标签归档：http-status-codes

知识问答

在Python中，如何使用urllib查看网站是404还是200？

问题：在Python中，如何使用urllib查看网站是404还是200？

如何通过urllib获取标头的代码？

点击查看英文原文

How to get the code of the headers through urllib?

回答 0

getcode（）方法（在python2.6中添加）返回与响应一起发送的HTTP状态代码；如果URL不是HTTP URL，则返回None。

>>> a=urllib.urlopen('http://www.google.com/asdfsf')
>>> a.getcode()
404
>>> a=urllib.urlopen('http://www.google.com/')
>>> a.getcode()
200
点击查看英文原文

The getcode() method (Added in python2.6) returns the HTTP status code that was sent with the response, or None if the URL is no HTTP URL.

>>> a=urllib.urlopen('http://www.google.com/asdfsf')
>>> a.getcode()
404
>>> a=urllib.urlopen('http://www.google.com/')
>>> a.getcode()
200

回答 1

您也可以使用urllib2：

import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

请注意，它HTTPError是一个子类，URLError用于存储HTTP状态代码。

点击查看英文原文

You can use urllib2 as well:

import urllib2

req = urllib2.Request('http://www.python.org/fish.html')
try:
    resp = urllib2.urlopen(req)
except urllib2.HTTPError as e:
    if e.code == 404:
        # do something...
    else:
        # ...
except urllib2.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
else:
    # 200
    body = resp.read()

Note that HTTPError is a subclass of URLError which stores the HTTP status code.

回答 2

对于Python 3：

import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')
点击查看英文原文

For Python 3:

import urllib.request, urllib.error

url = 'http://www.google.com/asdfsf'
try:
    conn = urllib.request.urlopen(url)
except urllib.error.HTTPError as e:
    # Return code error (e.g. 404, 501, ...)
    # ...
    print('HTTPError: {}'.format(e.code))
except urllib.error.URLError as e:
    # Not an HTTP-specific error (e.g. connection refused)
    # ...
    print('URLError: {}'.format(e.reason))
else:
    # 200
    # ...
    print('good')

回答 3

import urllib2

try:
    fileHandle = urllib2.urlopen('http://www.python.org/fish.html')
    data = fileHandle.read()
    fileHandle.close()
except urllib2.URLError, e:
    print 'you got an error with the code', e
点击查看英文原文 
import urllib2

try:
    fileHandle = urllib2.urlopen('http://www.python.org/fish.html')
    data = fileHandle.read()
    fileHandle.close()
except urllib2.URLError, e:
    print 'you got an error with the code', e
知识问答

带有参数数据的Python请求发布

问题：带有参数数据的Python请求发布

这是对API调用的原始请求：

POST http://192.168.3.45:8080/api/v2/event/log?sessionKey=b299d17b896417a7b18f46544d40adb734240cc2&format=json HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: application/json
Content-Length: 86
Host: 192.168.3.45:8080
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.1 (java 1.5)

{"eventType":"AAS_PORTAL_START","data":{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}"""

该请求返回成功（2xx）响应。

现在，我尝试使用发送此请求requests：

>>> import requests
>>> headers = {'content-type' : 'application/json'}
>>> data ={"eventType":"AAS_PORTAL_START","data{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}
>>> url = "http://192.168.3.45:8080/api/v2/event/log?sessionKey=9ebbd0b25760557393a43064a92bae539d962103&format=xml&platformId=1"
>>> requests.post(url,params=data,headers=headers)
<Response [400]>

一切对我来说看起来不错，我不太确定自己张贴的错误是什么引起400响应。

点击查看英文原文

This is the raw request for an API call:

POST http://192.168.3.45:8080/api/v2/event/log?sessionKey=b299d17b896417a7b18f46544d40adb734240cc2&format=json HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: application/json
Content-Length: 86
Host: 192.168.3.45:8080
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.1 (java 1.5)

{"eventType":"AAS_PORTAL_START","data":{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}"""

This request returns a success (2xx) response.

Now I am trying to post this request using requests:

>>> import requests
>>> headers = {'content-type' : 'application/json'}
>>> data ={"eventType":"AAS_PORTAL_START","data{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}
>>> url = "http://192.168.3.45:8080/api/v2/event/log?sessionKey=9ebbd0b25760557393a43064a92bae539d962103&format=xml&platformId=1"
>>> requests.post(url,params=data,headers=headers)
<Response [400]>

Everything looks fine to me and I am not quite sure what I posting wrong to get a 400 response.

回答 0

params用于GET样式的URL参数，data用于POST样式的正文信息。在请求中同时提供两种类型的信息是完全合法的，您的请求也是如此，但是您已经将URL参数编码为URL。

您的原始帖子虽然包含JSON数据。requests可以为您处理JSON编码，并且也会设置正确的代码Content-Header；您需要做的就是将Python对象传递为json关键字JSON编码。

您也可以拆分URL参数：

params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

然后通过以下方式发布您的数据：

import requests

url = 'http://192.168.3.45:8080/api/v2/event/log'

data = {"eventType": "AAS_PORTAL_START", "data": {"uid": "hfe3hf45huf33545", "aid": "1", "vid": "1"}}
params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

requests.post(url, params=params, json=data)

该json关键字是新的requests2.4.2版本; 如果仍然需要使用旧版本，请使用json模块手动编码JSON，然后将编码后的结果作为data密钥发布；在这种情况下，您将必须显式设置Content-Type标头：

import requests
import json

headers = {'content-type': 'application/json'}
url = 'http://192.168.3.45:8080/api/v2/event/log'

data = {"eventType": "AAS_PORTAL_START", "data": {"uid": "hfe3hf45huf33545", "aid": "1", "vid": "1"}}
params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

requests.post(url, params=params, data=json.dumps(data), headers=headers)
点击查看英文原文

params is for GET-style URL parameters, data is for POST-style body information. It is perfectly legal to provide both types of information in a request, and your request does so too, but you encoded the URL parameters into the URL already.

Your raw post contains JSON data though. requests can handle JSON encoding for you, and it’ll set the correct Content-Header too; all you need to do is pass in the Python object to be encoded as JSON into the json keyword argument.

You could split out the URL parameters as well:

params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

then post your data with:

import requests

url = 'http://192.168.3.45:8080/api/v2/event/log'

data = {"eventType": "AAS_PORTAL_START", "data": {"uid": "hfe3hf45huf33545", "aid": "1", "vid": "1"}}
params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

requests.post(url, params=params, json=data)

The json keyword is new in requests version 2.4.2; if you still have to use an older version, encode the JSON manually using the json module and post the encoded result as the data key; you will have to explicitly set the Content-Type header in that case:

import requests
import json

headers = {'content-type': 'application/json'}
url = 'http://192.168.3.45:8080/api/v2/event/log'

data = {"eventType": "AAS_PORTAL_START", "data": {"uid": "hfe3hf45huf33545", "aid": "1", "vid": "1"}}
params = {'sessionKey': '9ebbd0b25760557393a43064a92bae539d962103', 'format': 'xml', 'platformId': 1}

requests.post(url, params=params, data=json.dumps(data), headers=headers)

回答 1

将数据设置为此： 

data ={"eventType":"AAS_PORTAL_START","data":{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}
点击查看英文原文

Set data to this: 

data ={"eventType":"AAS_PORTAL_START","data":{"uid":"hfe3hf45huf33545","aid":"1","vid":"1"}}

回答 2

将响应分配给值并测试其属性。这些应该告诉您一些有用的信息。

response = requests.post(url,params=data,headers=headers)
response.status_code
response.text
  • status_code应该只重新确认您之前提供的代码
点击查看英文原文

Assign the response to a value and test the attributes of it. These should tell you something useful.

response = requests.post(url,params=data,headers=headers)
response.status_code
response.text
  • status_code should just reconfirm the code you were given before, of course