obj._meta.many_to_many:
        if field.name in exclude or \
           '%s.%s' % (type(obj).__name__, field.name) in exclude:
            continue

        try :
            value = getattr(obj, field.name)
        except obj.DoesNotExist:
            value = None

        if type(field) in [ForeignKey, OneToOneField]:
            tree[field.name] = to_dict(value, exclude=exclude)
        elif isinstance(field, ManyToManyField):
            vs = []
            for v in value.all():
                vs.append(to_dict(v, exclude=exclude))
            tree[field.name] = vs
        elif isinstance(field, DateTimeField):
            tree[field.name] = str(value)
        elif isinstance(field, FileField):
            tree[field.name] = {'url': value.url}
        else:
            tree[field.name] = value

    return tree

This function is mainly used to dump a model instance to json data:

def to_json(self):
    tree = to_dict(self, exclude=('id', 'User.password'))
    return json.dumps(tree, ensure_ascii=False)

回答 11

我建议不要编写每个模型,而是建议编写一个模板标签,该标签将返回给定模型的所有字段。
每个对象都有字段列表._meta.fields
每个字段对象都具有name返回其名称的属性,而value_to_string()模型随附的方法object将返回其值。
其余的就像Django文档中所说的那样简单。

这是我的示例,此templatetag可能如下所示:

    from django.conf import settings
    from django import template

    if not getattr(settings, 'DEBUG', False):
        raise template.TemplateSyntaxError('get_fields is available only when DEBUG = True')


    register = template.Library()

    class GetFieldsNode(template.Node):
        def __init__(self, object, context_name=None):
            self.object = template.Variable(object)
            self.context_name = context_name

        def render(self, context):
            object = self.object.resolve(context)
            fields = [(field.name, field.value_to_string(object)) for field in object._meta.fields]

            if self.context_name:
                context[self.context_name] = fields
                return ''
            else:
                return fields


    @register.tag
    def get_fields(parser, token):
        bits = token.split_contents()

        if len(bits) == 4 and bits[2] == 'as':
            return GetFieldsNode(bits[1], context_name=bits[3])
        elif len(bits) == 2:
            return GetFieldsNode(bits[1])
        else:
            raise template.TemplateSyntaxError("get_fields expects a syntax of "
                           "{% get_fields <object> [as <context_name>] %}")

Instead of editing every model I would recommend to write one template tag which will return all field of any model given.
Every object has list of fields ._meta.fields.
Every field object has attribute name that will return it’s name and method value_to_string() that supplied with your model object will return its value.
The rest is as simple as it’s said in Django documentation.

Here is my example how this templatetag might look like:

    from django.conf import settings
    from django import template

    if not getattr(settings, 'DEBUG', False):
        raise template.TemplateSyntaxError('get_fields is available only when DEBUG = True')


    register = template.Library()

    class GetFieldsNode(template.Node):
        def __init__(self, object, context_name=None):
            self.object = template.Variable(object)
            self.context_name = context_name

        def render(self, context):
            object = self.object.resolve(context)
            fields = [(field.name, field.value_to_string(object)) for field in object._meta.fields]

            if self.context_name:
                context[self.context_name] = fields
                return ''
            else:
                return fields


    @register.tag
    def get_fields(parser, token):
        bits = token.split_contents()

        if len(bits) == 4 and bits[2] == 'as':
            return GetFieldsNode(bits[1], context_name=bits[3])
        elif len(bits) == 2:
            return GetFieldsNode(bits[1])
        else:
            raise template.TemplateSyntaxError("get_fields expects a syntax of "
                           "{% get_fields <object> [as <context_name>] %}")

回答 12

是的,这并不漂亮,您必须自己制作包装纸。看一看内置的数据浏览应用程序,它具有您真正需要的所有功能。

Yeah it’s not pretty, you’ll have to make your own wrapper. Take a look at builtin databrowse app, which has all the functionality you need really.


回答 13

这可能被认为是黑客,但是在使用modelform_factory将模型实例转换为表单之前,我已经做到了。

Form类内部有很多信息,这些信息非常容易迭代,并且可以达到相同的目的,但开销会稍有增加。如果您的设备尺寸相对较小,我认为对性能的影响可以忽略不计。

当然,除了方便之外,一个优点是您可以在以后轻松地将表变成可编辑的数据网格。

This may be considered a hack but I’ve done this before using modelform_factory to turn a model instance into a form.

The Form class has a lot more information inside that’s super easy to iterate over and it will serve the same purpose at the expense of slightly more overhead. If your set sizes are relatively small I think the performance impact would be negligible.

The one advantage besides convenience of course is that you can easily turn the table into an editable datagrid at a later date.


回答 14

我想出了以下方法,该方法对我有用,因为在每种情况下,模型都会有一个与之关联的ModelForm。

def GetModelData(form, fields):
    """
    Extract data from the bound form model instance and return a
    dictionary that is easily usable in templates with the actual
    field verbose name as the label, e.g.

    model_data{"Address line 1": "32 Memory lane",
               "Address line 2": "Brainville",
               "Phone": "0212378492"}

    This way, the template has an ordered list that can be easily
    presented in tabular form.
    """
    model_data = {}
    for field in fields:
        model_data[form[field].label] = eval("form.data.%s" % form[field].name)
    return model_data

@login_required
def clients_view(request, client_id):
    client = Client.objects.get(id=client_id)
    form = AddClientForm(client)

    fields = ("address1", "address2", "address3", "address4",
              "phone", "fax", "mobile", "email")
    model_data = GetModelData(form, fields)

    template_vars = RequestContext(request,
        {
            "client": client,
            "model_data": model_data
        }
    )
    return render_to_response("clients-view.html", template_vars)

这是我用于此特定视图的模板的摘录:

<table class="client-view">
    <tbody>
    {% for field, value in model_data.items %}
        <tr>
            <td class="field-name">{{ field }}</td><td>{{ value }}</td>
        </tr>
    {% endfor %}
    </tbody>
</table>

关于此方法的好处是,我可以使用传递给GetModelData的元组并指定字段名称,在逐个模板的基础上选择要显示字段标签的顺序。这也使我可以排除某些字段(例如,用户外键),因为只有通过元组传递的字段名称才内置在最终字典中。

我不会接受这个答案,因为我敢肯定有人可以提出更多“ Djangonic”的概念:-)

更新:我选择此作为最终答案,因为这是我所需要的,是最简单的答案。感谢所有贡献答案的人。

I’ve come up with the following method, which works for me because in every case the model will have a ModelForm associated with it.

def GetModelData(form, fields):
    """
    Extract data from the bound form model instance and return a
    dictionary that is easily usable in templates with the actual
    field verbose name as the label, e.g.

    model_data{"Address line 1": "32 Memory lane",
               "Address line 2": "Brainville",
               "Phone": "0212378492"}

    This way, the template has an ordered list that can be easily
    presented in tabular form.
    """
    model_data = {}
    for field in fields:
        model_data[form[field].label] = eval("form.data.%s" % form[field].name)
    return model_data

@login_required
def clients_view(request, client_id):
    client = Client.objects.get(id=client_id)
    form = AddClientForm(client)

    fields = ("address1", "address2", "address3", "address4",
              "phone", "fax", "mobile", "email")
    model_data = GetModelData(form, fields)

    template_vars = RequestContext(request,
        {
            "client": client,
            "model_data": model_data
        }
    )
    return render_to_response("clients-view.html", template_vars)

Here is an extract from the template I am using for this particular view:

<table class="client-view">
    <tbody>
    {% for field, value in model_data.items %}
        <tr>
            <td class="field-name">{{ field }}</td><td>{{ value }}</td>
        </tr>
    {% endfor %}
    </tbody>
</table>

The nice thing about this method is that I can choose on a template-by-template basis the order in which I would like to display the field labels, using the tuple passed in to GetModelData and specifying the field names. This also allows me to exclude certain fields (e.g. a User foreign key) as only the field names passed in via the tuple are built into the final dictionary.

I’m not going to accept this as the answer because I’m sure someone can come up with something more “Djangonic” :-)

Update: I’m choosing this as the final answer because it is the simplest out of those given that does what I need. Thanks to everyone who contributed answers.


回答 15

我的Django 1.7解决方案:

这里有确切的变量,但是您肯定可以剖析此示例

这里的关键是几乎使用.__dict__模型
views.py的

def display_specific(request, key):
  context = {
    'question_id':question_id,
    'client':Client.objects.get(pk=key).__dict__,
  }
  return render(request, "general_household/view_specific.html", context)

模板

{% for field in gen_house %}
    {% if field != '_state' %}
        {{ gen_house|getattribute:field }}
    {% endif %}
{% endfor %}

在模板中,我使用了过滤器来访问dict
filter.py中的字段:

@register.filter(name='getattribute')
def getattribute(value, arg):
  if value is None or arg is None:
    return ""
  try:
    return value[arg]
  except KeyError:
    return ""
  except TypeError:
    return ""

Django 1.7 solution for me:

There variables are exact to the question, but you should definitely be able to dissect this example

The key here is to pretty much use the .__dict__ of the model
views.py:

def display_specific(request, key):
  context = {
    'question_id':question_id,
    'client':Client.objects.get(pk=key).__dict__,
  }
  return render(request, "general_household/view_specific.html", context)

template:

{% for field in gen_house %}
    {% if field != '_state' %}
        {{ gen_house|getattribute:field }}
    {% endif %}
{% endfor %}

in the template I used a filter to access the field in the dict
filters.py:

@register.filter(name='getattribute')
def getattribute(value, arg):
  if value is None or arg is None:
    return ""
  try:
    return value[arg]
  except KeyError:
    return ""
  except TypeError:
    return ""

回答 16

我正在使用它,https://github.com/miracle2k/django-tables

<table>
<tr>
    {% for column in table.columns %}
    <th><a href="?sort={{ column.name_toggled }}">{{ column }}</a></th>
    {% endfor %}
</tr>
{% for row in table.rows %}
    <tr>
    {% for value in row %}
        <td>{{ value }}</td>
    {% endfor %}
    </tr>
{% endfor %}
</table>

I’m using this, https://github.com/miracle2k/django-tables.

<table>
<tr>
    {% for column in table.columns %}
    <th><a href="?sort={{ column.name_toggled }}">{{ column }}</a></th>
    {% endfor %}
</tr>
{% for row in table.rows %}
    <tr>
    {% for value in row %}
        <td>{{ value }}</td>
    {% endfor %}
    </tr>
{% endfor %}
</table>

回答 17

这种方法显示了如何使用django的ModelForm之类的类和{{form.as_table}}之类的模板标签,但是如何使所有表看起来像数据输出,而不是表单。

第一步是继承django的TextInput小部件:

from django import forms
from django.utils.safestring import mark_safe
from django.forms.util import flatatt

class PlainText(forms.TextInput):
    def render(self, name, value, attrs=None):
        if value is None:
            value = ''
        final_attrs = self.build_attrs(attrs)
        return mark_safe(u'<p %s>%s</p>' % (flatatt(final_attrs),value))

然后,我将django的ModelForm子类化,以将默认小部件换成只读版本:

from django.forms import ModelForm

class ReadOnlyModelForm(ModelForm):
    def __init__(self,*args,**kwrds):
        super(ReadOnlyModelForm,self).__init__(*args,**kwrds)
        for field in self.fields:
            if isinstance(self.fields[field].widget,forms.TextInput) or \
               isinstance(self.fields[field].widget,forms.Textarea):
                self.fields[field].widget=PlainText()
            elif isinstance(self.fields[field].widget,forms.CheckboxInput):
                self.fields[field].widget.attrs['disabled']="disabled" 

这些是我唯一需要的小部件。但是将这个想法扩展到其他小部件并不难。

This approach shows how to use a class like django’s ModelForm and a template tag like {{ form.as_table }}, but have all the table look like data output, not a form.

The first step was to subclass django’s TextInput widget:

from django import forms
from django.utils.safestring import mark_safe
from django.forms.util import flatatt

class PlainText(forms.TextInput):
    def render(self, name, value, attrs=None):
        if value is None:
            value = ''
        final_attrs = self.build_attrs(attrs)
        return mark_safe(u'<p %s>%s</p>' % (flatatt(final_attrs),value))

Then I subclassed django’s ModelForm to swap out the default widgets for readonly versions:

from django.forms import ModelForm

class ReadOnlyModelForm(ModelForm):
    def __init__(self,*args,**kwrds):
        super(ReadOnlyModelForm,self).__init__(*args,**kwrds)
        for field in self.fields:
            if isinstance(self.fields[field].widget,forms.TextInput) or \
               isinstance(self.fields[field].widget,forms.Textarea):
                self.fields[field].widget=PlainText()
            elif isinstance(self.fields[field].widget,forms.CheckboxInput):
                self.fields[field].widget.attrs['disabled']="disabled" 

Those were the only widgets I needed. But it should not be difficult to extend this idea to other widgets.


回答 18

只需编辑@wonder

def to_dict(obj, exclude=[]):
    tree = {}
    for field in obj._meta.fields + obj._meta.many_to_many:
        if field.name in exclude or \
           '%s.%s' % (type(obj).__name__, field.name) in exclude:
            continue
        try :
            value = getattr(obj, field.name)
        except obj.DoesNotExist as e:
            value = None
        except ObjectDoesNotExist as e:
            value = None
            continue
        if type(field) in [ForeignKey, OneToOneField]:
            tree[field.name] = to_dict(value, exclude=exclude)
        elif isinstance(field, ManyToManyField):
            vs = []
            for v in value.all():
                vs.append(to_dict(v, exclude=exclude))
            tree[field.name] = vs
        else:
            tree[field.name] = obj.serializable_value(field.name)
    return tree

让Django处理除相关字段以外的所有其他字段。我觉得比较稳定

Just an edit of @wonder

def to_dict(obj, exclude=[]):
    tree = {}
    for field in obj._meta.fields + obj._meta.many_to_many:
        if field.name in exclude or \
           '%s.%s' % (type(obj).__name__, field.name) in exclude:
            continue
        try :
            value = getattr(obj, field.name)
        except obj.DoesNotExist as e:
            value = None
        except ObjectDoesNotExist as e:
            value = None
            continue
        if type(field) in [ForeignKey, OneToOneField]:
            tree[field.name] = to_dict(value, exclude=exclude)
        elif isinstance(field, ManyToManyField):
            vs = []
            for v in value.all():
                vs.append(to_dict(v, exclude=exclude))
            tree[field.name] = vs
        else:
            tree[field.name] = obj.serializable_value(field.name)
    return tree

Let Django handle all the other fields other than the related fields. I feel that is more stable


回答 19

看一下django-etc应用程序。它具有model_field_verbose_name用于从模板获取字段详细名称的模板标记:http : //django-etc.rtfd.org/en/latest/models.html#model-field-template-tags

Take a look at django-etc application. It has model_field_verbose_name template tag to get field verbose name from templates: http://django-etc.rtfd.org/en/latest/models.html#model-field-template-tags


回答 20

我只是在shell中测试了类似的东西,似乎可以做到这一点:

my_object_mapped = {attr.name: str(getattr(my_object, attr.name)) for attr in MyModel._meta.fields}

请注意,如果要用str()表示异物,则应在其str方法中对其进行定义。由此,您可以确定对象的值。然后,您可以渲染某种模板或其他任何模板。

I just tested something like this in shell and seems to do it’s job:

my_object_mapped = {attr.name: str(getattr(my_object, attr.name)) for attr in MyModel._meta.fields}

Note that if you want str() representation for foreign objects you should define it in their str method. From that you have dict of values for object. Then you can render some kind of template or whatever.


回答 21

Django> = 2.0

添加get_fields()到您的models.py

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

    def get_fields(self):
        return [(field.verbose_name, field.value_from_object(self)) for field in self.__class__._meta.fields]

然后object.get_fields按您的名称template.html

<table>
    {% for label, value in object.get_fields %}
        <tr>
            <td>{{ label }}</td>
            <td>{{ value }}</td>
        </tr>
    {% endfor %}
</table>

Django >= 2.0

Add get_fields() to your models.py:

class Client(Model):
    name = CharField(max_length=150)
    email = EmailField(max_length=100, verbose_name="E-mail")

    def get_fields(self):
        return [(field.verbose_name, field.value_from_object(self)) for field in self.__class__._meta.fields]

Then call it as object.get_fields on your template.html:

<table>
    {% for label, value in object.get_fields %}
        <tr>
            <td>{{ label }}</td>
            <td>{{ value }}</td>
        </tr>
    {% endfor %}
</table>

回答 22

<table border='1'>
	<tr>
		{% for mfild in fields%}
			<td>{{mfild}}</td>
		{% endfor%}
	</tr>
    {%for v in records%}
        <tr>
        	<td>{{v.id}}</td>
        	<td>{{v.title}}</td>
        	<td class="">{{v.desc}}</td>

        </tr>

    {% endfor%}
 </table>
 
 
enter code here

<table border='1'>
	<tr>
		{% for mfild in fields%}
			<td>{{mfild}}</td>
		{% endfor%}
	</tr>
    {%for v in records%}
        <tr>
        	<td>{{v.id}}</td>
        	<td>{{v.title}}</td>
        	<td class="">{{v.desc}}</td>

        </tr>

    {% endfor%}
 </table>
 
 
enter code here

如何在Django模板中访问字典元素?

问题:如何在Django模板中访问字典元素?

我想打印出每个选择获得的票数。我在模板中有以下代码:

{% for choice in choices %}
    {{choice.choice}} - {{votes[choice.id]}} <br />
{% endfor %}

votes只是一个字典,而choices只是一个模型对象。

该消息引发异常:

"Could not parse the remainder"

I would like to print out the number of votes that each choice got. I have this code in a template:

{% for choice in choices %}
    {{choice.choice}} - {{votes[choice.id]}} <br />
{% endfor %}

votes is just a dictionary while choices is a model object.

It raises an exception with this message:

"Could not parse the remainder"

回答 0

为了回应/扩展Jeff的评论,我认为您应该针对的只是Choice类中的一个属性,该属性计算与该对象关联的投票数:

    class Choice(models.Model):
        text = models.CharField(max_length=200) 

        def calculateVotes(self):
            return Vote.objects.filter(choice = self).count()

        votes = property(calculateVotes)

然后在模板中,您可以执行以下操作:

    {% for choice in choices %}
            {{choice.choice}} - {{choice.votes}} <br />
    {% endfor %}

模板标签,恕我直言,此解决方案有些过分,但也不是一个糟糕的解决方案。Django中模板的目标是使您与模板中的代码隔离,反之亦然。

我会尝试上述方法,并查看ORM生成的SQL,因为我不确定它是否会预先缓存属性并仅为该属性创建子选择,还是会迭代/启用-需求运行查询以计算投票数。但是,如果它产生了残酷的查询,您总是可以使用自己收集的数据填充视图中的属性。

To echo / extend upon Jeff’s comment, what I think you should aim for is simply a property in your Choice class that calculates the number of votes associated with that object:

class Choice(models.Model):
    text = models.CharField(max_length=200)

    def calculateVotes(self):
        return Vote.objects.filter(choice=self).count()

    votes = property(calculateVotes)

And then in your template, you can do:

{% for choice in choices %}
    {{choice.choice}} - {{choice.votes}} <br />
{% endfor %}

The template tag, is IMHO a bit overkill for this solution, but it’s not a terrible solution either. The goal of templates in Django is to insulate you from code in your templates and vice-versa.

I’d try the above method and see what SQL the ORM generates as I’m not sure off the top of my head if it will pre-cache the properties and just create a subselect for the property or if it will iteratively / on-demand run the query to calculate vote count. But if it generates atrocious queries, you could always populate the property in your view with data you’ve collected yourself.


回答 1

choices = {'key1':'val1', 'key2':'val2'}

这是模板:

<ul>
{% for key, value in choices.items %} 
  <li>{{key}} - {{value}}</li>
{% endfor %}
</ul>

基本上,.items是Django关键字,它将字典分为(key, value)成对的列表,很像Python方法.items()。这样可以在Django模板中的字典上进行迭代。

choices = {'key1':'val1', 'key2':'val2'}

Here’s the template:

<ul>
{% for key, value in choices.items %} 
  <li>{{key}} - {{value}}</li>
{% endfor %}
</ul>

Basically, .items is a Django keyword that splits a dictionary into a list of (key, value) pairs, much like the Python method .items(). This enables iteration over a dictionary in a Django template.


回答 2

您可以使用点符号:

点查找可以总结如下:当模板系统遇到变量名称中的点时,它将按以下顺序尝试以下查找:

  • 字典查询(例如foo [“ bar”])
  • 属性查询(例如foo.bar)
  • 方法调用(例如foo.bar())
  • 列表索引查找(例如,foo [2])

系统使用有效的第一种查找类型。这是短路逻辑。

you can use the dot notation:

Dot lookups can be summarized like this: when the template system encounters a dot in a variable name, it tries the following lookups, in this order:

  • Dictionary lookup (e.g., foo[“bar”])
  • Attribute lookup (e.g., foo.bar)
  • Method call (e.g., foo.bar())
  • List-index lookup (e.g., foo[2])

The system uses the first lookup type that works. It’s short-circuit logic.


回答 3

您需要在此处找到(或定义)“ get”模板标签。

标签定义:

@register.filter
def hash(h, key):
    return h[key]

它的用法如下:

{% for o in objects %}
  <li>{{ dictionary|hash:o.id }}</li>
{% endfor %}

You need to find (or define) a ‘get’ template tag, for example, here.

The tag definition:

@register.filter
def hash(h, key):
    return h[key]

And it’s used like:

{% for o in objects %}
  <li>{{ dictionary|hash:o.id }}</li>
{% endfor %}

回答 4

使用字典项目:

{% for key, value in my_dictionay.items %}
  <li>{{ key }} : {{ value }}</li>
{% endfor %}

Use Dictionary Items:

{% for key, value in my_dictionay.items %}
  <li>{{ key }} : {{ value }}</li>
{% endfor %}

回答 5

django_template_filter 过滤器名称get_value_from_dict

{{ your_dict|get_value_from_dict:your_key }}

django_template_filter filter name get_value_from_dict

{{ your_dict|get_value_from_dict:your_key }}

回答 6

类似于@russian_spy的回答:

<ul>
{% for choice in choices.items %} 
  <li>{{choice.0}} - {{choice.1}}</li>
{% endfor %}
</ul>

这可能适合分解更复杂的字典。

Similar to the answer by @russian_spy :

<ul>
{% for choice in choices.items %} 
  <li>{{choice.0}} - {{choice.1}}</li>
{% endfor %}
</ul>

This might be suitable for breaking down more complex dictionaries.


回答 7

理想情况下,您将在以投票方式发现自己的选择对象上创建方法,或者在模型之间创建关系。执行字典查找的模板标记也将起作用。

Ideally, you would create a method on the choice object that found itself in votes, or create a relationship between the models. A template tag that performed the dictionary lookup would work, too.


Django:显示选择值

问题:Django:显示选择值

models.py:

class Person(models.Model):
    name = models.CharField(max_length=200)
    CATEGORY_CHOICES = (
        ('M', 'Male'),
        ('F', 'Female'),
    )
    gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
    to_be_listed = models.BooleanField(default=True)
    description = models.CharField(max_length=20000, blank=True)

views.py:

def index(request):
    latest_person_list2 = Person.objects.filter(to_be_listed=True)
    return object_list(request, template_name='polls/schol.html',
                       queryset=latest_person_list, paginate_by=5)

在模板上,当我调用时person.gender,我得到'M'or 'F'而不是'Male'or 'Female'

如何显示值('Male''Female')而不是代码('M'/ 'F')?

models.py:

class Person(models.Model):
    name = models.CharField(max_length=200)
    CATEGORY_CHOICES = (
        ('M', 'Male'),
        ('F', 'Female'),
    )
    gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
    to_be_listed = models.BooleanField(default=True)
    description = models.CharField(max_length=20000, blank=True)

views.py:

def index(request):
    latest_person_list2 = Person.objects.filter(to_be_listed=True)
    return object_list(request, template_name='polls/schol.html',
                       queryset=latest_person_list, paginate_by=5)

On the template, when I call person.gender, I get 'M' or 'F' instead of 'Male' or 'Female'.

How to display the value ('Male' or 'Female') instead of the code ('M'/'F')?


回答 0

看来您处在正确的轨道上- get_FOO_display()无疑是您想要的:

模板中,您不包括()方法名称。请执行下列操作:

{{ person.get_gender_display }}

It looks like you were on the right track – get_FOO_display() is most certainly what you want:

In templates, you don’t include () in the name of a method. Do the following:

{{ person.get_gender_display }}

回答 1

对于每个设置了选项的字段,该对象将具有get_FOO_display()方法,其中FOO是字段的名称。此方法返回该字段的“人类可读”值。

在视图中

person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()

在模板中

{{ person.get_gender_display }}

get_FOO_display()的文档

For every field that has choices set, the object will have a get_FOO_display() method, where FOO is the name of the field. This method returns the “human-readable” value of the field.

In Views

person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()

In Template

{{ person.get_gender_display }}

Documentation of get_FOO_display()


回答 2

其他人指出,您需要的是get_FOO_display方法。我正在使用这个:

def get_type(self):
    return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]

遍历特定项目的所有选择,直到找到与项目类型匹配的项目

Others have pointed out that a get_FOO_display method is what you need. I’m using this:

def get_type(self):
    return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]

which iterates over all of the choices that a particular item has until it finds the one that matches the items type